I am looking for some guidance in looping through a function in Excel within a table without running into a circular reference error. I've spent quite some time trying out COUNTIF, MATCH, Essentially, I need to create a function/formula for the "Desired Date" column so that it takes value from the "Original Date" column and changes the value based on the following parameter:
If a date in the Original Date column does not exist within the previous values of the Desired Date column, it will list the exact date. I've already solved this part with IF and COUNTIF functions.
If a date in the Original Date column already exits within the previous values of the "Desired Date" column, it will add +1 day(s) until all the values within the Desired Date column have unique dates.
Here's what I would like the function to do:
Row 1 contains the original date value as 8/1, since no other values exist in the desired row column, it will return 8/1.
Row 2 contains the original date value as 8/1, but since row 1 of the desired date value already contains value 8/1, it will add +1 day so it becomes 8/2.
Row 3 contains the original date value as 8/1, but since row 1 & row 2 of the desired date contain the value, it will add +2 days, so it becomes 8/3.
Row 6 contains the original date value as 8/3, but since row 3 of the desired date contain the value, it will add +1 day so it becomes 8/4.
If at any given point a date within the original date changes, the values in desired dates should change accordingly by adding a variable amount of days until all values within the Desired Dates column are unique.
Row
Original Dates
Desired Dates
1
8/1/2021
8/1/2021
2
8/1/2021
8/2/2021
3
8/1/2021
8/3/2021
4
8/12/2021
8/12/2021
5
8/12/2021
8/13/2021
6
8/3/2021
8/4/2021
7
8/4/2021
8/5/2021
8
8/3/2021
8/6/2021
9
8/13/2021
8/14/2021
I've spent well over 9 hours on this issue so any help at this point would be very much appreciated. I wouldn't mind using VBA but a function would be preferred for compatibility purposes.
Thank You!
One approach might be to generate dates starting with the date in the first column but ignoring any dates that have already been used (countif>0), then pick the lowest of these:
=LET(maxdate,$D$2,
startdate,B2,
seq,SEQUENCE(maxdate-startdate,1,startdate),
MIN(IF(COUNTIF(E$1:E1,seq),maxdate,seq)))
or slightly shorter
=LET(maxdate,$D$2,
startdate,B2,
seq,SEQUENCE(maxdate-startdate,1,startdate),
MIN(IF(COUNTIF(E$1:E1,seq)=0,seq)))
If you don't have Excel 365, you can use Row instead of Sequence:
=MIN(IF(COUNTIF(E$1:E1,ROW(INDEX(A:A,B2):INDEX(A:A,$D$2)))=0,ROW(INDEX(A:A,B2):INDEX(A:A,$D$2))))
entered as an array formula using CtrlShiftEnter
EDIT
If you wanted to concatenate as in your comment, you wouldn't be able to use Min (because the values wouldn't be numeric) but you could use index/match to find the first available date for a particular person:
=LET(maxdate,$D$2,
startdate,A2,
name,B2,
seq,SEQUENCE(maxdate-startdate,1,startdate),
seqName,seq&name,
INDEX(seqName,MATCH(0,COUNTIF(H$1:H1,seqName),0)))
If you wanted to make the dates appear as a date rather than a number, you could wrap them in Text:
=LET(maxdate,$D$2,
startdate,A2,
name,B2,
seq,SEQUENCE(maxdate-startdate,1,startdate),
seqName,TEXT(seq,"mm/dd/yy")&name,
INDEX(seqName,MATCH(0,COUNTIF(H$1:H1,seqName),0)))
I have an Excel sheet with dates in the rows. A given month should be used only once in a row. How can I filter out, if there are two dates in the same row from the same month?
For example I have the following array, and I would like to have as a result, that there is a match in this row (2012-03).
2012-03-04 2012-02-05 2012-04-06 2012-03-07 2012-10-08 2012-11-09 2012-12-10
I have tried to combine aggregate and match functions, but I cannot find out how to do it properly.
One of my codes, of course it gave an error:
=aggregate(9,6,(MATCH("*"&LEFT(A8,7)&"*","*"&LEFT(b8,7)&"*",0), MATCH("*"&LEFT(b8,7)&"*","*"&LEFT(c8,7)&"*",0)))
Ok, now I have tried another way, and I could get a solution, but with a code which is like a km long...I have first created a new dataset, cutting down the days by using: =""&LEFT(A8,7)&""
Then I have compared all the cells in a given row of my new dataset. Could someone help me how to shorten the exact( ) parts? The aim is to compare all.
