If the total sum value is 100, I want to divide by 5 to all sum values of 10 and above. What will be a formula in excel for this?
In Office365 you could use the following:
=LET(sumrange,A1:A9,
summed,SUM(sumrange),
alteredsum,SUM(IF(sumrange>10,sumrange/5,sumrange)),
IF(summed=100,alteredsum,summed))
Else (ctrl+shift+enter required):
=IF(SUM(A1:A9)=100,
SUM(IF(A1:A9>10,A1:A9/5,A1:A9)),
SUM(A1:A9))
*Change the range to your needs.
Related
I have some data that looks like this
Condition 1
Condition 2
Condition 3
Condition 4
Condition 5
0
0
0
70
0
0
50
10
0
0
120
0
0
5
5
Where the value in each cell is the number of meters of an asset that is the given condition. Or in other words, a count of the number of meters that are a '4'.
How do I calculate a standard deviation for this? Obviously the std.dev would be '0' for the first row, higher for row 2, and fairly low for row 3.
Something similar to REPT, but that repeats a value x times in a formula?
I considered a helper column but the number of meters that there are in total makes this impractical.
I am not a math expert, but I can show you how to "make a range of numbers" based on the criteria shown, using Excel 365.
Suppose your data is in the range B2:F4 as shown below. In cell G2, enter the following formula and drag it down:
=STDEV.P(--FILTERXML("<t><s>"&TEXTJOIN("</s><s>",1,REPT($B$1:$F$1&"</s><s>",$B2:$F2))&"</s></t>","//s[number()=.]"))
The above will calculate the standard deviation using the STDEV.P function, but I am unsure if this is the right function to use as there are many other variations to the original STDEV function.
Regardless, the following part of the formula is able to return a range of numbers as desired:
=--FILTERXML("<t><s>"&TEXTJOIN("</s><s>",1,REPT($B$1:$F$1&"</s><s>",$B2:$F2))&"</s></t>","//s[number()=.]")
You can view this question and the answer by JvdV to understand the use of the FILTERXML function.
Another way of doing it is to use the alternative SD formula
which would give you
=SQRT((SUM(A2:E2*COLUMN(A2:E2)^2)-SUM(A2:E2*COLUMN(A2:E2))^2/SUM(A2:E2))/SUM(A2:E2))
for the population standard deviation.
The Excel 365 version using Let is more readable I think:
=LET(x,COLUMN(A2:E2),
mpy,A2:E2,
n,SUM(mpy),
sumxsq,SUM(mpy*x^2),
sumsqx,SUM(mpy*x)^2,
numerator,sumxsq-sumsqx/n,
SQRT(numerator/n)
)
A bit less obviously, you could get it from the original formula
=SQRT(SUM(A2:E2*(COLUMN(A2:E2)-SUM(A2:E2*COLUMN(A2:E2))/SUM(A2:E2))^2/SUM(A2:E2)))
Again, in Excel 365 you could write this as:
=LET(x,COLUMN(A2:E2),
mpy,A2:E2,
n,SUM(mpy),
xbar,SUM(mpy*x/n),
numerator,SUM(mpy*(x-xbar)^2),
SQRT(numerator/n)
)
Change the denominator to
(SUM(A2:E2)-1)
for the sample standard deviation.
I ended up figuring it out.
I added a column which calculated the average. (Say column F)
I then had a formula like this
=SQRT(SUM(A2*POWER((1-F2),2),B2*POWER((2-F2),2),C2*POWER((3-F2),2),D2*POWER((4-F2),2),E2*POWER((5-F2),2))/SUM(A2:E2))
Essentially this calculated the variance from the mean for each condition value, multiplied by the number of values (e.g. number of meters) of asset that are that particular condition, then did the normal other standard deviation calculations (sum, divide by total, square).
I'm trying to write a SUM(IF(zero, add 8), A1:G1) kind of excel function.
What it should do:
If the cell contains a number, add that number to the sum.
If the cell contains a number = 0, add 8 to the sum.
if the cell is empty, add nothing to the sum
I have tried using SUMIF, but it only "adds the numbers if they meet a criteria", and I rather need "add this when the criteria is met"
You could just make a longer formula:
=SUM(A1:G1)+COUNTIF(A1:G1, 0)*8
The first sum will only do your numbers ignore blanks and 0's, the second part counts the number of 0's and multiplies it by 8.
