does anyone know how I can pipe the results of ps -ef | grep ^$USER to wc -1
I already used ps -ef | grep ^$USER but know i want to pipe the command
As per my understanding of your question
you want all the running process from a particular user and pipe it to wc ( note its wc -l not -1)
so i used this
ps aux | grep ^$USER|wc -l
-a : Information for all processes associated with terminals.
-u : Information for processes in userlist.
-x : username (user running this command)
or this can also work
ps -u $USER|wc -l
for any commands if you want to know the details try man command in terminal for example man ps
Good Morning,
Context :
I would like to check every minute if a python script is running. In my cron, i call a script. The script's goal is to check if the process is running.
My script :
#!/bin/bash
DIR="path/to/directory"
CMD="python3 -u $DIR/script.py -arg1 $DIR/arg1 -arg2 $DIR/arg2 -arg3 $DIR/arg3"
if [ ! $(ps aux | grep 'my_pattern' | grep -v 'color')]
then
echo "Success"
"$CMD" > /dev/null
fi
With this script i want to grep the process and inverse the grep to exclude the color process. If the process is running, the command (ps aux | grep 'my_pattern' | grep -v 'color')returns me something if not, the command returns me nothing.
The error is ./script.sh: line 12: [!myuser+ : Untraceable command
The execution of the command did not returns me the result of the command but the process number of my command like if i did a ps aux of my command.
If it's not clear, please ask, difficult for me to translate the issue.
Thank you for answering.
EDIT : I HAVE APPLY the ocndition like this :
if [[ -z $(ps aux | grep 'my_pattern' | grep -v 'color') ]]
Now i don't have any errors but it never enter in my if condition.
With
if [[ -z $(ps aux | grep 'my_pattern' | grep -v 'color') ]]
(mind the typo as shown by klashxx)
you can check if the variable is empty.
So instead of using "!", i think it's more appropriate and effective to check if the grepping of ps aux is returning an empty string or not.
Let me know if this helped you or not.
EDITED: corrected '[' to '[['
EDITED AGAIN: for other users to know, if u need to check the existance of a process with this method append ! before -z flag to see if it is NOT empty
Im trying to write a bash script and trying to take input from user and executing a kill command to stop a specific tomcat.
...
read user_input
if [ "$user_input" = "2" ]
then
ps -ef | grep "search-tomcat" |awk {'"'"'print $2'"'"'}| xargs kill -9
echo "Search Tomcat Shut Down"
fi
...
I have confirmed that the line
ps -ef | grep "search-tomcat"
works fine in script but:
ps -ef | grep "search-tomcat" |awk {'"'"'print $2'"'"'}
doesnt yield any results in script, but gives desired output in terminal, so there has to be some problem with awk command
xargs can be tricky - Try:
kill -9 $(ps -ef | awk '/search-tomcat/ {print $2}')
If you prefer using xargs then check man page for options for your target OS (i.e. xargs -n.)
Also noting that 'kill -9' is a non-graceful process exit mechanism (i.e. possible file corruption, other strangeness) so I suggest only using as a last resort...
:)
This is what I have right now in the bash script:
ps aux | grep glassfish | grep domain1 | gawk '{print $2}' | xargs kill -9
The problem with this is that if someone else is logged in and pulling something related to glassfish, it wil pull that PID as well. Thus resulting in killing the wrong PID.
So My question is how do I fix what I have to only pull the correct PID, and how do I rewrite it to pull the PID from the PID file that glassfish generates.
Edit the script that starts glassfish and place something like echo $$ > /path/to/PID-file (this can contain ~ for home directory or some other mechanism like $USER to make user specific) on the line immediately following the line starting the process. You can then kill the correct process using kill $(cat /path/to/PID-file).
ps aux | grep ^$USER | grep glassfish | grep domain1 | gawk '{print $2}' | xargs kill -9
Below i did mistake with ps switches, so above grep should be fine.
ah it is not working, ps could be use like this ps -ao pid,tty,comm -u $USER, this grep above should be fine ...
someone else is logged in ...
