Print Vec<i32> in rust with a custom formatter - rust

I have the following:
{
let mut v = vec![1, 2, 3, 4, 5];
{
println!("v = {}", v);
let first = &v[0];
println!("The first element is: {}", first);
}
v.push(6);
{
println!("v = {}", v);
let first = &v[0];
println!("The first element is: {}", first);
}
}
And my error is:
println!("v = {}", v);
^ `Vec<{integer}>` cannot be formatted with the default formatter
`Vec<{integer}>` doesn't implement `std::fmt::Display`
help: the trait `std::fmt::Display` is not implemented for `Vec<{integer}>`
That seems straightforward. I will follow the error message and implement the fmt interface for a vector of integers, as suggested:
use std::fmt;
impl fmt::Display for Vec<integer>{
fn fmt(&self) {
for i in self.iter() {
println!("{}", i);
}
}
}
let mut v = vec![1, 2, 3, 4, 5];
{
println!("v = {}", v);
let first = &v[0];
println!("The first element is: {}", first);
}
v.push(6);
{
println!("v = {}", v);
let first = &v[0];
println!("The first element is: {}", first);
}
Which tells me it cannot find 'integer'
impl fmt::Display for Vec<integer>{
^^^^^^^ not found in this scope
cannot find type `integer` in this scope
help: you might be missing a type parameter
<integer>
impl fmt::Display for Vec<integer>{
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ impl doesn't use only types from inside the current crate
impl fmt::Display for Vec<integer>{
^^^^^^^^^^^^ `Vec` is not defined in the current crate
only traits defined in the current crate can be implemented for arbitrary types
Isn't integer already imported?
Well, fine. Instead of integer, let's do it generically. But this /also/ fails for
// This doesn't work because first is borrowing an element of v. So I can't modify v after.
use std::fmt;
impl fmt::Display for Vec<T>{
fn fmt(&self) {
for i in self.iter() {
println!("{}", i);
}
}
}
let mut v = vec![1, 2, 3, 4, 5];
{
println!("v = {}", v);
let first = &v[0];
println!("The first element is: {}", first);
}
v.push(6);
{
println!("v = {}", v);
let first = &v[0];
println!("The first element is: {}", first);
}
How does rust print a vector of integers?

You cannot. There are two issues here:
One, there is no {integer} type in Rust. If you write a integer literal, like 0, you could mean for it to be one of many different types. It will typically be inferred based on later usage (or sometimes can default to i32), but until then, and if an error needs to reference a integer type that has not-yet-been deduced, you'll see {integer}. You may also see {float}.
Two, you cannot implement implement Display for Vec. If you attempt it, the compiler will emit an error like:
error[E0117]: only traits defined in the current crate can be implemented for types defined outside of the crate
--> src/lib.rs:5:1
|
5 | impl Display for Vec<T> {
| ^^^^^^^^^^^^^^^^^------
| | |
| | `Vec` is not defined in the current crate
| impl doesn't use only types from inside the current crate
|
= note: define and implement a trait or new type instead
This is due to Rust's "orphan rules" that restrict what traits can be implemented for which types to preemptively reject potentially conflicting implementations and aid in trait-lookup.
To print a Vec<_> with a custom implementation, you'll need to use the newtype idiom that wraps a Vec and implements Display on that new type instead:
struct MyFormat(Vec<i32>);
impl Display for MyFormat {
// ...
}

The easier way would be to use the debug formatter {:?} instead of the display formatter {}.
However, if you really want your custom formatter for a vector, then you cannot do it directly.
In Rust, when you implement a trait for a type, the trait or the type (or both) must come from your crate.
In your attempt, both Display and Vec come from std.
The usual workaround is to use the newtype pattern: you define your own type which just wraps an existing one.
In order to ease the access to the inner type, we can implement Deref and DerefMut.
Please find a simple example below.
use std::{
fmt::{Display, Formatter, Result},
ops::{Deref, DerefMut},
};
struct VecProxy<T>(Vec<T>);
impl<T> Deref for VecProxy<T> {
type Target = Vec<T>;
fn deref(&self) -> &Self::Target {
&self.0
}
}
impl<T> DerefMut for VecProxy<T> {
fn deref_mut(&mut self) -> &mut Self::Target {
&mut self.0
}
}
impl<T: Display> Display for VecProxy<T> {
fn fmt(
&self,
f: &mut Formatter<'_>,
) -> Result {
for i in self.iter() {
writeln!(f, "~~> {}", i)?;
}
Ok(())
}
}
fn main() {
let mut v = VecProxy(vec![1, 2, 3, 4, 5]);
{
println!("v = {}", v);
let first = &v[0];
println!("The first element is: {}", first);
}
v.push(6);
{
println!("v = {}", v);
let first = &v[0];
println!("The first element is: {}", first);
}
}
/*
v = ~~> 1
~~> 2
~~> 3
~~> 4
~~> 5
The first element is: 1
v = ~~> 1
~~> 2
~~> 3
~~> 4
~~> 5
~~> 6
The first element is: 1
*/

Related

How can a Rust developer get an inferred data type? [duplicate]

