Problem to merge multiple streamings in the same table on apache iceberg - apache-spark

I have multiple spark streaming writing in the same table in diferents fields. The iceberg documentation said the following: Iceberg supports multiple concurrent writes using optimistic concurrency.
But the error message appear when trying to merge:
Caused by: org.apache.iceberg.exceptions.ValidationException: Found conflicting files that can contain records matching true
Spark Merge:
spark.sql(
f"""
MERGE INTO datahub.replicacao.pefin_table tgt
USING (select nu_documento, co_cadus, aud_enttyp, nu_particao from pefin_pf) src
ON tgt.nu_documento = src.nu_documento and src.nu_particao in ('1', '2', '4')
WHEN MATCHED AND src.aud_enttyp = 'D' THEN DELETE
WHEN MATCHED THEN UPDATE SET *
WHEN NOT MATCHED THEN INSERT *
""")
Spark Session Configs:
val spark = SparkSession.builder()
.master("local[*]")
.config("spark.sql.catalog.datahub", "org.apache.iceberg.spark.SparkSessionCatalog")
.config("spark.sql.catalog.datahub.type", "hadoop")
.config("spark.sql.catalog.datahub", "org.apache.iceberg.spark.SparkCatalog")
.config("spark.sql.catalog.datahub.warehouse", "file:///C:/dev/warehouse")
.config("spark.sql.extensions", "org.apache.iceberg.spark.extensions.IcebergSparkSessionExtensions")
.getOrCreate()

Related

How to prevent spark query against CSV glue catalog source from including headers?

I am attempting to build a Glue job that will execute a SQL query against an existing glue catalog, and store the results in another glue catalog (in the example below, only return the record with the highest cost for each value of sn.) When executing a spark query against CSV sourced data, however, it is including the header in the results. This issue does not occur when the source is parquet. The glue catalog Serde parameters includes skip.header.line.count 1, and executing the query against the source data through Athena does not include the headers.
Is there a way to explicitly tell spark to ignore header rows when using .sql()?
Here is the essence of the python code my glue job is executing:
from pyspark.context import SparkContext
from pyspark.sql.session import SparkSession
glue_source_database_name = 'source_database'
glue_destination_database_name = 'destination_database'
table_name = 'diamonds10_csv'
partition_count = 5
merge_query = 'SELECT SEQ.`sn`,SEQ.`carat`,SEQ.`cut`,SEQ.`color`,SEQ.`clarity`,SEQ.`depth`,SEQ.`table`,SEQ.`price`,SEQ.`x`,SEQ.`y`,SEQ.`z` FROM ( SELECT SUB.`sn`,SUB.`carat`,SUB.`cut`,SUB.`color`,SUB.`clarity`,SUB.`depth`,SUB.`table`,SUB.`price`,SUB.`x`,SUB.`y`,SUB.`z`, ROW_NUMBER() OVER ( PARTITION BY SUB.`sn` ORDER BY SUB.`price` DESC ) AS test_diamond FROM `diamonds10_csv` AS SUB) AS SEQ WHERE SEQ.test_diamond = 1'
spark_context = SparkContext.getOrCreate()
spark = SparkSession( spark_context )
spark.sql( f'use {glue_source_database_name}')
targettable = spark.sql(merge_query)
targettable.repartition(partition_count).write.option("path",f'{s3_output_path}/{table_name}').mode("overwrite").format("parquet").saveAsTable(f'`{glue_destination_database_name}`.`{table_name}`')

How to store data from a dataframe in a variable to use as a parameter in a select in cassandra?

