Azure Blob Storage .uploadStream() not uploading more than 42 bytes - node.js

Question

I am trying to upload a video from my azure VM to azure blob storage with #azure/storage-blob and using .uploadStream(), but it is not uploading more than 42 bytes
progress { loadedBytes: 42 }
even though the file is 5.7 kb
-rw-r--r-- 1 root root 5.7K Oct 11 10:33 345009243
My upload code is like this
const { BlobServiceClient, StorageSharedKeyCredential } = require("#azure/storage-blob");
const dotenv = require('dotenv');
const getStream = require('into-stream');
//import getStream from 'into-stream'
dotenv.config();
const account = process.env.STORAGE_ACCOUNT;
const accountKey = process.env.ACCOUNT_KEY;
const sharedKeyCredential = new StorageSharedKeyCredential(account, accountKey);
const blobServiceClient = new BlobServiceClient(
`https://${account}.blob.core.windows.net`,sharedKeyCredential
);
const containerName = process.env.CONTAINER_NAME;
const uploadFile = async(filePath,filename) => {
const containerClient = blobServiceClient.getContainerClient(containerName);
const blobName = "vimeoVedio" + new Date().getTime();
const blockBlobClient = containerClient.getBlockBlobClient(blobName);
const buffer = Buffer.from(filePath);
const stream = getStream(buffer);
const streamLenght = (1 * 1024 * 1024) / 2;
const uploadBlobResponse = await blockBlobClient.uploadStream(stream,streamLenght, 400, {
// abortSignal: AbortController.timeout(30 * 60 * 1000), // Abort uploading with timeout in 30mins
onProgress: (ev) => {console.log("progress", ev)},
blobHTTPHeaders: {blobContentType: filename.mimeType}
});
return Promise.resolve(`Upload block blob ${blobName} successfully`, uploadBlobResponse.requestId);
}
module.exports = {uploadFile}
I tried this upload with multiple different files with different file sizes but it still is only uploading 42 bytes

Answer 1

I believe the issue is in this line of code:
const buffer = Buffer.from(filePath);
What you are doing here is creating a buffer from a string representing the file path (e.g. C:\temp\myfile.txt) instead of the actual file contents.
You would want to use fs module and read the contents of the file using something like fs.readFile(path[, options], callback) or fs.readFileSync(path\[, options\]). Once you do that, you should be able to upload the file properly.