I got some trouble in hudi when i delete rows with the same record key by spark-sql.
e.g
I created a table and set the recordKey=empno
CREATE TABLE emp_duplicate_pk (
empno int,
ename string,
job string,
mgr int,
hiredate string,
sal int,
comm int,
deptno int,
tx_date string
)
using hudi
options(
type='cow'
,primaryKey='empno'
,payloadclass='org.apache.hudi.common.model.OverwriteNonDefaultWithLatestAvroPayLoad'
,preCombineField='tx_date'
,hoodie.cleaner.commits.retained='10'
,hoodie.keep.min.commits='20'
,hoodie.keep.max.commits='30'
,hoodie.index.type='SIMPLE'
,hoodie.sql.insert.mode='non-strict'
,hoodie.combine.before.insert='false'
,hoodie.combine.before.upsert='false'
,hoodie.merge.allow.duplicate.on.inserts='true'
);
then insert some test records
seems hudi allows duplicate primary key with these attributes
hoodie.sql.insert.mode='non-strict'
hoodie.combine.before.insert='false'
hoodie.combine.before.upsert='false'
hoodie.merge.allow.duplicate.on.inserts='true'
insert into emp_duplicate_pk values
(7369,'SMITH','CLERK',7902,'1980-12-17',800,100,20,'2022-11-17'),
(7499,'ALLEN','SALESMAN',7698,'1981-02-20',1600,300,30,'2022-11-17'),
(5233,'PTER','DEVELOPER',9192,'1996-05-30',5000,3000,10,'2022-11-13'),
(5233,'PTER','DEVELOPER',9192,'1996-05-30',5000,3000,10,'2022-11-14');
insert into emp_duplicate_pk values
(5233,'PTER','DEVELOPER',9192,'1996-05-30',5000,3000,10,'2022-11-15'),
(5233,'PTER','DEVELOPER',9192,'1996-05-30',5000,3000,10,'2022-11-16'),
(5233,'PTER','DEVELOPER',9192,'1996-05-30',5000,3000,10,'2022-11-17');
all data could be searched (image)
then i delete a record
delete from emp_duplicate_pk where tx_date='2022-11-16';
seems it delete all empno=5233 rows,only two rows left(7369 and 7499) (image)
How to delete tx_date='2022-11-16' exactly and reserve other rows,anyone can help?
Related
I am using Hive, and the IDE is Hue. I am trying different key combinations to choose for my partition key(s).
The definition of my original table is as follows:
CREATE External Table `my_hive_db`.`my_table`(
`col_id` bigint,
`result_section__col2` string,
`result_section_col3` string ,
`result_section_col4` string,
`result_section_col5` string,
`result_section_col6__label` string,
`result_section_col7__label_id` bigint ,
`result_section_text` string ,
`result_section_unit` string,
`result_section_col` string ,
`result_section_title` string,
`result_section_title_id` bigint,
`col13` string,
`timestamp` bigint,
`date_day` string
)
PARTITIONED BY (
`date_year` string,
`date_month` string)
ROW FORMAT SERDE
'org.apache.hadoop.hive.ql.io.parquet.serde.ParquetHiveSerDe'
STORED AS INPUTFORMAT
'org.apache.hadoop.hive.ql.io.parquet.MapredParquetInputFormat'
OUTPUTFORMAT
'org.apache.hadoop.hive.ql.io.parquet.MapredParquetOutputFormat'
LOCATION
's3a://some/where/in/amazon/s3';
The above code is working properly. But when I create a new table with date_day as partition key, the table is empty and I need to run MSCK Repair Table. However, I am getting the following error:
Error while compiling statement: FAILED: Execution Error, return code 1 from org.apache.hadoop.hive.ql.ddl.DDLTask
When the partion keys were date_year, date_month, MSCK worked properly.
Table definition of the table I am getting the error for is as follows:
CREATE External Table `my_hive_db`.`my_table`(
`col_id` bigint,
`result_section__col2` string,
`result_section_col3` string ,
`result_section_col4` string,
`result_section_col5` string,
`result_section_col6__label` string,
`result_section_col7__label_id` bigint ,
`result_section_text` string ,
`result_section_unit` string,
`result_section_col` string ,
`result_section_title` string,
`result_section_title_id` bigint,
`col13` string,
`timestamp` bigint,
`date_year` string,
`date_month` string
)
PARTITIONED BY (
`date_day` string)
ROW FORMAT SERDE
'org.apache.hadoop.hive.ql.io.parquet.serde.ParquetHiveSerDe'
STORED AS INPUTFORMAT
'org.apache.hadoop.hive.ql.io.parquet.MapredParquetInputFormat'
OUTPUTFORMAT
'org.apache.hadoop.hive.ql.io.parquet.MapredParquetOutputFormat'
LOCATION
's3a://some/where/in/amazon/s3';
After this the following query is empty:
Select * From `my_hive_db`.`my_table` Limit 10;
I therefore ran the following command:
MSCK REPAIR TABLE `my_hive_db`.`my_table`;
And I get the error: Error while compiling statement: FAILED: Execution Error, return code 1 from org.apache.hadoop.hive.ql.ddl.DDLTask
I checked this link as it is exactly the error I am getting, but by using the solution provided:
set hive.msck.path.validation=ignore;
MSCK REPAIR TABLE table_name;
I get a different error:
Error while processing statement: Cannot modify hive.msck.path.validation at runtime. It is not in list of params that are allowed to be modified at runtime.
