I have this script:
find test -type f \( -iname \*.html -o -iname \*.htm -o -iname \*.xhtml \) -exec grep -il ".swf" {} \; -printf '%k KB - \t %p\n' > result-swf-files.csv
This will search the directory "test" (and its subdirectories) for all HTML files which contains the word ".swf" in them. ANd will write a CSV file with the results.
But I want to get the file size too in the same line (now, the script outputs on one line the grep result - which doesn't have the file size - and in another line the printf result - which includes the file size).
How do I add an option to grep to get the file size?
A less verbose way is to use recursive grep (if your system supports it):
grep -rl --include="*.htm*" ".swf" test|xargs ls -l|awk '{ print $9 "," $5 }'
Explanation :
Grep recursively using the "rl" flag
include file pattern "*.htm"
search for the string ".swf" in each htm* file
search only under the "test" directory
pipe the result to xargs where each filename becomes argument to "ls -l" command
Then use awk to get to only filename and file size. Use comma "," in between 9th and 5th columns in awk print to get the csv output.
Feel free to replace "ls -l" with human readable variants such as "ls -lk" or "ls -lh"
Alternatively, in your script, you can just print only the 2nd line of each file (the one that contains the size). You can just pipe and use grep like this : grep "[0-9] [KB]"
Below is the complete command:
find . -type f \( -iname \*.html -o -iname \*.htm -o -iname \*.xhtml \) -exec grep -il ".swf" {} \; -printf '%k KB - \t %p\n'| grep "[0-9] [KB]"
find . -name *PATTERN*.gz -print0 | xargs -0 ls -lh
So you get ls for all files that you want.
GET_DIR=$ (find ${FIND_ROOT} -type -d 2>/dev/null | grep -Eiv ${EX_PATTERN| grep -Eio ${FIND_PATTERN})
but somehow when I try to print the result, its empty.
But when I am using my grep without a script I got results on the Command line.
You could avoid the pipe | and grep by using name or iname (case insensitive) within find, for example:
find /tmp -type d -iname "*foo*"
This will find directories -type d that match the pattern *foo* ignoring case -iname in /tmp
To save the output in a variable you could use:
FOO=$(find /tmp -type d -iname "*foo*")
From the find man:
-name pattern
True if the last component of the pathname being examined matches pattern. Special shell pattern matching
characters (``['', ``]'', ``*'', and ``?'') may be used as part of pattern. These characters may be matched
explicitly by escaping them with a backslash (``\'').
consider using xargs :
GET_DIR=$ (find ${FIND_ROOT} -type -d 2>/dev/null | xargs grep -Eiv ${EX_PATTERN| grep -Eio ${FIND_PATTERN})
I have a statement which
Finds a set of files
Cats their contents out
Then greps their contents
It is this pipeline:
find . | grep -i "Test_" | xargs cat | grep -i "start-node name="
produces an output such as:
<start-node name="Start" secure="false"/>
<start-node name="Run" secure="false"/>
What I was hoping to get is something like:
filename1-<start-node name="Start" secure="false"/>
filename2-<start-node name="Run" secure="false"/>
An easier may be to execute grep on the result of find, without xargs and cat:
grep -i "Test_" `find .` | grep -i "start-node name="
Because you cat all the files into a single stream, grep doesn't have any filename information. You want to give all the filenames to grep as arguments:
find ... | xargs grep "<start-node name=" /dev/null
Note two additional changes - I've dropped the -i flag, as it appears you're inspecting XML, and that's not case-insensitive; I've added /dev/null to the list of files, so that grep always has at least two files of input, even if find only gives one result. That's the portable way to get grep to print filenames.
Now, let's look at the find command. Instead of finding all files, then filtering through grep, we can use the -iregex predicate of GNU grep:
find . -iregex '.*Test_.*' \( -type 'f' -o -type 'l' \) | xargs grep ...
The mixed-case pattern suggests your filenames aren't really case-insensitive, and you might not want to grep symlinks (I'm sure you don't want directories and special files passed through), in which case you can simplify (and can use portable find again):
find . -name '*Test_*' -type 'f' | xargs grep ...
