Use the Laplace transform to analyze the following fourth order filter and obtain the transfer function.Calculate the final transfer function . R1 =2kΩ R2=4kΩ R3=1kΩ C1=200nF C2=500nFenter image description here
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I need to calculate the mean average precision (mAP) of specific keypoints (and not for all keypoints, as it done by default).
Here's my code :
from pycocotools.coco import COCO
from pycocotools.cocoeval import COCOeval
# https://github.com/cocodataset/cocoapi/blob/master/PythonAPI/pycocoEvalDemo.ipynb
cocoGt = COCO('annotations/person_keypoints_val2017.json') # initialize COCO ground truth api
cocoDt = cocoGt.loadRes('detections/results.json') # initialize COCO pred api
cat_ids = cocoGt.getCatIds(catNms=['person'])
imgIds = cocoGt.getImgIds(catIds=cat_ids)
cocoEval = COCOeval(cocoGt, cocoDt, 'keypoints')
cocoEval.params.imgIds = imgIds
cocoEval.evaluate()
cocoEval.accumulate()
cocoEval.summarize()
print(cocoEval.stats[0])
This code prints the mAP for all keypoints ['nose', ...,'right_ankle'] but I need only for few specific keypoints like ['nose', 'left_hip', 'right_hip']
I recently solved this and evaluated only the 13 key points, leaving behind the eyes and the ears as per my application.
Just open the cocoeval.py under pycocotools, then head over to the computeOKS function, where you will encounter two sets of keypoints—ground truth keypoints—and detection keypoints, such as a NumPy array.
Make sure to do proper slicing for that 51 array size Python lists.
For example, if you wish to only check the mAP for nose, the slicing would be as follows:
g= np.array(gt['keypoints'][0:3])
Similarly, do it for a dt array.
Also, set the sigma values of those unwanted key points to 0.
You are all set!
Currently I have the following code using TimeseriesGenerator from Keras:
TimeseriesGenerator(train, prediction, length=TIME_STEPS, batch_size=1)
Currently this shifts prediction one value backwards, so the train data for t will have the output of t+1. Which makes sense, but I want to predict t+2, thus train data for t will have the output of t+2.
Is there any way to do it using TimeseriesGenerator?
The quickest solution is to just shift your predictions by 1, ie.:
TimeseriesGenerator(train[:-1], prediction[1:], length=TIME_STEPS, batch_size=1)
Note that you have to trim the train set, so both datasets have equal lengths.
You can also use the timeseries_dataset_from_array function where you can align the data and targets according to your needs as you can read in the documentation:
data: Numpy array or eager tensor containing consecutive data points
(timesteps). Axis 0 is expected to be the time dimension.
targets:
Targets corresponding to timesteps in data. It should have same length
as data. targets[i] should be the target corresponding to the window
that starts at index i (see example 2 below). Pass None if you don't
have target data (in this case the dataset will only yield the input
data).
So in your case it would be something like this:
tf.keras.preprocessing.timeseries_dataset_from_array(
train[:-TIME_STEPS-2],
prediction[TIME_STEPS+2:],
length=TIME_STEPS,
batch_size=1
)
I have written a short Octave script for grabbing and summing the individual FFT's of each row in an image. When I plot the summed FFT's, I get the usual FFT mirror from the real values (which is fine), but I also get a secondary nested mirror. I don't understand why I am getting the nested mirror. The nested mirror has a lower amplitude, but the peak locations have a 1 to 1 correspondence to each other. Please help me understand why the nested mirror.
This is what the original image looks like:
Note that the linked image is downsampled from the original and will not display the behavior shown. I've posted the original image here: https://1drv.ms/u/s!AhAaA6XQyp6gqp1NgKNqL4QmcMw5Pw?e=P7rdRy
The image is acquired from a Fourier Transform spectrometer. The fringes are the interference pattern of the different wavelengths of light. The spectrum of the light source is derived by doing the FFT.
And finally here is the script:
#get image and convert to grayscale...
sum = abs(fftn(gray(1,:))); #get first row FFT and init sum
for i = 2:(rows(gray))
sum += abs(fftn(gray(i,:))); # add each row FFT together
end;
sum = sum/max(sum); # normalize 0-1 scale
sumHalf = sum(1:(end/2)); # move to single sided FFT
sumHalf = 2*sumHalf;
x = 1:numel(sumHalf);
sumHalf(1) = 0; #removed oversized DC component
semilogy(x,sumHalf); #plot in log scale
I have set of images on which I performed edge detection using OpenCV 3.1. The edges are stored in MAT of OpenCV. Can someone help me in processing for Java SVM train and test code on those set of images ?
Following discussion in comments I am providing you with an example project which I built for android studio a while back.
This was used to classify images depending on Lab color spaces.
//1.a Assign the parameters for SVM training here
double nu = 0.999D;
double gamma = 0.4D;
double epsilon = 0.01D;
double coef0 = 0;
//kernel types are Linear(0), Poly(1), RBF(2), Sigmoid(3)
//For Poly(1) set degree and gamma
double degree = 2;
int kernel_type = 4;
//1.b Create an SVM object
SVM B_channel_svm = SVM.create();
B_channel_svm.setType(104);
B_channel_svm.setNu(nu);
B_channel_svm.setCoef0(coef0);
B_channel_svm.setKernel(kernel_type);
B_channel_svm.setDegree(degree);
B_channel_svm.setGamma(gamma);
B_channel_svm.setTermCriteria(new TermCriteria(2, 10, epsilon));
// Repeat Step 1.b for the number of SVMs.
