Why does glob promise return an empty string array? - node.js

Question

I am only using typescript, ts-node, npm and path
I am simply trying to return a string array of files defined by my pattern using glob-promise (An npm that I imported which uses glob but its promise based).
I created a custom npm script to run my ts file for the terminal to display info in my package.json below
{
"name": "glob-test",
"version": "1.0.0",
"description": "A Glob Test",
"scripts": {
"build:glob": "ts-node --files globby.ts"
},
"dependencies": {
"glob-promise": "^6.0.1",
"path": "^0.12.7",
"ts-node": "^10.9.1",
"typescript": "^4.9.4"
}
}
And this below is my globby.ts file which runs the glob script
import * as path from 'path';
import glob from 'glob-promise';
const dir = path.dirname(__dirname);
const txtURL = path.resolve(dir, 'glob-test', 'folder-area', '*.txt');
glob(txtURL).then(function (cnt) {
console.log('Path: ' + txtURL);
console.log('Content: ', cnt);
});
My project directory looks like so:
I type in my terminal npm run build:glob but it returns an empty array and the path displays correctly I'm not sure what I am doing wrong. I've attempted to use path.join and path.resolve but either give the same result. It should return the joke.txt file. Anyone have any idea ?

Answer 1

Turns out the answer is that the path module with the glob-promise module are not playing nice in my windows environment. If I use a normal string with or without concats glob will return perfectly anything I ask.
This seems to be a bug/issue or incompatibility within the windows environment most likely. Yet to test on Linux.
e.g: Works below
import * as path from 'path';
import glob from 'glob-promise';
// const dir = path.dirname(__dirname);
const txtURL = path.resolve('folder-area', '*.txt');
const testURL = './folder-area/*.txt';
const returnTxtFiles = async () => {
const txtFiles = await glob(testURL);
console.log(txtFiles);
};
returnTxtFiles();
The above correctly returns ['joke.txt', 'file1.txt']
The other option is replace all the '/' to '' manually to any path.join("string", "string") by adding at the end .replace(/\\/g, "/")
Which is the method I went with as it took much less work adn I think is more understandable as well as it changes the original codebase the least.