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I have a big table with the size of 5,905,635*30 (see figure 1), and a list with the size 5,905,635 of rows (see figure 2). I want to reassign the cells' values in the table, given the elements of the list (see figure 3).
figure 1
figure 2
figure 3
For example, like the codes below, I want to get df2 given df1 and list1; an easy way is to loop the elements of list1, the first element is 'B', so assign the first row of column B to 1 in df1, and the second element is 'C', then assign the second row of column C to 1, and etc. The final result should be df2. The problem with this solution is too slow if I have a big size of table. I wonder if there is a fast way to achieve this goal.
df1 = pd.DataFrame({'A': ['0', '0','0', '0', '0', '0', '0'],
'B': ['0', '0','0', '0', '0', '0', '0'],
'C': ['0', '0','0', '0', '0', '0', '0'],
'D': ['0', '0','0', '0', '0', '0', '0'],
'E': ['0', '0','0', '0', '0', '0', '0']})
list1 = ['B','C','A','E','D','A','D']
df2 = pd.DataFrame({'A': ['0', '0','1', '0', '0', '1', '0'],
'B': ['1', '0','0', '0', '0', '0', '0'],
'C': ['0', '1','0', '0', '0', '0', '0'],
'D': ['0', '0','0', '0', '1', '0', '1'],
'E': ['0', '0','0', '1', '0', '0', '0']})
The problem of this solusion is too slow if I have a big size of the table. I wonder if there is a fast way to achieve this goal.
Suppose I have a list of lists of varying lengths.
list1 = [['0', '0'],['0', '1', '0', ' '],['0', '1', ' ', '0', '1', ' '],['1', '1', ' ', ' ', '1', '1', ' ', '0'],[]]
I want to compare this list against another list of lists:
list2=[['0','0','0','0'],['1','1','1','1']]
Now, I want to check if list2 is contained in list1. The output should be True since list1 has ['1', '1', ' ', ' ', '1', '1', ' ', '0'] which contains ['1','1','1','1']
What would be the best way to check if any of the list2 elements are present in list1? The answer should be a Boolean in case any of the list2 elements are found in list1 by maintaining order.
I have tried quite a few things, but can't seem to get the desired output. Thanks in advance for the suggestions.
This will do the trick
list1 = [['0', '0'], ['0', '1', '0', ' '], ['0', '1', ' ', '0', '1', ' '], ['1', '1', ' ', ' ', '1', '1', ' ', '0'], []]
list2 = [['0', '0', '0', '0'], ['1', '1', '1', '1']]
for i in list2:
string2 = ''.join(i)
for j in list1:
string1 = ''.join(j).replace(' ','')
if string2 in string1:
print('yes',i,j)
# output yes ['1', '1', '1', '1'] ['1', '1', ' ', ' ', '1', '1', ' ', '0']
Simplistic approach:
list1 = [['0', '0'],['0', '1', '0', ' '],['0', '1', ' ', '0', '1', ' '],
['1', '1', ' ', ' ', '1', '1', ' ', '0'],[]]
list2 = [['0','0','0','0'],['1','1','1','1']]
# computing the shortened strings once, storing as string,orignal - tuples
texts = [(''.join(inner).replace(" ",""),inner) for inner in list1]
find = [(''.join(inner).replace(" ",""),inner) for inner in list2]
for (shortened,inner) in texts:
for (pattern,f) in find:
if pattern in shortened:
print("Found", f , "in", inner)
to get
Found ['1', '1', '1', '1'] in ['1', '1', ' ', ' ', '1', '1', ' ', '0']
It is simplistic because it is a quadratic search.
I am trying to separate items in a list by character, and this is done but whenever i run the code it separates the items but shows them separated multiple times. How can I fix this?
I've already tried using range in a for function, but that hasn't worked. The only thing that gives an output is using
for character in x
My code:
def rle():
askq = int(input("How many lines of RLE compressed data do you want to enter?"))
if askq < 2:
print("You must enter at least 2 lines of RLE compressed data.")
rle()
print("Please enter your RLE compressed data one line at a time")
lines = []
for i in range (0, askq):
i = input("Which lines would you like to convert?")