//2. Train the SVM
// Note: training_data - If your image has n rows and m columns, you have to make a matrix of size (n*m, o), where o is the number of labels.
// Note: Label_data is same as above, n rows and m columns, make a matrix of size (n*m, o) where o is the number of labels.
// Note: Very Important - Train the SVM for the entire data as training input and the specific column of the Label_data as the Label. Here, I train the data using B, G and R channels and hence, the name B_channel_SVM. I make 3 different SVM objects separately but you can do this by creating only one object also.
B_channel_svm.train(training_data, Ml.ROW_SAMPLE, Label_data.col(0));
G_channel_svm.train(training_data, Ml.ROW_SAMPLE, Label_data.col(1));
R_channel_svm.train(training_data, Ml.ROW_SAMPLE, Label_data.col(2));
// Now after training we "predict" the outcome for a sample from the trained SVM. But first, lets prepare the Test data.
// As above for the training data, make a matrix of (n*m, o) and use the columns to predict. So, since I created 3 different SVMs, I will input three separate matrices for the three SVMs of size (n*m, 1).
//3. Predict the testing data outcome using the trained SVM.
B_channel_svm.predict(scene_ml_input, predicted_final_B, StatModel.RAW_OUTPUT);
G_channel_svm.predict(scene_ml_input, predicted_final_G, StatModel.RAW_OUTPUT);
R_channel_svm.predict(scene_ml_input, predicted_final_R, StatModel.RAW_OUTPUT);
//4. Here, predicted_final_ are matrices which gives you the final value as in Label(0,1,2... etc) for the input data (edge profile in your case)
Now, I hope you have an idea for how SVM works. You basically need to do these steps:
Step 1: Identify labels - In your case Gestures from edge profile.
Step 2: Assign values to the labels - For example, if you are trying to classify haptic gestures - Open Hand = 1, Closed Hand/Fist = 2, Thumbs up = 3 and so on.
Step 3: Prepare the training data (edge profiles) and Labels (1,2,3) etc. according to the process above.
Step 4: Prepare data for prediction using the transformation calculated using SVM.
Very Important for SVM on OpenCV - Normalize your data, make sure you all matrices are of Same Type - CvType
Hope it helps. Feel free to ask questions if you have any doubts and post what you have tried. I can solve the problem for you if you send me some images but then you won't learn anything right? ;)
I'm trying to perform feature selection by evaluating my regressions coefficient outputs, and select the features with the highest magnitude coefficients. The problem is, I don't know how to get the respective features, as only coefficients are returned form the coef._ attribute. The documentation says:
Estimated coefficients for the linear regression problem. If multiple
targets are passed during the fit (y 2D), this is a 2D array of
shape (n_targets, n_features), while if only one target is passed,
this is a 1D array of length n_features.
I am passing into my regression.fit(A,B), where A is a 2-D array, with tfidf value for each feature in a document. Example format:
"feature1" "feature2"
"Doc1" .44 .22
"Doc2" .11 .6
"Doc3" .22 .2
B are my target values for the data, which are just numbers 1-100 associated with each document:
"Doc1" 50
"Doc2" 11
"Doc3" 99
Using regression.coef_, I get a list of coefficients, but not their corresponding features! How can I get the features? I'm guessing I need to modfy the structure of my B targets, but I don't know how.
What I found to work was:
X = your independent variables
coefficients = pd.concat([pd.DataFrame(X.columns),pd.DataFrame(np.transpose(logistic.coef_))], axis = 1)
The assumption you stated: that the order of regression.coef_ is the same as in the TRAIN set holds true in my experiences. (works with the underlying data and also checks out with correlations between X and y)
You can do that by creating a data frame:
cdf = pd.DataFrame(regression.coef_, X.columns, columns=['Coefficients'])
print(cdf)
coefficients = pd.DataFrame({"Feature":X.columns,"Coefficients":np.transpose(logistic.coef_)})
I suppose you are working on some feature selection task. Well using regression.coef_ does get the corresponding coefficients to the features, i.e. regression.coef_[0] corresponds to "feature1" and regression.coef_[1] corresponds to "feature2". This should be what you desire.
Well I in its turn recommend tree model from sklearn, which could also be used for feature selection. To be specific, check out here.
Coefficients and features in zip
print(list(zip(X_train.columns.tolist(),logreg.coef_[0])))
Coefficients and features in DataFrame
pd.DataFrame({"Feature":X_train.columns.tolist(),"Coefficients":logreg.coef_[0]})
This is the easiest and most intuitive way:
pd.DataFrame(logisticRegr.coef_, columns=x_train.columns)
or the same but transposing index and columns
pd.DataFrame(logisticRegr.coef_, columns=x_train.columns).T
Suppose your train data X variable is 'df_X' then you can map into a dictionary and feed into pandas dataframe to get the mapping:
pd.DataFrame(dict(zip(df_X.columns,model.coef_[0])),index=[0]).T
Try putting them in a series with the data columns names as index:
coeffs = pd.Series(model.coef_[0], index=X.columns.values)
coeffs.sort_values(ascending = False)