TKinter Widget creation... Issue with arrangement of widgets - python-3.x

Question

I was trying to create some nested widgets within file widget however exit is appearing above open. I tried changing the index but still the problems persists any idea how to fix this?
#!/usr/bin/python3
import tkinter as tk
import tkinter.ttk as ttk
from tkinter import messagebox
import sys
class GuiBaseClass():
def __init__(self,root):
# create widgets
self.root=root
root.title('GUIBASECLASS V0.1')
root.option_add('*tearOff', False)
self.menu=dict()
self.menubar = tk.Menu(root)
#File
menu_file = tk.Menu(self.menubar)
self.menubar.add_cascade(menu=menu_file,label='File',underline=0)
menu_file.add_separator()
menu_file.add_command(label='Exit', command=self.Exit,underline=0)
#Edit
menu_edit = tk.Menu(self.menubar)
self.menubar.add_cascade(menu=menu_edit,label='Edit',underline=0)
#Help
menu_help = tk.Menu(self.menubar)
menu_help.add_command(label='About', command=self.About, underline=0)
self.menubar.add_cascade(menu=menu_help,label ='Help',underline=0)
#config
root.config(menu=self.menubar)
self.menu['menubar'] = self.menubar
self.menu['File'] = menu_file
self.menu['Edit'] = menu_edit
self.menu['Help'] = menu_help
self.frame = ttk.Frame(root)
self.frame.pack(fill='both',expand=True)
# public functions
def mainLoop(self):
self.root.mainloop()
def getFrame(self):
return(self.frame)
def getMenu(self,entry):
if entry in self.menu:
return (self.menu[entry])
else:
# we create a new one
last = self.menu['menubar'].index('end')
self.menu[entry]= tk.Menu(self.menubar)
self.menu['menubar'].insert_cascade(
last, menu=self.menu[entry],label=entry)
return(self.menu[entry])
# private functions
def Exit(self,ask=True):
res = tk.messagebox.askyesno(title='Are you sure',message='Really quit the application')
if res:
sys.exit(0)
pass
def About(self):
print('print GUIBASECLASS V0.1')
if __name__ == '__main__':
root=tk.Tk()
bapp = GuiBaseClass(root)
# example for using the BaseClass in other applications
mnu=bapp.getMenu('Edit')
mnu.add_command(label='Copy',command=lambda: print('Copy'))
# example for using getFrame
frm=bapp.getFrame()
btn=ttk.Button(frm,text="Button X",command=lambda: sys.exit(0))
btn.pack()
bapp.mainLoop()
#!/usr/bin/python3
import tkinter as tk
import tkinter.ttk as ttk
from tkinter import filedialog
from tkinter import messagebox
from GuiBaseClass import GuiBaseClass
import os , sys
class PumlEditor(GuiBaseClass):
def __init__(self, root):
super().__init__(root)
# Create the File menu and add a "Open..." option
mnu_file = self.getMenu('File')
mnu_file.add_command(0, label='Open...', underline=0, command=self.fileOpen)
mnu_file.add_separator()
# Create the main text area
frame = self.getFrame()
#insert tk.Text
self.text = tk.Text(frame, wrap='word', undo=True)
self.text.insert('end', 'Hello start writing, please...')
self.text.delete('1.0','end')
self.text.pack(fill='both', expand=True)
def fileOpen(self, filename=''):
# Open a file dialog to select a file to open
if filename == "":
filename = filedialog.askopenfilename()
if filename != "":
self.text.delete('1.0','end')
file = open(filename,'r')
for line in file:
self.text.insert('end',line)
if __name__ == '__main__':
root = tk.Tk()
root.geometry("300x200")
pedit = PumlEditor(root)
# Create the PumlEditor instance and start the main loop
root.title("PumlEditor 2022")
if len(sys.argv)>1:
if os.path.exits(sys.arg[1]):
pedit.fileOpen(sys.argv[1])
pedit.mainLoop()
Open to appear before exit in files widget