Is there any way in python to fill in the fields of a form (first name, last name) by taking them randomly from 2 pre-filled lists (name list and surname list)? And instead automatically randomise, without taking data from a list, the selection of the date of birth by keeping it over a certain range (e.g. 19 to 32 years)?
Thanks in advance for the help.
Try using choice function from random module.
from random import choice
names = ['a','b','c']
random_name = choice(names) # use this for getting random names and surnames
for selecting a random date from a range, you can look at this post
Generate a random date between two other dates
Related
I'm trying to write a python script that finds unique values (names) and reports the frequency of their occurrence, making use of Pandas library. There's a total of around 90 unique names, which I've anonymised in the head of the dataframe pasted below.
,1,2,3,4,5
0,monday09-01-2022,tuesday10-01-2022,wednesday11-01-2022,thursday12-01-2022,friday13-01-2022
1,Anonymous 1,Anonymous 1,Anonymous 1,Anonymous 1,
2,Anonymous 2,Anonymous 4,Anonymous 5,Anonymous 5,Anonymous 5
3,Anonymous 3,Anonymous 3,,Anonymous 6,Anonymous 3
4,,,,,
I'm trying to drop any row (the full row) that contains the regex expression "^monday.*", intending to indicate the word "monday" followed by any other number of random characters. I want to drop/deselect any cell/value within that row.
To achieve this goal, I've tried using the line of code below (and many other approaches I found on SO).
df = df[df[1].str.contains("^monday.*", case = True, regex=True) == False]
To clarify, I'm trying to search values of column "1" for the value "^.monday.*" and then deselecting the rows and all values in that row that match the regex expression. I've succesfully removed "monday09-01-2022" and "tuesday10-01-2022" etc.. but I'm also losing random names that are not in the matching rows.
Any help would be very much appreciated! Thank you!
I am trying to separate a single number (or multiple) from a list of randomly generated list without any repeating values. This random list can be, for example, a range of 7 values from 1-45, then take one or more of those values from the list and use the same range but cannot be the same as the values inside the main list.
import random
rndList = []
rndList = random.sample(range(1,45), 7)
rndList.sort()
print("Some numbers...", rndList[0:6])
print("Separate number...", rndList[6])
This will output a random and sorted list, e.g. [5,12,28,35,39,41] and the last separate value from the list, e.g. [43]. The problem is that the last number will always be greater than the previous whereas I need it to be between 1-45 but never use repeated values from the list.
Is it possible to select the separate value randomly from the list instead of creating another list? Appreciate the help!
The easiest thing would simply be to make your selection and remove it from the list before you sort the list.
rndList = random.sample(range(1,45), 7)
separate = rndList.pop()
rndList.sort()
print("Some numbers...", rndList)
print("Separate number...", separate)
I am working with some weather data that is missing some values (indicated via value code). For example, if SLP data is missing, it is assigned code 99999. I was able to use a window function to calculate a 7 day average and save it as a new column. A significantly reduced example of a single row is shown below:
SLP_ORIGIN
SLP_ORIGIN_7DAY_AVG
99999
11945.823516044207
I'm trying to write code such that when SLP_ORIGIN has the missing code it gets replaced using the SLP_ORIGIN_7DAY_AVG value. However, most code explains how to replace a column value based on a conditional with a constant value, not the column value. I tried using the following:
train_impute = train.withColumn("SLP_ORIGIN", \
when(train["SLP_ORIGIN"] == 99999, train["SLP_ORIGIN_7DAY_AVG"]).otherwise(train["SLP_ORIGIN"]))
where the dataframe is called train.
When I perform a count on the SLP_ORIGIN column using train.where("SLP_ORIGIN = 99999").count() I get the same count from before I attempted replacing the value in that column. I have already checked and my SLP_ORIGIN_7DAY_AVG does not have any values that match the missing code.
So how do I actually replace the 99999 values in the SLP_ORIGIN column with the associated SLP_ORIGIN_7DAY_AVG value?
EVEN BETTER, is there a way to do this replacement and window calculation without making a 7 day average column (I have other variables I need to do the same thing with so I'm hoping there is a more efficient way to do this).
Make sure to double check with dataframe you are verifying on.
I was using train.where("SLP_ORIGIN = 99999").count() when I should have been using train_impute.where("SLP_ORIGIN = 99999").count()
Additionally, instead of making a whole new column to store the imputed 7 day average, one can only calculate the average when the missing value code is present:
train = train.withColumn("SLP_ORIGIN", when(train["SLP_ORIGIN"] == 99999, f.avg('SLP_ORIGIN').over(w)).otherwise(train["SLP_ORIGIN"]))\
I am trying to import the data from an excel sheet in which there are 3 columns (Time; Id; and Data).
The first column contains time (in seconds) while the next column has numbers (Id). The third column (Data), however, has hexadecimal numbers, therefore Matlab is unable to process that information and shows 'NaN' in the command window/structure whenever I try to retrieve any information from the third column.
