i would like to write the program
when i input the number of 12
the program will print of digits ie.after '9' is '0'.
For example:
Enter the number: 12
output
0
1
2
3
4
5
6
7
8
9
0
1
x = input("Enter the number: ")
x = int(x)
for i in range (x):
print(str(i))
anyone can give an idea for me? thanks
Change this:
print(str(i))
To this:
print(i % 10)
Related
I try to write the number of words from the longest line. I was able to write the number of words in each line, but I can't print the maximum number. The max () function do not works. Can anyone help me?
import os
import sys
import numpy as np
with open('demofile.txt') as f:
lines = f.readlines()
for index, value in enumerate(lines):
number_of_words = len(value.split())
print(number_of_words)
demofile.txt
<=4 1 2 3 4 5 6 7 8 9 10 11
<=4 1 2 3 4 5 6 7 8 9
<=4 1 2 3 4 5 6 7 8 9 10 11 sdad adada affg
<=4 1 2 3 4 5 6 7 8 9 10 11
Output:
12
10
15
12
0
0
0
0
0
0
0
0
0
0
0
I also don't understand why it lists the number of words in the next lines where there are no words
If I understood correctly max() function doesn't work because you are searching max of strings so you need to convert them to ints(floats).
lines = [int(x) for x in lines.split(" ")] // converts to ints
maximum = max(lines)// should work now
UPD:
Edited with comment below.
Before:
int(x) for x in lines
Now:
int(x) for x in lines.split(" ")
I tried various programs to get the required pattern (Given below). The program which got closest to the required result is given below:
Input:
for i in range(1,6):
for j in range(i,i*2):
print(j, end=' ')
print( )
Output:
1
2 3
3 4 5
4 5 6 7
5 6 7 8 9
Required Output:
1
2 3
4 5 6
7 8 9 10
Can I get some hint to get the required output?
Note- A newbie to python.
Store the printed value outside of the loop, then increment after its printed
v = 1
lines = 4
for i in range(lines):
for j in range(i):
print(v, end=' ')
v += 1
print( )
If you don't want to keep track of the count and solve this mathematically and be able to directly calculate any n-th line, the formula you are looking for is the one for, well, triangle numbers:
triangle = lambda n: n * (n + 1) // 2
for line in range(1, 5):
t = triangle(line)
print(' '.join(str(x+1) for x in range(t-line, t)))
# 1
# 2 3
# 4 5 6
# 7 8 9 10
I'm wondering how to create a pyramid using only element (1,2,3) regardless of how many rows.
For eg. Rows = 7 ,
1
22
333
1111
22222
333333
1111111
I've have tried creating a normal pyramid with numbers according to rows.
eg.
1
22
333
4444
55555
666666
Code that I tried to make a Normal Pyramid
n = int(input("Enter the number of rows:"))
for rows in range (1, n+1):
for times in range (rows):
print(rows, end=" ")
print("\n")
You need to adjust your ranges and use the modulo operator % - it gives you the remainer of any number diveded by some other number.Modulo 3 returns 0,1 or 2. Add 1 to get your desired range of values:
1 % 3 = 1
2 % 3 = 2 # 2 "remain" as 2 // 3 = 0 - so remainder is: 2 - (2//3)*3 = 2 - 0 = 2
3 % 3 = 0 # no remainder, as 3 // 3 = 1 - so remainder is: 3 - (3//3)*3 = 3 - 1*3 = 0
Full code:
n = int(input("Enter the number of rows: "))
print()
for rows in range (0, n): # start at 0
for times in range (rows+1): # start at 0
print( rows % 3 + 1, end=" ") # print 0 % 3 +1 , 1 % 3 +1, ..., etc.
print("")
Output:
Enter the number of rows: 6
1
2 2
3 3 3
1 1 1 1
2 2 2 2 2
3 3 3 3 3 3
See:
Modulo operator in Python
What is the result of % in Python?
binary-arithmetic-operations
A one-liner (just for the record):
>>> n = 7
>>> s = "\n".join(["".join([str(1+i%3)]*(1+i)) for i in range(n)])
>>> s
'1\n22\n333\n1111\n22222\n333333\n1111111'
>>> print(s)
1
22
333
1111
22222
333333
1111111
Nothing special: you have to use the modulo operator to cycle the values.
"".join([str(1+i%3)]*(1+i)) builds the (i+1)-th line: i+1 times 1+i%3 (thats is 1 if i=0, 2 if i=1, 3 if i=2, 1 if i=4, ...).
Repeat for i=0..n-1 and join with a end of line char.
Using cycle from itertools, i.e. a generator.
from itertools import cycle
n = int(input("Enter the number of rows:"))
a = cycle((1,2,3))
for x,y in zip(range(1,n),a):
print(str(x)*y)
(update) Rewritten as two-liner
from itertools import cycle
n = int(input("Enter the number of rows:"))
print(*[str(y)*x for x,y in zip(range(1,n),cycle((1,2,3)))],sep="\n")
I want to print a list [1,2,3,4,5,6,7,8,9] as
1 2 3
4 5 6
7 8 9
Here is my code
for i,j in enumerate(list):
if i is not 0 and i % 3==0:
print()
else:
print(j,end=" ")
My result is
1 2 3
5 6
8 9
Can someone help explain why this happen and give me some advise?
You should print the list item j unconditionally instead of doing it only when you are not printing a newline:
l = [1,2,3,4,5,6,7,8,9]
for i,j in enumerate(l):
if i is not 0 and i % 3==0:
print()
print(j,end=" ")
You can do:
tgt=[1,2,3,4,5,6,7,8,9]
n=3
print('\n'.join([' '.join(map(str, sl)) for sl in [tgt[i:i+n] for i in range(0,len(tgt),n)]]))
Prints:
1 2 3
4 5 6
7 8 9
What I am trying to do below in my code is just print all the types of number formats available in right aligned manner.
def print_formatted(number):
for i in range(1, n+1):
width = len(format(i, 'b'))
print("{0:d} {0:o} {0:x} {0:{w}b}".format(i, w=len(format(i, 'b'))))
if __name__ == '__main__':
n = int(input())
print_formatted(n)
Input:
4
Expected Output:
1 1 1 1
2 2 2 10
3 3 3 11
4 4 4 100
But actual output:
1 1 1 1
2 2 2 10
3 3 3 11
4 4 4 100
The above code works fine if I give a static value in-place of 'w' but if I pass dynamic changing value it is not working as expected. What am I missing here
Thanks in advance for your help.