lines.append(i)
num=0
lines_input = [1,num]
lines2 = []
x = []
for i in range(0,askq):
num+=1
if num in lines_input:
x.append(lines[i])
for x in lines:
for character in x:
lines2.append(character)
print(lines2)
rle()
I expect the output of
lines2
to be
["0","1","d","6","1"," ","0","1","b"]
but instead i get
['0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b']
['0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b']
['0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b', '0', '1', 'd', '6', '1', ' ', '0', '1', 'b']
Try this update
def rle():
askq = int(input("How many lines of RLE compressed data do you want to enter?"))
if askq < 2:
print("You must enter at least 2 lines of RLE compressed data.")
rle()
print("Please enter your RLE compressed data one line at a time")
lines = []
for i in range (0, askq):
i = input("Which lines would you like to convert?")
lines.append(i)
new_list = []
for i in lines:
new_list.extend(list(i))
print(new_list)
rle()
I am fresh off the coding boat and I am attempting to have the return values of a python function all print on one line. I know to use print(argument, en= ''), although I cannot include a print function in the return of a defined function.
Ultimately I am trying to get each first item of a list in a list, then the second and so on to print the design turned 90 degrees. I am first getting each list in a for loop then getting each index from there and printing in a second for loop.
With the code the way I have it now, I get the result I need, but there is "None" at the end of each line because I have a print function in a function instead of a "return" so I can have each index value printed on one line per list. I am curious about how to have the values displayed on one line without using the end argument of a print function in a function return. And I would always love to see a better/faster way to achieve this result.
..OO.OO..
.OOOOOOO.
.OOOOOOO.
..OOOOO..
...OOO...
....O....
Thank you!
grid = [['.', '.', '.', '.', '.', '.',],
['.', '0', '0', '.', '.', '.',],
['0', '0', '0', '0', '.', '.',],
['0', '0', '0', '0', '0', '.',],
['.', '0', '0', '0', '0', '0',],
['0', '0', '0', '0', '0', '.',],
['0', '0', '0', '0', '.', '.',],
['.', '0', '0', '.', '.', '.',],
['.', '.', '.', '.', '.', '.',]]
xLength = len(grid[0])-1
yLength = len(grid)-1
listX = list(range(0, xLength))
listY = list(range(0, yLength))
def listGrid(y = 0):
for x in grid:
print(x[y], end = '')
for num in listX:
print(listGrid(num))
You need to return a value from the function - if a function does not return anythin, it returns None implicitly. Your code prints the "data" inside the function and you print the return of the function by
print(listGrid(num)) # prints None
Print the results of your function outside, using end="" is an option:
grid = [['.', '.', '.', '.', '.', '.',],
['.', '0', '0', '.', '.', '.',],
['0', '0', '0', '0', '.', '.',],
['0', '0', '0', '0', '0', '.',],
['.', '0', '0', '0', '0', '0',],
['0', '0', '0', '0', '0', '.',],
['0', '0', '0', '0', '.', '.',],
['.', '0', '0', '.', '.', '.',],
['.', '.', '.', '.', '.', '.',]]
xLength = len(grid[0]) # fix, do not subtract 1 - range is upper border exclusive
yLength = len(grid)-1
listX = list(range(0, xLength))
listY = list(range(0, yLength))
def listGrid(y = 0):
return [x[y] for x in grid] # return a list
for num in listX:
for r in listGrid(num):
print(r, end="")
print()
Or you leverate zip() to make columns from your rows and print them:
# directly operates on your data - you do not need anything of your code beside
# the grid definition
for c in zip(*grid):
print(''.join(c))
Output:
..00.00..
.0000000.
.0000000.
..00000..
...000...
....0....
I am trying to convert a list of strings to a list of letters/numbers but keeping the length of list the same. Here is my list look like,
a = ["0587828028", "2967480535"]
My code to convert the above list to split the string and save in a new list.
new_a = []
for i in range(len(a)):
new_a += a[i]
And the output is on list,
['0', '5', '8', '7', '8', '2', '8', '0', '2', '8', '2', '9', '6', '7', '4', '8', '0', '5', '3', '5']
Desired output should be 2 list:
['0', '5', '8', '7', '8', '2', '8', '0', '2', '8'] ['2', '9', '6', '7', '4', '8', '0', '5', '3', '5']
Any suggestion is much appreciated, I am very new in python.
Just use the built-in list() iterable expansion:
a = ["0587828028", "2967480535"]
new_a = [list(x) for x in a]
# [['0', '5', '8', '7', '8', '2', '8', '0', '2', '8'],
# ['2', '9', '6', '7', '4', '8', '0', '5', '3', '5']]