Trying to get selenium to check a box with python but it seems to keep timing out.
Current code is
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome()
driver.get('https://grabagun.com/giveaway')
WebDriverWait(driver, 5).until(EC.element_to_be_clickable((By.XPATH, '//*[#id="terms_and_conditions"]'))).click()
The error is:
InvalidSelectorException: Message: invalid selector: Unable to locate an element with the xpath expression //*[#id="terms_and_conditions" because of the following error:
SyntaxError: Failed to execute 'evaluate' on 'Document': The string '//*[#id="terms_and_conditions"' is not a valid XPath expression.
Any suggestions?
You could use action chains and the correct lookup:
from selenium.webdriver.common.action_chains import ActionChains
element = driver.find_element(By.ID, "terms_and_conditions")
ActionChains(driver).move_to_element(element).click().perform()
Related
I'm trying to get the attributes of a tag using selenium webdriver and using the xpath as a locator. I gave the xpath to the driver and it returned NoSuchElementException, but when I enter the xpath in the "Inspect element" window, it showed that particular tag, which means the locator does exist. So what's wrong with selenium? Its still the same even if I give the full xpath
from selenium import webdriver
driver = webdriver.Chrome('D:\\chromedriver.exe')
driver.get('https://cq-portal.webomates.com/#/login')
element=driver.find_element_by_xpath("//button[#type='button']")
print(element.get_attribute('class'))
driver.quit()
selenium version = 3.141.0
You need to just give wait to load the page. Your code is perfectly fine. Either give hardcode wait like sleep or presence of element. Both will work.
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium import webdriver
driver = webdriver.Chrome(PATH)
driver.maximize_window()
wait = WebDriverWait(driver, 20)
driver.get('https://cq-portal.webomates.com/#/login')
wait.until(EC.presence_of_element_located((By.XPATH, "//button[#type='button']")))
element = driver.find_element(By.XPATH, "//button[#type='button']")
print(element.get_attribute('class'))
driver.quit()
Output:
btn btn-md btn-primary btn-block
Loops like you are missing a delay.
Please try this:
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium import webdriver
driver = webdriver.Chrome('D:\\chromedriver.exe')
wait = WebDriverWait(driver, 20)
driver.get('https://cq-portal.webomates.com/#/login')
wait.until(EC.visibility_of_element_located((By.XPATH, "//button[#type='button']")))
element=driver.find_element_by_xpath("//button[#type='button']")
print(element.get_attribute('class'))
driver.quit()
I have a problem with selenium find_by_xpath
This is my xpath : //input [#type='text']
And I get this error:
enter image description here
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//input [#type='text']"}
from selenium import webdriver
path="C:\Program Files (x86)\chromedriver.exe"
username="123456"
password="123456"
url="https://www.foxesscloud.com/login"
driver=webdriver.Chrome(path)
driver.get(url)
driver.find_element_by_xpath("//input [#type='text']").send_keys("Pies123")
print("done")
print("Log")
It is because of Elements are not rendered properly and you are trying to interact with them. Please use Explicit wait to handle this situation and error.
driver = webdriver.Chrome(driver_path)
driver.maximize_window()
driver.implicitly_wait(30)
wait = WebDriverWait(driver, 30)
driver.get("https://www.foxesscloud.com/login")
wait.until(EC.visibility_of_element_located((By.XPATH, "//input [#type='text']"))).send_keys('Pies123')
wait.until(EC.visibility_of_element_located((By.XPATH, "//input [#type='password']"))).send_keys('Your password here')
wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button.login-click"))).click()
Imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
I am trying to work with the following site using Python.
Please advise how can I hit the Next button:
I have tried the following:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.action_chains import ActionChains
import time
driver = webdriver.Chrome(executable_path = r'C:/chromedriver.exe')
driver.maximize_window()
wait = WebDriverWait(driver,40)
driver.get('https://www.okcupid.com/login')
driver.execute_script('arguments[0].click();',wait.until(EC.element_to_be_clickable((By.ID, 'username'))))
wait.until(EC.element_to_be_clickable((By.ID, 'username'))).send_keys("abc")
driver.execute_script('arguments[0].click();',wait.until(EC.element_to_be_clickable((By.ID, 'username'))))
wait.until(EC.element_to_be_clickable((By.ID, 'password'))).send_keys("123")
# Find login button
login_button = driver.find_element_by_name('Next')
# Click login
login_button.click()
But got an error:
NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector","selector":"[name="Next"]"}
Name is a an attribute on a webelement. The next button has no Name attribute.
You can try this xpath:
//input[#value='Next']
login_button = driver.find_element_by_xpath('//input[#value="Next"]')
I am getting following error
no such element: Unable to locate element: {"method":"xpath","selector":"//input[#placeholder='User ID']"}
(Session info: chrome=78.0.3904.70). Let me know how can i pass user id here
Without additional context, I can only recommend that you wait on the element before sending keys to it:
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
input = WebDriverWait(driver, 30).until(
EC.visibility_of_element_located((By.XPATH, "//input[#placeholder='User ID']")))
input.send_keys("userId")
Full working sample as requested by asker:
from selenium import webdriver
from time import sleep
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome()
driver.get("https://kite.zerodha.com/connect/login?api_key=b8w63qg9m4c3zubd&sess_id=bW3U1OwidO97o11scfeTbyfX4j5tViNp")
input = WebDriverWait(driver, 30).until(
EC.visibility_of_element_located((By.XPATH, "//input[#placeholder='User ID']")))
input.send_keys("userId")
sleep(10) # this sleep is here so you can visually verify the text was sent.
driver.close()
driver.quit()
The above code has succeeded every time I have run it.
I'm a complete beginner with selenium, sorry if the question is dumb (it is dumb):)
I need to find Speed test link on https://www.netflix.com/ and then click it.
i've tried searching by text and some other options. But nothing seems to work, I don't know why.
from selenium import webdriver
from selenium.webdriver.common.keys import Keysfrom selenium.webdriver.common.keys import Keys
driver = webdriver.Chrome()
driver.get("https://www.netflix.com/")
driver.implicitly_wait(10)
elem = driver.find_element_by_link_text("Speed test")
elem.click()
NoSuchElementException: Message: no such element: Unable to locate element: {"method":"link text","selector":"Sign in"}
(Session info: chrome=75.0.3770.142)
The element with text as Speed Test is out ofthe Viewport so you need to induce WebDriverWait for the desired element to be clickable() and you can use the following Locator Strategy:
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//a[#class='footer-link']/span[text()='Speed Test']"))).click()
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
Use WebDriverWait and element_to_be_clickable with following xpath.
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium import webdriver
driver = webdriver.Chrome()
driver.get("https://www.netflix.com/")
elem = WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH,"//span[#data-uia='data-uia-footer-label'][contains(.,'Speed Test')]")))
elem.click()
Browser snapshot:
To added to this answer you need to use WebDriverWait and then click on the element Show more info
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium import webdriver
driver = webdriver.Chrome()
driver.get("https://www.netflix.com/")
elem = WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH,"//span[#data-uia='data-uia-footer-label'][contains(.,'Speed Test')]")))
elem.click()
WebDriverWait(driver,60).until(EC.element_to_be_clickable((By.XPATH,"//a[contains(.,'Show more info' )]"))).click()