How to add memory zone to linux - linux

I'd like to add a new memory zone (ZONE_DMA, ZONE_NORMAL, ZONE_HIGHMEM, etc) to the linux kernel. For example, this memory zone (ZONE_ALTERNATE), will have special properties that will make it desirable to use in certain instances. Imagine having a special DDR DIMM that performs some operations on the data. I would like to be able to use kmalloc to allocate from this zone. Specifically I would like to add this zone to kernel 2.6.32, but current kernels would also be of use.
Are there any resources or ideas on how to implement this?

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Find out pages used by mem_map[] array

Recently, I am working on the ARM Linux kernel, and I need to split the HighMem zone into two parts. So I have added a new zone into the kernel, let's say "NewMem". Therefore, I have three zones in my system, they are Normal, NewMem, and HighMem. The size of the NewMem zone is 512MB (, totally 131072 pages). My propose is that I want to manage all the page frames in NewMem zone in my own way, currently I use a doubly linked list to allocate/de-allocate pages. Note that the buddy system for NewMem zone is still exist, but I do not use it. To achieve this. I modified the page allocation routine to make sure that the kernel cannot allocate any page frame from my zone.
My concern is that can I use all the page frames in that zone as it is suggested that each zone is concerned with a subset of the mem_map[] array. I found that only 131084 pages are free in NewMem zone.Therefore, some page frames in my zone may used to store mem_map[], writing data to these pages may lead to unpredictable errors. So is there exist any way to find out which page frame is used to store mem_map[], so that I can avoid rewriting it.
You have to check the break down of physical and virtual memory. usually mem_map is stored on first mappable address of the virtual memory. In Unix, kernel image of usually 8MB is stored at physical address of 1MiB accessed with virtual address PAGE_OFFSET + 0x00100000. 8MiB is reserved in virtual memory for kernel image. Then comes the 16 MiB of zone_dma. So first address which can be used by kernel for mapping is 0xC1000000. Which is supposed to contain mem_map array.
I am not familiar with ARM memory break down but from your post it is evident that there is no zone_dma at least in your case. So your best bet is that address 0xC0800000 stores mem_map. I am assuming that kernel image is 8MB.
As stated above in general first mappable virtual address stores mem_map. You can calculate that address with size and location of kernel image and zone_dma(present or not).
Please come with your feedback.

Large physically contiguous memory area

For my M.Sc. thesis, I have to reverse-engineer the hash function Intel uses inside its CPUs to spread data among Last Level Cache slices in Sandy Bridge and newer generations. To this aim, I am developing an application in Linux, which needs a physically contiguous memory area in order to make my tests. The idea is to read data from this area, so that they are cached, probe if older data have been evicted (through delay measures or LLC miss counters) in order to find colliding memory addresses and finally discover the hash function by comparing these colliding addresses.
The same procedure has already been used in Windows by a researcher, and proved to work.
To do this, I need to allocate an area that must be large (64 MB or more) and fully cachable, so without DMA-friendly options in TLB. How can I perform this allocation?
To have a full control over the allocation (i.e., for it to be really physically contiguous), my idea was to write a Linux module, export a device and mmap() it from userspace, but I do not know how to allocate so much contiguous memory inside the kernel.
I heard about Linux Contiguous Memory Allocator (CMA), but I don't know how it works
Applications don't see physical memory, a process have some address space in virtual memory. Read about the MMU (what is contiguous in virtual space might not really be physically contiguous and vice versa)
You might perhaps want to lock some memory using mlock(2)
But your application will be scheduled, and other processes (or scheduled tasks) would dirty your CPU cache. See also sched_setaffinity(2)
(and even kernel code might be perhaps preempted)
This page on Kernel Newbies, has some ideas about memory allocation. But the max for get_free_pages looks like 8MiB. (Perhaps that's a compile-time constraint?)
Since this would be all-custom, you could explore the mem= boot parameter of the linux kernel. This will limit the amount of memory used, and you can party all over the remaining memory without anyone knowing. Heck, if you boot up a busybox system, you could probably do mem=32M, but even mem=256M should work if you're not booting a GUI.
You will also want to look into the Offline Scheduler (and here). It "unplugs" the CPU from Linux so you can have full control over ALL code running on it. (Some parts of this are already in the mainline kernel, and maybe all of it is.)

Write to a cacheable physical address in linux kernel without using ioremap or mmap

I am changing the linux kernel scheduler to print the pid of the next process in a known physical memory location. mmap is used for userspace programs while i read that ioremap marks the page as non-cacheable which would slowdown the execution of the program. I would like a fast way to write to a known physical memory. phys_to_virt is the option that i think is feasible. Any idea for a different technique.
PS: i am running this linux kernel on top of qemu. the physical address will be used by qemu to read information sent by guest kernel. writing to a known io-port is not feasible since the device code backing this io-device will be called every time there is an access to the device.
EDIT : I want the physical address location of the pid to be safe. How can I make sure that a physical address that the kernel is using is not being assigned to any process. As far as my knowledge goes, ioremap would mark the page as cacheable and would hence not be of great use.
The simplest way to do this would be to do kmalloc() to get some memory in the kernel. Then you can get the physical address of the pointer that returns by passing it to virt_to_phys(). This is a total hack but for your case of debugging / tracing under qemu, it should work fine.
EDIT: I misunderstood the question. If you want to use a specific physical address, there are a couple of things you could do. Maybe the cleanest thing to do would be to modify the e820 map that qemu passes in to mark the RAM page as reserved, and then the kernel won't use it. (ie the same way that ACPI tables are passed in).
If you don't want to modify qemu, you could also modify the early kernel startup (around arch/x86/kernel/setup.c probably) to do reserve_bootmem() on the specific physical page you want to protect from being used.
To actually use the specified physical address, you can just use ioremap_cache() the same way the ACPI drivers access their tables.
It seems I misunderstood the cache coherency between VM and host part, here is an updated answer.
What you want is "virtual adress in VM" <-> "virtual or physical adress in QEMU adress space".
Then you can either kmalloc it, but it may vary from instance to instance,
or simply declare a global variable in the kernel.
Then virt_to_phys would give you access to the physical address in VM space, and I suppose you can translate this in a QEMU adress space. What do you mean by "a physical address that the kernel is using is not assigned to any process ?" You are afraid the page conatining your variable might be swapped ? kmalloced memory is not swappable
Original (and wrong) answer
If the adress where you want to write is in it's own page, I can't see how an ioremap
of this page would slow down code executing in a different page.
You need a cache flush anyway, and without SSE, I can't see how you can bypass the cache if MMU and cache are on. I can see only this two options :
ioremap and declare a particular page non cacheable
use a "normal" address, and manually do a cache flush each time you write.

