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I need to update the value of a variable in a bash script and write the changes to the file. My attempts have either replace the key without strings or deleted the value.
Here's what ive tried :
sed -ri 's|^(VARIABLE_KEY\s*=\s*).*|\new_java-microservice.jar|' path_to_file/bashscript.sh
sed -i "s#\(.*VARIABLE_KEY =\)\( .*\)#\1 "new_java-microservice.jar"#" path_to_file/bashscript.sh
sed -i 's/VARIABLE_KEY =.*/VARIABLE_KEY ="new_java-microservice.jar"/' path_to_file/bashscript.sh
script
#!/bin/bash
COMMAND="$1"
HOME="/root/service/"
BASE="${HOME}/javaservice"
VARIABLE_KEY="existing-java.jar"
case "${COMMAND}" in
"start")
nohup java -jar ${BASE}/${VARIABLE_KEY} start > /dev/null 2>&1 &
;;
"stop")
#....
;;
*)
echo "Usage: $0 {start|stop}"
;;
esac
sed -i 's/^VARIABLE_KEY=.*/VARIABLE_KEY="new_java-microservice.jar"/' path_to_file/bashscript.sh
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experts i have many files in a directory and these files contain some numerical numbers.
Probably not POSIX-compatible; tested on Bash 5.0. Assuming that the filenames don't contain whitespaces and have fixed length.
for file_with_a in *A.??
do
target_left=${file_with_a:0:15} # e.g., 2019__01_NDV.NT
target_right=${file_with_a:16:3} # e.g., .AS
cat $target_left[A-C]$target_right > ${target_left}_ABC$target_right
done
With mapfile aka readarray which is a bash4+ feature.
#!/usr/bin/env bash
files=([0-9][0-9][0-9][0-9]__*[ABC]*.??)
while mapfile -d '' -n3 array && ((${#array[*]} == 3)); do
if [[ ${array[0]%%_*} == ${array[1]%%_*} && ${array[0]%%_*} == ${array[2]%%_*} ]]; then
paste "${array[0]}" "${array[1]}" "${array[2]}" > "${array[0]%${array[0]:(-4)}}_ABC.${array[0]:(-2)}"
fi
done < <(printf '%s\0' "${files[#]}")
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Here's my config file
#comment 1
--longoption1
#comment 2
--longoption2
#comment 3
-s
#comment 4
--longoption4
I want to write a bash script that will read this .conf file, skip comments and serialize the commandline options like so.
./binary --longoption1 --longoption2 -s --longoption4
Working off of this post on sed, you just need to pipe the output from sed to xargs:
sed -e 's/#.*$//' -e '/^$/d' inputFile | xargs ./binary
As Wiimm points out, xargs can be finicky with a lot of arguments and it might split it up across multiple calls to binary. It may be better off to use sed directly:
./binary $(sed -e 's/#.*$//' -e '/^$/d' inputFile)
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I know how to print all letters
{a..z} and {A..Z} and {0..9}
But is there a way to print all possible ASCII Characters via a bash loop?
You don't need a loop
echo -e \\x{0..7}{{0..9},{A..F}}
It prints all chars from 0 to 127.
If it is okay to use awk:
awk 'BEGIN{for (i=32;i<127;i++) printf("%c", i)}'
Or using printf:
for((i=32;i<127;i++)) do printf "\x$(printf %x $i)"; done
use this:
for ((i=32;i<127;i++)) do printf "\\$(printf %03o "$i")"; done;printf "\n"
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Why did printf didn't WORK for the final command printf "%s,%.2f\n" "$s","$a" and what's that extra 0.00 coming from?
When I ran them individually, they worked as expected but not in the final command.
$ s="giga,fifa"; a="8309.18694444444444444444"; echo "$s"; printf "%s\n" "$s"; echo -e "\n"; echo "$a"; printf "%.2f\n" "$a"; echo -e "\n"; echo "$s,$a"; printf "%s" "$s,"; printf "%.2f\n" "$a";echo;printf "%s,%.2f\n" "$s","$a"
giga,fifa
giga,fifa
8309.18694444444444444444
8309.19
giga,fifa,8309.18694444444444444444
giga,fifa,8309.19
giga,fifa,8309.18694444444444444444,0.00
How can I get this output: giga,fifa,8309.19 with just one printf command showing both variables?
You don't use a , in bash printf, you delimit with space. The 0.00 comes from trying to parse the "$s","$a" at once, and has odd results - everything is considered one argument and printed as the first string, so no argument exists for the second and a 0 is substituted as default. This works as expected:
>printf "%s,%.2f\n" "$s" "$a"
giga,fifa,8309.19
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Closed 9 years ago.
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I have a large list of files that I want to rename.
Much like this
So this is what my files look like
something.pcap1
something.pcap10
something.pcap11
something.pcap12
...
something.pcap111
something.pcap1111
essentially I want to rename all of the files so that the numbers get padded with 0's and they are 5 digit numbers.
something.pcap00001
A simple for loop should do the trick (can be script file):
for file in $(ls -1 something.pcap*); do
[[ ${file} =~ ^something.pcap([[:digit:]]*).* ]]
newfile=$(printf "something.pcap%05d" ${BASH_REMATCH[1]})
mv ${file} ${newfile}
done
Something like this?
rename 's/\d+$/sprintf("%05d",$&)/e' soemthing.pcap*
Note: this works with the rename as found in debian and its derivates.
What about something like this?
#!/bin/bash
for i in $(ls something.pcap*); do
q=$(echo $i|sed -e 's/pcap/pcap00000/;s/pcap0*\([0-9]\{6,\}\)$/pcap\1/')
mv $i $q
done
I hope this will help