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Cron job every three days
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please i want to create crontab that should runs evry 14th working day at 10am.
Im tried this row but still not giving what i want.
0 10 14 * 1-5
Thank you in advance
This will make it run on the 14th of the month (if that day falls between monday and friday)
0 10 */14 * 1-5
If you want it to run every 14 working days, you might want the cron job to call a script. Tell cron to run every day at 10. The script can then keep track of last time it ran, compare it and run if it's been 14 days and if today is a weekday.
Related
I want to create a reminder very similar to google calendar custom reminder feature.
Where user can select number of days/weeks/months/years using djano-celery periodic task and crontab.
For eg I want a task to run on every 26th May in every 2 years what can be the expression.
After research I found the below expression but it is not working.
58 10 26 5/24 *
For this i am getting the below result in crontab generator
Similarly I want a task to run on every Thursday and Friday which repeats in every 2 weeks.
As per my research it should be like
30 10 */14 * 4,5
But this as well is not working.
I want django-celery-crontab expression.
We have jobs that are scheduled to run 1 time per day - every day
We do maintenance every 3rd Sunday of the month.
Up until now every month we have manually adjusted the cron to make the job run a little later in the morning then after maintenance we reset to the desired schedule
I am trying to change cron so that we
run at 7:00am every day EXCEPT the third Sunday of the month
run at 9:00am only on the third Sunday of the month
the second item I am able to handle
0 13 15-21 * 0
however, the first has me stumped. I thought this would do the job but it will only execute this if the day is between 1-14 or 22-31 but what if the 15th is not Sunday - then it won't run.
0 11 1-14,22-31 * *
How do I tell cron to run a schedule EXCEPT the third Sunday of the month?
There is a large base of guidance on how to limit when a cron runs to a specific window but I haven't found much for how to EXCLUDE a cron from a specific window
******** UPDATE ********
I think I may have come up with an answer - not sure if it is the most efficient but
0 11 1-14,22-31 * 0
0 13 15-21 * 0
0 11 1-14,22-31 * 1-6
The above will
run at 11:00 UTC on Sunday if date is between 1-14 or 22-31
run at 13:00 UTC on Sunday if date is between 15-21 (3rd Sunday)
run at 11:00 UTC Monday through Saturday all month
If a cron job has different timing than others, then it best to just define it by itself rather than trying to combine, unless you put some code in your script to do what you actually want. Doing something in cron on some nth day of the month is a pretty well known problem. Most crontab man pages have this note:
Note: The day of a command's execution can be specified in the following two fields — 'day of month', and 'day of week'. If both fields are restricted (i.e., do not contain the "*" character), the command will be run when either field matches the crent time. For example,
"30 4 1,15 * 5" would cause a command to be run at 4:30 am on the 1st and 15th of each month, plus every Friday.
So it does OR between the day of the week and the day of the month, not an AND. I don't who ever thought this was helpful, but that's the way it is. You can see solutions at:
Run every 2nd and 4th Saturday of the month
you need something like (this assumes cron runs /bin/sh):
[ `date +\%w` -eq 6 ] && <command>
on your cron job line, the above is would restrict to running only on Saturday.
I have tried the crontab schedule 0 0 */6 * * to run my service for every 6 days. The service should start to run at 6th day of the month and continue to run for every six days. But suddenly the service started to run at 1st of the month then on 7th, 13th and so on. Could anyone please explain me why the crontab schedule is not behaving as expected?
I want a script to be executed each first Saturday of a quarter.
Therefore I have set a crontab line up with the following
24 9 1-7 1,4,7,10 6 /absolute/path/to/script
This script was now executed yesterday, at 9:24 (ok),on Saturay (ok), but on October(ok) 16th(NOK).
Any hints what I missed or misunderstood?
Thanks a lot.
The script runs every day the first 7 days and every Saturday of the specified months.
The reason is well explained in this crontab guru page (and crontab(5)'s man page). The relevant piece is:
Note: The day of a command's execution can be specified in the following two fields --- 'day of month', and 'day of week'. If both fields are restricted (i.e., do not contain the "*" character), the command will be run when either field matches the current time. For example,
"30 4 1,15 * 5" would cause a command to be run at 4:30 am on the 1st and 15th of each month, plus every Friday.
You can check that this is indeed what happens by checking the description and when your script will be run next ("next at") here.
The way to achieve what you want, i.e., run the script on the first Saturday, is described in other questions/answers. See, for instance, Run a cron job on the first Monday of every month? or How to schedule to run first Sunday of every month. In short, replace 6 with * and combine your command with a call to date.
i'm trying to do some stuff automatically every 8 Weeks, so i had open a new user crontab like this one:
crontab -e
0 9 * */2 1-5 do_this_stuff
# do it every 2 month on monday till friday at 9:00 am
This should do the job every 2 month on monday till friday on 9:00 am, but i does not. It is doing the job evey week once. Don't get it. What i'm doing wrong?
Running System is a latest debian.
regarding http://wiki.ubuntuusers.de/Cron it should run fine
The Anwer is, cron can't do a job randomly on a random day in a month. I had to change my crontab to: 0 9 1 */2 * do_sm_stuff -- this runs every two Month always on the first Day in a Month
thank you Igor