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I am new to excel please help me.
So the situation is we have two contact no column
contact no contact no 1
9864573828 0145883
9834765849 1923832
018294 9876547834
i want to merge two column into 1 having contact no of 10 digit.
contact no
9864573828
9834765849
9876547834
I'm using Excel 2013
In Excel 2013 this formula can be used to list the 10 digit numbers from the first and second range without gaps:
=IFERROR(IFERROR(INDEX(A:A,AGGREGATE(15,6,ROW(A:A)/(LEN(A:A)=10)/(ISNUMBER(--A:A)),ROW(1:1))),INDEX(B:B,AGGREGATE(15,6,ROW(B:B)/(LEN(B:B)=10)/(ISNUMBER(--B:B)),ROW(1:1)-SUMPRODUCT((LEN(A:A)=10)*(ISNUMBER(--A:A)))))),"")
It uses a lot of resources to calculate, so whole column references is highly discouraged. So use actual ranges instead like:
=IFERROR(
IFERROR(
INDEX(A:A,
AGGREGATE(15,6,
ROW($A$2:$A$5)
/(LEN($A$2:$A$5)=10)
/(ISNUMBER(--$A$2:$A$5)),
ROW(1:1))),
INDEX(B:B,
AGGREGATE(15,6,
ROW($B$2:$B$5)
/(LEN($B$2:$B$5)=10)
/(ISNUMBER(--$B$2:$B$5)),
ROW(1:1)
-SUMPRODUCT(
(LEN($A$2:$A$5)=10)
*(ISNUMBER(--$A$2:$A$5)))))),
"")
Note: I think (unable to verify myself) the formula needs entered with ctrl+shift+enter to make it an array formula.
What this formula does is get the first row of the first range where the string length is 10 and the string converted to a number does not produce an error (what would happen in case of text characters in the string).
When you drag down the formula it shows the second found, third, etc... until no values are found in the first range anymore.
In that case the IFERROR makes it look for the same logic in the second range.
As we want it to show the first found value first, we can't reset the ROW(1:1) * - that is used as a counter for the first smallest, second smallest, etc.. - * therefore we use the same counter and use SUMPRODUCT to subtract the total number of strings meeting the conditions in the first range. That way the counter will start at 1 for the second range and starts counting from there.
If no more values are found in the second range it will show a blank value.
So you can drag down the formula up to the first blank result to show each result.
It's probably still slow with actual range references. I highly advise to upgrade to Office 365.
Try the following formula-
=LET(x,TOCOL(A2:B13,1),FILTER(x,LEN(x)=10))
Since your excel version doesn't support TOCOL() and some other formulas you can use this simple solution:
=IF(LEN(A2)=10,A2,IF(LEN(B2)=10,B2,""))
Put it in C2 and drag id down for a result:
Since you didn't specify what to do if both columns has 10 digit number or both doesn't, in those cases it will return first 10 digit number or empty string.
I need help in writing a formula in cell b7. The formula must look to the right and multiply the nonempty cells by the corresponding value in row 3, and I would like to sum up the results.
File link provided.
FILE LINK
ScreenShot
Please see my comment to your original post.
That said, I will try to explain how to approach this as I think you intend. (This solution will be a Google Sheets solution which will not work in Excel.)
The first thing you will need to do is to delete everything from Row 11 down: all of your examples and notes must be deleted for the following proposed formula to work correctly.
Once you have no superfluous data below your main chart, delete everything from B6:B (including the header "Total").
Then, place the following formula in cell B6:
={"TOTAL"; FILTER(MMULT(C7:G*1, TRANSPOSE(C$3:G$3*1)), A7:A<>"")}
This formula will return the header text "TOTAL" (which you can change within the formula itself if you like) followed by the calculation you want for each row where a name is listed in A7:A.
MMULT is a difficult function to explain, but it multiplies one matrix ("grid") or numbers by another matrix ("grid") and returns the sum of all products per row (or per column, depending on how you set it up) —— which is what you are trying to do.
MMULT must have every element of both matrices be a real number. To convert potential nulls to zeroes, you'll see *1 appended to each range (since null times 1 is zero).
