I want to write a Python program that would take a user's age in years and will return their birth year. I tried to use the datetime module and find the current year, then subtract the age from the current year. Unfortunately, for certain birth months it's not giving me the right year. For example, if an user who was born in April 9 in 1990 inputs his birthday as 32 (since it's still January 2023, not April), he will get 1991 as his birth year which would be wrong, because he does not turn 33 until April 9, 2023. Also there are leap years. I don't know how to determine the birthday only from taking age as input. Any suggestions? Or is there any alternate ways of doing it?
This is my code:
from datetime import date
age = input("What's your age?")
today = date.today()
current_year=today.year
birth_year=current_year-age
But if I try giving 32 as age input for someone who has not yet turned 33 in the January 2023 (will turn 33 in April), then it will give me 1991 as the birth month, which is wrong.
Related
I'm new to python and new to pandas. Of course, if my project used exact dates, I could easily do this, but unfortunately, the date type is a little different, and as you can see, the sign 08 is after the year 1401, which means it is the eighth month of the year 1401.
I currently know that these 3 customers have bought from me this month. But I want to know if these 3 customers bought from me in the previous month or two months ago? If they do, I will give them a discount.
Of course, I should also say that the number 08 is not always fixed, but it could be 09 in the next month. I just want to know if they bought from me 1 month ago or not?
According to the picture, now only Sara should get a discount
You could convert the purchase date to an integer and calculate the number of months from there.
For instance, you have the purchase month 1901/07 and you want to know in 1901/08 how many months the last purchase took place. So you convert both values to integers and subtract them (190108 - 190107 = 1).
import pandas as pd
df = pd.DataFrame({'customer': ['david', 'sara'], 'date': ['1901/03', '1901/07']})
# Manually setting the reference month (190108 for Year 1901 and Month 08)
df['months'] = 190108 - df['date'].replace('/', '', regex=True).astype(int)
# Check if eligible for discount
df['discount'] = df['months'].isin([1, 2])
customer
date
months
discount
0
david
1901/03
5
False
1
sara
1901/07
1
True
To compare with today's month you could to the following:
df['months'] = int(pd.Timestamp.now().strftime('%Y%m'))\
- df['date'].replace('/', '', regex=True).astype(int)
I have a 2 months old dataset, from 15 October 2020, containing the ages of different persons. The age of each person is given in years, months, days.
Example
Input: Reference date = 15 October 2020
One entry in the input data set could be:
Input: Age = 21 years, 0 months, 10 days
Corresponding output: Date of Birth = 25 September 1999
This takes into account that their age was reported on 15 October 2020.
I have to convert this data set to get the Date of Birth of each person. How can I accomplish that?
You can use the dateutil.relativedelta function, which you can use to subtract years, months and days from another date.
I'll assume that you know the exact date on which the data was collected, ... let's say 15 October 2020:
from datetime import date
from dateutil.relativedelta import relativedelta
# Let's say the data was taken on 15 October 2020:
refdate = date(2020, 10, 15)
# The data itself: triplets of years, months, days as collected on 15 October 2020:
data = [
[20, 2, 1],
[53, 5, 10],
]
# Extend the data with the birthdate:
for person in data:
person.append(refdate - relativedelta(years=person[0],
months=person[1],
days=person[2]))
# Print the data:
for person in data:
print("{} years, {} months, {} days: born on {}".format(*person))
I developing a course app. In my app, if a student register for a new course, the teacher must input the starting course date for the student.
And in this app, the student can pick up the day that they want to learn to the teacher.
e.g: The student wants to learn 3 days for each week, Monday, Tuesday and Friday.
And for the day that the student taking, they must pay to the teacher on that day.
So, I want my app can automatically display on what day a student must pay the tuition to the teacher.
The thing that I need here is: if the teacher inputted the starting course date on 20-10-2019 (%d-m-Y%), and the days that the student taking are Monday, Tuesday and Friday, I want to print: print('please, pay it') every week on the selected day.
So, I want something like this:
import datetime
starting_course_date = datetime.datetime.strptime("20-10-2019", "%d-%m-%Y")
student_taking_days = [{'day': 'Monday'}, {'day': 'Tuesday'}, {'day': 'Friday'}]
today = datetime.datetime.utcnow()
if today > starting_course_date and today is one of day on the student_taking_days:
print('please, pay it')
Please, any answer, source or refer tutorial will be very appreciated :)
You can get weekday of your today. More info here
import datetime
weekday = datetime.datetime.today().weekday()
if (weekday in [0, 1, 4]): // 0 is monday, 1 is tuesday and 4 is friday
print('please, pay it')
You event can get day name like this using strftime:
weekday_name = weekday.strftime("%A")
if (weekday_name in ['Monday', 'Tuesday', 'Friday']):
print('please, pay it')
weekday = today.weekday()
This gives the result as an integer starting from Monday = 0.
