Snowflake operator (airflow) not rendering SQL properly - python-3.x

Question

I am trying to run a simple SQL Query using Airflow provider Snowflake (1.3.0)
SnowflakeOperator(
task_id=f'task',
snowflake_conn_id='snowflake_conn',
parameters={
"table": "dummy_table",
},
sql=["delete from %(table)s"],
autocommit=True,
dag=dag,
)
The SQL it is rendering is delete from ''dummy''. I want to get rid of '' but have tried everything and nothing seems to be working

Answer 1

To parametrize table name IDENFITIER should be used:
To use an object name specified in a literal or variable, use IDENTIFIER().
sql=["delete from IDENTIFIER(%(table)s)"],
The query DELETE FROM 'dummy' is not correct, but DELETE FROM IDENTIFIER('dummy') will work.
CREATE TABLE dummy(id INT);
DELETE FROM 'dummy';
-- Syntax error: unexpected ''dummy''. (line 4)
DELETE FROM IDENTIFIER('dummy');
-- number of rows deleted: 0

Answer 2

If you are using parameters then it's up to SQLAlchemy. You can find more information about it in How to render a .sql file with parameters in MySqlOperator in Airflow?
Alternatively, you can use Airflow rendering (Jinja engine) with params:
SnowflakeOperator(
task_id=f'task',
snowflake_conn_id='snowflake_conn',
params={
"table": "dummy_table",
},
sql=["delete from {{ params.table }}"],
autocommit=True,
dag=dag,
)
This will be rendered as:
thus the query that will be submitted to Snowflake is:
delete from dummy_table