I was searching for solution one by another and still have some problems, i am open to change even a whole schema, but i have time till weekend. If you have new solution show me, if i did something wrong please tell me.
This is where it happens
Also earlier i had problem with just initializing variable and puting there value from excel, but now i guess i am on right way. Earlier program told me that i am setting string to my int variable.
Yep, so i did that but still i receive:
InvalidTemplate. Unable to process template language expressions in
action 'var_name' inputs at line '0' and column '0': 'The template
language function 'int' was invoked with a parameter that is not
valid. The value cannot be converted to the target type.'.
I don't know what it meens and what to do, what i know is that i can still see and show what i got from my excel, also in excel file every cell i get is set to be Integer.
Can someone help me? I can show You more if its necessary.
I changed type of cells to intiger in my excel, also i made this function, and still none. Help, i do not have time and i worked on it for too long.
Related
an assignment operator is expected with the eval operation
a semi colon is not specified at the end of a free format statement
the name or indicator is not defined
the compiler cannot determine how the program can end try this please
hope its clear for issue
#1 & 2 are pretty evident, the error tells the line number in the source with the problem, just fix it. #3 is pretty evident as well, the error will tell you the name of the variable that is not defined.
#4 is the only one that is a bit tricky if you haven't seen it before. The compiler did not find a return from the main procedure, and also no place that *INLR is set on. Either of those things will fix that one.
Odds are that you just included some typos in your code. Please don't paste the entire source and error listing, just read the errors, and go find someone in your company that can tell you where in the source listing to find the errors. Or if you are using RDi, you could just click on the error, and it will take you directly to the problem.
I use the objSNMP.get method in Excel VBA without any problems.
I'd like to use the objSNMP.set method, but unfortunately it's not that easy. According to the website, it should work similarly to get, with the difference that there is one more parameter: the value to be sent.
If I try the official way:
objSNMP.Set ("43.18.1.1.2", OIDValue)
Image1
I get the message "Compile error: Syntax error".
I found another solution that works conditionally. Namely as follows (it can be seen commented out in the picture):
randomVarName = objSNMP.Set("OID", Value)
For example:
temp = objSNMP.Set(".1.3.6.1.4.1.9.9.68.1.2.2.1.2." & PortNum, 21)
In this case, the code runs without error. This is interesting because I haven't found any official information about this anywhere. Somewhere deep in the recesses of the internet, I only found this possible solution some time ago.
If, on the other hand, I do not enter the value directly, but write the name of a variable there (e.g. VLANNum),
temp = objSNMP.Set(".1.3.6.1.4.1.9.9.68.1.2.2.1.2." & PortNum, VLANNum)
I receive an error message. Image2
It doesn't matter if the type of the variable is not declared, string or integer. I also tried several different cell types in Excel, but nothing changed.
The error message is:
Run-time error '-2147467259 (80004005)':
The requested SNMP operation attempted to modify a variable, but
either a syntax or value error occurred.
Based on the above, I cannot insert the value read from the excel table at the end of the "objSNMP.Set" method in such a way that it can send the value. I could only solve the task if I create 4094 different "objSNMP.Set" lines and select what is necessary from among them. Not very efficient.
I have the solution. The value transferred with the variable works in the following form:
objSNMP.Set ".1.3.6.1.2.1.2.2.1.7.9", CInt(x)
Where x is the variable.
I am a beginner in python told my friend today, that the following code would throw an error, but it did not:
a = 5
a
So I wondered, what does "a" actually do and why is the interpreter fine with this?
If this is a duplicate, please refer me to the right post and sorry in advance.
edit: I used a *.py file.
If you type this code into the shell and click enter, the value of a is returned. Functionally, as there is no operation being performed on a, the value of a will not change.
You define the variable in the line above. The variable contains a value, so the "NameError: name 'a' is not defined" error is not triggered.
Also, even if the variable is a different data type, for example, a string, the value of a is returned.
If you run the code in a different environment, the line won't be printed and the line won't impact the value of itself or of any other variables.
I think you tried it in der REPL Console, paste it to a *.py file and execute that. So when you just type the variable name and hit enter this is actually a print command behind the scenes
You can type in a int into the shell or whatever, and it will return it. The variable you put is just a int, so it returns 5.
When I make the "Read Cell" in "Excel application scope", I tried to output the read data from Excel by using "Write Line". However, It's not working and it ouput the error as in the Title. Could you someone make it up?
I had the same issue. I'm using the LookupDataTable activity. In my Excel file I have a mix of Strings and Integers. But somehow I also got the error:
NotSupportedException: StringConverter cannot convert from
System.Double.
I solved it by changing the variable from String to GenericValue.
I also tried to give it the Double type, but it didn't work because I think I have different types in the column.
Try this maybe be it will help you to check out
Convert.todouble
I have a very simple if statement that is looking to see if $_FILES[] is set and if so create a variable. Here it is:
if(isset($_FILES['photo']['name'])){$image="yes";}
So if it finds the files is in fact set, give $image the value of yes. At the moment, regardless of if its set or not, the value is being passed to $image. Its driving me nuts. Doesnt matter if I drop the ['name'] part even. Ive been doing every incarnation of the if statement I can think of to make it behave but Im at a loss.
It turns out that checking to see if $_files isset will return a value in that even with no file being uploaded the array will contain information. If you were to do var_dump on $files['photos']['name'] you will see that the value for that bit of information is 0 and therefore when checking to see if its set you will get a positive response. This is how I overcame my problem:
$foo =$_FILES['photo']['name'];
$foopoo = $foo[0];
if (strlen($foopoo)>2){$image= "yes";}