I want to set csv files to open in a windows program thru Wine when I click on any csv file.
I use ROX 2.10 filemgr and have Set run action as:
' wine "/home/name/.wine/drive_c/Program Files/dbEdit/dbedit.exe" "z:$#" '
This causes the error of:
Z:\home\name\Documents\ZipCodes.csv\ZipCodes.csv
I thus far am unable to correct the double ZipCodes.csv, which doesn't exist.
Placing either slash following Z: or capitalizing the Z makes no difference in the error
Also, I had tried to Set run action as:
' wine "/home/name/.wine/drive_c/Program Files/dbEdit/dbedit.exe" "$#" '
which causes the error of:
Z:\ZipCodes.csv, which also doesn't exist at location
So does anyone know the proper syntax to be used to correct the error?
Obviously the best fix would be find a simple Linux database program to use, but I like the simplicity of the dbedit program.
Related
I am playing around with the basics of VBS and have a very simple Visual Basic script which executes a file using shell.
I am using Excel under Windows 10.
Sub Whatever()
Dim Example_One As String
Example_One = "C:\Users\IEUser\python-3.8.0.exe"
Shell Example_One, vbNormalFocus
End Sub
The weird thing is that some files will run (e.g. Python as above) while others e.g. VLC, WinRAR give the error: Run time error 5: Invalid procedure call or argument.
I simply cannot figure out why some .exe files will run and others will not. I thought it might be something to do with how the installation works but ChromeSetup.exe works while VLC.exe does not (even though they both ask "Do you want this app to make changes to your device?" (Python has it's own installer). Double-clicking all files in Windows Explorer runs them as normal (they don't ask for any special rights).
Working with Pure Data, trying to record audio output from a patch I've made, and am 1) unable to create a file within pure data to write to and 2) attempting to use the writesf~ object causes the program to freeze after about two to three seconds. I suspect the two things are related- perhaps the program is attempting to write data somewhere, somehow, but it's going in the wrong place or some such and causing the program to freeze?
I've uninstalled the latest Pure Data release (0.51-1) and installed an earlier stable release (0.5-2) and even tried an alternative called "purr data (latest release)" all with the exact same result on my windows 10 acer laptop: no file created, and program freezes after a few seconds.
I'm testing with this patch:
I first click on the message that reads "open rec.wav" then the start then the stop, and if I take longer than three or so seconds to click on "stop" the program freezes, otherwise nothing at all happens.
I have performed system wide search for the audio file, including the folder that the patch is in, all to no avail.
Any trouble shooting hints will be carefully attempted.
Are you sure you have write-permissions on the target directory?
If your example you use rec.wav which has no explicit target directory (and is just using the "current", so it's hard to tell from outside what this directory would be).
#max-n's answer suggests to use /tmp/foo.wav which is an illegal directory on Windows. Due to a known bug, using an illegal (or otherwise non-writable) path will lock up Pd.
If your "current" directory happens to be your system root (aka C:\), you might well lack the permissions to write there.
You could check by starting the Pd from the cmdline and see whether the terminal spits out any weird errors:
⊞ Win+R
type cmd and hit Enter
in the opening terminal type the full path to your Pd-executable, e.g.:
C:\Program Files\Pd\bin\pd + Enter
(ideally leave out the extension (that is: use .../pd rather than .../pd.exe)
If the problem is indeed a permission problem, you can simply work around it by specifying the full path of the output file (and make sure that it is in a writable directory).
The easiest way to do this is by using a file-selector to choose the output file:
[bang(
|
[savepanel]
|
[open $1(
|
[writesf~]
There might be a reason why the helpfile uses a [delay 1000] to schedule a stop message in a predefined time.
Is there a way to make Excel ignore certain command line arguments? I am launching via a command similar to:
Excel "C:\Temp\TestingCLAs.xlsx" /e service=http://localhost:61023/api/PortlandDev/2/ReportSource?Order='100146309'^&Line='0010'
The service string gets read by some VBA in the Excel file and is used to update a query. However, when I launch Excel the command line argument interpreter see's two things:
Open "C:\Temp\TestingCLASs.xlsx"
Open service=http://....
