I have a directory where there are files -:
abc_002.txt
abc_003.txt
abc_004.txt
abc_005.txt
xyz_001.txt
for_ex.sh
abc_001.txt
I want to gzip only files starting with names abc, like abc*.
for file in abc*.txt
do
gzip $file
done
Related
i need to recognize files with different extensions even when there is a combination of multiple extensions
so if my cwd has this files:
file-1 .zip
file-2 .tar
file-3 .tar.gz
file-4 .gz
file-5 .zip.tar
file-6 .tar.gz
file-7 .gz
i need to tell bash what to do when the extension (in this case) is:
zip
tar
zip.tar
tar.gz
gz
because for every extension i need to do different things, this implies that if the extension is .tar (only) or .gz (only) i need to do certain things, but if the extension is .tar.gz i need to run another snippet.
example:
if the filename has .tar extension i need to do
# stuff
tar xf filename.tar
# other stuff
if the filename has .zip.tar extension i need to run more complex code (but the code is not totally dependent on the extensions, my only objective is to get the full extension of the filename (filename.tar.gz should return .tar.gz instead of .gz or .tar)
Also, is there any way using gawk?
Use case:
case "$filename" in
*.tar.gz) code for .tar.gz ;;
*.gz) code for .gz ;;
*.zip.tar) code for .zip.tar ;;
*.tar) code for .tar ;;
...
esac
Just make sure you put the combined extensions before the single extensions that they contain, because case executes the statements for the first pattern that matches.
The file command is a good option to detect file types, then you can write a logic
file -i test.*
test.gz: application/x-gzip; charset=binary
test.tar: application/x-tar; charset=binary
test.tar.gz: application/x-gzip; charset=binary
test.zip: application/zip; charset=binary
Considering the file named:
foo.tar.bz2
What is the file extension? Is it .tar.bz2 or .bz2? Is it well defined?
Edit: The question here is one of the definition of a "file extension", or where the separation is between the file's name and its extension: is it "foo|.tar.bz2" or "foo.tar|.bz2"
The standard file extension would be .tar.bz2, but .tbz2 should suffice as a shortened extension.
tar - is archive file
bz2 - is compressed with bzip
to unarchive and get all files you should type in command line unix:
tar jxf foo.tar.bz2
after that you will have files unarchived and extracted
extension is the last one .bz2
I would like to know if there is any way to compress a set of .txt files in a folder using scripting when the number of files get more than a set limit.
The txt files are automatically generated by another script.
You can use array size to detect the number of files:
limit=100
files=(*.txt)
if (( ${#files[#]} > limit )) ; then
zip archive.zip *.txt
fi
It sounds like you want logrotate with a custom (non-/etc) configuration file with rules for compressing/removing by size.
I working with linux, bash.
I have one directory with 100 folders in it, each one named different.
In each of these 100 folders, there is a file called first.bars (so I have 100 files named first.bars). Although all named first.bars, the files are actually slightly different.
I want to get all these files moved to one new folder and rename/number these files so that I know which file comes from which folder. So the first first.bars file must be renamed to 001.bars, the second to 002.bars.. etc.
I have tried the following:
ls -d * >> /home/directorywiththe100folders/list.txt
cat list.txt | while read line;
do cd $line;
mv first.bars /home/newfolder
This does not work because I can't have 100 files, named the same, in one folder. So I only need to know how to rename them. The renaming must be connected to the cat list.txt, because the first line is the folder containing the first file wich is moved and renamed. That file will be called 001.bars.
Try doing this :
$ rename 's/^.*?\./sprintf("%03d.", $c++)/e' *.bar
If you want more information about this command, see this recent response I gave earlier : How do I rename multiple files beginning with a Unix timestamp - imapsync issue
If the rename command is not available,
for d in /home/directorywiththe100folders/*/; do
newfile=$(printf "/home/newfolder/%d.bars" $(( c++ )) )
mv "$d/first.bars" "$newfile"
done
I have following architecture of files in a directory.
Directory
/A/abc.xyz
/B/abc.xyz
/C/abc.xyz
/D/abc.xyz
/E/abc.xyz
I want to execute a program on acb.xyz in each SubDirectory. Save Output files in different directory i.e. Directory/processed with the name of SubDirectory appended in the name of output files.
Can it be written in following way? Need corrections.
for i in `ls "Directory/"`
do
program.pl $i/abc.xyz > processed/$i-abc.xyz
done
for dir in Directory/*; do
program.pl "$dir/abc.xyz" > "processed/${dir##*/}-abc.xyz"
done
The ${dir##*/} part strips the leading directory names from $dir, so Directory/A becomes just A. I added quotes to ensure directory names with whitespace don't cause issue (a good habit, even if you know there are no spaces).
As an alternative to the string munging you could simplify this if you first change directory:
cd Directory
for dir in *; do
program.pl "$dir/abc.xyz" > "processed/$dir-abc.xyz"
done