I have a list of version numbers like,
Versions = [0.0.10, 0.0.11, 0.0.13, 0.0.14, 0.0.15, 0.0.16, 0.0.17, 0.0.18, 0.0.19, 0.0.20, 0.0.21, 0.0.22, 0.0.23, 0.0.24, 0.0.25, 0.0.26, 0.0.27, 0.0.28, 0.0.29, 0.0.3, 0.0.30, 0.0.33, 0.0.34, 0.0.35, 0.0.36, 0.0.37, 0.0.38, 0.0.39, 0.0.4, 0.0.41, 0.0.42, 0.0.43, 0.0.44, 0.0.45, 0.0.46, 0.0.47, 0.0.48, 0.0.49, 0.0.5, 0.0.5-delivery.5, 0.0.50, 0.0.51, 0.0.52, 0.0.53, 0.0.54, 0.0.55, 0.0.56, 0.0.57, 0.0.58, 0.0.59, 0.0.6, 0.0.60, 0.0.61, 0.0.62, 0.0.63, 0.0.64, 0.0.7, 0.0.8, 0.0.9]'
And i need to get the last version (0.0.64), Versions.sort() && Collections.max(Versions) doesn't work for me.
So I developed this function blow
def mostRecentVersion(def versions) {
def lastversion = "0.0.0"
for (def items : versions) {
def version = items.tokenize('-')[0]
def ver = version.tokenize('.')
def lastver = lastversion.tokenize('.')
if (lastver[0].toInteger() < ver[0].toInteger() ){
lastversion = version
}else if(lastver[0].toInteger() == ver[0].toInteger()) {
if (lastver[1].toInteger() < ver[1].toInteger() ){
lastversion = version
}else if(lastver[1].toInteger() == ver[1].toInteger()){
if (lastver[2].toInteger() < ver[2].toInteger() ){
lastversion = version
}
}
}
}
return lastversion }
i'm asking if there is something better,
Thank you for help :)
the idea:
build map with sortable key and original version value, then sort map by keys, then get only values
to create sortable key for each value
split version to digits & not-digit strings array
prepend to each part 0 to have minimum length 3 (assume each number not longer then 3 digits)
join array to string
so, for 0.11.222-dev ->
1. [ '0', '.', '11', '222', '-dev' ]
2. [ '000', '00.', '011', '222', '-dev' ]
3. '00000.011222-dev'
the code
def mostRecentVersion(versions){
return versions.collectEntries{
[(it=~/\d+|\D+/).findAll().collect{it.padLeft(3,'0')}.join(),it]
}.sort().values()[-1]
}
//test cases:
def fullVersions = ['0.0.10', '0.0.11', '0.0.13', '0.0.14', '0.0.15', '0.0.16',
'0.0.17', '0.0.18', '0.0.19', '0.0.20', '0.0.21', '0.0.22', '0.0.23', '0.0.24',
'0.0.25', '0.0.26', '0.0.27', '0.0.28', '0.0.29', '0.0.3', '0.0.30', '0.0.33',
'0.0.34', '0.0.35', '0.0.36', '0.0.37', '0.0.38', '0.0.39', '0.0.4', '0.0.41',
'0.0.42', '0.0.43', '0.0.44', '0.0.45', '0.0.46', '0.0.47', '0.0.48', '0.0.49',
'0.0.5', '0.0.5-delivery.5', '0.0.50', '0.0.51', '0.0.52', '0.0.53', '0.0.54',
'0.0.55', '0.0.56', '0.0.57', '0.0.58', '0.0.59', '0.0.6', '0.0.60', '0.0.61',
'0.0.62', '0.0.63', '0.0.64', '0.0.7', '0.0.8', '0.0.9']
assert mostRecentVersion(fullVersions) == '0.0.64'
assert mostRecentVersion(['0.0.5-delivery.5', '0.0.3', '0.0.5']) == '0.0.5-delivery.5'
assert mostRecentVersion(['0.0.5.5', '0.0.5-delivery.5', '0.0.5']) == '0.0.5.5'
I believe this will work... it also keeps the original version strings around, incase 0.5.5-devel.5 is the latest... It relies on the fact that Groovy will use a LinkedHashMap for the sorted map, so the order will be preserved :-)
def mostRecentVersion(def versions) {
versions.collectEntries {
[it, it.split(/\./).collect { (it =~ /([0-9]+).*/)[0][1] }*.toInteger()]
}.sort { a, b ->
[a.value, b.value].transpose().findResult { x, y -> x <=> y ?: null } ?:
a.value.size() <=> b.value.size() ?:
a.key <=> b.key
}.keySet()[-1]
}
def fullVersions = ['0.0.10', '0.0.11', '0.0.13', '0.0.14', '0.0.15', '0.0.16', '0.0.17', '0.0.18', '0.0.19', '0.0.20', '0.0.21', '0.0.22', '0.0.23', '0.0.24', '0.0.25', '0.0.26', '0.0.27', '0.0.28', '0.0.29', '0.0.3', '0.0.30', '0.0.33', '0.0.34', '0.0.35', '0.0.36', '0.0.37', '0.0.38', '0.0.39', '0.0.4', '0.0.41', '0.0.42', '0.0.43', '0.0.44', '0.0.45', '0.0.46', '0.0.47', '0.0.48', '0.0.49', '0.0.5', '0.0.5-delivery.5', '0.0.50', '0.0.51', '0.0.52', '0.0.53', '0.0.54', '0.0.55', '0.0.56', '0.0.57', '0.0.58', '0.0.59', '0.0.6', '0.0.60', '0.0.61', '0.0.62', '0.0.63', '0.0.64', '0.0.7', '0.0.8', '0.0.9']
assert mostRecentVersion(fullVersions) == '0.0.64'
assert mostRecentVersion(['0.0.5-delivery.5', '0.0.3', '0.0.5']) == '0.0.5-delivery.5'
assert mostRecentVersion(['0.0.5.5', '0.0.5-delivery.5', '0.0.5']) == '0.0.5.5'
Edit:
Made a change so that 0.5.5.5 > 0.5.5-devel.5
I must be being incredibly stupid but I can't figure out how to do simple string concatenation in Terraform.
