Is there a way to make tkinter windows work independantly Tkinter? - python-3.x

Question

I have been looking to create a code that opens a second tkinter window to display stuffs live while a program is running on my main window. However, doing so, my main window gets frozen during 5s and then displays stuff on my second window when it is completed.
Is there a way to live display in the second window ?
My code below:
import tkinter as tk
from tkinter import ttk
import time
class PopUpLog(tk.Tk):
def __init__(self, parent):
tk.Tk.__init__(self)
self.y=5
tk.Button(self.master, text="Write in pop-up", command=self.write).pack(side="left")
# canvas
frameL = tk.Frame(self)
frameL.pack(side="left", fill="both")
self.canvasL = tk.Canvas(frameL, height=800, width=800)
self.canvasL.pack(fill="both", expand=True)
# scrollbar
vsb = ttk.Scrollbar(self, orient="v", command=self.canvasL.yview)
vsb.pack(side="left", fill="y")
self.canvasL.configure(yscrollcommand=vsb.set)
self.canvasL.bind("<Configure>", lambda e:self.canvasL.configure(scrollregion=self.canvasL.bbox("all")))
def write(self, text="hi im a pop-up"):
for i in range(5):
self.canvasL.create_text(5, self.y, anchor='nw', justify='left', text=text)
self.y += 25
time.sleep(1)
class App(tk.Tk):
def __init__(self):
tk.Tk.__init__(self)
tk.Button(self, text="Open window", command=self.popup).pack(side="left")
def popup(self):
self.top = PopUpLog(self)
self.top.geometry("400x400")
self.top.title("pop-up")
self.top.mainloop()
if __name__ == "__main__":
root = App()
root.mainloop()
So far, the program runs for 5s and then displays everything in self.top. BUT I need a live display (made every time create_text is called) in self.top but I can't even get that.
I am sorry if this is redundant to another question asked but I couldn't find helpful enough information.
Thanks a lot !

Answer 1

time.sleep is the reason why your window is freezing. This is the case for virtually any GUI toolkit. If you want the updates to happen incrementally you can use the after method which will execute the callback you assign after a certain number of milliseconds.
Also there should only be one mainloop. There is no need to start one per window and doing so could cause problems.
Here is an example using the after method:
class PopUpLog(tk.Tk):
def __init__(self, parent):
tk.Tk.__init__(self)
self.y=5
self.c=5 # counter
tk.Button(self.master, text="Write in pop-up", command=self.write).pack(side="left")
# canvas
frameL = tk.Frame(self)
frameL.pack(side="left", fill="both")
self.canvasL = tk.Canvas(frameL, height=800, width=800)
self.canvasL.pack(fill="both", expand=True)
# scrollbar
vsb = ttk.Scrollbar(self, orient="v", command=self.canvasL.yview)
vsb.pack(side="left", fill="y")
self.canvasL.configure(yscrollcommand=vsb.set)
self.canvasL.bind("<Configure>", lambda e:self.canvasL.configure(scrollregion=self.canvasL.bbox("all")))
def write(self, text="hi im a pop-up"):
if self.c > 0:
self.canvasL.create_text(5, self.y, anchor='nw', justify='left', text=text)
self.y += 25
self.c -= 1 # reduce counter
self.after(1000, self.write) # call again in 1 second
else:
self.c = 5 # when counter is 0 reset counter
class App(tk.Tk):
def __init__(self):
tk.Tk.__init__(self)
tk.Button(self, text="Open window", command=self.popup).pack(side="left")
def popup(self):
self.top = PopUpLog(self)
self.top.geometry("400x400")
self.top.title("pop-up")
if __name__ == "__main__":
root = App()
root.mainloop()