I need to find those values that are in column 1 and not in column 2 and vica versa. It can look like this: take fist row in the first column and look if there is same number in the second column if so then on the third column write 0 (substraction) and if there won't be the same number then write searched number or error, doesn't matter. This should work both ways (some numbers can be in col2 but not in col1, those i need to find aswell). So probably there would be 2 formulas in 2 columns. one searching from col1 to col2, and same for col2 to col1. And if there for example in col1 would be twice some value and in col2 just once, than it should show for the first number 0 and for second number error or searched number.
Dataset looks like this:
Col1
Col2.
42646
55
42646
77
33
25
77
Col3
Col4
0
55
0
0
33(or error,NA etc)
25
0
I have tried vlook up, but wasn't sucesfull.
I guess this is what you are looking for. You can use for Col3:
=IF(A2:A6="", "",IF(ISNA(XMATCH(A2:A6,B2:B6)),A2:A6,0))
and for Col4:
=IF(B2:B6="", "", IF(ISNA(XMATCH(B2:B6,A2:A6)),B2:B6,0))
Both formulas returns 0 if the value was found (including blanks), otherwise the missing value.
You can put all together using HSTACK:
= HSTACK(IF(A2:A6="", "",IF(ISNA(XMATCH(A2:A6,B2:B6)),A2:A6,0)),
IF(B2:B6="", "", IF(ISNA(XMATCH(B2:B6,A2:A6)),B2:B6,0)))
Or using LET to avoid repetitions.
= LET(A, A2:A6, B, B2:B6, HSTACK(IF(A="","",IF(ISNA(XMATCH(A,B)),A,0)),
IF(B="", "", IF(ISNA(XMATCH(B,A)),B,0))))
Here is the output:
You can use XLOOKUP too, but the formula is longer, because the first three input arguments are required:
=IF(ISNA(XLOOKUP(A2:A6,B2:B6, A2:A6)),A2:A6,0)
A shame you haven't added a sample in your data that would show what you meant with:
"And if there for example in col1 would be twice some value and in col2 just once, than it should show for the first number 0 and for second number error or searched number."
Your requirements make this a little tricky, but try:
Formula in C1:
=IF(A1="","",IF(COUNTIF(B:B,A1)-COUNTIF(A$1:A1,A1)<0,A1,0))
Formula in D1:
=IF(B1="","",IF(COUNTIF(A:A,B1)-COUNTIF(B$1:B1,B1)<0,B1,0))
Related
I have a table:
col1
col2
134
1
432
2
222
3
21
4
982
5
1352
8
111
9
I need to find all possible sum combinations of col1 values IF col2 sum is 10. (5+4+1, 2+3+5, etc.) & number of terms is 3
Please advice how to solve this task?
To get all unique possible sums based on a give count of items in col2 and sum of col2 is a specific amount, with ms365, try:
Formula in D1:
=LET(inp,B1:B7,cnt,3,sm,10,B,COUNTA(inp),A,MAKEARRAY(B,cnt,LAMBDA(r,c,INDEX(inp,r,1))),D,B^cnt,E,UNIQUE(MAKEARRAY(D,cnt,LAMBDA(rw,cl,INDEX(IF(A="","",A),MOD(CEILING(rw/(D/(B^cl)),1)-1,B)+1,cl)))),F,FILTER(E,MMULT(--(E<>""),SEQUENCE(cnt,,,0))=cnt),G,FILTER(F,BYROW(F,LAMBDA(a,(SUM(a)=sm)*(COUNT(UNIQUE(a,1))=cnt)))),UNIQUE(BYROW(G,LAMBDA(a,SUM(XLOOKUP(a,inp7,A1:A7))))))
You can now change parameters cnt and sm to whichever amount you like.
The trick is borrowed from my answer here to calculate all permutations first. Instead of a range, the single column input is extended using MAKEARRAY().
A short visual representation of what is happening:
Expand the given array based on cnt;
Create a complete list of all possible permutations;
Filter step 2 based on a sum per row and unique numbers (don't use values from col2 more than once);
Lookup each value per row to create a total sum per row;
Return only the unique summations as per screenshot at the top.