I would like the interpreter to ignore the second argument, however I get the following error when opening:
"Sorry, we couldn't find
service=http://localhost:61023/api/PortlandDev/2/ReportSource?Order='100146309'&Line='0010'.xlsx.
Is it possible it was moved, renamed or deleted?
I know this isn't due to the VBA within the excel file because it happens even when testing with a blank excel file.
I found this reference article: https://blogs.msdn.microsoft.com/twistylittlepassagesallalike/2011/04/23/everyone-quotes-command-line-arguments-the-wrong-way/ and tried to escape the URL with a '^' character but, got the same result.
Also looking at the error above, a .xlsx is tacked on to the end of the second URL above when it wasn't specified in the initial call.
Is there a way to make the command interpreter not try to execute the URL?
Any ideas are very much appreciated. Thanks
Not sure why it works but passing a "/p" switch makes it so that the command interpreter does not try to automatically open the URL. For example, the following can be consumed by my internal VBA without the command interpreter trying to create a new workbook from the URL.
Excel "C:\Temp\Template.xlsm" /e /p http://localhost:61023/api/PortlandDev/2/ReportSource?Order='100142574'&Line='0010'
When running an interactive session, PyCharm thinks of os.getcwd() as my project's directory. However, when I run my script from the command line, PyCharm thinks of os.getcwd() as the directory of the script.
Is there a good workaround for this? Here is what I tried and did not like:
going to Run/Edit Configurations and changing the working directory manually. I did not like this solution, because I will have to do it for every script that I run.
having one line in my code that "fixes" the path for the purposes of interactive sessions and commenting it out before running from command line. This works, but feels wrong.
Is there a way to do this or is it just the way it is supposed to be? Maybe I shouldn't be trying to run random scripts within my project?
Any insight would be greatly appreciated.
Clarification:
By "interactive session" I mean being able to run each line individually in a Python/IPython Console
By "running from command line" I mean creating a script my_script.py and running python path_to_myscript/my_script.py (I actually press the Run button at PyCharm, but I think it's the same).
Other facts that might prove worth mentioning:
I have created a PyCharm project. This contains (among other things) the package Graphs, which contains the module Graph and some .txt files. When I do something within my Graph module (e.g. read a graph from a file), I like to test that things worked as expected. I do this by running a selection of lines (interactively). To read a .txt file, I have to go (using os.path.join()) from the current working directory (the project directory, ...\\project_name) to the module's directory ...\\project_name\\Graphs, where the file is located. However, when I run the whole script via the command line, the command reading the .txt file raises an Error, complaining that no file was found. By looking on the name of the file that was not found, I see that the full file name is something like this:
...\\project_name\\Graphs\\Graphs\\graph1.txt
It seems that this time the current working directory is ...\\project_name\\Graphs\\, and my os.path.join() command actually spoils it.
I user various methods in my python scripts.
set the working directory as first step of your code using os.chdir(some_existing_path)
This would mean all your other paths should be referenced to this, as you hard set the path. You just need to make sure it works from any location and your specifically in your IDE. Obviously, another os.chdir() would change the working directory and os.getcwd() would return the new working directory
set the working directory to __file__ by using os.chdir(os.path.dirname(__file__))
This is actually what I use most, as it is quite reliable, and then I reference all further paths or file operations to this. Or you can simply refer to as os.path.dirname(__file__) in your code without actually changing the working directory
get the working directory using os.getcwd()
And reference all path and file operations to this, knowing it will change based on how the script is launched. Note: do NOT assume that this returns the location of your script, it returns the working directory of the shell !!
[EDIT based on new information]
By "interactive session" I mean being able to run each line
individually in a Python/IPython Console
By running interactively line-by-line in a Python console, the __file__ is not defined, afterall: you are not executing a file. Hence you cannot use os.path.dirname(__file__) you will have to use something like os.chdir(some_known_existing_dir) to reference a path. As a programmer you need to be very aware of working directory and changes to this, your code should reflect that.
