Update and get lastest data in one function - node.js

Question

I have the following javaScript code for Nodejs to update data in MongoDB.
I have a list of products that I want update (called itemsToBeUpdated). (Update the preference value in the order that they are passed-in)
Once all the updates have been completed, I would like to go and retrieve the product list by calling the function getProducts(req, res);
where should I put the getProducts(req, res)? Not position A because Product.findByIdAndUpdate is async so it will get to position A before the findByIdAndUpdate is completed.
Not position B because there are more items to loop through.
const updateAndRefreshProducts = (req,res) => {
const itemsToBeUpdated = req.body;
const counter = someValue
for(let i = 0; i<itemsToBeUpdated.length; i++){
const newPreference = counter;
counter++;
condition= {_id: itemsToBeUpdated[i]._id};
Product.findByIdAndUpdate(condition, {preference:newPreference})
.then(result => {
console.log('performing update completed for result' + result.name +" : ", result.preference);
//position B
})
.catch(error =>{
console.log('error', error);
});
}
//position A
}
thanks

Answer 1

There are a couple of way to handle this, the easiest way to accomplish this will be to utilize Promise.all().
You may want to read on this documentation
const updateAndRefreshProducts = (req,res) => {
const itemsToBeUpdated = req.body;
const productUpdatePromises = []
const counter = someValue
for(let i = 0; i<itemsToBeUpdated.length; i++){
const newPreference = counter;
counter++;
condition= {_id: itemsToBeUpdated[i]._id};
const productUpdatePromise = Product.findByIdAndUpdate(condition{preference:newPreference})
productUpdatePromises.push(productUpdatePromise)
}
await Promise.all(productUpdatePromises).then((results) => {
console.log(results);
//Called your get all products here
})
.catch((error) => {
console.error(error.message);
});
}