If so, add switch -u
ps aux -u $USER | grep glassfish | grep domain1 | gawk '{print $2}' | xargs kill -9
$USER is user name that will be selected and listed, by default should be already set in OS environment. Multiple users could be selected by comma ps aux -u root,$USER
Take a note: If there is no specific username in the system, ps will throw ERROR: User name does not exist.
Read man ps for more.
-u userlist Select by effective user ID (EUID) or name.
This selects the processes whose effective user name or ID is in userlist. The effective user ID describes the user whose
file access permissions are used by the process (see geteuid(2)).
Identical
to U and --user.
I was looking for the best way to find the number of running processes with the same name via the command line in Linux. For example if I wanted to find the number of bash processes running and get "5". Currently I have a script that does a 'pidof ' and then does a count on the tokenized string. This works fine but I was wondering if there was a better way that can be done entirely via the command line. Thanks in advance for your help.
On systems that have pgrep available, the -c option returns a count of the number of processes that match the given name
pgrep -c command_name
Note that this is a grep-style match, not an exact match, so e.g. pgrep sh will also match bash processes. If you want an exact match, also use the -x option.
If pgrep is not available, you can use ps and wc.
ps -C command_name --no-headers | wc -l
The -C option to ps takes command_name as an argument, and the program prints a table of information about processes whose executable name matches the given command name. This is an exact match, not grep-style. The --no-headers option suppresses the headers of the table, which are normally printed as the first line. With --no-headers, you get one line per process matched. Then wc -l counts and prints the number of lines in its input.
result=`ps -Al | grep command-name | wc -l`
echo $result
ps -Al | grep -c bash
You can try :
ps -ef | grep -cw [p]rocess_name
OR
ps aux | grep -cw [p]rocess_name
For e.g.,:
ps -ef | grep -cw [i]nit
Some of the above didn't work for me, but they helped me on my way to this.
ps aux | grep [j]ava -c
For newbies to Linux:
ps aux prints all the currently running processes, grep searches for all processes that match the word java, the [] brackets remove the process you just ran so it wont include that as a running process and finally the -c option stands for count.
List all process names, sort and count
ps --no-headers -A -o comm | sort | uniq -c
You also can list process attached to a tty
ps --no-headers a -o comm | sort | uniq -c
You may filter with:
ps --no-headers -A -o comm | awk '{ list[$1] ++ } END { for (i in list) { if (list[i] > 10) printf ("%20s: %s\n", i, list[i]) } }'
Following bash script can be run as a cron job and you can possibly get email if any process forks itself too much.
for i in `ps -A -o comm= --sort=+comm | uniq`;
do
if (( `ps -C $i --no-headers | wc -l` > 10 )); then
echo `hostname` $i `ps -C $i --no-headers | wc -l` ;
fi
done
Replace 10 with your number of concern.
TODO: "10" could be passed as command line parameter as well. Also, few system processes can be put into exception list.
You can use ps(will show snapshot of processes) with wc(will count number of words, wc -l option will count lines i.e. newline characters).
Which is very easy and simple to remember.
ps -e | grep processName | wc -l
This simple command will print number of processes running on current server.
If you want to find the number of process running on current server for current user then use -U option of ps.
ps -U root | grep processName | wc -l
change root with username.
But as mentioned in lot of other answers you can also use ps -e | grep -c process_name which is more elegant way.
ps aux | wc -l
This command shows number of processes running on the system by all the users.
For a specific user you can use the following command:
ps -u <username> | wc -l
replace with the actual username before running :)
ps -awef | grep CAP | wc -l
Here "CAP" is the word which is in the my Process_Names.
This command output = Number of Processes + 1
This is why When we are running this command , our system read thats "ps -awef | grep CAP | wc -l " is also a process.
So yes our real answer is (Number of Processes) = Command Output - 1
Note : These processes are only those processes who include the name of "CAP"