I have a Spark Structured Streaming application. The application receives data from kafka, and should use these values ​​as a parameter to process data from a cassandra database. My question is how do I use the data that is in the input dataframe (kafka), as "where" parameters in cassandra "select" without taking the error below:
Exception in thread "main" org.apache.spark.sql.AnalysisException: Queries with streaming sources must be executed with writeStream.start();
This is my df input:
val df = spark
.readStream
.format("kafka")
.options(
Map("kafka.bootstrap.servers"-> kafka_bootstrap,
"subscribe" -> kafka_topic,
"startingOffsets"-> "latest",
"fetchOffset.numRetries"-> "5",
"kafka.group.id"-> groupId
))
.load()
I get this error whenever I try to store the dataframe values ​​in a variable to use as a parameter.
This is the method I created to try to convert the data into variables. With that the spark give the error that I mentioned earlier:
def processData(messageToProcess: DataFrame): DataFrame = {
val messageDS: Dataset[Message] = messageToProcess.as[Message]
val listData: Array[Message] = messageDS.collect()
listData.foreach(x => println(x.country))
val mensagem = messageToProcess
mensagem
}
When you need to use data in Kafka to query data in Cassandra, then such operation is a typical join between two datasets - you don't need to call .collect to find entries, you just do the join. And it's quite typical thing - to enrich data in Kafka with data from the external dataset, and Cassandra provides low-latency operations.
Your code could look as following (you'll need to configure so-called DirectJoin, see link below):
import spark.implicits._
import org.apache.spark.sql.cassandra._
val df = spark.readStream.format("kafka")
.options(Map(...)).load()
... decode data in Kafka into columns
val cassdata = spark.read.cassandraFormat("table", "keyspace").load
val joined = df.join(cassdata, cassdata("pk") === df("some_column"))
val processed = ... process joined data
val query = processed.writeStream.....output data somewhere...start()
query.awaitTermination()
I have detailed blog post on how to perform efficient joins with data in Cassandra.
As the error message suggest, you have to use writeStream.start() in order to execute a Structured Streaming query.
You can't use the same actions you use for batch dataframes (like .collect(), .show() or .count()) on streaming dataframes, see the Unsupported Operations section of the Spark Structured Streaming documentation.
In your case, you are trying to use messageDS.collect() on a streaming dataset, which is not allowed. To achieve this goal you can use a foreachBatch output sink to collect the rows you need at each microbatch:
streamingDF.writeStream.foreachBatch { (microBatchDf: DataFrame, batchId: Long) =>
// Now microBatchDf is no longer a streaming dataframe
// you can check with microBatchDf.isStreaming
val messageDS: Dataset[Message] = microBatchDf.as[Message]
val listData: Array[Message] = messageDS.collect()
listData.foreach(x => println(x.country))
// ...
}

Change filter/where condition when restarting a Structured Streaming query reading data from Delta Table

In Structured Streaming, will the checkpoints keep track of which data has already been processed from a Delta Table?
def fetch_data_streaming(source_table: str):
print("Fetching now")
streamingInputDF = (
spark
.readStream
.format("delta")
.option("maxBytesPerTrigger",1024)
.table(source_table)
.where("measurementId IN (1351,1350)")
.where("year >= '2021'")
)
query = (
streamingInputDF
.writeStream
.outputMode("append")
.option("checkpointLocation", "/streaming_checkpoints/5")
.foreachBatch(customWriter)
.start()
.awaitTermination()
)
return query
def customWriter(batchDF,batchId):
print(batchId)
print(batchDF.count())
batchDF.show(10)
length = batchDF.count()
print("batchId,batch size:",batchId,length)
If I change the where clause in the streamingInputDF to add more measurentId, the structured streaming job doesn't always acknowledge the change and fetch the new data values. It continues to run as if nothing has changed, whereas at times it starts fetching new values.
Isn't the checkpoint supposed to identify the change?
Edit: Schema of delta table:
col_name
data_type
measurementId
int
year
int
time
timestamp
q
smallint
v
string
"In structured streaming, will the checkpoints will keep track of which data has already been processed?"
Yes, the Structured Streaming job will store the read version of the Delta table in its checkpoint files to avoid producing duplicates.
Within the checkpoint directory in the folder "offsets", you will see that Spark stored the progress per batchId. For example it will look like below:
v1
{"batchWatermarkMs":0,"batchTimestampMs":1619695775288,"conf":[...]}
{"sourceVersion":1,"reservoirId":"d910a260-6aa2-4a7c-9f5c-1be3164127c0","reservoirVersion":2,"index":2,"isStartingVersion":true}
Here, the important part is the "reservoirVersion":2 which tells you that the streaming job has consumed all data from the Delta Table as of version 2.
Re-starting your Structured Streaming query with an additional filter condition will therefore not be applied to historic records but only to those that were added to the Delta Table after version 2.
In order to see this behavior in action you can use below code and analyse the content in the checkpoint files.
val deltaPath = "file:///tmp/delta/table"
val checkpointLocation = "file:///tmp/checkpoint/"
// run the following two lines once
val deltaDf = Seq(("1", "foo1"), ("2", "foo2"), ("3", "foo2")).toDF("id", "value")
deltaDf.write.format("delta").mode("append").save(deltaPath)
// run this code for the first time, then add filter condition, then run again
val query = spark.readStream
.format("delta")
.load(deltaPath)
.filter(col("id").isin("1")) // in the second run add "2"
.writeStream
.format("console")
.outputMode("append")
.option("checkpointLocation", checkpointLocation)
.start()
query.awaitTermination()
Now, if you append some more data to the Delta table while the streaming query is shut down and then restart is with the new filter condition it will be applied to the new data.

