I am trying to create a svg pattern where size of it is relative to shape to which is applied. Pattern should consist of rect with linearGradient and text elements which repeats in x-axis n-times or every n pixels and is vertically aligned in middle of rect.
The results should look like this.
I have tried following approaches.
<svg width="100%" height="100">
<defs>
<linearGradient id="gradient" x1="0%" x2="0%" y1="0%" y2="100%">
<stop offset="0%" stop-color="#fff" />
<stop offset="100%" stop-color="#c6c6c6" />
</linearGradient>
<pattern id="pattern" width="25%" height="100%">
<rect width="100%" height="100%" fill="url(#gradient)"></rect>
<text x="10" y="50%" dx=50 fill="red">test</text>
</pattern>
</defs>
<rect width="1000" height="100" fill="url(#pattern)"></rect>
</svg>
This approach gives the result I want but the size of pattern is not relatve to shape to which is applied and fails when shape is resized, to solve this issue I have tried to create a pattern with patternContentUnits="objectBoundingBox" but then I am having problems positioning the text.
<svg width="100%" height="100%">
<defs>
<linearGradient id="gradient" x1="0%" x2="0%" y1="0%" y2="100%">
<stop offset="0%" stop-color="#fff" />
<stop offset="100%" stop-color="#c6c6c6" />
</linearGradient>
<pattern id="pattern" patternContentUnits="objectBoundingBox" width="25%" height="100%">
<rect width="1" height="1" fill="url(#gradient)"></rect>
<text x="0.1" y="0.5">test</text>
</pattern>
</defs>
<rect width="1000" height="100" fill="url(#pattern)"></rect>
</svg>
objectBoundingBox units are in the range [0, 1] so 10 is too big.
You'll need to use a suitable font-size too.
<svg width="100%" height="100%">
<defs>
<linearGradient id="gradient" x1="0%" x2="0%" y1="0%" y2="100%">
<stop offset="0%" stop-color="#fff" />
<stop offset="100%" stop-color="#c6c6c6" />
</linearGradient>
<pattern id="pattern" patternContentUnits="objectBoundingBox" width="25%" height="100%">
<rect width="1" height="1" fill="url(#gradient)"></rect>
<text transform="scale(0.2, 1)" x="0.1" y="0.5" font-size="0.1">test</text>
</pattern>
</defs>
<rect width="1000" height="100" fill="url(#pattern)"></rect>
</svg>
Related
I have this gradient that uses userSpaceOnUse.
<svg height="400px" width="800px" viewBox="0 0 800 400" xmlns="http://www.w3.org/2000/svg">
<defs>
<linearGradient id="grad1" x1="0" y1="0" x2="800" y2="400" gradientUnits="userSpaceOnUse">
<stop offset="0%" style="stop-color:green;stop-opacity:1" />
<stop offset="50%" style="stop-color:black;stop-opacity:1" />
<stop offset="100%" style="stop-color:red;stop-opacity:1" />
</linearGradient>
</defs>
<rect x="0" y="0" width="800" height="400" fill="url(#grad1)"/>
</svg>
I want to rewrite it to use objectBoundingBox but be rendered the same. How can I do this?
I imagine the rewritten SVG would be close to:
<svg height="400px" width="800px" viewBox="0 0 800 400" xmlns="http://www.w3.org/2000/svg">
<defs>
<linearGradient id="grad1" x1="0" y1="0" x2="1" y2="1" gradientUnits="objectBoundingBox">
<stop offset="0%" style="stop-color:green;stop-opacity:1" />
<stop offset="50%" style="stop-color:black;stop-opacity:1" />
<stop offset="100%" style="stop-color:red;stop-opacity:1" />
</linearGradient>
</defs>
<rect x="0" y="0" width="800" height="400" fill="url(#grad1)"/>
</svg>
This answer (https://stackoverflow.com/a/50624704/1283776) indicates that I need to use a transform, but I haven't been successful in found a solution.