Now protect against the kind of filenames that trip up pipelines, and you have
find . -name '*Test_*' -type 'f' -print0 \
| xargs -0 grep -e "<start-node name=" -- /dev/null
Alternatively, if you have GNU grep, you don't need find at all:
grep --recursive --include '*[Tt]est_*' -e "<start-node name=" .
If you just need to count them:
find . | grep -i "Test_" | xargs cat | grep -i "start-node name=" | awk 'BEGIN{n=0}{n=n+1;print "filename" n "-" $0}'
From man grep:
-H Always print filename headers with output lines.
How do I recursively view a list of files that has one string and specifically doesn't have another string? Also, I mean to evaluate the text of the files, not the filenames.
Conclusion:
As per comments, I ended up using:
find . -name "*.html" -exec grep -lR 'base\-maps' {} \; | xargs grep -L 'base\-maps\-bot'
This returned files with "base-maps" and not "base-maps-bot". Thank you!!
Try this:
grep -rl <string-to-match> | xargs grep -L <string-not-to-match>
Explanation: grep -lr makes grep recursively (r) output a list (l) of all files that contain <string-to-match>. xargs loops over these files, calling grep -L on each one of them. grep -L will only output the filename when the file does not contain <string-not-to-match>.
The use of xargs in the answers above is not necessary; you can achieve the same thing like this:
find . -type f -exec grep -q <string-to-match> {} \; -not -exec grep -q <string-not-to-match> {} \; -print
grep -q means run quietly but return an exit code indicating whether a match was found; find can then use that exit code to determine whether to keep executing the rest of its options. If -exec grep -q <string-to-match> {} \; returns 0, then it will go on to execute -not -exec grep -q <string-not-to-match>{} \;. If that also returns 0, it will go on to execute -print, which prints the name of the file.
As another answer has noted, using find in this way has major advantages over grep -Rl where you only want to search files of a certain type. If, on the other hand, you really want to search all files, grep -Rl is probably quicker, as it uses one grep process to perform the first filter for all files, instead of a separate grep process for each file.
These answers seem off as the match BOTH strings. The following command should work better:
grep -l <string-to-match> * | xargs grep -c <string-not-to-match> | grep '\:0'
Here is a more generic construction:
find . -name <nameFilter> -print0 | xargs -0 grep -Z -l <patternYes> | xargs -0 grep -L <patternNo>
This command outputs files whose name matches <nameFilter> (adjust find predicates as you need) which contain <patternYes>, but do not contain <patternNo>.
The enhancements are:
It works with filenames containing whitespace.
It lets you filter files by name.
If you don't need to filter by name (one often wants to consider all the files in current directory), you can strip find and add -R to the first grep:
grep -R -Z -l <patternYes> | xargs -0 grep -L <patternNo>
find . -maxdepth 1 -name "*.py" -exec grep -L "string-not-to-match" {} \;
This Command will get all ".py" files that don't contain "string-not-to-match" at same directory.
To match string A and exclude strings B & C being present in the same line I use, and quotes to allow search string to contain a space
grep -r <string A> | grep -v -e <string B> -e "<string C>" | awk -F ':' '{print $1}'
Explanation: grep -r recursively filters all lines matching in output format
filename: line
To exclude (grep -v) from those lines the ones that also contain either -e string B or -e string C. awk is used to print only the first field (the filename) using the colon as fieldseparator -F
After a few searches from Google, what I come up with is:
find my_folder -type f -exec grep -l "needle text" {} \; -exec file {} \; | grep text
which is very unhandy and outputs unneeded texts such as mime type information. Any better solutions? I have lots of images and other binary files in the same folder with a lot of text files that I need to search through.
I know this is an old thread, but I stumbled across it and thought I'd share my method which I have found to be a very fast way to use find to find only non-binary files:
find . -type f -exec grep -Iq . {} \; -print
The -I option to grep tells it to immediately ignore binary files and the . option along with the -q will make it immediately match text files so it goes very fast. You can change the -print to a -print0 for piping into an xargs -0 or something if you are concerned about spaces (thanks for the tip, #lucas.werkmeister!)
Also the first dot is only necessary for certain BSD versions of find such as on OS X, but it doesn't hurt anything just having it there all the time if you want to put this in an alias or something.
EDIT: As #ruslan correctly pointed out, the -and can be omitted since it is implied.