I want to create a structure for each Ids and display the respective information inside that Id.
Hence is there anyway to obtain the information from the third column without getting NaN error?
Here's my code:
[dat1, dat2, dat3] = xlsread('1');
flds=dat3(1,:);
bus=cell2struct(dat3(2:end,:),flds,2);
for k=1:length(bus)
if bus(k).Id == 150
i=i+1;
can_bus(k,:)
end
end
You can get the raw text and do the conversion yourselves:
To get the text, you have to get other output parameters
from xlsread. For example:
[num,txt,raw] = xlsread('file.xls');
will return the numeric values in num, the text values in txt, and
the raw cell data in raw.
Source
This is a pretty complicated question so be prepared! I want to generate some test data in excel for my EAV table. The columns I have are:
user_id, attribute, value
Each user_id will repeat for a random number of times between 1-4, and for each entry I want to pick a random attribute from a list, and then a random value which this can take on. Lastly I want the attributes for each id entry to be unique i.e. I do not want more than one entry with the same id and attribute. Below is an example of what I mean:
user_id attribute value
100001 gender male
100001 religion jewish
100001 university imperial
100002 gender female
100002 course physics
Possible values:
attribute value
gender male
female
course maths
physics
chemistry
university imperial
cambridge
oxford
ucl
religion jewish
hindu
christian
muslim
Sorry that the table above messed up. I don't know how to paste into here while retaining the structure! Hopefully you can see what I'm talking about otherwise I can get a screenshot.
How can I do this? In the past I have generated random data using a random number generator and a VLOOKUP but this is a bit out of my league.
My approach is to create a table with all four attributes for each ID and then filter that table randomly to get between one and four filtered rows per ID. I assigned a random value to each attribute. The basic setup looks like this:
To the left is the randomized eav table and to the left is the lookup table used for the randomized values. Here's the formulas. Enter them and copy down:
Column A - Establishes a random number every four digits. This determines the attribute that must be selected:
=IF(COUNTIF(C$2:C2,C2)=1,RANDBETWEEN(1,4),A1)
Column B - Uses the formula in A to determine if row is included:
=IF(COUNTIF(C$2:C2,C2)=A2,TRUE,RANDBETWEEN(0,1)=1)
Column C - Creates the IDs, starting with 100,001:
=(INT((ROW()-2)/4)+100000)+1
Column D - Repeats the four attributes:
=CHOOSE(MOD(ROW()-2,4)+1,"gender","course","university","religion")
Column E - Finds the first occurence of the Column D attribute in the lookup table and selects a randomly offset value:
=INDEX($H$2:$H$14,(MATCH(D2,$G$2:$G$14,0))+RANDBETWEEN(0,COUNTIF($G$2:$G$14,D2)-1))
When you filter on the TRUEs in Column B you'll get your list of one to four Attributes per ID. Disconcertingly, the filtering forces a recalculation, so the filtered list will no longer say TRUE for every cell in column B.
If this was mine I'd automate it a little more, perhaps by putting the "magic number" 4 in it's own cell (the count of attributes).
There are a number of ways to do this. You could use either perl or python. Both have modules for working with spreadsheets. In this case, I used python and the openpyxl module.
# File: datagen.py
# Usage: datagen.py <excel (.xlsx) filename to store data>
# Example: datagen.py myfile.xlsx
import sys
import random
from openpyxl import Workbook
from openpyxl.cell import get_column_letter
# verify that user specified an argument
if len(sys.argv) < 2:
print "Specify an excel filename to save the data, e.g myfile.xlsx"
exit(-1)
# get the excel workbook and worksheet objects
wb = Workbook()
ws = wb.get_active_sheet()
# Modify this line to specify the range of user ids
ids = range(100001, 100100)
# data structure for the attributes and values
data = { 'gender': ['male', 'female'],
'course': ['maths', 'physics', 'chemistry'],
'university': ['imperial','cambridge','oxford', 'ucla'],
'religion': ['jewish', 'hindu', 'christian','muslim']}
# Write column headers in the spreadsheet
ws.cell('%s%s'%('A', 1)).value = 'user_id'
ws.cell('%s%s'%('B', 1)).value = 'attribute'
ws.cell('%s%s'%('C', 1)).value = 'value'
row = 1
# Loop through each user id
for user_id in ids:
# randomly select how many attributes to use
attr_cnt = random.randint(1,4)
attributes = data.keys()
for idx in range(attr_cnt):
# randomly select attribute
attr = random.choice(attributes)
# remove the selected attribute from further selection for this user id
attributes.remove(attr)
# randomly select a value for the attribute
value = random.choice(data[attr])
row = row + 1
# write the values for the current row in the spreadsheet
ws.cell('%s%s'%('A', row)).value = user_id
ws.cell('%s%s'%('B', row)).value = attr
ws.cell('%s%s'%('C', row)).value = value
# save the spreadsheet using the filename specified on the cmd line
wb.save(filename = sys.argv[1])
print "Done!"