I have a sentence let's say :
{This is my test sentence}
And I would like to shorten by 3 characters at the end like this :
{This is my test sente}
Here is what I do in TCL language :
set sentence "This is my test sentence"
set remove "3"
set newSentence [string range $sentence 0 end-$remove]
and here is what I get :
"This"
I've tried with
set sentence {This is my test sentence}
and it is even worth because I got an error message
"failed: unmatched open brace in list"
Can someone have an idea where I am wrong ?
Or may be how I can shorten a string whatever spaces inside it ?
Thank you by advance for your help
Finally got it, I had to force it as a list :
set newSentence [list [string range $sentence 0 end-$remove]]
It seems my engine over interprete the output value.
Related
thanks to a fellow stack-overflower, i have recently learned how to use 'run-result' to pass patch attributes as input variables to a procedure. However, i am struggling using the same approach when i want to modify the patch attribute. To clarify, in the code below, i am successfully passing the attribute 'attr1' to Export.List.to.file, but when I pass it to Import.List.from.file, i get an 'this isn't something you can use set on' error in the line 'ask datum [set (run-result #attr) file-read]]'
can anyone help?
to setup
clear-all
let patch-list sort patches
ask patches [set attr1 random 10]
Export.List.to.file "attr1" patch-list "attr1.txt"
Import.List.from.file "attr2" patch-list "attr1.txt"
end
to Export.List.to.file [#attr #patch-list #filename]
let list1 map [ p -> [run-result #attr] of p ] #patch-list
carefully [file-delete #filename] []
file-open #filename
foreach list1 [?datum -> file-print ?datum]
file-close
end
to Import.List.from.file [#attr #patch-list #filename]
file-open #filename
foreach #patch-list [datum -> ask datum [set (run-result #attr) file-read]]
file-close
end
To be perfectly honest, I can't explain exactly why it doesn't work in the second case and does work in the first case. My best guess is that in the first case, the attribute is treated as a reporter, something to be used by other processes. In the second case, the attribute is treated as a property, for which different rules apply.
The workaround I would use is to turn the entire set command into a single string, and then turning it back into a command by using run. To combine the different parts of the command into a single string, you can use word: let commandstring (word "set " #attr-name " random 5"). Notice how I use quotation marks for "set " and " random 5" but I don't use them for #attr-name, since I don't want #attr-name in the final string, but rather the string contained within #attr-name. In my case that would be "attr3".
to go-3
change-attribute "attr3" patches
end
to change-attribute [#attr-name patchset]
let commandstring (word "set " #attr-name " random 5")
show commandstring
; this gives "set attr3 random 5"
ask patchset [run commandstring ]
end
I am trying to clean text strings containing any ' or ' (which includes an ; but if i add it here you will see just ' again. Because the the ANSI is also encoded by stackoverflow. The string content contains ' and when it does there is an error.
when i insert the string to my database i get this error:
psycopg2.ProgrammingError: syntax error at or near "s"
LINE 1: ...tment and has commenced a search for mr. whitnell's
the original string looks like this:
...a search for mr. whitnell's...
To remove the ' and ' ; I use:
stripped_content = stringcontent.replace("'","")
stripped_content = stringcontent.replace("' ;","")
any advice is welcome, best regards
When you try to replace("' ;","") it literally searching for "' ;" occurrences in string. You need to convert "' ;" to its character equivalent. Try this:
s = "That's how we 'roll"
r = s.replace(chr(int('''[2:])), "")
and with this chr(int('''[2:])) you'll get ' character.
Output:
Thats how we roll
Note
If you try to run this s.replace(chr(int('''[2:])), "") without saving your result in variable then your original string would not be affected.
I Googled it but i'm not able to find a GOOD solution.
My goal is to put a string which is composed of 6 lines in one string, and only one, in a variable.
For example, my string can look like :
a
b
c
and I want it to be in one string. I tried the thing witch ^, or with ECHO " " but it doesn't work : the cmd put an error "not recognized as an internal command" (and it's normal, it's just some sentences, not batch commands!)
Thanks, Clément
Not so simple but possible :
#echo off
REM Creating a Newline variable (the two blank lines are required!)
set NLM=^
set NL=^^^%NLM%%NLM%^%NLM%%NLM%
REM Example Usage:
setlocal enableDelayedExpansion
set "string_with_new_lines=a!nl!b!nl!c"
echo %string_with_new_lines%
Aacini has a simpler solution for this using empty variable,but I'm struggle to find the link.