I think the reason I am getting these errors is that there are more than 200 million records with date_day having null value.
There are 31 distinct date-day not null values. I would like to partition my table with 32 partitions, each for a distinct value of date_day field, and all the null values get into a different partition. Is there a way to do so (partitioning by a column with null values)?
If this can be achieved by spark, I am also open to use it.
This is part of a bigger problem of changing partition keys by recreating a table as mentioned in this link in answer to my other question.
Thank you for your help.
You seem to not understand how Hive's partitioning work.
Hive stores data into files on HDFS (or S3, or some other distributed folders).
If you create a non-partitioned parquet table called my_schema.my_table, you will see in your distributed storage files stored in a folder
hive/warehouse/my_schema.db/my_table/part_00001.parquet
hive/warehouse/my_schema.db/my_table/part_00002.parquet
...
If you create a table partitioned by a column p_col, the files will look like
hive/warehouse/my_schema.db/my_table/p_col=value1/part_00001.parquet
hive/warehouse/my_schema.db/my_table/p_col=value1/part_00002.parquet
...
hive/warehouse/my_schema.db/my_table/p_col=value2/part_00001.parquet
hive/warehouse/my_schema.db/my_table/p_col=value2/part_00002.parquet
...
The command MSCK repair table allows you to automatically reload the partitions, when you create an external table.
Let's say you have folders on s3 that look like this:
hive/warehouse/my_schema.db/my_table/p_col=value1/part_00001.parquet
hive/warehouse/my_schema.db/my_table/p_col=value2/part_00001.parquet
hive/warehouse/my_schema.db/my_table/p_col=value3/part_00001.parquet
You create an external table with
CREATE External Table my_schema.my_table(
... some columns ...
)
PARTITIONED BY (p_col STRING)
the table will be created but empty, because Hive hasn't detected the partitions yet. You run MSCK REPAIR TABLE my_schema.my_table, and Hive will recognize that your partition p_col matches the partitioning scheme on s3 (/p_col=value1/).
From what I could understand from your other question, you are trying to change the partitioning scheme of the table by doing
CREATE External Table my_schema.my_table(
... some columns ...
)
PARTITIONED BY (p_another_col STRING)
and you are getting an error message because p_another_col doesn't match with the column used in s3, which was p_col.
And this error is perfectly normal, since what you are doing doesn't make sense.
As stated in the other question's answer, you need to create a copy of the first table, with a different partitioning scheme.
You should instead try something like this:
CREATE External Table my_hive_db.my_table_2(
`col_id` bigint,
`result_section__col2` string,
`result_section_col3` string ,
`result_section_col4` string,
`result_section_col5` string,
`result_section_col6__label` string,
`result_section_col7__label_id` bigint ,
`result_section_text` string ,
`result_section_unit` string,
`result_section_col` string ,
`result_section_title` string,
`result_section_title_id` bigint,
`col13` string,
`timestamp` bigint,
`date_year` string,
`date_month` string
)
PARTITIONED BY (`date_day` string)
and then populate your new table with dynamic partitioning
INSERT OVERWRITE TABLE my_hive_db.my_table_2 PARTITION(date_day)
SELECT
col_id,
result_section__col2,
result_section_col3,
result_section_col4,
result_section_col5,
result_section_col6__label,
result_section_col7__label_id,
result_section_text,
result_section_unit,
result_section_col,
result_section_title,
result_section_title_id,
col13,
timestamp,
date_year,
date_month,
date_day
FROM my_hive_db.my_table_1
(
ResponseRgBasketId STRING,
RawStandardisedLoadDateTime TIMESTAMP,
InfoMartLoadDateTime TIMESTAMP,
Operaame STRING,
RequestTimestamp TIMESTAMP,
RequestSiteId STRING,
RequestSalePointId STRING,
RequestdTypeId STRING,
RequeetValue DECIMAL(10,2),
ResponsegTimestamp TIMESTAMP,
RequessageId STRING,
RequestBasketId STRING,
ResponsesageId STRING,
RequestTransmitAttempt INT,
ResponseCode STRING,
RequestasketItems INT,
ResponseFinancialTimestamp TIMESTAMP,
RequeketJsonString STRING,
LoyaltyId STRING
)
USING DELTA
PARTITIONED BY (RequestTimestamp)
TBLPROPERTIES
(
delta.deletedFileRetentionDuration = "interval 1 seconds",
delta.autoOptimize.optimizeWrite = true
)
It has been partitioned by RequestTimestamp(2020-12-12T07:39:35.000+0000
), but it has the format as below. Could I change the format to different format to something like 2020-12-34 in partition by?
Short answer: No regexp or other transformation is possible in PARTITIONED BY.
