How find integer in text - string

Help me figure out how to work with text
i have a string like: "word1 number: word2" for example : "result 0: Good" or "result 299: Bad"
i need print Undefined/Low or High
When string is null , print Undefined
When number 0-15, print Low
When number >15, print High
type GetResponse =
{
MyData: string voption
ErrorMessage: string voption }
val result: Result<GetResponse, MyError>
and then i try:
MyData =
match result with
| Ok value ->
if (value.Messages = null) then
ValueSome "result: Undefined"
else
let result =
value.Messages.FirstOrDefault(
(fun x -> x.ToUpperInvariant().Contains("result")),
"Undefined"
)
if (result <> "Undefined") then
ValueSome result
else
errors.Add("We don't have any result")
ValueNone
| Error err ->
errors.Add(err.ToErrorString)
ValueNone
ErrorMessage =
if errors.Any() then
(errors |> String.concat ", " |> ValueSome)
else
ValueNone
but i dont know gow check in string number and maybe there is some way print this without a billion if?

Parsing gets complex very quickly. I recommend using FParsec to simplify the logic and avoid errors. A basic parser that seems to meet your needs:
open System
open FParsec
let parseWord =
manySatisfy Char.IsLetter
let parseValue =
parseWord // parse any word (e.g. "result")
>>. spaces1 // skip whitespace
>>. puint32 // parse an unsigned integer value
.>> skipChar ':' // skip colon character
.>> spaces // skip whitespace
.>> parseWord // parse any word (e.g. "Good")
You can then use it like this:
type ParserResult = Undefined | Low | High
let parse str =
if isNull str then Result.Ok Undefined
else
match run parseValue str with
| Success (num, _ , _) ->
if num <= 15u then Result.Ok Low
else Result.Ok High
| Failure (errorMsg, _, _) ->
Result.Error errorMsg
parse null |> printfn "%A" // Ok Undefined
parse "result 0: Good" |> printfn "%A" // Ok Low
parse "result 299: Bad" |> printfn "%A" // Ok High
parse "invalid input" |> printfn "%A" // Error "Error in Ln: 1 Col: 9 ... Expecting: integer number"
There's definitely a learning curve with FParsec, but I think it's worth adding to your toolbelt.

I agree with Brian that parsing can become quite tricky very quickly. However if you have some well established format of the input and you're not very much into writing complex parsers, good old regular expressions can be of service ;)
Here is my take on the problem - please note that it has plenty of room to improve, this is just a proof of concept:
open System.Text.RegularExpressions
let test1 = "result 0: Good"
let test2 = "result 299: Bad"
let test3 = "some other text"
type ParserResult =
| Undefined
| Low of int
| High of int
let (|ValidNumber|_|) s =
//https://learn.microsoft.com/en-us/dotnet/api/system.text.regularexpressions.regex?view=net-6.0
let rx = new Regex("(\w\s+)(\d+)\:(\s+\w)")
let matches = rx.Matches(s)
if matches.Count > 0 then
let groups = matches.[0].Groups |> Seq.toList
match groups with
| [_; _; a; _] -> Some (int a.Value)
| _ -> None
else
None
let parseMyString str =
match str with
| ValidNumber n when n < 16 -> Low n
| ValidNumber n -> High n
| _ -> Undefined
//let r = parseMyString test1
printfn "%A" (parseMyString test1)
printfn "%A" (parseMyString test2)
printfn "%A" (parseMyString test3)
The active pattern ValidNumber returns the Some number if a match of the input string is found, otherwise it returns None. The parseMyString function uses the pattern and guards to initialise the final ParserOutput value.

