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I tried searching in here, but it's seems there is only commands that helps to delete blank lines in text file.
Is there a linux bash script that I can execute to delete blank lines in any text file I want ?
Replace file.txt with the name and path to your file and run this command in the shell:
sed -i '/^$/d' file.txt
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Display files in home directory starting with 'a' and third letter as 'c'.
This is what I have tried:
ls | grep '^a.c$'
But this is printing start with 'a' and ending with 'c'.
To meet your requirement, you can use
ls | grep -x a.c*
The -x option for grep means whole line match.
As for your current approach, $ stands for "end of line", so files ending with c will be printed.
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I'm trying to make cross compiler. And I commend like tar xvjf arm-linux-gcc-3.3.2.tar.bz2. But when ls /usr/local/arm there is nothing. arm directory doesn't exsist.... I dont know what to do.....
The command that you have there:
tar xvjf arm-linux-gcc-3.3.2.tar.bz2
extracts that archive within the directory you are currently in. So, if you expect things to show in /usr/local/arm ... you have to copy them there!
Thats about it - see here!
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My requirement is I will have xml and pdf files like pairs.(e.g.,file1.xml, file1.pdf and file2.xml,file2.pdf) in same folder.
I need to check for xml files which are not having pdf pair and move them to different folder.(e.g., if file3.xml doesn't have file3.pdf, I need to move it to different folder).
Please answer me the shell script to do get this functionality done.
You can remove the extension using parameter expansion:
#! /bin/bash
for file in *.xml ; do
if [[ ! -f ${file%.xml}.pdf ]] ; then
mv "$file" folder/
fi
done
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I've worked all night on this, but haven only solved part of the problem. I am trying to copy all files using the * wildcard that contain the word file in the filename into the work directory.
try doing this :
cp *file* ./work/
cp *file* work/
Is this homework?
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I have one file which contains filenames.
I want read those filenames from that file and move them to particular location.
awk '{old=$0;new=/path/pathsub/;system("mv \""old"\" "new)}' your_file_with_file_list
You can use a simple loop:
#!/bin/bash
while read -r filename;
do
mv "$filename" /DESTINATION/PATH/
done < input_filename