spark cassandra connector problem using catalogs

I am following the instructions found here to connect my spark program to read data from Cassandra. Here is how I have configured spark:
val configBuilder = SparkSession.builder
.config("spark.sql.extensions", "com.datastax.spark.connector.CassandraSparkExtensions")
.config("spark.cassandra.connection.host", cassandraUrl)
.config("spark.cassandra.connection.port", 9042)
.config("spark.sql.catalog.myCatalogName", "com.datastax.spark.connector.datasource.CassandraCatalog")
According to the documentation, once this is done I should be able to query Cassandra like this:
spark.sql("select * from myCatalogName.myKeyspace.myTable where myPartitionKey = something")
however when I do so I get the following error message:
mismatched input '.' expecting <EOF>(line 1, pos 43)
== SQL ==
select * from myCatalog.myKeyspace.myTable where myPartitionKey = something
----------------------------------^^^
When I try in the following format I am successful at retrieving entries from Cassandra:
val frame = spark
.read
.format("org.apache.spark.sql.cassandra")
.options(Map("keyspace" -> "myKeyspace", "table" -> "myTable"))
.load()
.filter(col("timestamp") > startDate && col("timestamp") < endDate)
However this query requires a full table scan to be performed. The table contains a few million entries and I would prefer to avail myself of the predicate Pushdown functionality, which it would seem is only available via the SQL API.
I am using spark-core_2.11:2.4.3, spark-cassandra-connector_2.11:2.5.0 and Cassandra 3.11.6
Thanks!
The Catalogs API is available only in SCC version 3.0 that is not released yet. It will be released with Spark 3.0 release, so it isn't available in the SCC 2.5.0. So for 2.5.0 you need to register your table explicitly, with create or replace temporary view..., as described in docs:
spark.sql("""CREATE TEMPORARY VIEW myTable
USING org.apache.spark.sql.cassandra
OPTIONS (
table "myTable",
keyspace "myKeyspace",
pushdown "true")""")
Regarding the pushdowns (they work the same for all Dataframe APIs, SQL, Scala, Python, ...) - such filtering will happen when your timestamp is the first clustering column. And even in that case, the typical problem is that you may specify startDate and endDate as strings, not timestamp. You can check by executing frame.explain, and checking that predicate is pushed down - it should have * marker near predicate name.
For example,
val data = spark.read.cassandraFormat("sdtest", "test").load()
val filtered = data.filter("ts >= cast('2019-03-10T14:41:34.373+0000' as timestamp) AND ts <= cast('2019-03-10T19:01:56.316+0000' as timestamp)")
val not_filtered = data.filter("ts >= '2019-03-10T14:41:34.373+0000' AND ts <= '2019-03-10T19:01:56.316+0000'")
the first filter expression will push predicate down, while 2nd (not_filtered) will require a full scan.