<!-- https://stackoverflow.com/questions/22214999/svg-linear-gradient-independent-of-the-shape-coordinates -->
<svg height="400px" width="800px" viewBox="0 0 800 400" xmlns="http://www.w3.org/2000/svg">
<defs>
<linearGradient id="grad1" x1="0" y1="0" x2="1" y2="0.5" gradientUnits="objectBoundingBox" gradientTransform="scale(1, 2)">
<stop offset="0%" style="stop-color:green;stop-opacity:1" />
<stop offset="50%" style="stop-color:black;stop-opacity:1" />
<stop offset="100%" style="stop-color:red;stop-opacity:1" />
</linearGradient>
</defs>
<rect x="0" y="0" width="800" height="400" fill="url(#grad1)"/>
</svg>
I try to build a reflection of my text with gradient. But the reflection (the second text) has an off set and by applying the rotation the letters are shifting.
body {
background-color: black;
}
<svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="1000" height="140" viewBox="0 0 1000 140">
<text x="260" y="70" font-size="60" fill=" #888888" style="text-anchor: right">Multimediale Kunst</text>
<defs>
<linearGradient id="linearGradient" x1="0%" y1="0%" x2="0%" y2="100%">
<stop offset="0%" stop-color="#000000" />
<stop offset="10%" stop-color="#666666" />
</linearGradient>
</defs>
<text rotate="180" x="310" y="80" font-size="60" fill="url(#linearGradient)" style="text-anchor: right">Multimediale Kunst</text>
</svg>
This is happening because the rotate attribute rotates individual start points. So wider characters end up further away from narrow characters and vice-versa.
The rotate attribute is the wrong approach anyway. If you want to vertically flip the text, then you should use a transform that scales the object on the y axis by -1.
body {
background-color: black;
}
<svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="1000" height="140" viewBox="0 0 1000 140">
<text x="260" y="70" font-size="60" fill=" #888888" style="text-anchor: right">Multimediale Kunst</text>
<defs>
<linearGradient id="linearGradient" x1="0%" y1="0%" x2="0%" y2="100%">
<stop offset="50%" stop-color="#000000" />
<stop offset="100%" stop-color="#666666" />
</linearGradient>
</defs>
<text x="260" y="-80" font-size="60" fill="url(#linearGradient)" style="text-anchor: right" transform="scale(1,-1)">Multimediale Kunst</text>
</svg>
I am making two gradients: one in objectBoundingBox units and another in userSpaceOnUse. The idea is to make them look the same. But somehow they are different. Here is the svg file.
<svg width="500" height="500" viewBox="0 0 500 500" version="1.1" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink">
<defs>
<linearGradient id="user-grad" gradientUnits="userSpaceOnUse" x1="0" y1="0" x2="200" y2="100">
<stop stop-color="orange" offset="0"/>
<stop stop-color="blue" offset="1"/>
</linearGradient>
<linearGradient id="box-grad" x1="0" y1="0" x2="1" y2="1">
<stop stop-color="orange" offset="0"/>
<stop stop-color="blue" offset="1"/>
</linearGradient>
</defs>
<rect x="0" y="0" width="200" height="100" fill="url(#user-grad)"/>
<rect x="250" y="0" width="200" height="100" fill="url(#box-grad)"/>
</svg>
Here is what it looks like
Shouldn't they look the same?
Shouldn't they look the same?
No. When using object bounding box coordinates, you are basically transforming a 1x1 square onto your rectangle. So the 0 to 1 coordinates are stretched to fit the rectangle. Thus causing the gradient to stretch also.
If you want them to look the same, you would need to apply a gradientTransform, to your userSpaceOnUse one, that applies the equivalent stretch.
<svg width="500" height="500" viewBox="0 0 500 500" version="1.1" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink">
<defs>
<linearGradient id="user-grad" gradientUnits="userSpaceOnUse" x1="0" y1="0" x2="100" y2="100" gradientTransform="scale(2, 1)">
<stop stop-color="orange" offset="0"/>
<stop stop-color="blue" offset="1"/>
</linearGradient>
<linearGradient id="box-grad" x1="0" y1="0" x2="1" y2="1">
<stop stop-color="orange" offset="0"/>
<stop stop-color="blue" offset="1"/>
</linearGradient>
</defs>
<rect x="0" y="0" width="200" height="100" fill="url(#user-grad)"/>
<rect x="250" y="0" width="200" height="100" fill="url(#box-grad)"/>
</svg>
I'm trying to program a graph like this one:
I tried with SVG, but it's not very good since I had to use 2 different rectangles and didn't manage to get only the 4 edges to be rounded.
