The formula is exactly the same in both yellow cells. both are text.
Why is the result different?
Here is the formula:
=IF(ISNUMBER(SEARCH("b",A1:A4)),"bb",IF(ISNUMBER(SEARCH("d",A1:A4)),"cc","ee"))
With some chages, still same problem. I don't understand.
The function SEARCH returns a result for every cell in the given range (A1:A4). To get only one result, you can wrap it with OR to check whether any cell contains the text you are searching for.
=IF(OR(ISNUMBER(SEARCH("b",A1:A4))),"bb",IF(OR(ISNUMBER(SEARCH("d",A1:A4))),"cc","ee"))
Or just search for one cell at a time:
=IF(ISNUMBER(SEARCH("b",A1)),"bb",IF(ISNUMBER(SEARCH("d",A1)),"cc","ee"))
Related
I have a formula that looks like this
=IFERROR(B83,"OPEN")
So if a certain cell has an error it changes it to OPEN, but if it doesn't then it returns the values within that cell.
I am trying to make the cell also short the text that is being returned to 7 characters.
I made this formula:
IFERROR(B83,"OPEN"),AND(LEFT(B83,7))
However it does not work and instead returns an "NA".
Appreciate any help.
Try
IFERROR(LEFT(B83,7),"OPEN")
You need to put your desired result as the first argument of IFERROR.
I am straggling with some formula that I have a spreadsheet that contains two range of cells. What I want to do is,
I would like to create a search Box that will search a value from Range A and if found return range B value and also will count of range B value is repeated.
Below image is for what I mean
I used INDEX, MATCH and also IF Functions :( but not really get what I wanted.
I am poor in formula, so it would be great if someone can figure out what kind of functions I should use for this.
For information, it can be achieved through formula as below.
E3 houses the value being searched for e.g. "A"
In cell F3 insert following array formula which needs to be committed by hitting CTRL+SHIFT+ENTER simultaneously.
=IFERROR(INDEX($B$1:$B$1000,SMALL(IF(IFERROR(MATCH($E$3&$B$1:$B$1000,$A$1:$A$1000&$B$1:$B$1000,0),0)=ROW($B$1:$B$1000),ROW($B$1:$B$1000)),ROWS($A$1:A1))),"")
Copy down as much as you need.
You need to adjust 1000 to suit your data. It should match last row.
In cell G3 you can use following formula.
=IF(F3="","",COUNTIFS(A:A,$E$3,B:B,F3))
Copy down as much as you need.
Trying to format a cell (throughout entire column) if formula result of SAME CELL returns value of >.001
In other words, if result is 0, nothing will be entered into cell.
The comment would work. Another way would be suppose your desired formula is A2-B2 (you are testing whether the things are meaningfully different). Using your criterion (leaving aside whether it might be more meaningful to say the absolute value must exceed .001), you could rewrite your formula as:
=if(A2-B2>0.001,A2-B2,"")
This would generalize to any formula.
I've devised a formula that I want my cells to have, but I only want the value to show up if ANOTHER cell is populated with the value that I want.
My current formula is below:
=COUNTIFS($R$3:R21, "Brain")
However, this formula doesn't check whether or not the other cell has the value that I want to check for.
I put together a formula that I thought would check for whether or not the cell is populated:
=COUNTIFS($R$3:R21, "Brain", R21, "Brain")
Unfortunately, this formula doesn't work (it returns #VALUE!). I think it fails because R21 is already included in the COUNTIFS.
I also tried this similar formula, which also failed to work:
=COUNTIFS($R$3:R21, "Brain", R21:R21, "Brain")
I looked online and I found this possible solution:
=IF(ISNUMBER(SEARCH("Brain",R21)),"COUNTIFS($R$3:R21, 'Brain')","")
Unfortunately, this formula displays the text of the formula I want, and not the actual value of the formula.
Does anyone know how I could display the value from the formula ONLY if the cell I'm checking has the value that I want? Thanks.