You can do this with the following formula:
=SUMIF(A1:G1,">0")+8*COUNTIFS(A1:G1,0,A1:G1,"<>")
should be self-explaining :)
Method 1
If you can spare another column, just use an IF statement to replace all 0's by 8's and blanks by 0's (not really necessary) in a new column
=IF(A1=0,8,A1) and take a SUM of this column.
Method 2
Just SUM over your original data, count the number of zeros in your data and multiply this number by 8.
=SUM(A1:A10)+8*COUNTIF(A1:A10,"=0")
Note: The data is in A1:A10 in this case.
When I calculate the median of even numbers for e.g 1,2,3,4,5,6,7,8.. i want the return value to be 5 i.e. the higher value of the two middle values and not the average of 4 & 5. Please help
I don't have Excel, so I can't try it, but I think you should be able to accomplish this with a combination of the LARGE function the COUNT function, and the TRUNC function. For example, if the numbers you are working with are in cells A1 through A8, you should be able to find the answer you want, though technically it's not the median, with the formula
=LARGE(A1:A8,TRUNC(COUNT(A1:A8)/2))
Edit
=LARGE(A1:A8,TRUNC((1+COUNT(A1:A8))/2))
If you know you will always be working with an even number of entries, the call to TRUNC could be omitted.
With data in column A:
=IF(ISODD(COUNT(A:A)),MEDIAN(A:A),ROUNDUP(MEDIAN(A:A),0))
EDIT#1:
Consider the array formula:
=IF(ISODD(COUNT(A:A)),MEDIAN(A:A),MIN(IF(A:A>MEDIAN(A:A),A:A)))
If the number of values is odd, return the median. If the number of value is even, return the smallest value greater than the median.
Array formulas must be entered with Ctrl + Shift + Enter rather than just the Enter key.
This approach does not require the data to be sorted.
EDIT#2:
This array formula appears to handle Ron's case:
=IF(ISODD(COUNT(A:A)),MEDIAN(A:A),MIN(IF(A:A>=MEDIAN(A:A),A:A)))
It returns the smallest value greater than or equal to the median (for the even case)
But I don't know if this is what the Poster wants.
=LARGE(A1:A9,INT((COUNT(A1:A9)/2)+0.5))
you can use Roundafter the Median
in your case you can type: =ROUND(MEDIAN(B4:I4),0)
lets say that the given range is from B4 to I4 from 1 to 8.
I've a Excel spreadsheet and there's summation and multiplication in my last result a have a big number like this
482362534
and what i want to sum this number for example
4+8+2+3+6+2+5+3+4
and show me the result 37 in another column, is there's a function to do this ?
Try it as,
=SUMPRODUCT(--MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1))
I asked a similar question before this but it turned out that whatever formula I was using does not give me the correct result. So I have to reask the question and make it more specific.
Suppose I have the following spreadsheet:
I want a formula which gives me the latest date that have percentage change that is greater than zero and "Orange" is not mentioned in the "Comments" column. Only 1 of the percentage changes (Column Pct1 to Pct 5) needs to be >0. So the formula will output 11/20/2012 since it has % change that is greater than 0% and it is non-Orange.
I tried match, offset, max but it didnt give me the correct result. I am hoping to input this as a formula into VBA because I have a total of 20 excel files that I need to have the macro to check against. Please help me! Thanks!!
{=MAX((B2:F6>0)*(ISERR(FIND("ORANGE",UPPER(G2:G6))))*(A2:A6))}
Enter with Ctrl+Shift+Enter, not just Enter. Don't type the curly braces, Excel will insert them if you enter as an array formula.
The first section returns a matrix of TRUEs and FALSEs based on whether the percentages are greater than zero.
The second section returns TRUEs and FALSES based on whether FINDing "Orange" generates an error.
The last section returns an array of the dates.
When you multiply the arrays/matrices the TRUEs are 1, the FALSEs are 0 and you end up with an array of dates where all the conditions are TRUE. Finally, MAX picks the largest.