I have the following:
let mut my_number = 32.90;
How do I print the type of my_number?
Using type and type_of did not work. Is there another way I can print the number's type?
You can use the std::any::type_name function. This doesn't need a nightly compiler or an external crate, and the results are quite correct:
fn print_type_of<T>(_: &T) {
println!("{}", std::any::type_name::<T>())
}
fn main() {
let s = "Hello";
let i = 42;
print_type_of(&s); // &str
print_type_of(&i); // i32
print_type_of(&main); // playground::main
print_type_of(&print_type_of::<i32>); // playground::print_type_of<i32>
print_type_of(&{ || "Hi!" }); // playground::main::{{closure}}
}
Be warned: as said in the documentation, this information must be used for a debug purpose only:
This is intended for diagnostic use. The exact contents and format of the string are not specified, other than being a best-effort description of the type.
If you want your type representation to stay the same between compiler versions, you should use a trait, like in the phicr's answer.
If you merely wish to find out the type of a variable and are willing to do it at compile time, you can cause an error and get the compiler to pick it up.
For example, set the variable to a type which doesn't work:
let mut my_number: () = 32.90;
// let () = x; would work too
error[E0308]: mismatched types
--> src/main.rs:2:29
|
2 | let mut my_number: () = 32.90;
| ^^^^^ expected (), found floating-point number
|
= note: expected type `()`
found type `{float}`
Or call an invalid method:
let mut my_number = 32.90;
my_number.what_is_this();
error[E0599]: no method named `what_is_this` found for type `{float}` in the current scope
--> src/main.rs:3:15
|
3 | my_number.what_is_this();
| ^^^^^^^^^^^^
Or access an invalid field:
let mut my_number = 32.90;
my_number.what_is_this
error[E0610]: `{float}` is a primitive type and therefore doesn't have fields
--> src/main.rs:3:15
|
3 | my_number.what_is_this
| ^^^^^^^^^^^^
These reveal the type, which in this case is actually not fully resolved. It’s called “floating-point variable” in the first example, and “{float}” in all three examples; this is a partially resolved type which could end up f32 or f64, depending on how you use it. “{float}” is not a legal type name, it’s a placeholder meaning “I’m not completely sure what this is”, but it is a floating-point number. In the case of floating-point variables, if you don't constrain it, it will default to f64¹. (An unqualified integer literal will default to i32.)
See also:
What is the {integer} or {float} in a compiler error message?
¹ There may still be ways of baffling the compiler so that it can’t decide between f32 and f64; I’m not sure. It used to be as simple as 32.90.eq(&32.90), but that treats both as f64 now and chugs along happily, so I don’t know.
There is an unstable function std::intrinsics::type_name that can get you the name of a type, though you have to use a nightly build of Rust (this is unlikely to ever work in stable Rust). Here’s an example:
#![feature(core_intrinsics)]
fn print_type_of<T>(_: &T) {
println!("{}", unsafe { std::intrinsics::type_name::<T>() });
}
fn main() {
print_type_of(&32.90); // prints "f64"
print_type_of(&vec![1, 2, 4]); // prints "std::vec::Vec<i32>"
print_type_of(&"foo"); // prints "&str"
}
If you know all the types beforehand, you can use traits to add a type_of method:
trait TypeInfo {
fn type_of(&self) -> &'static str;
}
impl TypeInfo for i32 {
fn type_of(&self) -> &'static str {
"i32"
}
}
impl TypeInfo for i64 {
fn type_of(&self) -> &'static str {
"i64"
}
}
//...
No intrisics or nothin', so although more limited this is the only solution here that gets you a string and is stable. (see Boiethios's answer) However, it's very laborious and doesn't account for type parameters, so we could...
trait TypeInfo {
fn type_name() -> String;
fn type_of(&self) -> String;
}
macro_rules! impl_type_info {
($($name:ident$(<$($T:ident),+>)*),*) => {
$(impl_type_info_single!($name$(<$($T),*>)*);)*
};
}
macro_rules! mut_if {
($name:ident = $value:expr, $($any:expr)+) => (let mut $name = $value;);
($name:ident = $value:expr,) => (let $name = $value;);
}
macro_rules! impl_type_info_single {
($name:ident$(<$($T:ident),+>)*) => {
impl$(<$($T: TypeInfo),*>)* TypeInfo for $name$(<$($T),*>)* {
fn type_name() -> String {
mut_if!(res = String::from(stringify!($name)), $($($T)*)*);
$(
res.push('<');
$(
res.push_str(&$T::type_name());
res.push(',');
)*
res.pop();
res.push('>');
)*
res
}
fn type_of(&self) -> String {
$name$(::<$($T),*>)*::type_name()
}
}
}
}
impl<'a, T: TypeInfo + ?Sized> TypeInfo for &'a T {
fn type_name() -> String {
let mut res = String::from("&");
res.push_str(&T::type_name());
res
}
fn type_of(&self) -> String {
<&T>::type_name()
}
}
impl<'a, T: TypeInfo + ?Sized> TypeInfo for &'a mut T {
fn type_name() -> String {
let mut res = String::from("&mut ");
res.push_str(&T::type_name());
res
}
fn type_of(&self) -> String {
<&mut T>::type_name()
}
}
macro_rules! type_of {
($x:expr) => { (&$x).type_of() };
}
Let's use it:
impl_type_info!(i32, i64, f32, f64, str, String, Vec<T>, Result<T,S>)
fn main() {
println!("{}", type_of!(1));
println!("{}", type_of!(&1));
println!("{}", type_of!(&&1));
println!("{}", type_of!(&mut 1));
println!("{}", type_of!(&&mut 1));
println!("{}", type_of!(&mut &1));
println!("{}", type_of!(1.0));
println!("{}", type_of!("abc"));
println!("{}", type_of!(&"abc"));
println!("{}", type_of!(String::from("abc")));
println!("{}", type_of!(vec![1,2,3]));
println!("{}", <Result<String,i64>>::type_name());
println!("{}", <&i32>::type_name());
println!("{}", <&str>::type_name());
}
output:
i32
&i32
&&i32
&mut i32
&&mut i32
&mut &i32
f64
&str
&&str
String
Vec<i32>
Result<String,i64>
&i32
&str
Rust Playground
UPD The following does not work anymore. Check Shubham's answer for correction.
Check out std::intrinsics::get_tydesc<T>(). It is in "experimental" state right now, but it's OK if you are just hacking around the type system.
Check out the following example:
fn print_type_of<T>(_: &T) -> () {
let type_name =
unsafe {
(*std::intrinsics::get_tydesc::<T>()).name
};
println!("{}", type_name);
}
fn main() -> () {
let mut my_number = 32.90;
print_type_of(&my_number); // prints "f64"
print_type_of(&(vec!(1, 2, 4))); // prints "collections::vec::Vec<int>"
}
This is what is used internally to implement the famous {:?} formatter.
Update, original answer below
How about trait function type_name, which is useful to get type name quickly.
pub trait AnyExt {
fn type_name(&self) -> &'static str;
}
impl<T> AnyExt for T {
fn type_name(&self) -> &'static str {
std::any::type_name::<T>()
}
}
fn main(){
let my_number = 32.90;
println!("{}",my_number.type_name());
}
Output:
f64
Original answer
I write a macro type_of!() to debug, which is original from std dbg!().
pub fn type_of2<T>(v: T) -> (&'static str, T) {
(std::any::type_name::<T>(), v)
}
#[macro_export]
macro_rules! type_of {
// NOTE: We cannot use `concat!` to make a static string as a format argument
// of `eprintln!` because `file!` could contain a `{` or
// `$val` expression could be a block (`{ .. }`), in which case the `eprintln!`
