Groovy resource from classpath not loaded - groovy

Question

Good day everyone.
I am using spock framework for testing in my groovy project(IDE - Intellij Idea 12.6). My spock specification class pass filename to groovy object for processing (that file is in classpath for sure), but when i try to get that file this way
def resource = getClass().getClassloader().getResourceAsStream(filepath)
assert resource != null : "No input stream found for path ${filepath}"
def rootNode = new XmlParser().parse(resource)
Then resource == null.
I tried debugging and in Expression Evaluation windows this code getClass().getResource(fileName) returns resource.
I tried to check which classloader used in first case (in class with the code) and in second case (Expression Evaluation window).
In first case classloader was sun.misc.Launcher$AppClassLoader#18dabf1, but in Expression Evaluation window classloader was groovy.lang.GroovyClassLoader$InnerLoader#1e69757 I suppose that's the reason my resource was null.
Can someone guide me about what I am doing wrong and how can I load that resource file ?
UPDATE:
Changed the way resource file was parsed. When filepath - full path to file this works, but if filepath is just file name and that file in classpath then resource == null
UPDATE2:
Change the way resource file loaded, clean up dependencies bit and all is working, I guess yesterday just wasn't my day.

Answer 1

The problem is very likely unrelated to Spock. It's hard to say from a distance what's causing it, but the safest way to read a resource is getClass().getClassLoader().getResourceAsStream() or Thread.currentThread().getContextClassLoader().getResourceAsStream(), depending on the environment.
Not sure what Groovy does when you do new File(resource), as there is no File(URL) constructor (only a File(URI) constructor). In any case, getting a File from a class path should be avoided whenever possible.

Answer 2

This is likely due to the fact that Groovy may interpret the class of the object differently that what you think is happening. See the following other StackOverflow item:
Why does groovy .class return a different value than .getClass()
When the class is wrong, then the ClassLoader may well by the bootstrap loader and getClassLoader returns null.
So instead of using a statement like
def resource = getClass().getClassloader().getResourceAsStream(filepath)
specify the actual class using a statement like
def resource = MyClass.class.getClassLoader().getResourceAsStream(filePath)
worked for me in nearly identical circumstances.

Answer 3

def resource = MyClass.class.getResourceAsStream(fileName)
or if you want the content of the file as String:
def str = new String(MyClass.class.getResourceAsStream(fileName).readAllBytes(), StandardCharsets.UTF_8)
Please note:
MyClass is used, not this.getClass();
In resources you must create the same directory structure as the package of your class, and put the files there;
fileName is just simply the name of the file, without any path;
You must clean and rebuild your project.