=if((or(exact(A2, B2), exact(A2,C2),exact(A2,D2),exact(A2,E2),exact(A2,F2),exact(A2,G2),exact(A2,H2),exact(A2,I2),exact(A2,J2),exact(A2,K2),exact(A2,L2),exact(A2,M2),exact(A2,N2),exact(A2,O2),exact(A2,P2),exact(A2,Q2),exact(A2,R2),exact(B2,C2),exact(B2,D2),exact(B2,E2),exact(B2,F2),exact(B2,G2),exact(B2,H2),exact(B2,I2),exact(B2,J2),exact(B2,K2),exact(B2,L2),exact(B2,M2),exact(B2,N2),exact(B2,O2),exact(B2,P2),exact(B2,Q2),exact(B2,R2),exact(C2,D2),exact(C2,E2),exact(C2,F2),exact(C2,G2),exact(C2,H2),exact(C2,I2),exact(C2,J2),exact(C2,K2),exact(C2,K2),exact(C2,L2),exact(C2,M2),exact(C2,N2),exact(C2,O2),exact(C2,P2),exact(C2,Q2),exact(C2,R2),exact(D2,E2),exact(D2,F2),exact(D2,G2),exact(D2,H2),exact(D2,I2),exact(D2,J2),exact(D2,K2),exact(D2,L2),exact(D2,M2),exact(D2,N2),exact(D2,O2),exact(D2,P2),exact(D2,Q2),exact(D2,R2),exact(E2,F2),exact(E2,G2),exact(E2,H2),exact(E2,I2),exact(E2,J2),exact(E2,K2),exact(E2,L2),exact(E2,M2),exact(E2,N2),exact(E2,O2),exact(E2,P2),exact(E2,Q2),exact(E2,R2),exact(F2,G2),exact(F2,H2),exact(F2,I2),exact(F2,J2),exact(F2,K2),exact(F2,L2),exact(F2,M2),exact(F2,N2),exact(F2,O2),exact(F2,P2),exact(F2,Q2),exact(F2,R2),exact(G2,H2),exact(G2,I2),exact(G2,J2),exact(G2,K2),exact(G2,L2),exact(G2,M2),exact(G2,N2),exact(G2,O2),exact(G2,P2),exact(G2,Q2),exact(G2,R2),exact(H2,I2),exact(H2,J2),exact(H2,K2),exact(H2,L2),exact(H2,M2),exact(H2,N2),exact(H2,O2),exact(H2,P2),exact(H2,Q2),exact(H2,R2),exact(I2,J2),exact(I2,K2),exact(I2,L2),exact(I2,M2),exact(I2,N2),exact(I2,O2),exact(I2,P2),exact(I2,Q2),exact(I2,R2),exact(J2,K2),exact(J2,L2),exact(J2,M2),exact(J2,N2),exact(J2,O2),exact(J2,P2),exact(J2,Q2),exact(J2,R2),exact(K2,L2),exact(K2,M2),exact(K2,N2),exact(K2,O2),exact(K2,P2),exact(K2,Q2),exact(K2,R2),exact(L2,M2),exact(L2,N2),exact(L2,O2),exact(L2,P2),exact(L2,Q2),exact(L2,R2),exact(M2,N2),exact(M2,O2),exact(M2,P2),exact(M2,Q2),exact(M2,R2),exact(N2,O2),exact(N2,P2),exact(N2,Q2),exact(N2,R2),exact(O2,P2),exact(O2,Q2),exact(O2,R2),exact(P2,Q2),exact(P2,R2),exact(Q2,R2))),"same month","ok")
Thank you in advance.
I am not sure if there is a better way, but this is how I'd tackle the problem based on my Excel knowledge:
Add data of dates above in cells A1-G1
On row below date add formulas for dates: A2=DATE(A1) ..... G2=DATE(G1)
At the end of the original row of dates add the numbers 1 thru 12:
using formula cell H1=1, I1=H1+1 ..... S1=R1+1
After the months on row 2:H2=COUNTIF($A2:$G2,H1) ..... S2=COUNTIF($A2:$G2,S1)Counting frequency for each of the 12 months
T2=MAX(H2:S2)
Then select on cell T2being more than 1.
Here it is as a Google sheet (you can download it and open in Excel if you want)
Maybe this will help. Assume that the range of dates is in $A$1:$G$1. Also assume that the entries are numerical dates; if they are instead text you can handle this by using the DATEVALUE function. Then we can get the years and months of the range with:
{=YEAR($A$1:$G$1)}
{=MONTH($A$1:$G$1))
This and all other formulas must be entered as array formulas (CrtlShiftEnter).
