I wish to retitle an Ubuntu terminal and then run a script which is very long term. I can successfully retitle, at which point I could enter a second command to perform the task, but I have not been able to do both in one step. If I try to to both with one step, the retitling only happens after the second task exit.
For example, in the .bashrc script I have entered:
function retitle(){
PS1="\[\e]0;HELLO\a\]${debian_chroot:+($debian_chroot)}\[\033[01;32m\]\u#\h\[\033[00m\]:\[\033[01;34m\]\w\[\033[00m\]\$"
read temp
}
The read temp is just to simulate my long task. I would actually wish to call another script at that point. So, I want to change the environment PS1 and have the change reflected in the title right away so that the user knows that this terminal is working on a long term task.
I am working with Ubuntu 22.04.1 LTS.
I have tried:
Using scripts for changing PS1.
Ending the first script with &&.
Sourcing the first script that changes PS1 (this is necessary if the scripts are to successfully change the PS1 variable in this 'scope'
Adding a sleep in between.
Thanks so much!
Related
Excuse me for the imprecisions in the question but I don't know how it is called what I'm trying.
In the CodeShip documentation is stated that I can pass to the SSH CodeShip debug build some commands using their command line application.
So, I should do something like cs setup-commands and I'm prompted with this:
rof#railsonfire_unique_string_sfivbe8bwucb9:~$ cs setup-commands
Your setup commands:
phpenv local 5.6
phpenv local 5.6
In Your setup commands: I put my commands but then, how can I "execute" them?
The second phpenv local 5.6 line is wrote by the command-line application. I think is something to signal the command were taken, but the behavior is ever the same: I remain "blocked" in the command setup-commands. After setting setup-commands I have to set also test-commands but all the things I write are taken by Your setup commands:.
How can I "submit and exit" the command setup-commands to then launch test-commands and set those other commands?
I think this is something related to Bash, but I don't know what it is...
And I don't know which is the correct terminology.
Can someone help me with this? So I will can also update my question to be more precise. Thank you.
Not sure about your case, but usually the input is considered finished, when th input file (in your case stdin) is closed.
Try to press Ctrl+D, it should end your input (and so signal the program hat you stopped typing for this session)
We have put together a perl script that essentially looks at the argument that is being passed to it checks if is creating or modifying a file then it saves that in a mysql database so that it is easily accessible later. Here is the interesting part, how do I make this perl script run before all of the commands typed in the terminal. I need to make this dummy proof so people don't forget to run it.
Sorry I didn't formulate this question properly. What I want to do is prepend to each command such that each command will run like so "./run.pl ls" for example. That way I can track file changes if the command is mv or it creates an out file for example. The script pretty much takes care of that but I just don't know how to run it seamlessly to the user.
I am running ubuntu server with the bash terminal.
Thanks
If I understood correctly you need to execute a function before running every command, something similar to preexec and precmd in zsh.
Unfortunately bash doesn't have a native support for this but you can do it using DEBUG trap.
Here is a sample code applying this method.
This page also provide some useful information.
You can modify the ~/.bashrc file and launch your script there. Do note that each user would (and should) still have the privelege to modify this file, potentially removing the script invocation.
The /etc/bash.bashrc file is system-wide and only changeable by root.
These .bashrcs are executed when a new instance of bash is created (e.g. new terminal).
It is not the same as sh, the system shell, that is dash on Ubuntu systems.
After I make changes in .bash_rc or .bash_profile, when I start GNU screen, it doesn't recognize those changes.
I can
source ~/.bash_profile
and it works for the current screen window I have open, but I have to do that for every screen window I have open.
How do I get screen to read my latest changes in my bash configuration?
If you want screen to always treat your shell as a login shell, and source the same files that would be read if just started a new shell normally, add the following to ~/.screenrc (or maybe ~/.byobu/.screenrc, as pointed out in the comment):
shell -$SHELL
This way, you don't need to manually tell it to source your files each time you start a new screen. Though you would have to if you just made changes and wanted those changes to be reflected in your current screen.