Based on this SO question :
grep -rIl "needle text" my_folder
Why is it unhandy? If you need to use it often, and don't want to type it every time just define a bash function for it:
function findTextInAsciiFiles {
# usage: findTextInAsciiFiles DIRECTORY NEEDLE_TEXT
find "$1" -type f -exec grep -l "$2" {} \; -exec file {} \; | grep text
}
put it in your .bashrc and then just run:
findTextInAsciiFiles your_folder "needle text"
whenever you want.
EDIT to reflect OP's edit:
if you want to cut out mime informations you could just add a further stage to the pipeline that filters out mime informations. This should do the trick, by taking only what comes before :: cut -d':' -f1:
function findTextInAsciiFiles {
# usage: findTextInAsciiFiles DIRECTORY NEEDLE_TEXT
find "$1" -type f -exec grep -l "$2" {} \; -exec file {} \; | grep text | cut -d ':' -f1
}
find . -type f -print0 | xargs -0 file | grep -P text | cut -d: -f1 | xargs grep -Pil "search"
This is unfortunately not space save. Putting this into bash script makes it a bit easier.
This is space safe:
#!/bin/bash
#if [ ! "$1" ] ; then
echo "Usage: $0 <search>";
exit
fi
find . -type f -print0 \
| xargs -0 file \
| grep -P text \
| cut -d: -f1 \
| xargs -i% grep -Pil "$1" "%"
Another way of doing this:
# find . |xargs file {} \; |grep "ASCII text"
If you want empty files too:
# find . |xargs file {} \; |egrep "ASCII text|empty"
How about this:
$ grep -rl "needle text" my_folder | tr '\n' '\0' | xargs -r -0 file | grep -e ':[^:]*text[^:]*$' | grep -v -e 'executable'
If you want the filenames without the file types, just add a final sed filter.
$ grep -rl "needle text" my_folder | tr '\n' '\0' | xargs -r -0 file | grep -e ':[^:]*text[^:]*$' | grep -v -e 'executable' | sed 's|:[^:]*$||'
You can filter-out unneeded file types by adding more -e 'type' options to the last grep command.
EDIT:
If your xargs version supports the -d option, the commands above become simpler:
$ grep -rl "needle text" my_folder | xargs -d '\n' -r file | grep -e ':[^:]*text[^:]*$' | grep -v -e 'executable' | sed 's|:[^:]*$||'
Here's how I've done it ...
1 . make a small script to test if a file is plain text
istext:
#!/bin/bash
[[ "$(file -bi $1)" == *"file"* ]]
2 . use find as before
find . -type f -exec istext {} \; -exec grep -nHi mystring {} \;
Here's a simplified version with extended explanation for beginners like me who are trying to learn how to put more than one command in one line.
If you were to write out the problem in steps, it would look like this:
// For every file in this directory
// Check the filetype
// If it's an ASCII file, then print out the filename
To achieve this, we can use three UNIX commands: find, file, and grep.
find will check every file in the directory.
file will give us the filetype. In our case, we're looking for a return of 'ASCII text'
grep will look for the keyword 'ASCII' in the output from file
So how can we string these together in a single line? There are multiple ways to do it, but I find that doing it in order of our pseudo-code makes the most sense (especially to a beginner like me).
find ./ -exec file {} ";" | grep 'ASCII'
Looks complicated, but not bad when we break it down:
find ./ = look through every file in this directory. The find command prints out the filename of any file that matches the 'expression', or whatever comes after the path, which in our case is the current directory or ./
The most important thing to understand is that everything after that first bit is going to be evaluated as either True or False. If True, the file name will get printed out. If not, then the command moves on.
-exec = this flag is an option within the find command that allows us to use the result of some other command as the search expression. It's like calling a function within a function.
file {} = the command being called inside of find. The file command returns a string that tells you the filetype of a file. Regularly, it would look like this: file mytextfile.txt. In our case, we want it to use whatever file is being looked at by the find command, so we put in the curly braces {} to act as an empty variable, or parameter. In other words, we're just asking for the system to output a string for every file in the directory.