// will be malformed.
() => {
eprintln!("[{}:{}]", file!(), line!());
};
($val:expr $(,)?) => {
// Use of `match` here is intentional because it affects the lifetimes
// of temporaries - https://stackoverflow.com/a/48732525/1063961
match $val {
tmp => {
let (type_,tmp) = $crate::type_of2(tmp);
eprintln!("[{}:{}] {}: {}",
file!(), line!(), stringify!($val), type_);
tmp
}
}
};
($($val:expr),+ $(,)?) => {
($($crate::type_of!($val)),+,)
};
}
fn main(){
let my_number = type_of!(32.90);
type_of!(my_number);
}
Output:
[src/main.rs:32] 32.90: f64
[src/main.rs:33] my_number: f64
** UPDATE ** This has not been verified to work any time recently.
I put together a little crate to do this based off vbo's answer. It gives you a macro to return or print out the type.
Put this in your Cargo.toml file:
[dependencies]
t_bang = "0.1.2"
Then you can use it like so:
#[macro_use] extern crate t_bang;
use t_bang::*;
fn main() {
let x = 5;
let x_type = t!(x);
println!("{:?}", x_type); // prints out: "i32"
pt!(x); // prints out: "i32"
pt!(5); // prints out: "i32"
}
You can also use the simple approach of using the variable in println!("{:?}", var). If Debug is not implemented for the type, you can see the type in the compiler's error message:
mod some {
pub struct SomeType;
}
fn main() {
let unknown_var = some::SomeType;
println!("{:?}", unknown_var);
}
(playpen)
It's dirty but it works.
There's a #ChrisMorgan answer to get approximate type ("float") in stable rust and there's a #ShubhamJain answer to get precise type ("f64") through unstable function in nightly rust.
Now here's a way one can get precise type (ie decide between f32 and f64) in stable rust:
fn main() {
let a = 5.;
let _: () = unsafe { std::mem::transmute(a) };
}
results in
error[E0512]: cannot transmute between types of different sizes, or dependently-sized types
--> main.rs:3:27
|
3 | let _: () = unsafe { std::mem::transmute(a) };
| ^^^^^^^^^^^^^^^^^^^
|
= note: source type: `f64` (64 bits)
= note: target type: `()` (0 bits)
Update
The turbofish variation
fn main() {
let a = 5.;
unsafe { std::mem::transmute::<_, ()>(a) }
}
is slightly shorter but somewhat less readable.
Some other answers don't work, but I find that the typename crate works.
Create a new project:
cargo new test_typename
Modify the Cargo.toml
[dependencies]
typename = "0.1.1"
Modify your source code
use typename::TypeName;
fn main() {
assert_eq!(String::type_name(), "std::string::String");
assert_eq!(Vec::<i32>::type_name(), "std::vec::Vec<i32>");
assert_eq!([0, 1, 2].type_name_of(), "[i32; 3]");
let a = 65u8;
let b = b'A';
let c = 65;
let d = 65i8;
let e = 65i32;
let f = 65u32;
let arr = [1,2,3,4,5];
let first = arr[0];
println!("type of a 65u8 {} is {}", a, a.type_name_of());
println!("type of b b'A' {} is {}", b, b.type_name_of());
println!("type of c 65 {} is {}", c, c.type_name_of());
println!("type of d 65i8 {} is {}", d, d.type_name_of());
println!("type of e 65i32 {} is {}", e, e.type_name_of());
println!("type of f 65u32 {} is {}", f, f.type_name_of());
println!("type of arr {:?} is {}", arr, arr.type_name_of());
println!("type of first {} is {}", first, first.type_name_of());
}
The output is:
type of a 65u8 65 is u8
type of b b'A' 65 is u8
type of c 65 65 is i32
type of d 65i8 65 is i8
type of e 65i32 65 is i32
type of f 65u32 65 is u32
type of arr [1, 2, 3, 4, 5] is [i32; 5]
type of first 1 is i32
If your just wanting to know the type of your variable during interactive development, I would highly recommend using rls (rust language server) inside of your editor or ide. You can then simply permanently enable or toggle the hover ability and just put your cursor over the variable. A little dialog should come up with information about the variable including the type.
This is simplified version of #Boiethios answer. I have removed some '&' symbols from original solution.
fn print_type_of<T>(_: T) {
println!("{}", std::any::type_name::<T>())
}
fn main() {
let s = "Hello";
let i = 42;
print_type_of(s); // &str
print_type_of(i); // i32
print_type_of(main); // playground::main
print_type_of(print_type_of::<i32>); // playground::print_type_of<i32>
print_type_of(|| "Hi!" ); // playground::main::{{closure}}
}
View in Rust Playground
Newly added in version 1.38 std::any::type_name
use std::any::type_name;
fn type_of<T>(_: T) -> &'static str {
type_name::<T>()
}
fn main() {
let x = 21;
let y = 2.5;
println!("{}", type_of(&y));
println!("{}", type_of(x));
}
short story;
fn tyof<T>(_: &T) -> String {
std::any::type_name::<T>().into()
}
long story;
trait Type {
fn type_of(&self) -> String;
}
macro_rules! Type {
($($ty:ty),*) => {
$(
impl Type for $ty {
fn type_of(&self) -> String {
stringify!($ty).into()
}
}
)*
}
}
#[rustfmt::skip]
Type!(
u8, i8, u16, i16, u32, i32, i64, u64, i128, String, [()], (), Vec<()>, &u8, &i8, &u16, &i16, &u32, &i32, &i64, &u64, &i128, &str, &[()], &Vec<()>, &()
// add any struct, enum or type you want
);
macro_rules! tyof {
($var: expr) => {{
$var.type_of()
}};
}
fn main() {
let x = "Hello world!";
println!("{}", tyof!(x));
// or
println!("{}", x.type_of());
let x = 5;
println!("{}", tyof!(x));
// or
println!("{}", x.type_of());
}
Macro form permits an usage "everywhere" while the function need an object to be parse.
Macro form (one liner):
macro_rules! ty {($type:ty) => {std::any::type_name::<$type>()}}
Macro form formated:
macro_rules! ty {
($type:ty) => {
std::any::type_name::<$type>()
};
}
Function form (borrowing is to not destroy the parsed var):
fn type_of<T>(_: &T) -> &'static str {std::any::type_name::<T>()}
fn type_of<T>(_: &T) -> &'static str {
std::any::type_name::<T>()
}
Example:
macro_rules! ty {($type:ty) => {std::any::type_name::<$type>()}}
fn type_of<T>(_: &T) -> &'static str {std::any::type_name::<T>()}
struct DontMater<T>(T);
impl<T: std::fmt::Debug> std::fmt::Debug for DontMater<T> {
fn fmt(&self, fmt: &mut std::fmt::Formatter<'_>) -> std::fmt::Result {
fmt.write_fmt(format_args!("DontMater<{}>({:?})", ty!(T), self.0))
}
}
fn main() {
type µ = [Vec<String>; 7];
println!("{:?}", DontMater(5_usize));
println!("{:?}", DontMater("¤"));
println!("{}", ty!(char));
println!("{:?}", ty!(µ));
println!("{}", type_of(&DontMater(72_i8)));
println!("{:?}", type_of(&15_f64));
}
Returns:
DontMater<usize>(5)
DontMater<&str>("¤")
char
"[alloc::vec::Vec<alloc::string::String>; 7]"
env_vars::DontMater<i8>
"f64"
I like previous answer by #Coautose very much, but in case anyone wants just the type name without the namespace, for example C instead of a::b::C, here is a modified version of the macro that appears to work as intended:
macro_rules! ty {
($type:ty) => {{
let result = std::any::type_name::<$type>();
match result.rsplit_once(':') {
Some((_, s)) => s,
None => result,
}
}};
}
Usage:
debug!("Testing type name: {}", ty!(A));
Better to use this:
fn print_type_of<T>(_: &T) -> String {
format!("{}", std::any::type_name::<T>())
}
fn main() {
let s = &"hello world".to_string();
let cloned_s = s.clone();
println!("{:?}", print_type_of(&s));
println!("{:?}", print_type_of(&cloned_s));
}
Taken inference from https://stackoverflow.com/a/29168659/6774636