By "running from command line" I mean creating a script my_script.py
and running python path_to_myscript/my_script.py (I actually press the
Run button at PyCharm, but I think it's the same).
This, both executing a .py from command line as well as running in your IDE, will populate the __file__, hence you can use os.path.dirname(__file__)
HTH
I am purposely adding another answer to this post, in regards the following:
Other facts that might prove worth mentioning:
I have created a PyCharm project. This contains (among other things)
the package Graphs, which contains the module Graph and some .txt
files. When I do something within my Graph module (e.g. read a graph
from a file), I like to test that things worked as expected. I do this
by running a selection of lines (interactively). To read a .txt file,
I have to go (using os.path.join()) from the current working directory
(the project directory, ...\project_name) to the module's directory
...\project_name\Graphs, where the file is located. However, when I
run the whole script via the command line, the command reading the
.txt file raises an Error, complaining that no file was found. By
looking on the name of the file that was not found, I see that the
full file name is something like this:
...\project_name\Graphs\Graphs\graph1.txt It seems that this time
the current working directory is ...\project_name\Graphs\, and my
os.path.join() command actually spoils it.
I strongly believe that if a python script takes input from any file, that the author of the script needs to cater for this in the script.
What I mean is you as the author need to make sure you know the following regardless of how your script is executed:
What is the working directory
What is the script directory
These two you have no control over when you hand off your script to others, or run it on other peoples machines. The working directory is dependent on how the script is launched. It seems that you run on Windows, so here is an example:
C:\> c:\python\python your_script.py
The working directory is now C:\ if your_script.py is in C:\
C:\some_dir\another_dir\> c:\python\python.exe c:\your_script_dir\your_script.py
The working directory is now C:\some_dir\another_dir
And the above example may even give different results if the SYSTEM PATH variable is set to the path of the location of your_script.py
You need to ensure that your script works even if the user(s) of your script are placing this in various locations on their machines. Some people (and I don't know why) tend to put everything on the Desktop. You need to ensure your script can cope with this, including any spaces in the path name.
Furthermore, if your script is taking input from a file, the you as the author need to ensure that you can cope with changes in working directory, and changes of script directory. There are a few things you may consider:
Have your script input from a known (static) directory, something like C:\python_input\
Have your script input from a known (configurable) directory, use ConfigParser, you can search here on stackoverflow on many posts
Have your script input from a known directory related to the location of the script (using os.path.dirname(__file__))
any other method you may employ to ensure your script can get to the input
Ultimately this is all in your control, and you need to code to ensure it is working.
HTH,
Edwin.
I am writing a program that handles some data on a server. Throughout the program, many files are made and sent as input into other programs. To do this, I usually make the command string, then run it like so:
cmd = "prog input_file1 input_file2 > outputfile"
os.system(cmd)
When I run the command, however, the programs being called report that they cannot open the files. If I run the python code on my local computer, it is fine. When I loaded it onto the server, it started to fail. I think this is related to issues with permissions, but am not sure how I can fix this. Many of the files, particularly the output files, are being created at run time. The input files have full permissions for all users. Any help or advice would be appreciated!
Cheers!
The python code you list is simple and correct, so the problem is likely not in the two lines of your example. Here are some related areas for you to check out.
Permissions
The user running the python script must have the appropriate permission (read, write, execute). I see from comments that you've already checked this.
What command are you running
If the command is literally typed into your source code like in the example, then you know what command is being run, but if you are generating any part of it (eg. the list of operands, the name of the output file, other parameters, etc), make sure there are no bugs in the portions of your code that generate the command. For example before the call to os.system(cmd) consider including a line like print("About to execute: " + cmd) so you can see exactly what will be run.
Directly invoke the command
If all the above looks good, try to execute the command directly at a terminal on your server. What output do you get then. It's possible that the problem is with the underlying command itself rather than your python code.