PyQt LineEdit.textEdited pass object to another function - python-3.x

I have 2 functions that call similar proxy object. But i don't know how to pass it as an argument so i have 2 identical functions that are referencing different proxy objects.
def func1(self, inEdrpou):
...
self.proxyKeys = QSortFilterProxyModel(self)
self.proxyKeys.setSourceModel(model)
self.tableViewKeys.setModel(self.proxyKeys)
self.lineEditKeys.textEdited.connect(self.filerClicked)
def func2(self, inEdrpou):
...
self.proxyLic = QSortFilterProxyModel(self)
self.proxyLic.setSourceModel(model)
self.tableViewKeys.setModel(self.proxyLic)
self.lineEditKeys.textEdited.connect(self.filerClicked2)
def filerClicked(self, text):
self.proxyKeys.setFilterKeyColumn(1)
search = QRegExp(text, Qt.CaseInsensitive, QRegExp.RegExp)
self.proxyKeys.setFilterRegExp(search)
def filerClicked2(self, text):
self.proxyLic.setFilterKeyColumn(1)
search = QRegExp(text, Qt.CaseInsensitive, QRegExp.RegExp)
self.proxyLic.setFilterRegExp(search)

Related

How to check which function has been returned in python?

I have two methods which take different number of arguments. Here are the two functions:
def jumpMX(self,IAS,list):
pass
def addMX(self,IAS):
pass
I am using a function which will return one of these functions to main.I have stored this returned function in a variable named operation.
Since the number of parameters are different for both,how do I identify which function has been returned?
if(operation == jumpMX):
operation(IAS,list)
elif(operation == addMX):
operation(IAS)
What is the syntax for this?Thanks in advance!
You can identify a function through its __name__ attribute:
def foo():
pass
print(foo.__name__)
>>> foo
...or in your case:
operation.__name__ #will return either "jumpMX" or "addMX" depending on what function is stored in operation
Here's a demo you can modify to your needs:
import random #used only for demo purposes
def jumpMX(self,IAS,list):
pass
def addMX(self,IAS):
pass
def FunctionThatWillReturnOneOrTheOtherOfTheTwoFunctionsAbove():
# This will randomly return either jumpMX()
# or addMX to simulate different scenarios
funcs = [jumpMX, addMX]
randomFunc = random.choice(funcs)
return randomFunc
operation = FunctionThatWillReturnOneOrTheOtherOfTheTwoFunctionsAbove()
name = operation.__name__
if(name == "jumpMX"):
operation(IAS,list)
elif(name == "addMX"):
operation(IAS)
You can import those functions and test for equality like with most objects in python.
classes.py
class MyClass:
#staticmethod
def jump(self, ias, _list):
pass
#staticmethod
def add(self, ias):
pass
main.py
from classes import MyClass
myclass_instance = MyClass()
operation = get_op() # your function that returns MyClass.jump or MyClass.add
if operation == MyClass.jump:
operation(myclass_instance, ias, _list)
elif operation == MyClass.add:
operation(myclass_instance, ias)
However, I must emphasize that I don't know what you're trying to accomplish and this seems like a terribly contrived way of doing something like this.
Also, your python code examples are not properly formatted. See the PEP-8 which proposes a standard style-guide for python.

Python / Attributes between methods of a class

I'm new in Python and I'm trying to get my head around how are managed attributes between methods of a class.
In the following example, I'm trying to modify a list in the method "regex" and use it afterwards in another method "printsc".
The "regex" part works without issues, but the attribute "self.mylist" is not updated so when I call "printsc" the result is "None".
class MyClass():
def __init__(self):
self.mylist = None
def regex(self, items):
self.mylist = []
for item in items:
if re.match(r"^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}$", item):
self.mylist.append("IP:" + item)
else:
self.mylist.append("DNS:" + item)
return self.mylist
def printsc(self):
print(self.mylist)
items = ['192.168.0.1', 'hostname1', '10.0.1.15', 'server.local.fr']
MyClass().regex(items)
MyClass().printsc()
What am I missing ? What is the best way to achieve this goal ?
Thank you for your answers!
When you do MyClass(), it returns you an object.. And you are calling your methods on the object. Since you are doing it twice, each time a new object is created and regex and printsc are called on different objects.
what you should do is
myObj = MyClass()
myObj.regex(items)
myObj.printsc()
The problem is that when you do:
MyClass().regex(items)
MyClass().printsc()
You are creating 2 separate instances of MyClass, each of which will have a different .mylist attribute.
Either mylist is an instance attribute, and then this will work:
instance = MyClass()
instance.regex(items)
instance.printsc()
Or, if you want to share .mylist across instances, it should be
a class attribute:
class MyClass():
class_list = None
def __init__(self):
pass
def regex(self, items):
cls = self.__class__
if cls.class_list is None:
cls.class_list = []
for item in items:
if re.match(r"^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}$", item):
cls.class_list.append("IP:" + item)
else:
cls.class_list.append("DNS:" + item)
return cls.class_list
def printsc(self):
# Going throuhgh `.__class__.` is actually optional for
# reading an attribute - if it is not in the instance
# Python will fetch it from the class instead.
# i.e. , the line bellow would work with `self.class_list`
print(self.__class__.class_list)
This way, the list persists across different instances of the class, as you try to do in your example.
You should create an object of the class:
a = MyClass()
a.regex(items)
a.printsc()
>>> ['IP:192.168.0.1', 'DNS:hostname1', 'IP:10.0.1.15', 'DNS:server.local.fr']

how to use python decorator with argument?