This assumes that all data entered into C7:G and C3:G3 will always be either a number or null. If you enter text, you'll throw the formula into an error. If you think accidental text entries in those ranges are possible, use this version instead:
={"TOTAL"; FILTER(MMULT(IFERROR(C7:G*1, ROW(C7:G)*0), TRANSPOSE(IFERROR(C$3:G$3*1, COLUMN(C$3:G$3)*0))), A7:A<>"")}
The extra bits use IFERROR to exchange error-producing entries with zeroes, since MMULT must have every space in both matrices filled with a real number.
I am trying to create a formula that checks for several things at the same time but I am having trouble with one part of it.
The formula is the following:
=IF(COUNTIFS($N$2:$N$17095,N3,$K$2:$K$17095,"<>"&"")>6,
IF((SUMPRODUCT(--(ROUND($K$2:$K$49,2)=ROUND(K3,2)))>9),"Always Late / Possible Automation",
IF(COUNTIFS($N$2:$N$17088,N3,$K$2:$K$17088,"<3.5")>0,"Delivered Earlier At Least Once",IF(COUNTIFS($N$2:$N$17088,N3,$K$2:$K$17088,">3.5")>6,"Always Late","False"))))
The first part checks how many entries in the range having the same value as it is in cell N3 have values different to blank and we want those to be more than 6.
Second part is the tough one, it is supposed to check how many values in the rounded range match the rounded value in cell K3. The issue is the formula checks the whole range and I want to check only for the values which match N3 (in essence like the CountIf works only for that value).
The rest is not so relevant.
Some example data:
![enter image description here][1]
As you see in the end of the table the formula with the rounding works but only because I have limited the data shown to 3 unique values in column N. Even here though if i have a blank it doesnt work becaus ei haven't considered it.
Thanks in advance.
Assuming you have Office 365 compatibility/Excel version, use a bunch of filters. To avoid an unwieldy formula I've extended ranges to maximum number of rows (customize as required)...
=LET(x_,$E$3:$E$25,a_,FILTER($E$3:$E$25,--(x_=E3)),b_,FILTER($B$3:$B$25,--(x_=E3)),IF(SUM(--(a_=E3)*(b_<>""))>6,IF((SUMPRODUCT(--(ROUND(b_,2)=ROUND(B3,2)))>9),"Always Late / Possible Automation",IF(SUM(--(a_=E3)*(b_<3.5))>0,"Delivered Earlier At Least Once",IF(SUM(--(a_=E3)*(b_>3.5))>6,"Always Late","False")))))
Note: filter does not appear to work too well within countifs for some reason (must be related to syntax RE: arrays vs. criteria TBC). Thus have replaced countifs(filter_range,X) eqn 'types' with sum(--(filter_range=X)) which works as intended.
I am trying to convert text of the month to the number
B2 cell:
BirthMonth_Jan
BirthMonth_Feb
BirthMonth_mar
BirthMonth_Apr
BirthMonth_May
BirthMonth_Jun, ect to december
for example, BirthMonth_Jan will output 1 based on the search of Jan, so i can compare this to another set of numbers
I have this, and tried this, but only works with two if statements, is there anyway i can do this with 12?
=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
I get #Value!
If i try this, it also doesn't work
=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
the second option only works with two but if i add more it throws an error
The questioner is trying to obtain a numeral equivalent to a partial month name extracted from a string. There are any number of examples in stackoverflow and the net generally on this theme. What is special in this case is the partial month name in the target cell, and use of the IF statement. The questioner is right to use search since it is not case-sensitive
Two formula are offered:
Formula 1
=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
The questioner said "I get #Value!"
This is not a surprise because it is essentially a series of nine, self-contained, unrelated if statements, each separated by a comma. It is an invalid statement.
However, if the if statements were nested, then the formula would work. Something along these lines:
=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3")))
Formula 2
=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
So close and yet so far... This statement uses the nested approach mentioned above. There is a major typo for the October search (instead of searching for "oct", the formula searches for "DSH_KnowBe4_BirthMonth_Oc") though this doesn't cause the formula to fail.
Failure is caused by two things:
1) The double bracket following "11")) in the "November" search. There should be zero brackets here.
2) The formula needs an additional closing bracket.
Two other things to note:
1) in the event of a match, the value returned is a string not an integer.
2) there's no provision to return a value in the event of a failure to match.
Working IF statement formula
The following formula, consisting of nested IF statements, works as intended by the questioner.