How to print out type of variable in Rust? [duplicate]

I have the following:
let mut my_number = 32.90;
How do I print the type of my_number?
Using type and type_of did not work. Is there another way I can print the number's type?
You can use the std::any::type_name function. This doesn't need a nightly compiler or an external crate, and the results are quite correct:
fn print_type_of<T>(_: &T) {
println!("{}", std::any::type_name::<T>())
}
fn main() {
let s = "Hello";
let i = 42;
print_type_of(&s); // &str
print_type_of(&i); // i32
print_type_of(&main); // playground::main
print_type_of(&print_type_of::<i32>); // playground::print_type_of<i32>
print_type_of(&{ || "Hi!" }); // playground::main::{{closure}}
}
Be warned: as said in the documentation, this information must be used for a debug purpose only:
This is intended for diagnostic use. The exact contents and format of the string are not specified, other than being a best-effort description of the type.
If you want your type representation to stay the same between compiler versions, you should use a trait, like in the phicr's answer.
If you merely wish to find out the type of a variable and are willing to do it at compile time, you can cause an error and get the compiler to pick it up.
For example, set the variable to a type which doesn't work:
let mut my_number: () = 32.90;
// let () = x; would work too
error[E0308]: mismatched types
--> src/main.rs:2:29
|
2 | let mut my_number: () = 32.90;
| ^^^^^ expected (), found floating-point number
|
= note: expected type `()`
found type `{float}`
Or call an invalid method:
let mut my_number = 32.90;
my_number.what_is_this();
error[E0599]: no method named `what_is_this` found for type `{float}` in the current scope
--> src/main.rs:3:15
|
3 | my_number.what_is_this();
| ^^^^^^^^^^^^
Or access an invalid field:
let mut my_number = 32.90;
my_number.what_is_this
error[E0610]: `{float}` is a primitive type and therefore doesn't have fields
--> src/main.rs:3:15
|
3 | my_number.what_is_this
| ^^^^^^^^^^^^
These reveal the type, which in this case is actually not fully resolved. It’s called “floating-point variable” in the first example, and “{float}” in all three examples; this is a partially resolved type which could end up f32 or f64, depending on how you use it. “{float}” is not a legal type name, it’s a placeholder meaning “I’m not completely sure what this is”, but it is a floating-point number. In the case of floating-point variables, if you don't constrain it, it will default to f64¹. (An unqualified integer literal will default to i32.)
See also:
What is the {integer} or {float} in a compiler error message?
¹ There may still be ways of baffling the compiler so that it can’t decide between f32 and f64; I’m not sure. It used to be as simple as 32.90.eq(&32.90), but that treats both as f64 now and chugs along happily, so I don’t know.
There is an unstable function std::intrinsics::type_name that can get you the name of a type, though you have to use a nightly build of Rust (this is unlikely to ever work in stable Rust). Here’s an example:
#![feature(core_intrinsics)]
fn print_type_of<T>(_: &T) {
println!("{}", unsafe { std::intrinsics::type_name::<T>() });
}
fn main() {
print_type_of(&32.90); // prints "f64"
print_type_of(&vec![1, 2, 4]); // prints "std::vec::Vec<i32>"
print_type_of(&"foo"); // prints "&str"
}
If you know all the types beforehand, you can use traits to add a type_of method:
trait TypeInfo {
fn type_of(&self) -> &'static str;
}
impl TypeInfo for i32 {
fn type_of(&self) -> &'static str {
"i32"
}
}
impl TypeInfo for i64 {
fn type_of(&self) -> &'static str {
"i64"
}
}
//...
No intrisics or nothin', so although more limited this is the only solution here that gets you a string and is stable. (see Boiethios's answer) However, it's very laborious and doesn't account for type parameters, so we could...
trait TypeInfo {
fn type_name() -> String;
fn type_of(&self) -> String;
}
macro_rules! impl_type_info {
($($name:ident$(<$($T:ident),+>)*),*) => {
$(impl_type_info_single!($name$(<$($T),*>)*);)*
};
}
macro_rules! mut_if {
($name:ident = $value:expr, $($any:expr)+) => (let mut $name = $value;);
($name:ident = $value:expr,) => (let $name = $value;);
}
macro_rules! impl_type_info_single {
($name:ident$(<$($T:ident),+>)*) => {
impl$(<$($T: TypeInfo),*>)* TypeInfo for $name$(<$($T),*>)* {
fn type_name() -> String {
mut_if!(res = String::from(stringify!($name)), $($($T)*)*);
$(
res.push('<');
$(
res.push_str(&$T::type_name());
res.push(',');
)*
res.pop();
res.push('>');
)*
res
}
fn type_of(&self) -> String {
$name$(::<$($T),*>)*::type_name()
}
}
}
}
impl<'a, T: TypeInfo + ?Sized> TypeInfo for &'a T {
fn type_name() -> String {
let mut res = String::from("&");
res.push_str(&T::type_name());
res
}
