How to replace the string in special characters '' using sed [duplicate] - linux

I need use sed into bash script, for add lines after any line numer of script with some pair of values (below work)
sed -i.bak '14i\some_text=some_text' file
But I need on script bash (sh) for expand variables (below not work)
sed -i.bak '$number_linei\$var1=$var2' $var3

Just use double quotes instead of single quotes. You'll also need to use {} to delimit the number_line variable correctly and escape the \, too.
sed -i.bak "${number_line}i\\$var1=$var2" $var3
I'd personally prefer to see all of the variables use the {}, ending up with something like:
sed -i.bak "${number_line}i\\${var1}=${var2}" ${var3}

Change single quotes to double quotes:
man bash:
Enclosing characters in single quotes preserves the literal value of
each character within the quotes.
Enclosing characters in double quotes preserves the literal value of
all characters within the quotes, with the exception of $, `, \, and,
when history expansion is enabled, !. The characters $ and ` retain
their special meaning within double quotes.

Related

How do I get the sed command to evaluate an environment variable? [duplicate]

I need use sed into bash script, for add lines after any line numer of script with some pair of values (below work)
sed -i.bak '14i\some_text=some_text' file
But I need on script bash (sh) for expand variables (below not work)
sed -i.bak '$number_linei\$var1=$var2' $var3
Just use double quotes instead of single quotes. You'll also need to use {} to delimit the number_line variable correctly and escape the \, too.
sed -i.bak "${number_line}i\\$var1=$var2" $var3
I'd personally prefer to see all of the variables use the {}, ending up with something like:
sed -i.bak "${number_line}i\\${var1}=${var2}" ${var3}
Change single quotes to double quotes:
man bash:
Enclosing characters in single quotes preserves the literal value of
each character within the quotes.
Enclosing characters in double quotes preserves the literal value of
all characters within the quotes, with the exception of $, `, \, and,
when history expansion is enabled, !. The characters $ and ` retain
their special meaning within double quotes.

remove backslash only from quote character using sed

I have string: this is a [\"sample\"] sample\'s.
What would be the correct way to remove backslashes from the double quote, preserving the double quote.
Expected output: this is a ["sample"] sample\'s.
I've tested: sed -i 's/\\\"//g' file.txt which is removing the "
Your command is almost correct. You just forgot to substitute with a double quote:
sed -i 's/\\"/"/g' file.txt
sed's s command substitutes the first part (between / here) with the second part. The g flag repeats the operation throughout the line. Your mistake was that the second part was empty, thus effectively deleting the whole \" string.
BTW, escaping the double quote is not necessary since your sed command is inside single quotes.

Grep issue after escaping backslash

I am trying to grep the string
"SNTCHDCS06-Filesystem D:\\ Label:Data Serial Number f8271450"
from a csv file, but somehow I failed miserably.
I understand that I need to add two backlashes on top of the two backslashes (one for shell, one for bash), but it doesn't work after that.
The below command works.
[root#nagiospdc01 folder]# grep -e "^SNTCHDCS06-Filesystem D:\\\\" in/masterlist.csv
SNTCHDCS06-Filesystem D:\\ Label:Data Serial Number f8271450,SNTCHDCS06,10.24.64.210,Active Directory,AD Server,UCS,Filesystem D:\\ Label:Data Serial Number f8271450,Windows Team,0,XM_OPS_WIN,Windows Team,Y,Y,N,N,Y,Y,Y,Y,Y,N,N,Y,Y,ITOC
When I try to grep for the space after that, grep doesn't work and simply fails.
[root#nagiospdc01 folder]# grep -e "^SNTCHDCS06-Filesystem D:\\\\ " in/masterlist.csv
Appreciate if someone can enlighten me on the correct grep syntax and command.
Use single quotes,
grep -e '^SNTCHDCS06-Filesystem D:\\ Label:Data Serial Number f8271450'
When using double quotes \\ gets converted to a single \ by bash. However bash does not look inside single quotes.
From the Bash manual:
3.1.2.2 Single Quotes
Enclosing characters in single quotes (') preserves the literal value of each character within the quotes. A single quote may not occur between single quotes, even when preceded by a backslash.
3.1.2.3 Double Quotes
Enclosing characters in double quotes (") preserves the literal value of all characters within the quotes, with the exception of $, `, \, and, when history expansion is enabled, !. The characters $ and ` retain their special meaning within double quotes (see Shell Expansions). The backslash retains its special meaning only when followed by one of the following characters: $, `, ", \, or newline. Within double quotes, backslashes that are followed by one of these characters are removed. Backslashes preceding characters without a special meaning are left unmodified. A double quote may be quoted within double quotes by preceding it with a backslash. If enabled, history expansion will be performed unless an ! appearing in double quotes is escaped using a backslash. The backslash preceding the ! is not removed.
The special parameters * and # have special meaning when in double quotes (see Shell Parameter Expansion).
The -F option in grep allows to search for fixed strings. Also the single quotes helps to search for the exact string.
-F, --fixed-strings :
Interpret PATTERN as a list of fixed strings, separated by newlines, any of which is to be matched.
grep -F 'SNTCHDCS06-Filesystem D:\\ Label:Data Serial Number f8271450' masterlist.csv
*SNTCHDCS06-Filesystem D:\\ Label:Data Serial Number f8271450*

Replace a string using sed

I want to replace a string ip_ttl="1" with ip_ttl="2" using sed.
I've tried sed -i "s/ip_ttl="1"/ip_ttl="2"/g" - but its not working.
Please help!
Put your sed code inside single quotes, because your code already contains double quotes.
sed -i 's/ip_ttl="1"/ip_ttl="2"/g' file
If you put your code within two double quotes, sed would terminate the program once another double quote was reached. So " before 1 was reached, it would consider as the end and terminates the program.
Update:
If the number always changes then it's better to define the pattern which matches any number.
sed -i 's/ip_ttl="[0-9]\+"/ip_ttl="2"/g' file
If you are using quotation marks in your pattern either escape double quotes in pattern:
sed -i "s/ip_ttl=\"1\"/ip_ttl=\"2\"/g"
or enclose whole pattern in single quotes:
sed -i 's/ip_ttl="1"/ip_ttl="2"/g'
Alternatively you can escape the quotation marks
sed -i "s/ip_ttl=\"1\"/ip_ttl=\"2\"/g" file
Sometimes that's useful because you have both single and double quotes in a string you're selecting for.

Trouble with sed [duplicate]

I need use sed into bash script, for add lines after any line numer of script with some pair of values (below work)
sed -i.bak '14i\some_text=some_text' file
But I need on script bash (sh) for expand variables (below not work)
sed -i.bak '$number_linei\$var1=$var2' $var3
Just use double quotes instead of single quotes. You'll also need to use {} to delimit the number_line variable correctly and escape the \, too.
sed -i.bak "${number_line}i\\$var1=$var2" $var3
I'd personally prefer to see all of the variables use the {}, ending up with something like:
sed -i.bak "${number_line}i\\${var1}=${var2}" ${var3}
Change single quotes to double quotes:
man bash:
Enclosing characters in single quotes preserves the literal value of
each character within the quotes.
Enclosing characters in double quotes preserves the literal value of
all characters within the quotes, with the exception of $, `, \, and,
when history expansion is enabled, !. The characters $ and ` retain
their special meaning within double quotes.

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