Overwrite specific partitions in spark dataframe write method

I want to overwrite specific partitions instead of all in spark. I am trying the following command:
df.write.orc('maprfs:///hdfs-base-path','overwrite',partitionBy='col4')
where df is dataframe having the incremental data to be overwritten.
hdfs-base-path contains the master data.
When I try the above command, it deletes all the partitions, and inserts those present in df at the hdfs path.
What my requirement is to overwrite only those partitions present in df at the specified hdfs path. Can someone please help me in this?
Finally! This is now a feature in Spark 2.3.0:
SPARK-20236
To use it, you need to set the spark.sql.sources.partitionOverwriteMode setting to dynamic, the dataset needs to be partitioned, and the write mode overwrite. Example:
spark.conf.set("spark.sql.sources.partitionOverwriteMode","dynamic")
data.write.mode("overwrite").insertInto("partitioned_table")
I recommend doing a repartition based on your partition column before writing, so you won't end up with 400 files per folder.
Before Spark 2.3.0, the best solution would be to launch SQL statements to delete those partitions and then write them with mode append.
This is a common problem. The only solution with Spark up to 2.0 is to write directly into the partition directory, e.g.,
df.write.mode(SaveMode.Overwrite).save("/root/path/to/data/partition_col=value")
If you are using Spark prior to 2.0, you'll need to stop Spark from emitting metadata files (because they will break automatic partition discovery) using:
sc.hadoopConfiguration.set("parquet.enable.summary-metadata", "false")
If you are using Spark prior to 1.6.2, you will also need to delete the _SUCCESS file in /root/path/to/data/partition_col=value or its presence will break automatic partition discovery. (I strongly recommend using 1.6.2 or later.)
You can get a few more details about how to manage large partitioned tables from my Spark Summit talk on Bulletproof Jobs.
spark.conf.set("spark.sql.sources.partitionOverwriteMode","dynamic")
data.toDF().write.mode("overwrite").format("parquet").partitionBy("date", "name").save("s3://path/to/somewhere")
This works for me on AWS Glue ETL jobs (Glue 1.0 - Spark 2.4 - Python 2)
Adding 'overwrite=True' parameter in the insertInto statement solves this:
hiveContext.setConf("hive.exec.dynamic.partition", "true")
hiveContext.setConf("hive.exec.dynamic.partition.mode", "nonstrict")
df.write.mode("overwrite").insertInto("database_name.partioned_table", overwrite=True)
By default overwrite=False. Changing it to True allows us to overwrite specific partitions contained in df and in the partioned_table. This helps us avoid overwriting the entire contents of the partioned_table with df.
Using Spark 1.6...
The HiveContext can simplify this process greatly. The key is that you must create the table in Hive first using a CREATE EXTERNAL TABLE statement with partitioning defined. For example:
# Hive SQL
CREATE EXTERNAL TABLE test
(name STRING)
PARTITIONED BY
(age INT)
STORED AS PARQUET
LOCATION 'hdfs:///tmp/tables/test'
From here, let's say you have a Dataframe with new records in it for a specific partition (or multiple partitions). You can use a HiveContext SQL statement to perform an INSERT OVERWRITE using this Dataframe, which will overwrite the table for only the partitions contained in the Dataframe:
# PySpark
hiveContext = HiveContext(sc)
update_dataframe.registerTempTable('update_dataframe')
hiveContext.sql("""INSERT OVERWRITE TABLE test PARTITION (age)
SELECT name, age
FROM update_dataframe""")
Note: update_dataframe in this example has a schema that matches that of the target test table.
One easy mistake to make with this approach is to skip the CREATE EXTERNAL TABLE step in Hive and just make the table using the Dataframe API's write methods. For Parquet-based tables in particular, the table will not be defined appropriately to support Hive's INSERT OVERWRITE... PARTITION function.
Hope this helps.
Tested this on Spark 2.3.1 with Scala.