We next convert back to a date, but use 1 for the day, so that all dates get shifted to the first day of the month (this means that any dates from the same month are shifted to the same date):
{=DATE(YEARS,MONTHS,1)}
We can produce an NxN comparison of the shifted dates by:
{=TRANSPOSE(SHIFTED_DATES)=SHIFTED_DATES}
We can count the number of True's in this array by:
{=SUM(--(ARRAY))}
If there we no dates from the same month we'd expect this to sum to N because this method compare each date to itself as well as the other dates. The causes the N elements on the main diagonal of this array to be True. If any dates are in the same month off-diagonal elements will also be True. So to detect if there are dates from the same month we make the comparison:
{=SUM(--(ARRAY)) > N}
or more generally:
{=SUM(--(ARRAY)) > COUNT($A$1:$G$1)}
Rolling all of these up into one formula:
=IF(SUM(--(TRANSPOSE(DATE(YEAR($A$1:$G$1),MONTH($A$1:$G$1),1))=DATE(YEAR($A$1:$G$1),MONTH($A$1:$G$1),1)))>COUNT(DATE(YEAR($A$1:$G$1),MONTH($A$1:$G$1),1)),"same month","ok")
If your dates are in a range other than $A$1:$G$1 then make the appropriate substitutions.
Hope that helps.
This formulae "works", but it seems a bit long winded. Can anyone suggest an "easier" formulae. It returns the value in the 5th Column to a date in the 1st column which is called from a separate (and discrete) worksheet. If there is no data in the 5th column (because we haven't reached or passed that date), then the latest available data is called ($A$20, is the "calling date, on a current worksheet):-
IF(VLOOKUP($A$20,'[FTSE100.xlsx]Meteor Step Down
Plans'!$A$18:$E$2828,5)="",VLOOKUP(HLOOKUP(A20,'[FTSE100.xlsx]Meteor Step
Down Plans'!$A$18:$A$2628,MATCH(TRUE,INDEX(ISBLANK('[FTSE100.xlsx]Meteor
Step Down Plans'!$E$18:$E$2828),0,0),0)-1),'[FTSE100.xlsx]Meteor Step Down
Plans'!$A$18:$E$2828,5),VLOOKUP($A$20,'[FTSE100.xlsx]Meteor Step Down
Plans'!$A$18:$E$2828,5))
The formula is in a different workbook to the data. The formula is used to determine the last value in an array, the first column of which is a date range (01/01/2000 to 31/12/2027....say) The required data is in column 5. Entries may be up to date (i.e. the last entry was made today, therefore it will pickup todays value. The last entry may have been several days (weeks) ago, therefore it will pick up the last value in the designated column (column 5). I don't see why it can't go into a named range, as the array size is fixed. Does that help?
Thanks Ron, nearly there. That works beautifully for "missing" dates in the array. i.e. when Saturday and Sunday dates are missing, it finds the value (in column 5) of the previous Friday. However (and there is usually a "however"), if $A$20 is a date in advance of the date of the last data in the array i.e. column 5 is blank at that date, your formulae returns 0 (zero), instead of the data as at the last date that data has been entered. i.e. enter 02/04/2018 and your formulae returns 0, not the data at the last date available 28/02/2018. Is that a little more clear?? (Thank you anyway, for spending the time - I'm still trying to work out how your formulae works as it does. Is the "/" significant (other than being a "divide by" symbol, if so it's something I've never come across before? Regards...........Mike. P.S. The dates in the array (Column 1) are all in from 2016 to 2027 (excluding weekend and bank holidays), and are arranged in ascending order i.e. from 01/01/2016 to 31/12/2027
Ron - Sorry mate, buy I can't see a "second" formulae???
If I understand what you want to do correctly, (and that is hard to do since you give NO examples of your data, actual output or desired output), try:
=LOOKUP(2,1/((myDate>=A:A)*(LEN(A:A)>0)),E:E)
If it is the case that you have dates in column A and no entries in Column E, then you might have to do something like:
=LOOKUP(2,1/((myDate>=A:A)*(LEN(A:A)>0)*(LEN(E:E)>0)),E:E)
Of course, you will have to modify the cell references and named range to refer to the proper workbooks and cell.
Possibly something like:
=LOOKUP(2,1/(($A$20>='[FTSE100.xlsx]Meteor Step Down Plans'!$A$18:$E$2828)*(LEN('[FTSE100.xlsx]Meteor Step Down Plans'!$A$18:$E$2828)>0)),'[FTSE100.xlsx]Meteor Step Down Plans'!$E$18:$E$2828)
This should return the item from Column E that is either at or above the same row as myDate in Column A. If myDate does not exist in column A, it will match the nearest earlier date in Column A and return from that row in Column E.
In the second version of the formula, it also checks that there is an entry in Column E matching the column A date, and, if not, it will look above.