Here's my code:
<svg width="400" height="250">
<defs>
<linearGradient id="solids" x1="0%" y1="0%" x2="100%" y2="0%">
<stop offset="0%" style="stop-color:rgb(255,0,0);stop-opacity:1" />
<stop offset="50%" style="stop-color:rgb(255,0,0);stop-opacity:1" />
<stop offset="50%" style="stop-color:rgb(0,255,0);stop-opacity:1" />
<stop offset="100%" style="stop-color:rgb(0,255,0);stop-opacity:1" />
</linearGradient>
<linearGradient id="solids2" x1="0%" y1="0%" x2="100%" y2="0%">
<stop offset="0%" style="stop-color:rgb(255,255,0);stop-opacity:1" />
<stop offset="50%" style="stop-color:rgb(255,255,0);stop-opacity:1" />
<stop offset="50%" style="stop-color:rgb(0,0,255);stop-opacity:1" />
<stop offset="100%" style="stop-color:rgb(0,0,255);stop-opacity:1" />
</linearGradient>
</defs>
<text x="135" y="12" style="fill:black;">Conservadorismo
<tspan x="150" y="240">Liberalismo</tspan>
<tspan x="20" y="125">Esquerda</tspan>
<tspan x="305" y="125">Direita</tspan>
</text>
<rect x="100" y="20" rx="20" ry="20" width="200" height="100" style="fill:url(#solids); opacity:0.76" />
<rect x="100" y="120" rx="20" ry="20" width="200" height="100" style="fill:url(#solids2); opacity:0.76" />
<line x1="100" y1="120" x2="300" y2="120" style="stroke:black;stroke-width:2" />
<line x1="200" y1="20" x2="200" y2="220" style="stroke:black;stroke-width:2" />
</svg>
What should I do to fix it or do it better?
I would use ordinary <rect> objects without rounded corners, and apply a clipPath to the whole drawing to round off the corners.
Here's a simple example:
<svg width="400" height="400" viewBox="0 0 400 400">
<defs>
<clipPath id="roundRect">
<rect x="10" y="10" rx="20" ry="20" width="380" height="380"/>
</clipPath>
</defs>
<g clip-path="url(#roundRect)">
<rect fill="#0a0" stroke="none" x="10" y="10" width="190" height="190"/>
<rect fill="#f00" stroke="none" x="200" y="10" width="190" height="190"/>
<rect fill="#0bf" stroke="none" x="10" y="200" width="190" height="190"/>
<rect fill="#fd0" stroke="none" x="200" y="200" width="190" height="190"/>
</g>
</svg>
I can use linear gradient in SVG with defs-section like:
<svg xmlns="http://www.w3.org/2000/svg"
xmlns:xlink="http://www.w3.org/1999/xlink">
<defs>
<linearGradient id="myLinearGradient1"
x1="0%" y1="0%"
x2="0%" y2="100%"
spreadMethod="pad">
<stop offset="0%" stop-color="#00cc00" stop-opacity="1"/>
<stop offset="100%" stop-color="#006600" stop-opacity="1"/>
</linearGradient>
</defs>
<rect x="0" y="0" width="100" height="100"
style="fill:url(#myLinearGradient1)" />
</svg>
Can I use linear gradient without defs-section? I find something like this:
<rect style="fill:lineargradient(foo)">
<defs> is only needed for structuring purposes, the elements in it are not displayed, but since a gradient can only be visible when applied to a shape or another element, you can define it in any place of the document.
But you still have to stick to the correct syntax:
<rect style="fill:url(#myLinearGradient1)" ... />
Yes you can indeed have a gradient without needing to have a defs element; you simply put the gradient element anywhere else in the code instead, for example like this:
<svg xmlns="http://www.w3.org/2000/svg"
xmlns:xlink="http://www.w3.org/1999/xlink">
<linearGradient id="myLinearGradient1"
x1="0%" y1="0%"
x2="0%" y2="100%"
spreadMethod="pad">
<stop offset="0%" stop-color="#00cc00" stop-opacity="1"/>
<stop offset="100%" stop-color="#006600" stop-opacity="1"/>
</linearGradient>
<rect x="0" y="0" width="100" height="100"
style="fill:url(#myLinearGradient1)" />
</svg>