fn type_of(&self) -> String {
<&T>::type_name()
}
}
impl<'a, T: TypeInfo + ?Sized> TypeInfo for &'a mut T {
fn type_name() -> String {
let mut res = String::from("&mut ");
res.push_str(&T::type_name());
res
}
fn type_of(&self) -> String {
<&mut T>::type_name()
}
}
macro_rules! type_of {
($x:expr) => { (&$x).type_of() };
}
Let's use it:
impl_type_info!(i32, i64, f32, f64, str, String, Vec<T>, Result<T,S>)
fn main() {
println!("{}", type_of!(1));
println!("{}", type_of!(&1));
println!("{}", type_of!(&&1));
println!("{}", type_of!(&mut 1));
println!("{}", type_of!(&&mut 1));
println!("{}", type_of!(&mut &1));
println!("{}", type_of!(1.0));
println!("{}", type_of!("abc"));
println!("{}", type_of!(&"abc"));
println!("{}", type_of!(String::from("abc")));
println!("{}", type_of!(vec![1,2,3]));
println!("{}", <Result<String,i64>>::type_name());
println!("{}", <&i32>::type_name());
println!("{}", <&str>::type_name());
}
output:
i32
&i32
&&i32
&mut i32
&&mut i32
&mut &i32
f64
&str
&&str
String
Vec<i32>
Result<String,i64>
&i32
&str
Rust Playground
UPD The following does not work anymore. Check Shubham's answer for correction.
Check out std::intrinsics::get_tydesc<T>(). It is in "experimental" state right now, but it's OK if you are just hacking around the type system.
Check out the following example:
fn print_type_of<T>(_: &T) -> () {
let type_name =
unsafe {
(*std::intrinsics::get_tydesc::<T>()).name
};
println!("{}", type_name);
}
fn main() -> () {
let mut my_number = 32.90;
print_type_of(&my_number); // prints "f64"
print_type_of(&(vec!(1, 2, 4))); // prints "collections::vec::Vec<int>"
}
This is what is used internally to implement the famous {:?} formatter.
Update, original answer below
How about trait function type_name, which is useful to get type name quickly.
pub trait AnyExt {
fn type_name(&self) -> &'static str;
}
impl<T> AnyExt for T {
fn type_name(&self) -> &'static str {
std::any::type_name::<T>()
}
}
fn main(){
let my_number = 32.90;
println!("{}",my_number.type_name());
}
Output:
f64
Original answer
I write a macro type_of!() to debug, which is original from std dbg!().
pub fn type_of2<T>(v: T) -> (&'static str, T) {
(std::any::type_name::<T>(), v)
}
#[macro_export]
macro_rules! type_of {
// NOTE: We cannot use `concat!` to make a static string as a format argument
// of `eprintln!` because `file!` could contain a `{` or
// `$val` expression could be a block (`{ .. }`), in which case the `eprintln!`
// will be malformed.
() => {
eprintln!("[{}:{}]", file!(), line!());
};
($val:expr $(,)?) => {
// Use of `match` here is intentional because it affects the lifetimes
// of temporaries - https://stackoverflow.com/a/48732525/1063961
match $val {
tmp => {
let (type_,tmp) = $crate::type_of2(tmp);
eprintln!("[{}:{}] {}: {}",
file!(), line!(), stringify!($val), type_);
tmp
}
}
};
($($val:expr),+ $(,)?) => {
($($crate::type_of!($val)),+,)
};
}
fn main(){
let my_number = type_of!(32.90);
type_of!(my_number);
}
Output:
[src/main.rs:32] 32.90: f64
[src/main.rs:33] my_number: f64
** UPDATE ** This has not been verified to work any time recently.
I put together a little crate to do this based off vbo's answer. It gives you a macro to return or print out the type.
Put this in your Cargo.toml file:
[dependencies]
t_bang = "0.1.2"
Then you can use it like so:
#[macro_use] extern crate t_bang;
use t_bang::*;
fn main() {
let x = 5;
let x_type = t!(x);
println!("{:?}", x_type); // prints out: "i32"
pt!(x); // prints out: "i32"
pt!(5); // prints out: "i32"
}
You can also use the simple approach of using the variable in println!("{:?}", var). If Debug is not implemented for the type, you can see the type in the compiler's error message:
mod some {
pub struct SomeType;
}
fn main() {
let unknown_var = some::SomeType;
println!("{:?}", unknown_var);
}
(playpen)
It's dirty but it works.
There's a #ChrisMorgan answer to get approximate type ("float") in stable rust and there's a #ShubhamJain answer to get precise type ("f64") through unstable function in nightly rust.
Now here's a way one can get precise type (ie decide between f32 and f64) in stable rust:
fn main() {
let a = 5.;
let _: () = unsafe { std::mem::transmute(a) };
}
results in
error[E0512]: cannot transmute between types of different sizes, or dependently-sized types
--> main.rs:3:27
|
3 | let _: () = unsafe { std::mem::transmute(a) };
| ^^^^^^^^^^^^^^^^^^^
|
= note: source type: `f64` (64 bits)
= note: target type: `()` (0 bits)
Update
The turbofish variation
fn main() {
let a = 5.;
unsafe { std::mem::transmute::<_, ()>(a) }
}
is slightly shorter but somewhat less readable.
Some other answers don't work, but I find that the typename crate works.
Create a new project:
cargo new test_typename
Modify the Cargo.toml
[dependencies]
typename = "0.1.1"