I have the following data null_data_source:
data "null_data_source" "api_gw_url" {
inputs = {
main_api_gw = "app.api.${var.env_name == "prod" ? "" : var.env_name}mydomain.com"
}
}
So when env_name="prod" I want the output app.api.mydomain.com and for anything else - let's say env_name="staging" I want app.api.staging.mydomain.com.
But the above will output app.api.stagingmydomain.com <-- notice the missing dot after staging.
I tried concating the "." if the env_name was anything but "prod" but Terraform errors:
data "null_data_source" "api_gw_url" {
inputs = {
main_api_gw = "app.api.${var.env_name == "prod" ? "" : var.env_name + "."}mydomain.com"
}
}
The error is __builtin_StringToInt: strconv.ParseInt: parsing ""
The concat() function in TF appears to be for lists not strings.
So as the title says: How do you do simple string concatenation in Terraform?
I can't believe I'm asking how to concat 2 strings together XD
Update:
For anyone that has a similar issue I did this horrific workaround for the time being:
main_api_gw = "app.api.${var.env_name == "prod" ? "" : var.env_name}${var.env_name == "prod" ? "" : "."}mydomain.com"
I know this was already answered, but I wanted to share my favorite:
format("%s/%s",var.string,"string2")
Real world example:
locals {
documents_path = "${var.documents_path == "" ? format("%s/%s",path.module,"documents") : var.documents_path}"
}
More info:
https://www.terraform.io/docs/configuration/functions/format.html
so to add a simple answer to a simple question:
enclose all strings you want to concatenate into one pair of ""
reference variables inside the quotes with ${var.name}
Example: var.foo should be concatenated with bar string and separated by a dash
Solution: "${var.foo}-bar"
Try Below data resource :
data "null_data_source" "api_gw_url" {
inputs = {
main_api_gw = "app.api${var.env_name == "prod" ? "." : ".${var.env_name}."}mydomain.com"
}
}
For Terraform 0.12 and later, you can use join() function:
join(separator, list)
Example:
> join(", ", ["foo", "bar", "baz"])
foo, bar, baz
> join(", ", ["foo"])
foo
If you just want to concatenate without a separator like "foo"+"bar" = "foobar", then:
> join("", ["foo", "bar"])
foobar
Reference: https://www.terraform.io/docs/configuration/functions/join.html
Use the Interpolation Syntax for versions < 0.12
Here is a simple example:
output "s3_static_website_endpoint" {
value = "http://${aws_s3_bucket.bucket_tf.website_endpoint}"
}
Reference the Terraform Interpolation docs:
https://developer.hashicorp.com/terraform/language/expressions/strings#string-templates
after lot of research, It finally worked for me. I was trying to follow https://www.hashicorp.com/blog/terraform-0-12-preview-first-class-expressions/, but it did not work. Seems string can't be handled inside the expressions.
data "aws_vpc" "vpc" {
filter {
name = "tag:Name"
values = ["${var.old_cluster_fqdn == "" ? "${var.cluster_fqdn}" : "${var.old_cluster_fqdn}"}-vpc"]
}
}
When try this sample code:
use(groovy.time.TimeCategory) {
800.millisecond + 300.millisecond
}
in groovy web console, I get a funny result:
0.1100 seconds
Does any one know why this happens or how to fix it?
That looks like a bug, the TimeDuration contains 1100 milliseconds, but when it prints it out, it converts it wrongly to seconds.
I've added it to the Groovy JIRA as a bug EDIT It's now marked as FIXED for versions 2.0.6, 1.8.9 and 2.1.0
In the mean time, I guess you'll need to do your own converter from TimeDuration to String :-/
Edit
You could do something like this (and there is probably a neater way of doing it)
groovy.time.TimeDuration.metaClass.normalize = { ->
def newdmap = ['days','hours','minutes','seconds','millis'].collectEntries {
[ (it):delegate."$it" ]
}.with { dmap ->
[millis:1000,seconds:60,minutes:60,hours:24,days:-1].inject( [ dur:[ days:0, hours:0, minutes:0, seconds:0, millis:0 ], roll:0 ] ) { val, field ->
val.dur."$field.key" = dmap."$field.key" + val.roll
val.roll = val.dur."$field.key".intdiv( field.value )
val.dur."$field.key" = field.value < 0 ?
val.dur."$field.key" :
val.dur."$field.key" % field.value
val
}.dur
}
new TimeDuration( newdmap.days, newdmap.hours, newdmap.minutes, newdmap.seconds, newdmap.millis )
}
That adds a normalize method to TimeDuration, so then doing:
use(groovy.time.TimeCategory) {
800.millisecond + 300.millisecond
}.normalize()
Shows 1.100 seconds
I haven't done a huge amount of testing on that method, so be warned it could do with some unit tests to make sure it doesn't fall over with other situations.