Following the comments on the post answer of #npocmaka
It's currently in Python, so the """ thing works.
requete = """
PREFIX resources: <http://www.fluidops.com/resource/>
SELECT DISTINCT ?id ?marque ?modele WHERE {
?voiture resources:uid ?id.
?voiture resources:bpqmqvc ?marque. #myComment
?voiture resources:bpqmodvc ?modele
}
"""
The problem:
The objective is to convert: "tan(x)*arctan(x)"
Into: "np.tan(x)*np.arctan(x)"
What I've tried:
s = "tan(x)*arctan(x)"
s = s.replace('tan','np.tan')
Out: np.tan(x)*arcnp.tan(x)
However, using pythons replace method resulted in arcnp.tan.
Taking one additional step:
s = s.replace('arcnp.', 'np.arc')
Out: np.tan(x)*np.arctan(x)
Achieves the desired result... but this solution is sloppy and inefficient.
Is there a more efficient solution to this problem?
Any help is appreciated. Thanks in advance.
Here is a way to do the job:
var string = 'tan(x)*arctan(x)';
var res = string.replace(/\b(?:arc)?tan\b/g,'np.$&');
console.log(res);
Explanation:
/ : regex delimiter
\b : word boundary, make sure we don't have any word character before
(?:arc)? : non capture group, literally 'arc', optional
tan : literally 'tan'
\b : word boundary, make sure we don't have any word character after
/g : regex delimiter, global flag
Replace:
$& : means the whole match, ie. tan or arctan
You can use regular expression to solve your issue. Following code is in javascript. Since, u didn't mention the language you are using.
var string = 'tan(x)*arctan(x)*xxxtan(x)';
console.log(string.replace(/([a-z]+)?(tan)/g,'np.$1$2'));
I want to match a few lines for a string and a few numbers.
The lines can look like
" Code : 75.570 "
or
" ..dll : 13.559 1"
or
" ..node : 4.435 1.833 5461"
or
" ..NavRegions : 0.000 "
I want something like
local name, numberLeft, numberCenter, numberRight = line:match("regex");
But I'm very new to the string matching.
This pattern will work for every case:
%s*([%w%.]+)%s*:%s*([%d%.]+)%s*([%d%.]*)%s*([%d%.]*)
Short explanation: [] makes a set of characters (for example the decimals). The last to numbers use [set]* so an empty match is valid too. This way the number that haven't been found will effectively be assigned nil.
Note the difference between using + - * in patterns. More about patterns in the Lua reference.
This will match any combination of dots and decimals, so it might be useful to try and convert it to a number with tonumber() afterwards.
Some test code:
s={
" Code : 75.570 ",
" ..dll : 13.559 1",
" ..node : 4.435 1.833 5461",
" ..NavRegions : 0.000 "
}
for k,v in pairs(s) do
print(v:match('%s*([%w%.]+)%s*:%s*([%d%.]+)%s*([%d%.]*)%s*([%d%.]*)'))
end
Here is a starting point:
s=" ..dll : 13.559 1"
for w in s:gmatch("%S+") do
print(w)
end
You may save these words in a table instead of printing, of course. And skip the second word.
#Ihf Thank you, I now have a working solution.
local moduleInfo, name = {};
for word in line:gmatch("%S+") do
if (word~=":") then
word = word:gsub(":", "");
local number = tonumber(word);
if (number) then
moduleInfo[#moduleInfo+1] = number;
else
if (name) then
name = name.." "..word:gsub("%$", "");
else
name = word:gsub("%$", "");
end
end
end
end
#jpjacobs Really nice, thanks too. I'll rewrite my code for synthetic reasons ;-) I'll implement your regex of course.
I have no understanding of the Lua language, so I won't help you there.
But in Java this regex should match your input
"([a-z]*)\\s+:\\s+([\\.\\d]*)?\\s+([\\.\\d]*)?\\s+([\\.\\d]*)?"
You have to test each group to know if there is data left, center, right
Having a look at Lua, it could look like this. No guarantee, I did not see how to escape . (dot) which has a special meaning and also not if ? is usable in Lua.
"([a-z]*)%s+:%s+([%.%d]*)?%s+([%.%d]*)?%s+([%.%d]*)?"