Modify your source code
use typename::TypeName;
fn main() {
assert_eq!(String::type_name(), "std::string::String");
assert_eq!(Vec::<i32>::type_name(), "std::vec::Vec<i32>");
assert_eq!([0, 1, 2].type_name_of(), "[i32; 3]");
let a = 65u8;
let b = b'A';
let c = 65;
let d = 65i8;
let e = 65i32;
let f = 65u32;
let arr = [1,2,3,4,5];
let first = arr[0];
println!("type of a 65u8 {} is {}", a, a.type_name_of());
println!("type of b b'A' {} is {}", b, b.type_name_of());
println!("type of c 65 {} is {}", c, c.type_name_of());
println!("type of d 65i8 {} is {}", d, d.type_name_of());
println!("type of e 65i32 {} is {}", e, e.type_name_of());
println!("type of f 65u32 {} is {}", f, f.type_name_of());
println!("type of arr {:?} is {}", arr, arr.type_name_of());
println!("type of first {} is {}", first, first.type_name_of());
}
The output is:
type of a 65u8 65 is u8
type of b b'A' 65 is u8
type of c 65 65 is i32
type of d 65i8 65 is i8
type of e 65i32 65 is i32
type of f 65u32 65 is u32
type of arr [1, 2, 3, 4, 5] is [i32; 5]
type of first 1 is i32
If your just wanting to know the type of your variable during interactive development, I would highly recommend using rls (rust language server) inside of your editor or ide. You can then simply permanently enable or toggle the hover ability and just put your cursor over the variable. A little dialog should come up with information about the variable including the type.
This is simplified version of #Boiethios answer. I have removed some '&' symbols from original solution.
fn print_type_of<T>(_: T) {
println!("{}", std::any::type_name::<T>())
}
fn main() {
let s = "Hello";
let i = 42;
print_type_of(s); // &str
print_type_of(i); // i32
print_type_of(main); // playground::main
print_type_of(print_type_of::<i32>); // playground::print_type_of<i32>
print_type_of(|| "Hi!" ); // playground::main::{{closure}}
}
View in Rust Playground
Newly added in version 1.38 std::any::type_name
use std::any::type_name;
fn type_of<T>(_: T) -> &'static str {
type_name::<T>()
}
fn main() {
let x = 21;
let y = 2.5;
println!("{}", type_of(&y));
println!("{}", type_of(x));
}
short story;
fn tyof<T>(_: &T) -> String {
std::any::type_name::<T>().into()
}
long story;
trait Type {
fn type_of(&self) -> String;
}
macro_rules! Type {
($($ty:ty),*) => {
$(
impl Type for $ty {
fn type_of(&self) -> String {
stringify!($ty).into()
}
}
)*
}
}
#[rustfmt::skip]
Type!(
u8, i8, u16, i16, u32, i32, i64, u64, i128, String, [()], (), Vec<()>, &u8, &i8, &u16, &i16, &u32, &i32, &i64, &u64, &i128, &str, &[()], &Vec<()>, &()
// add any struct, enum or type you want
);
macro_rules! tyof {
($var: expr) => {{
$var.type_of()
}};
}
fn main() {
let x = "Hello world!";
println!("{}", tyof!(x));
// or
println!("{}", x.type_of());
let x = 5;
println!("{}", tyof!(x));
// or
println!("{}", x.type_of());
}
Macro form permits an usage "everywhere" while the function need an object to be parse.
Macro form (one liner):
macro_rules! ty {($type:ty) => {std::any::type_name::<$type>()}}
Macro form formated:
macro_rules! ty {
($type:ty) => {
std::any::type_name::<$type>()
};
}
Function form (borrowing is to not destroy the parsed var):
fn type_of<T>(_: &T) -> &'static str {std::any::type_name::<T>()}
fn type_of<T>(_: &T) -> &'static str {
std::any::type_name::<T>()
}
Example:
macro_rules! ty {($type:ty) => {std::any::type_name::<$type>()}}
fn type_of<T>(_: &T) -> &'static str {std::any::type_name::<T>()}
struct DontMater<T>(T);
impl<T: std::fmt::Debug> std::fmt::Debug for DontMater<T> {
fn fmt(&self, fmt: &mut std::fmt::Formatter<'_>) -> std::fmt::Result {
fmt.write_fmt(format_args!("DontMater<{}>({:?})", ty!(T), self.0))
}
}
fn main() {
type µ = [Vec<String>; 7];
println!("{:?}", DontMater(5_usize));
println!("{:?}", DontMater("¤"));
println!("{}", ty!(char));
println!("{:?}", ty!(µ));
println!("{}", type_of(&DontMater(72_i8)));
println!("{:?}", type_of(&15_f64));
}
Returns:
DontMater<usize>(5)
DontMater<&str>("¤")
char
"[alloc::vec::Vec<alloc::string::String>; 7]"
env_vars::DontMater<i8>
"f64"
I like previous answer by #Coautose very much, but in case anyone wants just the type name without the namespace, for example C instead of a::b::C, here is a modified version of the macro that appears to work as intended:
macro_rules! ty {
($type:ty) => {{
let result = std::any::type_name::<$type>();
match result.rsplit_once(':') {
Some((_, s)) => s,
None => result,
}
}};
}
Usage:
debug!("Testing type name: {}", ty!(A));
Better to use this:
fn print_type_of<T>(_: &T) -> String {
format!("{}", std::any::type_name::<T>())
}
fn main() {
let s = &"hello world".to_string();
let cloned_s = s.clone();
println!("{:?}", print_type_of(&s));
println!("{:?}", print_type_of(&cloned_s));
}
Taken inference from https://stackoverflow.com/a/29168659/6774636

