I want to print out all words in a string, line by line without using split() funcion in Python 3.
The phrase is a str(input) by the user, and it has to print all the words in the string, no matter it's size.Here's my code:
my_string = str(input("Phrase: "))
tam = len(my_string)
s = my_string
ch = " "
cont = 0
for i, letter in enumerate(s):
if letter == ch:
#print(i)
print(my_string[cont:i])
cont+=i+1
The output to this is:
Phrase: Hello there my friend
Hello
there
It is printing only two words in the string, and I need it to print all the words , line by line.
My apologies, if this isn't a homework question, but I will leave you to figure out the why.
a = "Hello there my friend"
b = "".join([[i, "\n"][i == " "] for i in a])
print(b)
Hello
there
my
friend
Some variants you can add to the process which you can't get easily with if-else syntax:
print(b.Title()) # b.lower() or b.upper()
Hello
There
My
Friend
def break_words(x):
x = x + " " #the extra space after x is nessesary for more than two word strings
strng = ""
for i in x: #iterate through the string
if i != " ": #if char is not a space
strng = strng+i #assign it to another string
else:
print(strng) #print that new string
strng = "" #reset new string
break_words("hell o world")
output:
hell
o
world
This question already has answers here:
How to extract the substring between two markers?
(22 answers)
Closed 4 years ago.
How do I find a string between two substrings ('123STRINGabc' -> 'STRING')?
My current method is like this:
>>> start = 'asdf=5;'
>>> end = '123jasd'
>>> s = 'asdf=5;iwantthis123jasd'
>>> print((s.split(start))[1].split(end)[0])
iwantthis
However, this seems very inefficient and un-pythonic. What is a better way to do something like this?
Forgot to mention:
The string might not start and end with start and end. They may have more characters before and after.
import re
s = 'asdf=5;iwantthis123jasd'
result = re.search('asdf=5;(.*)123jasd', s)
print(result.group(1))
s = "123123STRINGabcabc"
def find_between( s, first, last ):
try:
start = s.index( first ) + len( first )
end = s.index( last, start )
return s[start:end]
except ValueError:
return ""
def find_between_r( s, first, last ):
try:
start = s.rindex( first ) + len( first )
end = s.rindex( last, start )
return s[start:end]
except ValueError:
return ""
print find_between( s, "123", "abc" )
print find_between_r( s, "123", "abc" )
gives:
123STRING
STRINGabc
I thought it should be noted - depending on what behavior you need, you can mix index and rindex calls or go with one of the above versions (it's equivalent of regex (.*) and (.*?) groups).
start = 'asdf=5;'
end = '123jasd'
s = 'asdf=5;iwantthis123jasd'
print s[s.find(start)+len(start):s.rfind(end)]
gives
iwantthis
s[len(start):-len(end)]
String formatting adds some flexibility to what Nikolaus Gradwohl suggested. start and end can now be amended as desired.
import re
s = 'asdf=5;iwantthis123jasd'
start = 'asdf=5;'
end = '123jasd'
result = re.search('%s(.*)%s' % (start, end), s).group(1)
print(result)
Just converting the OP's own solution into an answer:
def find_between(s, start, end):
return (s.split(start))[1].split(end)[0]
If you don't want to import anything, try the string method .index():
text = 'I want to find a string between two substrings'
left = 'find a '
right = 'between two'
# Output: 'string'
print(text[text.index(left)+len(left):text.index(right)])
source='your token _here0#df and maybe _here1#df or maybe _here2#df'
start_sep='_'
end_sep='#df'
result=[]
tmp=source.split(start_sep)
for par in tmp:
if end_sep in par:
result.append(par.split(end_sep)[0])
print result
must show:
here0, here1, here2
the regex is better but it will require additional lib an you may want to go for python only
Here is one way to do it
_,_,rest = s.partition(start)
result,_,_ = rest.partition(end)
print result
Another way using regexp
import re
print re.findall(re.escape(start)+"(.*)"+re.escape(end),s)[0]
or
print re.search(re.escape(start)+"(.*)"+re.escape(end),s).group(1)
Here is a function I did to return a list with a string(s) inbetween string1 and string2 searched.
def GetListOfSubstrings(stringSubject,string1,string2):
MyList = []
intstart=0
strlength=len(stringSubject)
continueloop = 1
while(intstart < strlength and continueloop == 1):
intindex1=stringSubject.find(string1,intstart)
if(intindex1 != -1): #The substring was found, lets proceed
intindex1 = intindex1+len(string1)
intindex2 = stringSubject.find(string2,intindex1)
if(intindex2 != -1):
subsequence=stringSubject[intindex1:intindex2]
MyList.append(subsequence)
intstart=intindex2+len(string2)
else:
continueloop=0
else:
continueloop=0
return MyList
#Usage Example
mystring="s123y123o123pp123y6"
List = GetListOfSubstrings(mystring,"1","y68")
for x in range(0, len(List)):
print(List[x])
output:
mystring="s123y123o123pp123y6"
List = GetListOfSubstrings(mystring,"1","3")
for x in range(0, len(List)):
print(List[x])
output:
2
2
2
2
mystring="s123y123o123pp123y6"
List = GetListOfSubstrings(mystring,"1","y")
for x in range(0, len(List)):
print(List[x])
output:
23
23o123pp123
To extract STRING, try:
myString = '123STRINGabc'
startString = '123'
endString = 'abc'
mySubString=myString[myString.find(startString)+len(startString):myString.find(endString)]
You can simply use this code or copy the function below. All neatly in one line.
def substring(whole, sub1, sub2):
return whole[whole.index(sub1) : whole.index(sub2)]
If you run the function as follows.