Related

F# - Error Loading Table With Empty Last Row Using HtmlProvider

When loading a Wikipedia table using HtmlProvider, I get an error message because the last row in the table is empty!
module SOQN =
open System
open FSharp.Data
let [<Literal>] wikiUrl = #"https://en.wikipedia.org/wiki/COVID-19_testing#Virus_testing_statistics_by_country"
type Covid = HtmlProvider<wikiUrl>
let main() =
printfn ""
printfn "SOQN: Error Loading Table With Empty Last Row Using HtmlProvider?"
printfn ""
let feed = Covid.Load(wikiUrl)
feed.Tables.``Virus testing statistics by country``.Rows
|> Seq.map (fun r -> r.Date)
|> printf "%A "
printfn ""
0
[<EntryPoint>]
main() |> ignore
printfn "Fini!"
printfn ""
// Actual Output:
// "Date is missing"
//
// Expected Output:
// seq [ "Albania"; "19 Apr"; "5542"; "562"; "10.1"; "1,936"; "196"; "[121]" ]
// ...
//
What am I missing?
For instance, can I preset the column types to 'string' similar to using 'schema' with CsvProvider?

reading integers from a string

I want to read a line from a file, initialize an array from that line and then display the integers.
Why is is not reading the five integers in the line? I want to get output 1 2 3 4 5, i have 1 1 1 1 1
open Array;;
open Scanf;;
let print_ints file_name =
let file = open_in file_name in
let s = input_line(file) in
let n = ref 5 in
let arr = Array.init !n (fun i -> if i < !n then sscanf s "%d" (fun a -> a) else 0) in
let i = ref 0 in
while !i < !n do
print_int (Array.get arr !i);
print_string " ";
i := !i + 1;
done;;
print_ints "string_ints.txt";;
My file is just: 1 2 3 4 5
You might want to try the following approach. Split your string into a list of substrings representing numbers. This answer describes one way of doing so. Then use the resulting function in your print_ints function.
let ints_of_string s =
List.map int_of_string (Str.split (Str.regexp " +") s)
let print_ints file_name =
let file = open_in file_name in
let s = input_line file in
let ints = ints_of_string s in
List.iter (fun i -> print_int i; print_char ' ') ints;
close_in file
let _ = print_ints "string_ints.txt"
When compiling, pass str.cma or str.cmxa as an argument (see this answer for details on compilation):
$ ocamlc str.cma print_ints.ml
Another alternative would be using the Scanf.bscanf function -- this question, contains an example (use with caution).
The Scanf.sscanf function may not be particularly suitable for this task.
An excerpt from the OCaml manual:
the scanf facility is not intended for heavy duty lexical analysis and parsing. If it appears not expressive enough for your needs, several alternative exists: regular expressions (module Str), stream parsers, ocamllex-generated lexers, ocamlyacc-generated parsers
There is though a way to parse a string of ints using Scanf.sscanf (which I wouldn't recommend):
let rec int_list_of_string s =
try
Scanf.sscanf s
"%d %[0-9-+ ]"
(fun n rest_str -> n :: int_list_of_string rest_str)
with
| End_of_file | Scanf.Scan_failure _ -> []
The trick here is to represent the input string s as a part which is going to be parsed into a an integer (%d) and the rest of the string using the range format: %[0-9-+ ]", which will match the rest of the string, containing only decimal digits 0-9, the - and + signs, and whitespace .

do block with flower brackets in ghci throws error

I have a code that works with print inside do block as,
do { print ([(n, 2^n) | n <- [0..19]]) }
Then i tried a much simpler version to print a variable value,
do { let a = 1; print (a) }
It throws error as parse error on input }
What else, i tried with no success ---
ghci> let a = 1; print (a)
And
ghci> :{
| let a = 1;
| print (a)
| :}
Once you start a let statement, the rest of the line is considered to be additional let assignments. Consider this error message:
ghci> do print 1; let c = 2; d = 3
<interactive>:3:13:
The last statement in a 'do' block must be an expression
let c = 2
d = 3
Note that the let keyword is not needed for d = 3.
To add a monadic statement after a let you'll need to put it on a separate line (with the correct indentation):
ghci> :{
| do print 1; let a = 2; b = 3
| print b
| :}
1
3
AFAIK, there is no way to put a monadic statement after a let on the same line.