Most of the answers above are writing to a Hive table. However, I wanted to write directly to disk, which has an external hive table on top of this folder.
First the required configuration
val sparkSession: SparkSession = SparkSession
.builder
.enableHiveSupport()
.config("spark.sql.sources.partitionOverwriteMode", "dynamic") // Required for overwriting ONLY the required partitioned folders, and not the entire root folder
.appName("spark_write_to_dynamic_partition_folders")
Usage here:
DataFrame
.write
.format("<required file format>")
.partitionBy("<partitioned column name>")
.mode(SaveMode.Overwrite) // This is required.
.save(s"<path_to_root_folder>")
I tried below approach to overwrite particular partition in HIVE table.
### load Data and check records
raw_df = spark.table("test.original")
raw_df.count()
lets say this table is partitioned based on column : **c_birth_year** and we would like to update the partition for year less than 1925
### Check data in few partitions.
sample = raw_df.filter(col("c_birth_year") <= 1925).select("c_customer_sk", "c_preferred_cust_flag")
print "Number of records: ", sample.count()
sample.show()
### Back-up the partitions before deletion
raw_df.filter(col("c_birth_year") <= 1925).write.saveAsTable("test.original_bkp", mode = "overwrite")
### UDF : To delete particular partition.
def delete_part(table, part):
qry = "ALTER TABLE " + table + " DROP IF EXISTS PARTITION (c_birth_year = " + str(part) + ")"
spark.sql(qry)
### Delete partitions
part_df = raw_df.filter(col("c_birth_year") <= 1925).select("c_birth_year").distinct()
part_list = part_df.rdd.map(lambda x : x[0]).collect()
table = "test.original"
for p in part_list:
delete_part(table, p)
### Do the required Changes to the columns in partitions
df = spark.table("test.original_bkp")
newdf = df.withColumn("c_preferred_cust_flag", lit("Y"))
newdf.select("c_customer_sk", "c_preferred_cust_flag").show()
### Write the Partitions back to Original table
newdf.write.insertInto("test.original")
### Verify data in Original table
orginial.filter(col("c_birth_year") <= 1925).select("c_customer_sk", "c_preferred_cust_flag").show()
Hope it helps.
Regards,
Neeraj
As jatin Wrote you can delete paritions from hive and from path and then append data
Since I was wasting too much time with it I added the following example for other spark users.
I used Scala with spark 2.2.1
import org.apache.hadoop.conf.Configuration
import org.apache.hadoop.fs.Path
import org.apache.spark.SparkConf
import org.apache.spark.sql.{Column, DataFrame, SaveMode, SparkSession}
case class DataExample(partition1: Int, partition2: String, someTest: String, id: Int)
object StackOverflowExample extends App {
//Prepare spark & Data
val sparkConf = new SparkConf()
sparkConf.setMaster(s"local[2]")
val spark = SparkSession.builder().config(sparkConf).getOrCreate()
val tableName = "my_table"
val partitions1 = List(1, 2)
val partitions2 = List("e1", "e2")
val partitionColumns = List("partition1", "partition2")
val myTablePath = "/tmp/some_example"
val someText = List("text1", "text2")
val ids = (0 until 5).toList
val listData = partitions1.flatMap(p1 => {
partitions2.flatMap(p2 => {
someText.flatMap(
text => {
ids.map(
id => DataExample(p1, p2, text, id)
)
}
)
}
)
})
val asDataFrame = spark.createDataFrame(listData)
//Delete path function
def deletePath(path: String, recursive: Boolean): Unit = {
val p = new Path(path)
val fs = p.getFileSystem(new Configuration())
fs.delete(p, recursive)
}
def tableOverwrite(df: DataFrame, partitions: List[String], path: String): Unit = {
if (spark.catalog.tableExists(tableName)) {
//clean partitions
val asColumns = partitions.map(c => new Column(c))
val relevantPartitions = df.select(asColumns: _*).distinct().collect()
val partitionToRemove = relevantPartitions.map(row => {
val fields = row.schema.fields
s"ALTER TABLE ${tableName} DROP IF EXISTS PARTITION " +
s"${fields.map(field => s"${field.name}='${row.getAs(field.name)}'").mkString("(", ",", ")")} PURGE"
})
val cleanFolders = relevantPartitions.map(partition => {
val fields = partition.schema.fields
path + fields.map(f => s"${f.name}=${partition.getAs(f.name)}").mkString("/")