print(substring("5+(5*2)+2", "(", "("))
You will pobably be left with the output:
(5*2
rather than
5*2
If you want to have the sub-strings on the end of the output the code must look like below.
return whole[whole.index(sub1) : whole.index(sub2) + 1]
But if you don't want the substrings on the end the +1 must be on the first value.
return whole[whole.index(sub1) + 1 : whole.index(sub2)]
These solutions assume the start string and final string are different. Here is a solution I use for an entire file when the initial and final indicators are the same, assuming the entire file is read using readlines():
def extractstring(line,flag='$'):
if flag in line: # $ is the flag
dex1=line.index(flag)
subline=line[dex1+1:-1] #leave out flag (+1) to end of line
dex2=subline.index(flag)
string=subline[0:dex2].strip() #does not include last flag, strip whitespace
return(string)
Example:
lines=['asdf 1qr3 qtqay 45q at $A NEWT?$ asdfa afeasd',
'afafoaltat $I GOT BETTER!$ derpity derp derp']
for line in lines:
string=extractstring(line,flag='$')
print(string)
Gives:
A NEWT?
I GOT BETTER!
This is essentially cji's answer - Jul 30 '10 at 5:58.
I changed the try except structure for a little more clarity on what was causing the exception.
def find_between( inputStr, firstSubstr, lastSubstr ):
'''
find between firstSubstr and lastSubstr in inputStr STARTING FROM THE LEFT
http://stackoverflow.com/questions/3368969/find-string-between-two-substrings
above also has a func that does this FROM THE RIGHT
'''
start, end = (-1,-1)
try:
start = inputStr.index( firstSubstr ) + len( firstSubstr )
except ValueError:
print ' ValueError: ',
print "firstSubstr=%s - "%( firstSubstr ),
print sys.exc_info()[1]
try:
end = inputStr.index( lastSubstr, start )
except ValueError:
print ' ValueError: ',
print "lastSubstr=%s - "%( lastSubstr ),
print sys.exc_info()[1]
return inputStr[start:end]
from timeit import timeit
from re import search, DOTALL
def partition_find(string, start, end):
return string.partition(start)[2].rpartition(end)[0]
def re_find(string, start, end):
# applying re.escape to start and end would be safer
return search(start + '(.*)' + end, string, DOTALL).group(1)
def index_find(string, start, end):
return string[string.find(start) + len(start):string.rfind(end)]
# The wikitext of "Alan Turing law" article form English Wikipeida
# https://en.wikipedia.org/w/index.php?title=Alan_Turing_law&action=edit&oldid=763725886
string = """..."""
start = '==Proposals=='
end = '==Rival bills=='
assert index_find(string, start, end) \
== partition_find(string, start, end) \
== re_find(string, start, end)
print('index_find', timeit(
'index_find(string, start, end)',
globals=globals(),
number=100_000,
))
print('partition_find', timeit(
'partition_find(string, start, end)',
globals=globals(),
number=100_000,
))
print('re_find', timeit(
're_find(string, start, end)',
globals=globals(),
number=100_000,
))
Result:
index_find 0.35047444528454114
partition_find 0.5327825636197754
re_find 7.552149639286381
re_find was almost 20 times slower than index_find in this example.
My method will be to do something like,
find index of start string in s => i
find index of end string in s => j
substring = substring(i+len(start) to j-1)
This I posted before as code snippet in Daniweb:
# picking up piece of string between separators
# function using partition, like partition, but drops the separators
def between(left,right,s):
before,_,a = s.partition(left)
a,_,after = a.partition(right)
return before,a,after
s = "bla bla blaa <a>data</a> lsdjfasdjöf (important notice) 'Daniweb forum' tcha tcha tchaa"
print between('<a>','</a>',s)
print between('(',')',s)
print between("'","'",s)
""" Output:
('bla bla blaa ', 'data', " lsdjfasdj\xc3\xb6f (important notice) 'Daniweb forum' tcha tcha tchaa")
('bla bla blaa <a>data</a> lsdjfasdj\xc3\xb6f ', 'important notice', " 'Daniweb forum' tcha tcha tchaa")
('bla bla blaa <a>data</a> lsdjfasdj\xc3\xb6f (important notice) ', 'Daniweb forum', ' tcha tcha tchaa')
"""
Parsing text with delimiters from different email platforms posed a larger-sized version of this problem. They generally have a START and a STOP. Delimiter characters for wildcards kept choking regex. The problem with split is mentioned here & elsewhere - oops, delimiter character gone. It occurred to me to use replace() to give split() something else to consume. Chunk of code:
nuke = '~~~'
start = '|*'
stop = '*|'
julien = (textIn.replace(start,nuke + start).replace(stop,stop + nuke).split(nuke))
keep = [chunk for chunk in julien if start in chunk and stop in chunk]
logging.info('keep: %s',keep)
Further from Nikolaus Gradwohl answer, I needed to get version number (i.e., 0.0.2) between('ui:' and '-') from below file content (filename: docker-compose.yml):
version: '3.1'
services:
ui:
image: repo-pkg.dev.io:21/website/ui:0.0.2-QA1
#network_mode: host
ports:
- 443:9999
ulimits:
nofile:test
and this is how it worked for me (python script):
import re, sys
f = open('docker-compose.yml', 'r')
lines = f.read()
result = re.search('ui:(.*)-', lines)
print result.group(1)
Result:
0.0.2
This seems much more straight forward to me:
import re
s = 'asdf=5;iwantthis123jasd'
x= re.search('iwantthis',s)
print(s[x.start():x.end()])