=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3",IF(ISNUMBER(SEARCH("apr",B2)),"4",IF(ISNUMBER(SEARCH("may",B2)),"5",IF(ISNUMBER(SEARCH("jun",B2)),"6",IF(ISNUMBER(SEARCH("jul",B2)),"7",IF(ISNUMBER(SEARCH("aug",B2)),"8",IF(ISNUMBER(SEARCH("sep",B2)),"9",IF(ISNUMBER(SEARCH("oct",B2)),"10",IF(ISNUMBER(SEARCH("nov",B2)),"11",IF(ISNUMBER(SEARCH("dec",B2)),"12",NA()))))))))))))
Note, the formula uses the NA() function to return #N/A if there is no match.
VLOOKUP alternative
Though the above-mentioned formula works, I find it complicated and inflexible. My preference in situations like this is VLOOKUP. My equivalent formula would be:
=VLOOKUP(RIGHT(B2,LEN(B2)-SEARCH("_",B2)),Sheet2!$A$2:$B$13,2,FALSE)
Using January as an example: BirthMonth_Jan, the formula lookup works like this:
RIGHT(B2,LEN(B2)-SEARCH("_",B2))
1) search for the underline character SEARCH("_",B2),
2) deduct the result from the total length LEN(B2)-SEARCH("_",B2) to give the number of characters to the right of the underline.
3) get all the characters to the right of the underline RIGHT(B2,LEN(B2)-SEARCH("_",B2)). This is the lookup value
4) Create a reference table on another sheet (refer screenshot); lookup this table and return column 2 (the number for that month).
5) If there is no valid result, VLOOKUP automatically returns #N/A.
The reference table on a separate sheet:
Not sure what you are trying to do with the formula but if your "BirthMonth_" text is consistent, you can use :
=MONTH(DATEVALUE("1 "&SUBSTITUTE(A12,"BirthMonth_","")&" 2018"))
Having a view of your data and expected result would help if this is not what you're after.
It is seems just possible what you might want is:
=MONTH(MID(B2,SEARCH("BirthMonth_",B2)+11,3)&0)
Returns a Number.
Does anyone know the formula to find the value of the last non-empty cell in a column, in Microsoft Excel?
Using following simple formula is much faster
=LOOKUP(2,1/(A:A<>""),A:A)
For Excel 2003:
=LOOKUP(2,1/(A1:A65535<>""),A1:A65535)
It gives you following advantages:
it's not array formula
it's not volatile formula
Explanation:
(A:A<>"") returns array {TRUE,TRUE,..,FALSE,..}
1/(A:A<>"") modifies this array to {1,1,..,#DIV/0!,..}.
Since LOOKUP expects sorted array in ascending order, and taking into account that if the LOOKUP function can not find an exact match, it chooses the largest value in the lookup_range (in our case {1,1,..,#DIV/0!,..}) that is less than or equal to the value (in our case 2), formula finds last 1 in array and returns corresponding value from result_range (third parameter - A:A).
Also little note - above formula doesn't take into account cells with errors (you can see it only if last non empty cell has error). If you want to take them into account, use:
=LOOKUP(2,1/(NOT(ISBLANK(A:A))),A:A)
image below shows the difference:
This works with both text and numbers and doesn't care if there are blank cells, i.e., it will return the last non-blank cell.
It needs to be array-entered, meaning that you press Ctrl-Shift-Enter after you type or paste it in. The below is for column A:
=INDEX(A:A,MAX((A:A<>"")*(ROW(A:A))))
Here is another option: =OFFSET($A$1;COUNTA(A:A)-1;0)
I know this question is old, but I'm not satisfied with the answers provided.
LOOKUP, VLOOKUP and HLOOKUP has performance issues and should really never be used.
Array functions has a lot of overhead and can also have performance issues, so it should only be used as a last resort.
COUNT and COUNTA run into problems if the data is not contiguously non-blank, i.e. you have blank spaces and then data again in the range in question
INDIRECT is volatile so it should only be used as a last resort
OFFSET is volatile so it should only be used as a last resort
any references to the last row or column possible (the 65536th row in Excel 2003, for instance) is not robust and results in extra overhead
This is what I use
when the data type is mixed: =max(MATCH(1E+306,[RANGE],1),MATCH("*",[RANGE],-1))
when it's known that the data contains only numbers: =MATCH(1E+306,[RANGE],1)
when it's known that the data contains only text: =MATCH("*",[RANGE],-1)
MATCH has the lowest overhead and is non-volatile, so if you're working with lots of data this is the best to use.