better way to get the last character in a string in f#

I want the last character from a string
I've got str.[str.Length - 1], but that's ugly. There must be a better way.
There's no better way to do it - what you have is fine.
If you really plan to do it a lot, you can author an F# extension property on the string type:
let s = "food"
type System.String with
member this.Last =
this.Chars(this.Length-1) // may raise an exception
printfn "%c" s.Last
This could be also handy:
let s = "I am string"
let lastChar = s |> Seq.last
Result:
val lastChar : char = 'g'
(This is old question), someone might find this useful, orig answer from Brian.
type System.String with
member this.Last() =
if this.Length > 1 then
this.Chars(this.Length - 1).ToString()
else
this.[0].ToString()
member this.Last(n:int) =
let absn = Math.Abs(n)
if this.Length > absn then
let nn =
let a = if absn = 0 then 1 else absn
let b = this.Length - a
if b < 0 then 0 else b
this.Chars(nn).ToString()
else
this.[0].ToString()
"ABCD".Last() -> "D"
"ABCD".Last(1) -> "D"
"ABCD".Last(-1) -> "D"
"ABCD".Last(2) -> "C"
You could also treat it as a sequence, but I'm not sure if that's any more or less ugly than the solution you have:
Seq.nth (Seq.length str - 1) str

How do I strip whitespace from a string in OCaml?

To learn the basics of OCaml, I'm solving one of the easy facebook engineering puzzles using it. Essentially, I'd like to do something like the following Python code:
some_str = some_str.strip()
That is, I'd like to strip all of the whitespace from the beginning and the end. I don't see anything obvious to do this in the OCaml Str library. Is there any easy way to do this, or am I going to have to write some code to do it (which I wouldn't mind, but would prefer not to :) ).
Bear in mind that I'm limited to what's in the libraries that come with the OCaml distribution.
I know this question is uber-old, but I was just pondering the same thing and came-up with this (from toplevel):
let strip str =
let str = Str.replace_first (Str.regexp "^ +") "" str in
Str.replace_first (Str.regexp " +$") "" str;;
val strip : string -> string = <fun>
then
strip " Hello, world! ";;
- : string = "Hello, world!"
UPDATE:
As of 4.00.0, standard library includes String.trim
It is really a mistake to limit yourself to the standard library, since the standard ilbrary is missing a lot of things. If, for example, you were to use Core, you could simply do:
open Core.Std
let x = String.strip " foobar "
let () = assert (x = "foobar")
You can of course look at the sources of Core if you want to see the implementation. There is a similar function in ExtLib.
how about
let trim str =
if str = "" then "" else
let search_pos init p next =
let rec search i =
if p i then raise(Failure "empty") else
match str.[i] with
| ' ' | '\n' | '\r' | '\t' -> search (next i)
| _ -> i
in
search init
in
let len = String.length str in
try
let left = search_pos 0 (fun i -> i >= len) (succ)
and right = search_pos (len - 1) (fun i -> i < 0) (pred)
in
String.sub str left (right - left + 1)
with
| Failure "empty" -> ""
(Via Code Codex)
I believe at the point when the other answers were given, version 4.00 was not out yet. Actually, in OCaml 4.00, there is a String.trim function in the string module to trim leading and trailing white spaces.
Alternatively, if you're restricted to an older version of OCaml, you may use this function that is shamelessly copied from the source of 4.00's string module.
let trim s =
let is_space = function
| ' ' | '\012' | '\n' | '\r' | '\t' -> true
| _ -> false in
let len = String.length s in
let i = ref 0 in
while !i < len && is_space (String.get s !i) do
incr i
done;
let j = ref (len - 1) in
while !j >= !i && is_space (String.get s !j) do
decr j
done;
if !i = 0 && !j = len - 1 then
s
else if !j >= !i then
String.sub s !i (!j - !i + 1)
else
""
;;
Something simple like this should work fine:
#require "str";;
let strip_string s =
Str.global_replace (Str.regexp "[\r\n\t ]") "" s
Standard library's
String.trim
does exactly that.

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