How to get a list of all documents that contain the search string in their document id in Firestore's collection? [duplicate] - node.js

Question

Is it possible to query a firestore collection to get all document that starts with a specific string?
I have gone through the documentation but do not find any suitable query for this.

Answer 1

You can but it's tricky. You need to search for documents greater than or equal to the string you want and less than a successor key.
For example, to find documents containing a field 'foo' staring with 'bar' you would query:
db.collection(c)
.where('foo', '>=', 'bar')
.where('foo', '<', 'bas');
This is actually a technique we use in the client implementation for scanning collections of documents matching a path. Our successor key computation is called by a scanner which is looking for all keys starting with the current user id.

Answer 2

same as answered by Gil Gilbert.
Just an enhancement and some sample code.
use String.fromCharCode and String.charCodeAt
var strSearch = "start with text here";
var strlength = strSearch.length;
var strFrontCode = strSearch.slice(0, strlength-1);
var strEndCode = strSearch.slice(strlength-1, strSearch.length);
var startcode = strSearch;
var endcode= strFrontCode + String.fromCharCode(strEndCode.charCodeAt(0) + 1);
then filter code like below.
db.collection(c)
.where('foo', '>=', startcode)
.where('foo', '<', endcode);
Works on any Language and any Unicode.
Warning: all search criteria in firestore is CASE SENSITIVE.

Answer 3

Extending the previous answers with a shorter version:
const text = 'start with text here';
const end = text.replace(/.$/, c => String.fromCharCode(c.charCodeAt(0) + 1));
query
.where('stringField', '>=', text)
.where('stringField', '<', end);
IRL example
async function search(startsWith = '') {
let query = firestore.collection(COLLECTION.CLIENTS);
if (startsWith) {
const end = startsWith.replace(
/.$/, c => String.fromCharCode(c.charCodeAt(0) + 1),
);
query = query
.where('firstName', '>=', startsWith)
.where('firstName', '<', end);
}
const result = await query
.orderBy('firstName')
.get();
return result;
}

Answer 4

If you got here looking for a Dart/Flutter version
Credit to the java answer by Kyo
final strFrontCode = term.substring(0, term.length - 1);
final strEndCode = term.characters.last;
final limit =
strFrontCode + String.fromCharCode(strEndCode.codeUnitAt(0) + 1);
final snap = await FirebaseFirestore.instance
.collection('someCollection')
.where('someField', isGreaterThanOrEqualTo: term)
.where('someField', isLessThan: limit)
.get();

Answer 5

I found this, which works perfectly for startsWith
const q = query(
collection(firebaseApp.db, 'capturedPhotos'),
where('name', '>=', name),
where('name', '<=', name + '\uf8ff')
)

Answer 6

The above are correct! Just wanted to give an updated answer!
var end = s[s.length-1]
val newEnding = ++end
var newString = s
newString.dropLast(1)
newString += newEnding
query
.whereGreaterThanOrEqualTo(key, s)
.whereLessThan(key, newString)
.get()