How to instruct cron to execute a job in airflow Run every 3rd Jan, 3rd April, 3rd July, 3rd Oct at 11:00 AM UTC Time Zone - cron

How to instruct cron to execute a job in airflow Run every 22nd Jan, 22nd April, 22nd July, 22nd Oct at 11:00 AM UTC Time Zone.
I have written below cron command to execute in airflow but it is not running at per scheudled
schedule_interval="0 11 22 1/3 *"


A cron-to-human-translator such as crontab.guru is a convenient tool for writing cron expressions:
0 11 22 1,4,7,10 *
0 = Minute 0
11 = Hour 11
22 = Day 22
1,4,7,10 = Months January, April, July, and October
* = Any day of the week
By default, UTC is applied in Airflow, but you can configure this globally (AIRFLOW__CORE__DEFAULT_TIMEZONE), or per DAG. See documentation: https://airflow.apache.org/docs/apache-airflow/stable/timezone.html#default-time-zone.

Related

how schedule a job in airflow for first 4 business day (not on weekends) of the month

job should run on first 4 business day(not on weekends) at 3 am
ex : 00 03 1-6 * 1-5 ==> jobs are running every day-of-week from Monday through Friday
1 - fri 03:00
4 - mon 03:00
5 - tue 03:00
6- wed 03:00

This is currently not possible with a single cron expression. You could configure "the first Monday-Friday of the month" using the # symbol:
0 3 * * MON#1,TUE#1,WED#1,THU#1,FRI#1
However, sometimes Friday is part of the 4 business days (e.g. Wednesday 1 Thursday 2 Friday 3 Saturday 4 Sunday 5 Monday 6 Tuesday 7), so you cannot simply exclude that.
Within Airflow, you currently have 2 options to work around this:
Implement a timetable
Run your DAG with the expression shown above, and start your DAG with a task to skip all remaining tasks in case the DAG run's date is a fifth working day.

I like to schedule crontab run alternative Week in Jenkins. Example: If it runs on may 26th 2020 next run should be on June 9th

Right now, The Crontab which I have is doing for every 3 weeks. Ex: May 19th and June 9th.
I want to have to have May 26th and next run should be on June 9th.
00 11 */2 * 2

How to create cronjob for stopping the application in every month different date

I need to create a cronjob for stopping an application every month at different date. For example: time: 2 am, date: jan 5th, feb 7th, mar 15th
00 02 * * * /export/home/jira-8.5.3-install/bin/stop-jira.sh

Is there a Cron expression to schedule task after every 5 months across year boundaries?

I have an agenda job that I want to schedule for every five months. Suppose I started that job on Jan 20th, so now the schedule should be Jan 20th 2019, June 20th 2019, Nov 20th 2019, April 20th 2020 and so on.
Agenda uses cron for scheduling.
The problem with 00 00 20 1,6,11 * is that it will never run in April, this will run
at 2019-06-01 00:00:00
then at 2019-11-01 00:00:00
then at 2020-01-01 00:00:00
then at 2020-06-01 00:00:00
then at 2020-11-01 00:00:00.
Another expression that I used is 00 00 20 */5 *. The next run times are
at 2019-06-20 00:00:00
then at 2019-11-20 00:00:00
then at 2020-01-20 00:00:00
then at 2020-06-20 00:00:00
then at 2020-11-20 00:00:00
but they are not the month that I want it to run, i.e., at a regular interval of five months.

I couldn't find a way to start on the exact date in the month when it's started. If it is ok it's the first (like example below), you can use this:
Contab guru
“At 00:00 on day-of-month 1 in every 5th month.”
Otherwise play with the values to suit your needs.

Cron can't do this directly, but you can move that logic into a script that you call every month. Your cron job could look like
0 0 20 * * monthcheck 2019 1 5
and monthcheck is a script somewhere in your path with this content:
#!/usr/bin/env bash
baseyear=$1
basemonth=$2
interval=$3
read -r year month <<< "$(date '+%Y %-m')"
if (( (12*(year-baseyear) + (month-basemonth)) % interval == 0 )); then
echo "Run the script"
fi
This takes a base date specified by year and month (baseyear and basemonth, supplied as arguments with 2019 and 1 in the crontab entry) plus an interval in months (interval, value 5 in the example).
It then reads the current year and month into year and month, checks how many months have passed since the basedate, and if that difference is a multiple of interval (modulo division by the interval is 0), then it runs your script (just an echo command in this example).
The formatting string for date uses %-m to avoid zero padding for the month (gets 1 instead of 01). This feature might not be present in every date – I'm using GNU date here.

Quartz cron trigger for every 2 weeks and 2 times a day ( 6 AM and 6PM)

I want to run a quartz job for every 2 weeks at morning 6'o clock and evening 6'o clock . how to achieve this .please advice.
I tried to schedule using below cron expression
01 01 1 1-0/14 01 ? *
but the next fire times are as below.
Sunday, January 1, 2017 1:01 AM
Sunday, January 15, 2017 1:01 AM
Sunday, January 29, 2017 1:01 AM
Monday, January 1, 2018 1:01 AM
Monday, January 15, 2018 1:01 AM

There are some kinds of date triggers cron is good at. Every N days is often not one of them. For instance, if you use something like this:
0 0 6,18 */14 * ?
You might get something like this:
Tuesday, March 29, 2016 6:00 AM
Tuesday, March 29, 2016 6:00 PM
Friday, April 1, 2016 6:00 AM
Friday, April 1, 2016 6:00 PM
Friday, April 15, 2016 6:00 AM
Friday, April 15, 2016 6:00 PM
As you can see, the 29th, followed by the 1st -- not exactly fourteen days apart.
It's useful to have something that lets you play with the expression and see the resulting dates. CronMaker can do that, if that's helpful.
However, since you say you are using Quartz, it supports other kinds of triggers, like DateIntervalTrigger that might be better suited for what you're looking for?

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