I would like to define a decorator that will register classes by a name given as an argument of my decorator. I could read from stackoverflow and other sources many examples that show how to derive such (tricky) code but when adapted to my needs my code fails to produce the expected result. Here is the code:
import functools
READERS = {}
def register(typ):
def decorator_register(kls):
#functools.wraps(kls)
def wrapper_register(*args, **kwargs):
READERS[typ] = kls
return wrapper_register
return decorator_register
#register(".pdb")
class PDBReader:
pass
#register(".gro")
class GromacsReader:
pass
print(READERS)
This code produces an empty dictionary while I would expect a dictionary with two entries. Would you have any idea about what is wrong with my code ?
Taking arguments (via (...)) and decoration (via #) both result in calls of functions. Each "stage" of taking arguments or decoration maps to one call and thus one nested functions in the decorator definition. register is a three-stage decorator and takes as many calls to trigger its innermost code. Of these,
the first is the argument ((".pdb")),
the second is the class definition (#... class), and
the third is the class call/instantiation (PDBReader(...))
This stage is broken as it does not instantiate the class.
In order to store the class itself in the dictionary, store it at the second stage. As the instances are not to be stored, remove the third stage.
def register(typ): # first stage: file extension
"""Create a decorator to register its target for the given `typ`"""
def decorator_register(kls): # second stage: Reader class
"""Decorator to register its target `kls` for the previously given `typ`"""
READERS[typ] = kls
return kls # <<< return class to preserve it
return decorator_register
Take note that the result of a decorator replaces its target. Thus, you should generally return the target itself or an equivalent object. Since in this case the class is returned immediately, there is no need to use functools.wraps.
READERS = {}
def register(typ): # first stage: file extension
"""Create a decorator to register its target for the given `typ`"""
def decorator_register(kls): # second stage: Reader class
"""Decorator to register its target `kls` for the previously given `typ`"""
READERS[typ] = kls
return kls # <<< return class to preserve it
return decorator_register
#register(".pdb")
class PDBReader:
pass
#register(".gro")
class GromacsReader:
pass
print(READERS) # {'.pdb': <class '__main__.PDBReader'>, '.gro': <class '__main__.GromacsReader'>}
If you don't actually call the code that the decorator is "wrapping" then the "inner" function will not fire, and you will not create an entry inside of READER. However, even if you create instances of PDBReader or GromacsReader, the value inside of READER will be of the classes themselves, not an instance of them.
If you want to do the latter, you have to change wrapper_register to something like this:
def register(typ):
def decorator_register(kls):
#functools.wraps(kls)
def wrapper_register(*args, **kwargs):
READERS[typ] = kls(*args, **kwargs)
return READERS[typ]
return wrapper_register
return decorator_register
I added simple init/repr inside of the classes to visualize it better:
#register(".pdb")
class PDBReader:
def __init__(self, var):
self.var = var
def __repr__(self):
return f"PDBReader({self.var})"
#register(".gro")
class GromacsReader:
def __init__(self, var):
self.var = var
def __repr__(self):
return f"GromacsReader({self.var})"
And then we initialize some objects:
x = PDBReader("Inside of PDB")
z = GromacsReader("Inside of Gromacs")
print(x) # Output: PDBReader(Inside of PDB)
print(z) # Output: GromacsReader(Inside of Gromacs)
print(READERS) # Output: {'.pdb': PDBReader(Inside of PDB), '.gro': GromacsReader(Inside of Gromacs)}
If you don't want to store the initialized object in READER however, you will still need to return an initialized object, otherwise when you try to initialize the object, it will return None.
You can then simply change wrapper_register to:
def wrapper_register(*args, **kwargs):
READERS[typ] = kls
return kls(*args, **kwargs)

How to memoize at class level?

I have the following class, with a cached property as so:
class Object:
def __init__(self, var):
self._var = var
#property
#lru_cache()
def some_property(self):
print("i did some calculation")
return self._var + 3
>> obj = Object(3)
>> obj.some_property
i did some calculation
6
How can I make it so that whenever I make a new Object, with the same var, it will not recalculate, but rather memoize the result fat class level and not recalculate somme_property.
In other words I would need it to behave as so:
>> new_obj = Object(3)
>> new_obj.some_property
6
Maybe not the answer but a suggestion. You could just create a function inside Object which will hold the variable.
Something like this:
def memorize(x):
self.MemorizedValue = x
Then you can pass the value through Object.memorize(3).

How can I make this body of code through a for loop?

So, I'm trying to get this code to work in a cleaner way, mainly, through the use of a for loop, but having a really hard time trying to do so. I haven't been able to make a loop that assigns each value of the dictionary to a correspondent variable, so it can be used in the class. For context, the dictionary contains values obtained from another class, I just put those in the dict and sent it to this class, so I don't need to calculate those again.
def get_ipr_data(self):
self.reservoir_result_dict = ReservoirDataFrame.reservoir_result_dict
self.pb = self.reservoir_result_dict.get("pb")
self.rs = self.reservoir_result_dict.get("rs")
self.bo = self.reservoir_result_dict.get("bo")
self.uo = self.reservoir_result_dict.get("uo")
self.re = self.reservoir_result_dict.get("re")
self.j_index = self.reservoir_result_dict.get("j_index")
self.q_max = self.reservoir_result_dict.get("q_max")
self.pws = self.reservoir_result_dict.get("pws")
self.qb = self.reservoir_result_dict.get("qb")
You can use setattr function
for name in ["pb", "rs", "bo", "uo", "re", "j_index", "q_max", "pws", "qb"]:
setattr(self, name, self.reservoir_result_dict.get(name))
Documentation of setattr:
https://docs.python.org/3/library/functions.html#setattr
Delegating attributes is done by defining the __getattr__ method. You should store the dictionary only and then define __getattr__.
class Foo:
...
def get_ipr_data(self):
self.reservoir_result_dict = ReservoirDataFrame.reservoir_result_dict
def __getattr__(self, item):
return self.reservoir_result_dict[item]

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