How to return the fields defined by the interface not by the mongoose schema - node.js

Question

How can I return "id" insted of "_id" and without "__v" to the client with express, mongoose and TypeScript?
My code below:
Interface
export default interface Domain {
name: string;
objects: DomainObject[]
}
Creation Interface
export default interface DomainCreate {
name: string
}
Mongoose Model
const DomainSchema = new Schema<Domain>({
name: { type: String, required: true },
});
const DomainModel = mongoose.model<Domain>("Domain", DomainSchema);
export { DomainModel, DomainSchema };
Service
export default class DomainService {
public async create(params: DomainCreate): Promise<Domain> {
const domainModel = new DomainModel<Domain>({name: params.name, objects: []});
const domainCreated = await domainModel.save().then();
return domainCreated;
}
}
Controller (POST)
#Post()
#SuccessResponse("201", "Created")
#Response<ValidateErrorJSON>(422, "Validation Failed")
#Response<UnauthorizedErrorJson>(401, "Unauthorized")
#Security("api_key")
public async createDomain(#Body() requestBody: DomainCreate): Promise<Domain> {
const createdDomain = await new DomainService().create(requestBody);
if (createdDomain) this.setStatus(201);
else this.setStatus(500);
return createdDomain;
}
Test:
POST http://localhost:3000/domains
{
"name": "D1"
}
Response:
{
"name": "D1",
"_id": "6291e582ade3b0f8be6921dd",
"__v": 0
}
Expected response:
{
"name": "D1",
"id": "6291e582ade3b0f8be6921dd"
}

Answer 1

There can be different ways to do it, but you can choose normalize-mongoose. It will remove _id, __v and gives you id;
So, in your schema you can add this plugin like this:
import normalize from 'normalize-mongoose';
const DomainSchema = new Schema<Domain>({
name: { type: String, required: true },
});
DomainSchema.plugin(normalize);
const DomainModel = mongoose.model<Domain>("Domain", DomainSchema);
export { DomainModel, DomainSchema };