Is it possible to allocate a certain sector of RAM under Linux?

I have recently gotten a faulty RAM and despite already finding out this I would like to try a much easier concept - write a program that would allocate faulty regions of RAM and never release them. It might not work well if they get allocated before the program runs, but it'd be much easier to reboot on failure than to build a kernel with patches.
So the question is:
How to write a program that would allocate given sectors (or pages containing given sectors)
and (if possible) report if it was successful.
This will problematic. To understand why, you have to understand the relation between physical and virtual memory.
On any modern Operating System, programs will get a very large address space for themselves, with the remainder of the address space being used for the OS itself. Other programs are simply invisible: there's no address at which they're found. How is this possible? Simple: processes use virtual addresses. A virtual address does not correspond directly to physical RAM. Instead, there's an address translation table, managed by the OS. When your process runs, the table only contains mappings for RAM that's allocated to you.
Now, that implies that the OS decides what physical RAM is allocated to your program. It can (and will) change that at runtimke. For instance, swapping is implemented using the same mechanism. When swapping out, a page of RAM is written to disk, and its mapping deleted from the translation table. When you try to use the virtual address, the OS detects the missing mapping, restores the page from disk to RAM, and puts back a mapping. It's unlikely that you get back the same page of physical RAM, but the virtual address doesn't change during the whole swap-out/swap-in. So, even if you happened to allocate a page of bad memory, you couldn't keep it. Programs don't own RAM, they own a virtual address space.
Now, Linux does offer some specific kernel functions that allocate memory in a slightly different way, but it seems that you want to bypass the kernel entirely. You can find a much more detailed description in http://lwn.net/images/pdf/LDD3/ch08.pdf
Check out BadRAM: it seems to do exactly what you want.
Well, it's not an answer on how to write a program, but it fixes the issue whitout compiling a kernel:
Use memmap or mem parameters:
http://gquigs.blogspot.com/2009/01/bad-memory-howto.html
I will edit this answer when I get it running and give details.
The thing is write own kernel module, which can allocate physical address. And make it noswap with mlock(2).
I've never tried it. No warranty.

Force Linux to use only memory over 4G?

I have a Linux device driver that interfaces to a device that, in theory, can perform DMA using 64-bit addresses. I'd like to test to see that this actually works.
Is there a simple way that I can force a Linux machine not to use any memory below physical address 4G? It's OK if the kernel image is in low memory; I just want to be able to force a situation where I know all my dynamically allocated buffers, and any kernel or user buffers allocated for me are not addressable in 32 bits. This is a little brute force, but would be more comprehensive than anything else I can think of.
This should help me catch (1) hardware that wasn't configured correctly or loaded with the full address (or is just plain broken) as well as (2) accidental and unnecessary use of bounce buffers (because there's nowhere to bounce to).
clarification: I'm running x86_64, so I don't care about most of the old 32-bit addressing issues. I just want to test that a driver can correctly interface with multitudes of buffers using 64-bit physical addresses.
/usr/src/linux/Documentation/kernel-parameters.txt
memmap=exactmap [KNL,X86] Enable setting of an exact
E820 memory map, as specified by the user.
Such memmap=exactmap lines can be constructed based on
BIOS output or other requirements. See the memmap=nn#ss
option description.
memmap=nn[KMG]#ss[KMG]
[KNL] Force usage of a specific region of memory
Region of memory to be used, from ss to ss+nn.
memmap=nn[KMG]#ss[KMG]
[KNL,ACPI] Mark specific memory as ACPI data.
Region of memory to be used, from ss to ss+nn.
memmap=nn[KMG]$ss[KMG]
[KNL,ACPI] Mark specific memory as reserved.
Region of memory to be used, from ss to ss+nn.
Example: Exclude memory from 0x18690000-0x1869ffff
memmap=64K$0x18690000
or
memmap=0x10000$0x18690000
If you add memmap=4G$0 to the kernel's boot parameters, the lower 4GB of physical memory will no longer be accessible. Also, your system will no longer boot... but some variation hereof (memmap=3584M$512M?) may allow for enough memory below 4GB for the system to boot but not enough that your driver's DMA buffers will be allocated there.
IIRC there's an option within kernel configuration to use PAE extensions which will enable you to use more than 4GB (I am a bit rusty on the kernel config - last kernel I recompiled was 2.6.4 - so please excuse my lack of recall). You do know how to trigger a kernel config
make clean && make menuconfig
Hope this helps,
Best regards,
Tom.

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