Inspired by the great lead given by Doug Glancy's answer, I came up with a way to do the same thing without the need of an array-formula. Do not ask me why, but I am keen to avoid the use of array formulae if at all possible (not for any particular reason, it's just my style).
Here it is:
=SUMPRODUCT(MAX(($A:$A<>"")*(ROW(A:A))))
For finding the last non-empty row using Column A as the reference column
=SUMPRODUCT(MAX(($1:$1<>"")*(COLUMN(1:1))))
For finding the last non-empty column using row 1 as the reference row
This can be further utilized in conjunction with the index function to efficiently define dynamic named ranges, but this is something for another post as this is not related to the immediate question addressed herein.
I've tested the above methods with Excel 2010, both "natively" and in "Compatibility Mode" (for older versions of Excel) and they work. Again, with these you do not need to do any of the Ctrl+Shift+Enter. By leveraging the way sumproduct works in Excel we can get our arms around the need to carry array-operations but we do it without an array-formula. I hope someone out there may appreciate the beauty, simplicity and elegance of these proposed sumproduct solutions as much as I do. I do not attest to the memory-efficiency of the above solutions though. Just that they are simple, look beautiful, help the intended purpose and are flexible enough to extend their use to other purposes :)
Hope this helps!
All the best!
This works in Excel 2003 (& later with minor edit, see below). Press Ctrl+Shift+Enter (not just Enter) to enter this as an array formula.
=IF(ISBLANK(A65536),INDEX(A1:A65535,MAX((A1:A65535<>"")*(ROW(A1:A65535)))),A65536)
Be aware that Excel 2003 is unable to apply an array formula to an entire column. Doing so yields #NUM!; unpredictable results may occur! (EDIT: Conflicting information from Microsoft: The same may or may not be true about Excel 2007; problem may have been fixed in 2010.)
That's why I apply the array formula to range A1:A65535 and give special treatment to the last cell, which is A65536 in Excel 2003. Can't just say A:A or even A1:A65536 as the latter automatically reverts to A:A.
If you're absolutely sure A65536 is blank, then you can skip the IF part:
=INDEX(A1:A65535,MAX((A1:A65535<>"")*(ROW(A1:A65535))))
Note that if you're using Excel 2007 or 2010, the last row number is 1048576 not 65536, so adjust the above as appropriate.
If there are no blank cells in the middle of your data, then I would just use the simpler formula, =INDEX(A:A,COUNTA(A:A)).
An alternative solution without array formulas, possibly more robust than that of a previous answer with a (hint to a) solution without array formulas, is
=INDEX(A:A,INDEX(MAX(($A:$A<>"")*(ROW(A:A))),0))
See this answer as an example.
Kudos to Brad and barry houdini, who helped solving this question.
Possible reasons for preferring a non-array formula are given in:
An official Microsoft page (look for "Disadvantages of using array formulas").
Array formulas can seem magical, but they also have some disadvantages:
You may occasionally forget to press CTRL+SHIFT+ENTER. Remember to press this key combination whenever you enter or edit an array formula.
Other users may not understand your formulas. Array formulas are relatively undocumented, so if other people need to modify your workbooks, you should either avoid array formulas or make sure those users understand how to change them.
Depending on the processing speed and memory of your computer, large array formulas can slow down calculations.
Array Formula Heresy.
if you search in Column (A) use :
=INDIRECT("A" & SUMPRODUCT(MAX((A:A<>"")*(ROW(A:A)))))
if your range is A1:A10 you can use:
=INDIRECT("A" & SUMPRODUCT(MAX(($A$1:$A10<>"")*(ROW($A$1:$A10)))))
in this formula :
SUMPRODUCT(MAX(($A$1:$A10<>"")*(ROW($A$1:$A10))))
returns last non blank row number ,and indirect() returns cell value.
=INDEX(A:A, COUNTA(A:A), 1) taken from here
=MATCH("*";A1:A10;-1) for textual data
=MATCH(0;A1:A10;-1) for numerical data
Ive tried all the non-volatile versions but Not one version given above has worked.. excel 2003/2007update. Surely this can be done in excel 2003. Not as an array nor standard formula.
I either get just a blank, 0 or #value error.
So I resort to the volatile methods .. This worked..
=LOOKUP(2,1/(T4:T369<>""),T4:T369)
#Julian Kroné .. Using ";" instead of "," does NOT work! I think you are using Libre Office not MS excel?