";" = this is required by find and is the punctuation mark at the end of our -exec command. See the manual for 'find' for more explanation if you need it by running man find.
| grep 'ASCII' = | is a pipe. Pipe take the output of whatever is on the left and uses it as input to whatever is on the right. It takes the output of the find command (a string that is the filetype of a single file) and tests it to see if it contains the string 'ASCII'. If it does, it returns true.
NOW, the expression to the right of find ./ will return true when the grep command returns true. Voila.
I have two issues with histumness' answer:
It only list text files. It does not actually search them as
requested. To actually search, use
find . -type f -exec grep -Iq . {} \; -and -print0 | xargs -0 grep "needle text"
It spawns a grep process for every file, which is very slow. A better solution is then
find . -type f -print0 | xargs -0 grep -IZl . | xargs -0 grep "needle text"
or simply
find . -type f -print0 | xargs -0 grep -I "needle text"
This only takes 0.2s compared to 4s for solution above (2.5GB data / 7700 files), i.e. 20x faster.
Also, nobody cited ag, the Silver Searcher or ack-grep¸as alternatives. If one of these are available, they are much better alternatives:
ag -t "needle text" # Much faster than ack
ack -t "needle text" # or ack-grep
As a last note, beware of false positives (binary files taken as text files). I already had false positive using either grep/ag/ack, so better list the matched files first before editing the files.
Although it is an old question, I think this info bellow will add to the quality of the answers here.
When ignoring files with the executable bit set, I just use this command:
find . ! -perm -111
To keep it from recursively enter into other directories:
find . -maxdepth 1 ! -perm -111
No need for pipes to mix lots of commands, just the powerful plain find command.
Disclaimer: it is not exactly what OP asked, because it doesn't check if the file is binary or not. It will, for example, filter out bash script files, that are text themselves but have the executable bit set.
That said, I hope this is useful to anyone.
I do it this way:
1) since there're too many files (~30k) to search thru, I generate the text file list daily for use via crontab using below command:
find /to/src/folder -type f -exec file {} \; | grep text | cut -d: -f1 > ~/.src_list &
2) create a function in .bashrc:
findex() {
cat ~/.src_list | xargs grep "$*" 2>/dev/null
}
Then I can use below command to do the search:
findex "needle text"
HTH:)
I prefer xargs
find . -type f | xargs grep -I "needle text"
if your filenames are weird look up using the -0 options:
find . -type f -print0 | xargs -0 grep -I "needle text"
bash example to serach text "eth0" in /etc in all text/ascii files
grep eth0 $(find /etc/ -type f -exec file {} \; | egrep -i "text|ascii" | cut -d ':' -f1)
If you are interested in finding any file type by their magic bytes using the awesome file utility combined with power of find, this can come in handy:
$ # Let's make some test files
$ mkdir ASCII-finder
$ cd ASCII-finder
$ dd if=/dev/urandom of=binary.file bs=1M count=1
1+0 records in
1+0 records out
1048576 bytes (1.0 MB, 1.0 MiB) copied, 0.009023 s, 116 MB/s
$ file binary.file
binary.file: data
$ echo 123 > text.txt
$ # Let the magic begin
$ find -type f -print0 | \
xargs -0 -I ## bash -c 'file "$#" | grep ASCII &>/dev/null && echo "file is ASCII: $#"' -- ##
Output:
file is ASCII: ./text.txt
Legend: $ is the interactive shell prompt where we enter our commands
You can modify the part after && to call some other script or do some other stuff inline as well, i.e. if that file contains given string, cat the entire file or look for a secondary string in it.
Explanation:
find items that are files
Make xargs feed each item as a line into one liner bash
command/script
file checks type of file by magic byte, grep checks if ASCII
exists, if so, then after && your next command executes.
find prints results null separated, this is good to escape
filenames with spaces and meta-characters in it.
xargs , using -0 option, reads them null separated, -I ##
takes each record and uses as positional parameter/args to bash
script.
-- for bash ensures whatever comes after it is an argument even
if it starts with - like -c which could otherwise be interpreted
as bash option
If you need to find types other than ASCII, simply replace grep ASCII with other type, like grep "PDF document, version 1.4"
find . -type f | xargs file | grep "ASCII text" | awk -F: '{print $1}'
Use find command to list all files, use file command to verify they are text (not tar,key), finally use awk command to filter and print the result.
How about this
find . -type f|xargs grep "needle text"