Using * to dereference custom type implemented Deref trait raise error [duplicate]

Code:
use std::collections::HashSet;
use std::{mem, ptr, fmt};
use std::ops::Deref;
enum Unsafety {
Normal
}
enum ImplPolarity { Positive }
struct TraitRef;
struct Ty;
struct ImplItem;
enum ItemKind {
Impl(Unsafety,
ImplPolarity,
Option<TraitRef>, // (optional) trait this impl implements
Box<Ty>, // self
),
}
struct Item {
node: ItemKind,
}
pub struct P<T: ?Sized> {
ptr: Box<T>
}
impl<T: 'static> P<T> {
pub fn unwrap(self) -> T {
*self.ptr
}
}
impl<T: ?Sized> Deref for P<T> {
type Target = T;
fn deref(&self) -> &T {
&self.ptr
}
}
fn main() {
let mut items = Vec::<P<Item>>::new();
let mut item2: Item;
for item in items.drain(..) {
if let ItemKind::Impl(Unsafety::Normal,
ImplPolarity::Positive,
Some(ref trait_type),
ref for_type) = item.node {
} else {
// item2 = *item; // AAA
item2 = item.unwrap(); // BBB
}
}
}
Produce the compile-time error:
error[E0505]: cannot move out of `item` because it is borrowed
--> /home/xxx/.emacs.d/rust-playground/at-2017-07-29-204629/snippet.rs:64:21
|
61 | ref for_type) = item.node {
| ---- borrow of `item` occurs here
...
64 | item2 = item.unwrap();
I do not understand two things:
Why does it complain about the borrow in the if branch while we in else branch? They are supposed to be mutually exclusive, and a borrow in one should not influence another.
If I replace Vec in let mut items = Vec::<P<Item>>::new(); with Vec<Box<Item>> and uncomment line AAA and comment line BBB, then it compiles. Both Box and P implement Deref, so the item.node expression should be the same.
Here's a much clearer example:
struct Item;
struct P<T> {
ptr: Box<T>,
}
impl<T> P<T> {
fn new(v: T) -> Self {
P { ptr: Box::new(v) }
}
}
impl<T> std::ops::Deref for P<T> {
type Target = T;
fn deref(&self) -> &T {
&self.ptr
}
}
fn main() {
let mut item = P::new(Item);
// let mut item = Box::new(Item);
*item;
}
Both Box and P implement Deref, so the item.node expression should be the same.
Hard truth time: moving out of Box is special-cased in the compiler. It does not use Deref. Moving out of a Box deallocates the memory and gives you ownership. It is not possible to implement this special ability ourselves.
Maybe at some point in the future a hypothetical trait like DerefMove will be added. This trait is hard to get right. There have been a number of attempts for an RFC for it, but none are currently open.
See also:
Dereferencing Box<T> gives back value instead of reference
How can I reuse a box that I have moved the value out of?