LOOKUP is so annoyingly volitile I use it as a last resort only
For Microsoft office 2013
"Last but one" of a non empty row:
=OFFSET(Sheet5!$C$1,COUNTA(Sheet5!$C:$C)-2,0)
"Last" non empty row:
=OFFSET(Sheet5!$C$1,COUNTA(Sheet5!$C:$C)-1,0)
Place this code in a VBA module. Save. Under functions, User defined look for This function.
Function LastNonBlankCell(Range As Excel.Range) As Variant
Application.Volatile
LastNonBlankCell = Range.End(xlDown).Value
End Function
for textual data:
EQUIV("";A1:A10;-1)
for numerical data:
EQUIV(0;A1:A10;-1)
This give you the relative index of the last non empty cell in the range selected (here A1:A10).
If you want to get the value, access it via INDIRECT after building -textually- the absolute cell reference, eg:
INDIRECT("A" & (nb_line_where_your_data_start + EQUIV(...) - 1))
I had the same problem too. This formula also works equally well:-
=INDIRECT(CONCATENATE("$G$",(14+(COUNTA($G$14:$G$65535)-1))))
14 being the row number of the first row in the rows you want to count.
Chronic Clawtooth
I used HLOOKUP
A1 has a date;
A2:A8 has forecasts captured at different times, I want the latest
=Hlookup(a1,a1:a8,count(a2:a8)+1)
This uses a standard hlookup formula with the lookup array defined by the number of entries.
If you know that there are not going to be empty cells in between, the fastest way is this.
=INDIRECT("O"&(COUNT(O:O,"<>""")))
It just counts the non-empty cells and refers to the appropriate cell.
It can be used for a specific range as well.
=INDIRECT("O"&(COUNT(O4:O34,"<>""")+3))
This returns the last non empty cell in the range O4:O34.
This formula worked with me for office 2010:
=LOOKUP(2;1/(A1:A100<>"");A1:A100)
A1: the first cell
A100: refer to the last cell in comparing
I think the response from W5ALIVE is closest to what I use to find the last row of data in a column. Assuming I am looking for the last row with data in Column A, though, I would use the following for the more generic lookup:
=MAX(IFERROR(MATCH("*",A:A,-1),0),IFERROR(MATCH(9.99999999999999E+307,A:A,1),0))
The first MATCH will find the last text cell and the second MATCH finds the last numeric cell. The IFERROR function returns zero if the first MATCH finds all numeric cells or if the second match finds all text cells.
Basically this is a slight variation of W5ALIVE's mixed text and number solution.
In testing the timing, this was significantly quicker than the equivalent LOOKUP variations.
To return the actual value of that last cell, I prefer to use indirect cell referencing like this:
=INDIRECT("A"&MAX(IFERROR(MATCH("*",A:A,-1),0),IFERROR(MATCH(9.99999999999999E+307,A:A,1),0)))
The method offered by sancho.s is perhaps a cleaner option, but I would modify the portion that finds the row number to this:
=INDEX(MAX((A:A<>"")*(ROW(A:A))),1)
the only difference being that the ",1" returns the first value while the ",0" returns the entire array of values (all but one of which are not needed). I still tend to prefer addressing the cell to the index function there, in other words, returning the cell value with:
=INDIRECT("A"&INDEX(MAX((A:A<>"")*(ROW(A:A))),1))
Great thread!
If you are not afraid to use arrays, then the following is a very simple formula to solve the problem:
=SUM(IF(A:A<>"",1,0))
You must press CTRL + SHIFT + ENTER because this is an array formula.
INDEX returns a value by index position in an array and ROWS then is used to specify the last position of the array.
=LET(array,A1:A10,INDEX(array,ROWS(array)))
Also works for multiple columns when setting the parameter [column_num] of INDEX to 0:
=LET(array,A1:C10,INDEX(array,ROWS(array),0))
A simple one which works for me:
=F7-INDEX(A:A,COUNT(A:A))
Okay, so I had the same issue as the asker, and tried both top answers. But only getting formula errors. Turned out that I needed to exchange the "," to ";" for the formulas to work. I am using XL 2007.
Example:
=LOOKUP(2;1/(A:A<>"");A:A)
or
=INDEX(A:A;MAX((A:A<>"")*(ROW(A:A))))
For version tracking (adding the letter v to the beginning of the number), I found this one to work well in Xcelsius (SAP Dashboards)
="v"&MAX(A2:A500)