The only solution is to apply substr(timestamp, 1, 10) during/before load.
See also this answer: https://stackoverflow.com/a/64171676/2700344
Long answer:
No regexp is possible in PARTITIONED BY. No functions are allowed in table DDL, only type can be specified. Type in column specification works as constraint and at the same time can cause implicit type conversion. For example if you are loading strings into dates, it will be casted implicitly if possible and loaded into null default partition if not possible to cast. Also if you are loading BIGINT, it will be silently truncated to INT, as a result you will see corrupted data and duplicates.
Does the same implicit cast work with partitioned by? Let,s see:
DROP TABLE IF EXISTS test_partition;
CREATE TABLE IF NOT EXISTS test_partition (Id int)
partitioned by (dt date) --Hope timestamp will be truncated to DATE
;
set hive.exec.dynamic.partition=true;
set hive.exec.dynamic.partition.mode=nonstrict;
insert overwrite table test_partition partition(dt)
select 1 as id, current_timestamp as dt;
show partitions test_partition;
Result (We expect timestamp truncated to DATE...):
dt=2021-03-24 10%3A19%3A19.985
No, it does not work. Tested the same with varchar(10) column with strings like yours.
See short answer.
Why AWS Athena returns "string" datatype to all table's fields on
"show create table" command or on describe tables:
for example table t_mus_albums:
albumid (bigint)
title (string)
artistid (bigint)
whan running
show create table t_mus_albums;
I get:
CREATE EXTERNAL TABLE `t_mus_albums`(
`albumid` string COMMENT 'from deserializer',
`title` string COMMENT 'from deserializer',
`artistid` string COMMENT 'from deserializer')
I think you might be doing something wrong or while generating the table automatically, you may not have correct formatted data.
Here are the systematic steps to solve your problem.
Assume that your data is in below format.
ID,Code,City,State
41,5,"Youngstown", OH
42,52,"Yankton", SD
46,35,"Yakima", WA
42,16,"Worcester", MA
43,37,"Wisconsin Dells", WI
36,5,"Winston-Salem", NC
Then your create table will go something like below.
CREATE EXTERNAL TABLE IF NOT EXISTS example.tbl_datatype (
`id` int,
`code` int,
`city` string,
`state` string
)
ROW FORMAT SERDE 'org.apache.hadoop.hive.serde2.lazy.LazySimpleSerDe'
WITH SERDEPROPERTIES (
'serialization.format' = ',',
'field.delim' = ','
) LOCATION 's3://example-bucket/location/a/'
TBLPROPERTIES ('has_encrypted_data'='false');
Then, run the Query to description the table.
SHOW CREATE TABLE tbl_datatype;
It will give you output something like below.
CREATE EXTERNAL TABLE `tbl_datatype`(
`id` int,
`code` int,
`city` string,
`state` string)
ROW FORMAT DELIMITED
FIELDS TERMINATED BY ','
STORED AS INPUTFORMAT
'org.apache.hadoop.mapred.TextInputFormat'
OUTPUTFORMAT
'org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat'
LOCATION
's3://example-bucket/location/a/';
Hope it helps!
This is because you use CSV serde and not e.g. TEXT serde.
CSV serde does support only string data type, so all columns are of this type.
From https://docs.aws.amazon.com/athena/latest/ug/csv.html
The OpenCSV SerDe [...] Converts all column type values to STRING.
The documentation outlines some conditions under which the table schema could be different than all strings ("For example, it parses the values into BOOLEAN, BIGINT, INT, and DOUBLE data types when it can discern them"), but apparently this was not effective in your case.
How can I insert json objects to Cassandra table without creating table? Can Cassandra parse json to table which is not created? Or, Can I create a table with no column and insert json?
Thanks.
After Cassandra 2.2 you can insert json directly, but the table still should be created beforehead.
You need to create table First, then you can insert data
You can create table like the below one :
CREATE TABLE json_data (
id timeuuid PRIMARY KEY,
data text
);
And you can insert the json as string with the below query :
INSERT INTO json_data (id , data ) VALUES ( now(), '{"first_name" : "Ashraful", "last_name" : "Islam"}') ;
I'm using Spark Cassandra Connector to update counters in this table:
CREATE TABLE IF NOT EXISTS analytics.minute_usage_stats (
metric_date timestamp,
user_id uuid,
metric_name text,
h1_m1 counter,
h1_m2 counter,
h1_m3 counter,
...
h24_m60 counter,
PRIMARY KEY ((metric_date), user_id, metric_name)
);
The code looks something like this:
class Metric(metricName: String, metricDate: Date, userId: String, ???)
metricEventStream
.map(event => {
// Parsing logic
new Metric(metricName, metricDate, userId, h1M1???)
})
.saveToCassandra("analytics", "minute_usage_stats")
I need to be able to update one counter column at a time and the columns could be different for each item in the map.
Looking through the documentation, there doesn't seem to be a way to do this without using the Cassandra driver itself and losing all the great functionality of the Spark connector.
Is there any way to specify column names per RDD row with the current Spark Cassandra Connector?