I'm trying to open a text file and print it as a string. I've made sure there is text in the .txt file but when I run the code it just prints an empty space, I don't know what to do at this point since I couldn't find anything that could help me with my problem.
with open('test.txt', 'r') as file:
data = file.read().rstrip()
print(data)
When things aren't opening check the following:
You wrote exactly the same in your code as the one you saved. "file.txt" is not the same as "File.txt" for Python (same goes for accents and special characters).
The file you are trying to read is in the same directory. If your code is at users/bla/documents/another_folder and you just pass the name of the file to your code, then the file must be at users/bla/documents/another_folder too. If not, be shure to add it into the string path as "path/to/your/file/file.txt"
Make sure that the extension .txt is the same as your file.
If you checked that but everything seems correct, try:
with open(path_to_file) as f:
contents = f.readlines()
And see if "contents" has something.
I think it is better if you use open("file.txt","r") function to do it. So your code will be like this:
file=open("test.txt","r")
data=file.read().strip()
print(data)
Related
I saved a text file to my desktop named "test.txt" within the file I wrote only my name, David. Then, I opened terminal and opened python 3.7.1 and wrote the following code in attempt to see my name, David, populate:
open("/Users/David/Desktop/test.txt,"r")
However, I receive the following error message:
SyntaxError: EOL while scanning string literal
Does anyone know how I can avoid this error and have my name, David, read from the test.txt file on my desktop? Or am I going about this completely wrong?
As #Matt explained, you are missing quotes.
You can follow below approach to open file and read from it.
myfile = open("/Users/David/Desktop/test.txt","r") #returns file handle
myfile.read() # reading from the file
myfile.close() # closing the file handle, to release the resources.
For more information on how to do read/write operations on file
You are missing a quotation mark, after your file path. It should look like this:
open("/Users/David/Desktop/test.txt","r")
^ This quotation mark
This will open the file correctly, however you will still need to actually read from it.
You are missing the other quotations as the others have mentioned. Try using the with open statement, as it handles your resources for you, meaning you don't need to specify .close()
with open("/Users/David/Desktop/test.txt", "r") as file:
file.read()
you can use with which will close the file automatically as you come out of the block and put your Directory link
with open(r"Directory_link", "r") as file1:
FileContent = file1.read()
print(FileContent)
My input file is a gzipped file containing genomic information. I'm trying to parse the content on a line-by-line basis and have run into a strange problem.
Any given line looks something like this:
AC=26;AF=0.00519169;AN=5008;NS=2504;DP=17308;EAS_AF=0;AMR_AF=0.0072;AFR_AF=0.0015;EUR_AF=0.0109;SAS_AF=0.0082;AA=A|||;VT=SNP
However, when I print out what is being read in...
import gzip
with gzip.open(myfile.gz, 'rt') as f:
for line in f:
print(line)
The line looks like this:
AC=26;AF=0.00519169;AN=5008;NS=2504;DP=17308;EAS_AF=0;AMR_AF=0.0072;AFR_AF=0.0015;EUR_AF=0.0109;SAS_AF=0.0082;AA=A|||
Whatever information comes after the "|||" has been truncated.
Moreover, I can't even search the lines for strings that follow the "|||" (e.g. "VT=SNP" in line always returns False) I also can't line.strip("|||")
Any advice on what is causing this or what I need to look at?
Thank you for any help
EDIT: ok, it looks like there was something wrong with the gzip file. I uncompressed it and the script ran fine. Then I recompressed it and the script again ran fine (using gzip.open). Is there any straightforward way to compare the two compressed files (ie, the one that doesn't get read properly vs the one that works) so that I might get a hint at the root cause?
I am trying to append to a text file and write on a new line each time I append the file for readability in notepad. I believe this should be simple and researched thoroughly but I am still having an issue. Here is the snippet of code that writes to a .txt file:
appending_Text = data2
with open(file_Name, 'a+') as file:
file.write(appending_Text)
file.write('\n')
When I run this code and then check the text file, I get my appended data on the same line. When I open the .txt file using notepad, I want it to look like:
data1
data2
When I open the .txt file using notepad in windows, it looks like:
data1data2
What am I missing?
I figured out the answer and it's not python related but rather a limitation of notepad in windows. Notepad uses a different new line termination than is used in linux systems. Linux uses '\n' and notepad uses '/r/n'
I developed a software in Python3.4 which has as input a config file with a set of variables and some of them are paths.
I have a problem with the separator in the file path name.
I know I can put a "r" in front of the string or use the double backslash or the slash so to have a raw string, but because this software will be used by other users and the average one is just a "copy and paste" guy, I don't want they manipulate the file name.
So the users have just to copy from the Windows Explorer the file path and paste into the config file, something like:
path_variable = "C:\Users\home\room\table.txt"
and I want to write a function that modify it so can be used.
How can I do it? If I leave the string in this way I obtain an unicode error because of \U...
Thanks a lot,
Ciccio
Update
The config file is not a python file but just a .txt file within the variables and their values:
var_name = var_val
path_variable = "C:\Users\home\room\table.txt"
height = 20
plot_write_variable = ["y", "n"]
This is just a temporary solution until I finalize the GUI. This file must be really easy to understand and the software has to be used by people don't have any knowledge of Python or programming. The final user has just to change the variables value and click on the executable file to run the program and nothing else. For this reason I want to avoid as much as possible the use of any python command.
To read the config file I use this function:
import imp
def read_inputFile(path):
file = open(path)
variables = imp.load_source('data', '', file)
file.close()
return variables
Your config files don't have to be written in Python. You could use configparser, which so far as I can tell does not interpret backslashes specially.
This may require some re-working of your logic for the config file. Instead of importing the config file directly with an import statement, you would parse it with the configparser module. You may also need to adjust the syntax of your config file to match what configparser is expecting.
You say that your users are "copy and paste" kind of guys, but you are having them paste file locations into a config file. I don't know your code, but if the config file is in python, you could add a line:
path_variable = input("Enter the path").replace("\\", "\\\\")
Python interprets \\ as \, which fixes your problem
This solves the problem of them copy-pasting into the file, and instead prompts them for the filepath.
All the examples I find are in the current directory or are not examples at all. For the life of me, I can't figure out how to open a file in Python if it is not in the current directory.
Just use an absolute path.
f = open('C:/file.txt', 'w')
f.read()
If you actually wanted to change the working directory, use os.chdir