Problem with node.js twitch bot shoutout command - node.js

Question

When the !so command is used it works fine if you use "#" at the start of the username but if you just do !so without the # the username is deleted from the output.. here's my code.
client.on('message', (channel, tags, message, user, self) => {
if(self) return;
const badges = tags.badges || {};
const isBroadcaster = badges.broadcaster;
const isMod = badges.moderator;
const isModUp = isBroadcaster || isMod;
const args = message.slice(1).split(' ');
const command = args.shift().toLowerCase();
// so command
if(isModUp) {
if(command === 'so') {
const args = message.slice(1).split('#');
const command = args.shift().toLowerCase();
client.say(channel, `Go check out ${args.join(' ')}! www.twitch.tv/${args.join(' ')}`);
}
}
I tried changing "const args = message.slice(1).split('#');" to "const args = message.slice(1).split(' ');" but that method left the "#" in the output link.
I'm hoping to be able to use the command either by using !so "username" or !so "#username"
any help would be appreciated

Answer 1

The problem is that if you don't include the "#", the .split('#') is only converting your string into an array of one element. Then, the following .shift() is removing that unique element:
// message -> "!so user"
const args = message.slice(1).split('#');
// args -> ["so user"]
const command = args.shift().toLowerCase();
// args -> []
Just in case it can help you, I am removing the "#" if it is present. My "!so" command:
const commandArgs = message.split(' ');
const command = commandArgs.shift()?.toLowerCase?.();
// ...
const userName = commandArgs.shift();
if (userName[0] === '#') {
userName.shift(); // Here, userName is an string.
}
client.say(
channel,
`... #${userName}, ... -> https://twitch.tv/${userName}`
);