Hi i am trying to replace a string with special character at the end with new string. For Example, I want to replace
qwerty_CRS_abc\
to
qwerty_CRS_abc
I tried with this:
:%s/qwerty_CRS_abc\/qwerty_CRS_abc/g
but I'm getting this error:
Pattern not found: padring_CRS_CAN\/padring_CRS_CAN\g
Basically, I just want to remove that backslash in whole file. It should be just
qwerty_CRS_abc
Use:
:%s/qwerty_CRS_abc\\/qwerty_CRS_abc/g
Certain characters such as /&!.^*$\? carry a special significance to the search process and must be escaped using the \ character when they are used in a search. Hence the \\ used to escape the backslash in your example.
Related
how I could use eval(rlang::parse_expr(string))’ or alternative with such expresssion string <-"print('A\s*B')"`? I am getting unrecognized escape character. The expression is evaluated inside function, print is an example, I am using grepl in similar manier.
Simply using second escape slash helped "print('A\s*B')"
For instance, if I wanted to a find and replace with strings containing backward or forward slashes, how would this be accomplished in vim?
Examples
Find & Replace is: :%s/foo/bar/g
what if I wanted to find all occurrences of <dog/> and replace it with <cat\>
Same way you escape characters most anywhere else in linuxy programs, with a backslash:
:%s/<dog\/>/<cat\\>
But note that you can select a different delimiter instead:
:%s#<doc/>#<cat\\>#
This saves you all typing all those time-consuming, confusing backslashes in patterns with a ton of slashes.
From the documentation:
Instead of the / which surrounds the pattern and replacement string, you
can use any other single-byte character, but not an alphanumeric character,
\, " or |. This is useful if you want to include a / in the search
pattern or replacement string.
%s:<dog/>:<cat>
You can replace the / delimiters if they become annoying for certain patterns.
Quote them with a backslash. Also, it often helps to use another delimiter besides slash.
:%s#<dog/>#<cat\\>#
or if you have to use slash as the substitute command delimiter
:%s/<dog\/>/<cat\\>/
I was looking for something similar, to search for register values containing the / character (to record a macro). The solution was to search using the ? token instead of the /.
The syntax is:
:%s/<dog\/>/<cat\\>/g
backslash slash backslash star
/(<- the prompt)\/\*
so after you type it looks like
/\/\*
I have a string looks like this:
(The whole code block is a string, aka, this string contains quotation marks.)
"he\"llo", "world\n", "fro,m"
[update] Aka, the "actual" string is this:
"\"he\\\"llo\", \"world\\n\", \"fro,m\""
I want to get an array of strings like this:
[ "\"he\\\"llo\"", "\"world\\n\"", "\"fro,m\"" ]
[update] Comma inside quotation marks should be remained.
In my opinion, there are several ways to solve this:
build a automata (DFA or NFA) for this syntax
using several status flags like inQuote, handle judging logics with lots of if else
write a complex but clever Regular Expression for this
Are there any general solutions to this problem? Or how should I actually do using those thinkings above?
P.S. It couldn't be better if some syntax errors like "unclosed quotation mark" can be found.
You need to first define your grammar. This is a simple grammar for your case:
document = *WS [string *WS *(',' *WS string *WS)]
string = %x22 *char %x22
char = %x20-21 / %x23-5B / escape / %x5D-10FFFF
escape = %x5C (%x5C / %x22 / 't' / 'n' / 'r')
WS = %x9 / %x20
You can read it as:
A document may begin/end with a white space, then may have one or more strings separated by commas. Before and after each comma there may be some white space.
A string is made of characters and begins and ends with double quotes Unicode/ASCII hex code 22.
Each character (char), may be: 1) any non control Unicode character before the double quotes i.e. hex 20 (space) or hex 21 (exclamation mark); 2) any character after the double quotes and before the escape slash \ (hex 5C); 3) an escape character sequence; 4) any other Unicode character after the slash (hex 5C).
The escape sequence (rule escape) begins with the escape slash \ and is followed by another slash, or the characters t for tab, n for line feed and r for carriage return. You may add and other escapable characters if you want, as for a C++ string syntax you can see here: https://en.cppreference.com/w/cpp/language/escape .
A white space (WS) is a tab or space, you may add and %xA and %xD for line feed and carriage return respectively.
By the use of this grammar you will get this tree for your input:
The screenshort is from the Tunnel Grammar Studio online laboratory that can run ABNF grammars (as the one above), and I work on.
After you have the grammar, you may use tools to generate a parser, or you can write one yourself. If you want to do it by hand (preferable for so small and simple grammar), you may have one function per each grammar rule that reads one character and checks is it the expected one. If your input finishes when you are parsing the string rule, then you have an input with a started but not finished string.
Your actual string syntax tree will look like that:
I want to replace a line, that represents a part of mathematical equation:
f(x,z,time,temp)=-(2.0)/(exp(128*((x-2.5*time)*(x-2.5*time)+(z-0.2)*(z-0.2))))+(
with a new one similar to the above. Both new and old lines are saved in bash variables.
Main problem is that mathematical equation is full with special characters that do not allow proper search and replace in bash mode, even when I used as delimiter special character that is not used in equation.
I used
sed -n "s|$OLD|$NEW|g" restart.k
and
sed -i "s|$OLD|$NEW|g" restart.k
but all times I get wrong results.
Any idea to solve this?
There is only * in your pattern here that is special for sed, so escape it and do replacement as usual:
sed "s:$(sed 's:[*]:\\&:g' <<<"$old"):$new:" infile
if there are more special characters in your real sample, then you will need to add them inside bracket []; there are some exceptions like:
if ^ character: it can be place anywhere in [] but not first character, because ^ character at first negates the characters within its bracket expression.
if ] character: it should be the first character, because this character is also used to end the bracket expression.
if - character: it should be the first or last character, because this character is also can be used for defining the range of characters too.
I editing a latex file into html and I want to change all \\ with a <br /> -tag.
:%s#\\#<br />#g
Vim uses the first character after the :%s as delimiter so that not a problem.
But I keep getting all the single \ in my search just as as \\. I'm guessing that the first \ is mapped to something but I don't no what or how to fix it.
And if I instead search do
:%s#\\\#<br />#g
I get E59 : invalid character after \# and E476 Invalid command.
Are you trying to replace all occurrences of two backslashes with <br />? If so, you need to escape both backslashes:
:%s#\\\\#<br />#g
A backslash is interpreted as an escape character that pairs up with the next character to indicate something special. For example, \t is used to indicate a tab character. To specify a backslash itself, you need two backslashes, so if you want two backslashes consecutively, you need to enter four.