So I've ready alot of xsd documentation and similar questions but I've run into a problem: The specified path, file name, or both are too long. The fully qualified file name must be less than 260 characters, and the directory name must be less than 248 characters.
this is the command:
xsd BulkmailAnnouncement2.xsd Components1.xsd Components2.xsd Components3.xsd Components4.xsd Fields1.xsd ManufacturingComponents1.xsd ManufacturingComponents2.xsd Meta1.xsd QualifiedDataTypes.xsd UnqualifiedDataTypes.xsd CodeLists1.xsd CodeList_UnitCode_UNECE_7_04.xsd CodeList_MIMEMediaTypeCode_IANA_7_04.xsd CodeList_LanguageCode_ISO_7_04.xsd CodeList_CurrencyCode_ISO_7_04.xsd /c
How can I create a class if xsd cannot support the includes.
Move files to another directory or rename folders / files in the current path.
The problem occurs because the full path to the file / files exceeds the allowed limit.
Quote from the official documentation:
In the Windows API (with some exceptions discussed in the following
paragraphs), the maximum length for a path is MAX_PATH, which is
defined as 260 characters. A local path is structured in the following
order: drive letter, colon, backslash, name components separated by
backslashes, and a terminating null character. For example, the
maximum path on drive D is "D:\some 256-character path string"
where "" represents the invisible terminating null character for
the current system codepage. (The characters < > are used here for
visual clarity and cannot be part of a valid path string.)
Related
I am following the 10x Cellranger steps and using the same files for cellranger count. I run this from the fastq directory that contains all the PBMCs fastq files and the GRCh38 files too.
You put a space between --fastqs= and /home/.../pbmc_1k_v3_fastqs, and thus it think you didn't provide an argument after --fastqs. There are two possible syntax:
either you want a space, but then don't put a =, as in --fastqs /home/.../pbmc_1k_v3_fastqs;
or you put an equal sign, but then don't put a space, as in --fastqs=/home/.../pbmc_1k_v3_fastqs.
I have 10 files in a folder and want to move 4 of them in a different location.
I tried 2 approaches to achieve this -
using lookup to retrieve the filenames from a json file- then feeding it to a for each iterator
using metadata to get file names from source folder and then adding if condition inside a for each to copy the files.
But in both the cases, all the files in source folder gets copied.
Any help would be appreciated.
Thanks!!
There a 3 ways you can consider selecting your files depending on the requirement or blockers.
Checkout official MS doc: Copy activity properties
1. Dynamic content for FilePath property in Source Dataset.
2. You can use Wildcard character in the source folder and file path in the source Dataset.
Allowed wildcards are: * (matches zero or more characters) and ?
(matches zero or single character); use ^ to escape if your actual
folder name has wildcard or this escape char inside. See more
examples in Folder and file filter
examples.
3. List of Files
Point to a text file that includes a list of files you want to copy,
one file per line, which is the relative path to the path configured
in the dataset. When using this option, do not specify file name in
dataset. See more examples in File list
examples.
Example:
Parameterize source dataset and set source file name to that which passes the expression evaluation in IfCondition Activity.
I added a file named 'testingClip' of mp4 format in a directory i made named 'raw' under 'res',it keeps on showing this error message saying it doesn't recognize the file type.
Don't use any capital letter in resource file name Change your testingClip.mp4 to testingclip.mp4
resource names must contain only lowercase a-z, 0-9, or underscore and The resource name must start with a letter.
I am trying to read the name of some files from a weblogic server.
dir.eachFileRecurse(FileType.FILES) { file ->
println file.getName()
}
However the base filename must be too long, since it's cutted of when i print the file.getName(). Looking at the deployed jar, I have the file
OnlineOfflineSomethingknowledgement-2.DDD
The result of the print however is
OnlineOfflineSomethingknowledgement-2.D
It's like 40 characters is the maximum length of the filename.
Looking at the SB-console, and look at the list of files. The 40 character maximum is also present in the web view. Hovering the mouse over the filename though, will show the full name of the file.
Is there a way to get the full file name from the code?
not clear of the environment of your script execution.
normally, there is no such limitation.
try to print the class of your dir and file variables and probably this will give you an answer.
I have created sample windows form based application.(Exe name is Sample.exe)
I renamed ‘Sample.exe’ to maximum length of characters allowed by windows before launching.
I am getting an error (CLR error:8007007a. The program will now terminate.)
Can anyone please let me know how to resolve this issue.
Individual components of a filename (i.e. each subdirectory along the
path, and the final filename) are limited to 255 characters, and the
total path length is limited to approximately 32,000 characters.
However, you should generally try to limit path lengths to below 260
characters ( MAX_PATH ) when possible
Don't rename your file to be longer than 260 characters.
Renaming the file back to something considerably smaller should fix it.
If you want to change the Executable file name:
Change the project
Rebuild
In such way you keep consistent and you can trace back from your executable to the source code if there is a problem.