})
println(s"Going to clean ${partitionToRemove.size} partitions")
partitionToRemove.foreach(partition => spark.sqlContext.sql(partition))
cleanFolders.foreach(partition => deletePath(partition, true))
}
asDataFrame.write
.options(Map("path" -> myTablePath))
.mode(SaveMode.Append)
.partitionBy(partitionColumns: _*)
.saveAsTable(tableName)
}
//Now test
tableOverwrite(asDataFrame, partitionColumns, tableName)
spark.sqlContext.sql(s"select * from $tableName").show(1000)
tableOverwrite(asDataFrame, partitionColumns, tableName)
import spark.implicits._
val asLocalSet = spark.sqlContext.sql(s"select * from $tableName").as[DataExample].collect().toSet
if (asLocalSet == listData.toSet) {
println("Overwrite is working !!!")
}
}
If you use DataFrame, possibly you want to use Hive table over data.
In this case you need just call method
df.write.mode(SaveMode.Overwrite).partitionBy("partition_col").insertInto(table_name)
It'll overwrite partitions that DataFrame contains.
There's not necessity to specify format (orc), because Spark will use Hive table format.
It works fine in Spark version 1.6
Instead of writing to the target table directly, i would suggest you create a temporary table like the target table and insert your data there.
CREATE TABLE tmpTbl LIKE trgtTbl LOCATION '<tmpLocation';
Once the table is created, you would write your data to the tmpLocation
df.write.mode("overwrite").partitionBy("p_col").orc(tmpLocation)
Then you would recover the table partition paths by executing:
MSCK REPAIR TABLE tmpTbl;
Get the partition paths by querying the Hive metadata like:
SHOW PARTITONS tmpTbl;
Delete these partitions from the trgtTbl and move the directories from tmpTbl to trgtTbl
I would suggest you doing clean-up and then writing new partitions with Append mode:
import scala.sys.process._
def deletePath(path: String): Unit = {
s"hdfs dfs -rm -r -skipTrash $path".!
}
df.select(partitionColumn).distinct.collect().foreach(p => {
val partition = p.getAs[String](partitionColumn)
deletePath(s"$path/$partitionColumn=$partition")
})
df.write.partitionBy(partitionColumn).mode(SaveMode.Append).orc(path)
This will delete only new partitions. After writing data run this command if you need to update metastore:
sparkSession.sql(s"MSCK REPAIR TABLE $db.$table")
Note: deletePath assumes that hfds command is available on your system.
My solution implies overwriting each specific partition starting from a spark dataframe. It skips the dropping partition part. I'm using pyspark>=3 and I'm writing on AWS s3:
def write_df_on_s3(df, s3_path, field, mode):
# get the list of unique field values
list_partitions = [x.asDict()[field] for x in df.select(field).distinct().collect()]
df_repartitioned = df.repartition(1,field)
for p in list_partitions:
# create dataframes by partition and send it to s3
df_to_send = df_repartitioned.where("{}='{}'".format(field,p))
df_to_send.write.mode(mode).parquet(s3_path+"/"+field+"={}/".format(p))
The arguments of this simple function are the df, the s3_path, the partition field, and the mode (overwrite or append). The first part gets the unique field values: it means that if I'm partitioning the df by daily, I get a list of all the dailies in the df. Then I'm repartition the df. Finally, I'm selecting the repartitioned df by each daily and I'm writing it on its specific partition path.
You can change the repartition integer by your needs.
You could do something like this to make the job reentrant (idempotent):
(tried this on spark 2.2)
# drop the partition
drop_query = "ALTER TABLE table_name DROP IF EXISTS PARTITION (partition_col='{val}')".format(val=target_partition)
print drop_query
spark.sql(drop_query)
# delete directory
dbutils.fs.rm(<partition_directoy>,recurse=True)
# Load the partition
df.write\
.partitionBy("partition_col")\
.saveAsTable(table_name, format = "parquet", mode = "append", path = <path to parquet>)
For >= Spark 2.3.0 :
spark.conf.set("spark.sql.sources.partitionOverwriteMode","dynamic")
data.write.insertInto("partitioned_table", overwrite=True)

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