Move files to folder by date in a bash script - linux

Question

I have few files named as per year+month+date format.
Example:
20220101
20220102
20220103
20220104
..
20220130
20220131
As the file generated daily, I need to move 1st 2(20220101,20220102) and last 2(20220130,20220131) files in a specific folder every month. Can someone help me out how can I write the script?

Answer 1

This helped me a long back -
#!/bin/bash
DIR=/Users/limeworks/Downloads/target
target=$DIR
cd "$DIR"
for file in *; do
# Top tear folder name
year=$(stat -f "%Sm" -t "%Y" $file)
# Secondary folder name
subfolderName=$(stat -f "%Sm" -t "%d-%m-%Y" $file)
if [ ! -d "$target/$year" ]; then
mkdir "$target/$year"
echo "starting new year: $year"
fi
if [ ! -d "$target/$year/$subfolderName" ]; then
mkdir "$target/$year/$subfolderName"
echo "starting new day & month folder: $subfolderName"
fi
echo "moving file $file"
mv "$file" "$target/$year/$subfolderName"
done

Answer 2

well if you want to do this in bash i would suggest having a single script file and one log file to keep track of the current month/previous month.
#!/bin/bash
x=$(date +%D | cut -c 4,5 | sed 's|0||g')
y=$(sed -n 1p date.log 2>/dev/null)
if ! [ -d date.log ]; then
printf "$x" > date.log
exit 0
fi
if [[ $y -ge 0 && $y -le 12 && $x != $y ]]; then
#if the current month equal the previous month then everthing here will be exicuted
echo "a new month is here"
else
sed -i "1s/^.*$/$x/" date.log
fi
what this script essentially dose is that it creates log file containing the current month "if it doesn't already exist and". After that "if executed again" it matches the new month value to the one contained in the log file if it doesn't match it executes everything where the commented text is which is most likely a bunch of mv commands.

Answer 3

Try this Shellcheck-clean code:
#! /bin/bash -p
datefiles=( 20[0-9][0-9][01][0-9][0-3][0-9] )
mv -n -v -- "${datefiles[#]:0:2}" "${datefiles[#]: -2}" /path/to/folder
datefiles=( 20[0-9][0-9][01][0-9][0-3][0-9] ) makes an array of the files in the current directory with date-formatted names, sorted by name.
"${datefiles[#]:0:2}" expands to the first two elements in the datefiles array.
"${datefiles[#]: -2}" expands to the last two elements in the datefiles array.
You'll need to change /path/to/folder.
Unless it is absolutely guaranteed that there will always be at least 4 date files, you should add a check on the number of files found (eg. if (( ${#datefiles[*]} >= 4 )) ...).

Answer 4

$ string="20220101 20220102 20220103 20220104 .. 20220130 20220131"
$ awk '{ print |"mv " $1" "$2" "$(NF-1)" "$NF " /your/folder"}' <<<"$string"
or
$ myArray=(20220101 20220102 20220103 20220104 .. 20220130 20220131)
$ mv ${myArray[0]} ${myArray[1]} ${myArray[-2]} ${myArray[-1]} /your/folder
Files to array
$ myArray=($(find /path/to/files -mindepth 1 -maxdepth 1 -type f -name "[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]" -print0))
or
$ readarray myArray < <(find /path/to/files -mindepth 1 -maxdepth 1 -type f -name "[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]")

Answer 5

My purpose has been served.
`
for i in {1..12}; do
mv $(date -d "20220101 $i months" +'%Y%m%d') /path/to/folder/
mv $(date -d "20220102 $i months" +'%Y%m%d') /path/to/folder/
mv $(date -d "20220101 + $i month - 1 day" +'%Y%m%d') /path/to/folder/
mv $(date -d "20220101 + $i month - 2 day" +'%Y%m%d') /path/to/folder/
done
`
that's the solution.
thanks everyone who has been participated.