Cannot create a generic function that transmutes a slice of bytes into an integer because the size is not known at compile time

I'm trying to create a generic function that transmutes a slice of bytes into an integer.
fn i_from_slice<T>(slice: &[u8]) -> Option<T>
where
T: Sized,
{
match slice.len() {
std::mem::size_of::<T>() => {
let mut buf = [0; std::mem::size_of::<T>()];
buf.copy_from_slice(slice);
Some(unsafe { std::mem::transmute_copy(&buf) })
}
_ => None,
}
}
Rust won't let me do that:
error[E0532]: expected tuple struct/variant, found function `std::mem::size_of`
--> src/lib.rs:6:9
|
6 | std::mem::size_of::<T>() => {
| ^^^^^^^^^^^^^^^^^^^^^^ not a tuple struct/variant
error[E0277]: the size for values of type `T` cannot be known at compilation time
--> src/lib.rs:7:31
|
7 | let mut buf = [0; std::mem::size_of::<T>()];
| ^^^^^^^^^^^^^^^^^^^^^^ doesn't have a size known at compile-time
|
= help: the trait `std::marker::Sized` is not implemented for `T`
= note: to learn more, visit <https://doc.rust-lang.org/book/ch19-04-advanced-types.html#dynamically-sized-types-and-the-sized-trait>
= help: consider adding a `where T: std::marker::Sized` bound
= note: required by `std::mem::size_of`
Is there a way that I can statically know the size of T?
If your T is an integer, you don't need any unsafe code, since there is from_ne_bytes.
If you absolutely want a generic function, you can add a trait:
use std::convert::TryInto;
trait FromBytes: Sized {
fn from_ne_bytes_(bytes: &[u8]) -> Option<Self>;
}
impl FromBytes for i32 {
fn from_ne_bytes_(bytes: &[u8]) -> Option<Self> {
bytes.try_into().map(i32::from_ne_bytes).ok()
}
}
// Etc. for the other numeric types.
fn main() {
let i1: i32 = i_from_slice(&[1, 2, 3, 4]).unwrap();
let i2 = i32::from_ne_bytes_(&[1, 2, 3, 4]).unwrap();
assert_eq!(i1, i2);
}
// This `unsafe` usage is invalid, but copied from the original post
// to compare the result with my implementation.
fn i_from_slice<T>(slice: &[u8]) -> Option<T> {
if slice.len() == std::mem::size_of::<T>() {
Some(unsafe { std::mem::transmute_copy(&slice[0]) })
} else {
None
}
}
You don't need your intermediate buffer, you can call transmute_copy directly on the input slice. Moreover, as pointed out by #BenjaminLindley in the comments, you need to make sure that you transmute from the first item in the slice and not the fat pointer that is the slice itself:
fn i_from_slice<T>(slice: &[u8]) -> Option<T> {
if slice.len() == std::mem::size_of::<T>() {
Some(unsafe { std::mem::transmute_copy(&slice[0]) })
} else {
None
}
}
Is there a way that i can know statically the size of T?
Yes, you do know the size at compile time. But the size can vary and is not a constant. Instead of using a fixed-size array, you can use a vector which is a contiguous growable array.
Also, Sized is an opt-out marker trait. All type parameters have an implicit Sized bound. You don't need to spell that fact out.
You need a match arm guard to use pattern matching the way you did, but it is more straightforward to use if-else expression here.
All in all, this works:
fn i_from_slice<T>(slice: &[u8]) -> Option<T> {
let n = std::mem::size_of::<T>();
if slice.len() == n {
let mut buf = vec![0; n];
buf.copy_from_slice(slice);
Some(unsafe { std::mem::transmute_copy(&buf) })
} else {
None
}
}

How do I modify the content of a `RefCell<Option<T>>`?

I have an Option<T> that is shared by several structures and that must be mutable. I'm using a RefCell since, as I understand, it is the tool for that job. How do I access (and alter) the content of that Option<T> ?
I tried the following:
use std::cell::RefCell;
#[derive(Debug)]
struct S {
val: i32
}
fn main() {
let rc: RefCell<Option<S>> = RefCell::new(Some(S{val: 0}));
if let Some(ref mut s2) = rc.borrow_mut() {
s2.val += 1;
}
println!("{:?}", rc);
}
But the compiler won't let me do it:
error[E0308]: mismatched types
--> <anon>:10:12
|
10 | if let Some(ref mut s2) = rc.borrow_mut() {
| ^^^^^^^^^^^^^^^^ expected struct `std::cell::RefMut`, found enum `std::option::Option`
|
= note: expected type `std::cell::RefMut<'_, std::option::Option<S>, >`
found type `std::option::Option<_>`
When you borrow_mut the RefCell, you get a RefMut, as the compiler says. To get the value inside it, just use the operator deref_mut:
use std::cell::RefCell;
#[derive(Debug)]
struct S {
val: i32
}
fn main() {
let rc: RefCell<Option<S>> = RefCell::new(Some(S{val: 0}));
if let Some(ref mut s2) = *rc.borrow_mut() { // deref_mut
s2.val += 1;
}
println!("{:?}", rc);
}

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