I have two columns in Excel. I would like to populate col1 with number 25 if in col2 it is greater than 80000. But, I only want the number 25 to appear the first time the value in col2 is g>= than a multiple 80000. Lastly, the number 25 should appear again the first time a value in col2 is >=160000...and so on.
VALUE expected output
1,631
39,716
85,022 25
123,192
151,744
173,125 25
190,520
205,108
217,553
228,323
237,753
254,024 25
299,957
331,953 25
354,286
333,296
297,460
In B2:
=IF(INT(A2/80000)>0,IF(INT(A2/80000)<>INT(A1/80000),25,""),"")
and copy down
0 546/001441
1 540/001495
2 544/000796
3 544/000797
4 544/000798
I have a column in my dataframe that I've provided above. It can have any number of rows depending on the data being crunched. It is one of many columns but the first three numbers match another columns data. I need to cut off everything after the first 3 numbers in order to append it to another dataframe based off of the similar values. Any ideas as to how to get only the first 3 numbers and cut off the remaining 8 values?
So far I've got the whole column singled out as a Series and also as a numpy.array in order to try to convert it to a str instead of an object.
I know this is getting me closer to an answer but i can't seem to figure out how to cut out the unnecessary values
testcut=dfwhynot[0][:3]
this cuts the string where i need it, but how do i do this for the whole column is what i can't figure out.
Assuming the name of your column is col, you can
# Split the column into two
df['col'] = df['col'].apply(lambda row: row.split('/'))
df[['col1', 'col2']] = pd.DataFrame(df_out.values.tolist())
col1 col2
0 546 001441
1 540 001495
2 544 000796
3 544 000797
4 544 000798
then get the minimal element of each col1 group
df.groupby('col1').min().reset_index()
resulting in
col1 col2
0 540 001495
1 544 000796
2 546 001441
I have been looking through all different sources and cannot find the exact answer to this. Was hoping someone can help me out.
I have two columns:
COL1 COL2
abc defghe
def iabclmn
ghi zhued
fgh lmnop
I want to know if a value in COL1 exist in COL2. So in this case I want it to look like this:
COL1 COL2 COL3
abc defghe TRUE
def iabclmn TRUE
ghi zhued FALSE
fgh lmnop TRUE
Is there a function that can do this, I have over 500 rows so I cannot just call out specific values?
I know there is an example that does specific values like this, but I want it to be by the entire column:
=ISNUMBER(SEARCH(substring,text))
Thanks!
To do it for full columns as real non-array formula:
=COUNTIF(B:B,"*"&A1&"*")>0
This will do it:
=SUMPRODUCT(ISNUMBER(SEARCH(A1,$B$1:$B$4))*1)>0
The SUMPRODUCT() forces it to iterate through Column B and keep track of the ones that return true. So if any are found it adds 1 to the pool.
The >0 test whether any returned TRUE.
I'm looking for a way to find the first specific value above a certain cell.
Using the example below, in the result column every time I hit a A in COL2, I need to substract the value in COL1 to the first A value above.
The trouble seems finding a way to keep the range dynamic...
I thought of =IF(B5="A";A5-INDIRECT("A"&MATCH("A";B:B;0));"")
But of course that only works for the first one as Match will always pick up the first one.
Any ideas? Thanks!
Example :
COL1 COL2 Result
1 A
2 0
3 0
4 A 4 - 1 = 3
5 0
6 A 6 - 4 = 2
7 0
8 0
9 0
10 A 10 - 6 = 4
Try this:
=IF(AND(ROW(B2)<>2,B2="A"),A2-INDEX($A$1:$A1,AGGREGATE(14,6,ROW($1:1)/($B$1:$B1="A"),1)),"")
The AGGREGATE() Function was introduced in 2010.
In D2 enter =IF(B2="A",A2-INDIRECT("A"&MATCH("A"&(E2-1),F:F,0)),"")
In E2 enter =IF(B2="a",COUNTIFS($B$2:B2,"a"),"")
In F2 enter =B2&E2
Copy formulas from D, E and F down all your rows
Column D is the result you're looking for