You could directly use this variable in your 'if' statement.
if weekday == 0 or weekday == 1 or weekday == 4:
print('please, pay it')
The Excel/Google-Sheets/LibreOffice function DAYS360() returns the number of days between two dates based on a 360-day year. 0 (default) is used for the US-based method and here are some examples
A = 30 Apr 2016, B = 29 Feb 2016, DAYS360(A, B) = -61
A = 29 Feb 2016, B = 30 Apr 2016, DAYS360(A, B) = 60
This seems ok according to the rules here
But the Excel/Google-Sheets/LibreOffice function YEARFRAC() returns the number of years, including fractional years, between two dates using a specified day count convention. Even here 0 (default) uses US method, (US (NASD) 30/360) which I presumed will also be equal to the value of number of days calculated by DAYS360 * the number of seconds in a day/number of seconds in 360 days. The values in the sheets are as follows
A = 30 Apr 2016, B = 29 Feb 2016, YEARFRAC(A, B) = 0.1666666667
A = 29 Feb 2016, B = 30 Apr 2016, YEARFRAC(A, B) = 0.1666666667
Since it can be seen that the absolute value of the DAYS360 is different by one, the YEARFRAC value is same and assumes 60 days according to the presumption made above, so are the US-based convention mentioned here is the same as mentioned for DAYS360.
If not, what are the exact rules for this one, or is there some other problem?
NOTE: Tested these values on Google Sheets and Libre Office.
DAYS360 parameter 3:
0 indicates the US method - Under the US method, if start_date is the last day of a month, the day of month of start_date is changed to
30 for the purposes of the calculation. Furthermore if end_date is the
last day of a month and the day of the month of start_date is earlier
than the 30th, end_date is changed to the first day of the month
following end_date, otherwise the day of month of end_date is changed
to 30.
1 or any other value indicates the European method - Under the European method, any start_date or end_date that falls on the 31st of
a month has its day of month changed to 30.
YEARFRAC parameter 3:
0 indicates US (NASD) 30/360 - This assumes 30 day months and 360 day
years as per the National Association of Securities Dealers standard,
and performs specific adjustments to entered dates which fall at the
end of months.
1 indicates Actual/Actual - This calculates based upon the actual
number of days between the specified dates, and the actual number of
days in the intervening years. Used for US Treasury Bonds and Bills,
but also the most relevant for non-financial use.
2 indicates Actual/360 - This calculates based on the actual number of
days between the specified dates, but assumes a 360 day year.
3 indicates Actual/365 - This calculates based on the actual number of
days between the specified dates, but assumes a 365 day year.
4 indicates European 30/360 - Similar to 0, this calculates based on a
30 day month and 360 day year, but adjusts end-of-month dates
according to European financial conventions.
I would like to calculte the number of the week in a year. I see this post
In this post the acepted answer use this code:
public static int GetIso8601WeekOfYear(DateTime time)
{
// Seriously cheat. If its Monday, Tuesday or Wednesday, then it'll
// be the same week# as whatever Thursday, Friday or Saturday are,
// and we always get those right
DayOfWeek day = CultureInfo.InvariantCulture.Calendar.GetDayOfWeek(time);
if (day >= DayOfWeek.Monday && day <= DayOfWeek.Wednesday)
{
time = time.AddDays(3);
}
// Return the week of our adjusted day
return CultureInfo.InvariantCulture.Calendar.GetWeekOfYear(time, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);
}
However I see a problem. The number of the week is repeated if the last day of a month is in Sunday.
For example, the last day of March of 2013 year is in sunday. This week is the number 13th, is correct. But in April, how C# use always 6 weeks in a month to calculate the number of week, the first week of april has not any day of april, because all the days belong to march because the last day of the week is 30th March. So C# says that the first week of april is th 15th week, but this is incorrect, it has to be 14th.
So I would like to know if there are any way to calculate the number of a week in a right way.
EDIT:
I mean this:
In march, the last week is this:
25 26 27 28 29 30 31
This is the 13th, is correct.
In april, the first week is:
1 2 3 4 5 6 7
And this week is calculated as 15th.
So if I see the march calendar the last week is calculated as 13th and if I see the april calendar the last week of march is caluclated as 14th. This is incorrect.
SOLUTION:
DateTime dtCalendar = Calendar.DisplayDate;
int gridRow = (int)GetValue(Grid.RowProperty);
// Return the week of our adjusted day
int wueekNumber= System.Globalization.CultureInfo.InvariantCulture.Calendar.GetWeekOfYear(dtCalendar, System.Globalization.CalendarWeekRule.FirstDay, DayOfWeek.Monday);
if (dtCalendar.DayOfWeek == DayOfWeek.Monday)
{
gridRow = gridRow - 1;
}
Text = (weekNumbe r+ gridRow - 1).ToString();
Thanks.
The problem is that you are using the wrong CalendarWeekRule. To get the result you want you should use FirstDay. I have seen various codes in internet saying that you should use FirstFourDayWeek but, after some testing, I realised that the "right one" is FirstDay. I have tested it with your example and it delivers the right result: 14th week.
int targetYear = 2013;
DateTime targetDate = new DateTime(targetYear, 4, 1);
int week = System.Globalization.CultureInfo.CurrentCulture.Calendar.GetWeekOfYear(targetDate, System.Globalization.CalendarWeekRule.FirstDay, DayOfWeek.Monday);