The documentation for this (and lots of other screen details) can be found here. Basically, shell is a command to screen telling it to run the following when it needs to create a new shell. $SHELL is the usual variable holding the path to your preferred shell. And the dash - in front of $SHELL indicates that it should be run as a login shell (which will typically mean it sources your ~/.bash_profile, etc.).
It's worth pointing out, however, that screen defaults to just inheriting most environment variables from the shell where you start screen; and a login sub-shell may alter some environment variables in unexpected ways. I ran into a situation where elements of my $PATH were basically permuted. I solved the problem thanks to this particularly excellent answer on superuser.
You may notice the source command available. It's important to note that this sources a file of screen commands, rather than shell commands. Other relevant (screen) commands include eval and exec.
You have to do it in each screen that you have open since they are all different shells. If you need the change every time a new shell is opened, I suggest you put the changes in ~/.bashrc instead.
Apparently, you can send a command to all windows at once using this syntax:
C-a :
at "#" stuff "source ~/.bash_profile^M"
I have a simple command in a Linux shell script (say foo.sh). In it I do this:
export INSTALL_DIR=/mnt/share/TEST_Linux
I run the script with:
> sh foo.sh
When it finishes I try to get the variable but the value is blank.
> echo $INSTALL_DIR
If I type the command directly the exported var becomes global to the opened terminal window. I'm using Ubuntu.
Setting environment variables is local to the child bash process running your script. To achieve what you want, you need to source it like this: source foo.sh. It means that it's run by your main bash process. Then, the setting of a variable will remain after the script is finished.
The variable is exported only in the new shell you are starting. You probably want to execute your script with source.
source foo.sh
I don't know the answer but i know how to overcome it.
# source ./foo.sh
# echo $INSTALL_DIR
And it's like magic.
I think it's because that script gets executed in it's own "shell". Not sure.
Because the process you are running (the shell running your script) can do whatever it wants, but its actions won't affect the parent process (your current shell).
A somewhat weird analogy would be: I can take 5 tequila shots and my environment will become blurry and gravity laws would be affected according to my perception. But to my father, his environment is the same, he doesn't get drunk because of my actions.
If you want that variables created/altered in your script affect your current shell, you should source the script as other answers pointed out. Please do note that doing this also may change the resulting working dir in your shell if the script does cd /whatever/path, that any other functions setted, but also altered or removed, would get affected in the same way in your shell.
A really weird and not very good analogy would be if I take 5 tekila shots and then my father kills me and drinks my blood.
Am I disturbed or what? ;-)
I'm new to Linux and especially to Ubuntu 11 which I'm just trying today for the first time. I need Linux for some development which requires a Linux-based emulator, so I'm trying to write a shell script that sets up my dev environment.
Now I've created a .scripts folder in my home dir and added it to my path by exporting it in .bashrc so every time I start a new terminal instance, I can execute any custom scripts I drop in there.
Now one (three actually) of those scripts sets up all my dev-related paths, exports, as well as a cd command which switches to the appropriate folder for this dev. However (again forgive me if you already know this...) the script runs in its own 'session' (for lack of a better word) so although the enviro-vars and such are all set up and do execute (as was proven by embedding echo calls throughout) when the script finishes and I'm returned back to the terminal where I executed the script, that other session no longer exists and with the exception of clearing the screen and echoing output, there's nothing else showing the script ever ran.
Now I'm not sure its even possible to extend exported variables outside of that script back to the calling 'instance' or of there's some kind of flag I can set to execute the script in the existing session, so I'm stumped.
Now if that is not possible, is it at least possible to write a script or set up an icon that can launch a new terminal window, then execute the script but leaving the window open and initialized?
Thanks!
Mark
Put the script in a function definition in ~/.bashrc. For example
enter_dev_env() {
cd /home/foo/src
export foo="bar"
}
Run the command with source.
source foo.sh