Try
=IF(ISNUMBER(SEARCH("Brain",R21)),COUNTIFS($R$3:R21, 'Brain'),"")
This links to question 12299700 - I want to understand why SEARCH returns #Value when used alone but works when embedded into LOOKUP, and how I can make it work alone:
In Cell A1 I have a string of text: "This is some sample text"
In Cells D1:D4 I have words: "text, sample1, sample2, string" (all in separate cells)
I want to see if my string contains any of the words in my range - I don't need the matching word/s returned.
Using the Search function in any empty cell in Row 1 =SEARCH($D$1:$D$4,A1), returns 22. Good!
Using this in any other row returns #VALUE. Why?
If I keep my formula in Row 1, but move my range of words down to D2:D5, I get #Value. Why?
How can I make SEARCH work for my cell and ranges, in any cell?
(From the answer to question 12299700 I know I can use this formula to return the matched text, in any cell of the spreadsheet: =LOOKUP(2^15,SEARCH($D$1:$D$4,A1),$D$1:$D$4) - this includes a term that gives #VALUE on its own ... intriguing).
First question asked on Stackoverflow - feedback appreciated.
The function SEARCH returns #VALUE if the searched string was not found within the text. The function SEARCH expect only one searched string. It is not a array function itself. So if it gets a range as searched string, it uses only one of these range values as searched string. Which one it is, depends on the position of the formula.
Within LOOKUP the case is completely different. LOOKUP is an array formula itself. It gets the SEARCH($D$1:$D$4,$A$1) as { SEARCH($D$1,$A$1), SEARCH($D$2,$A$1), SEARCH($D$3,$A$1), SEARCH($D$4,$A$1) } which results in a array like { #VALUE, 21, #VALUE, 21 } depending of if SEARCH finds the string or not. That LOOKUP even works with such an array is strange. Normally it needs a sorted array. But it works and gets the last value which is lower or equal than the searched value.
If you need to use SEARCH like an array formula outside a native array formula, then you have to create this array context by entering the formula with [CTRL]+[SHIFT]+[ENTER] instead of only [ENTER]. The formula gets then curly braces around it.
In my example I have created such a formula in Cell E10.
If you are interested in how formulas work, you should often click fx and look how the single parameters comes through. And you should often use Evaluate Formula on the Formulas tab, in the Formula Auditing group.
What happens is that SEARCH is being used in an array form and is outputting in a linear form (non-array).
So, what happens in row 1 is that you're actually doing:
=SEARCH($D$1,A1)
Because evaluating a linear formula with an array tends to take the value from the array in the same row/column depending on the situation. So that means the above is looking for text in A1 which can be found.
On the second row, you will get:
=SEARCH($D$2,A1)
Which means it is searching for sample1 from A1 and since it cannot be found, you get #VALUE!.
To evaluate an array formula as an array, you will have to use Ctrl+Shift+Enter instead of pushing Enter after typing in the formula. Now the problem is that the formula above will return the same thing if you use only 1 cell...
If you want to see if your string contains any of the words in your range (and it's not important to know what word was found), then you will have to use another function along with SEARCH, for example, SUM and ISNUMBER and evaluating it as an array formula:
=SUM(ISNUMBER(SEARCH($D$1:$D$4,A1)))
And if you get a number above 0, you know there's at least 1 word in the text. Maybe to make the output more explicit:
=IF(SUM(ISNUMBER(SEARCH($D$1:$D$4,A1)))>0, "Word(s) found!", "No words found...")
If you want to know what word was found, you will have to use it as a normal formula and drag it down:
The reason why it works in VLOOKUP is that this function actually expects an array as the second parameter and since SEARCH is returning an array, well, that works out just well.
Also, you can view how functions work by clicking on the cell with the function, then do to 'Formulas' in the menu bar and clicking on 'Evaluate formula':
From there you can see if something is being evaluated as a linear or array formula and see how cell references are being substituted with the actual values.