I have got this problem. I´m trying to set text on a lineEdit object on pyqt4, then wait for a few seconds and changing the text of the same lineEdit. For this I´m using the time.sleep() function given on the python Time module. But my problem is that instead of setting the text, then waiting and finally rewrite the text on the lineEdit, it just waits the time it´s supposed to sleep and only shows the final text. My code is as follows:
from PyQt4 import QtGui
from gui import *
class Ventana(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.setupUi(self)
self.button.clicked.connect(self.testSleep)
def testSleep(self):
import time
self.lineEdit.setText('Start')
time.sleep(2)
self.lineEdit.setText('Stop')
def mainLoop(self, app ):
sys.exit( app.exec_())
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
window = Ventana()
window.show()
sys.exit(app.exec_())
You can't use time.sleep here because that freezes the GUI thread, so the GUI will be completely frozen during this time.
You should probably use a QTimer and use it's timeout signal to schedule a signal for deferred delivery, or it's singleShot method.
For example (adapted your code to make it run without dependencies):
from PyQt4 import QtGui, QtCore
class Ventana(QtGui.QWidget):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.setLayout(QtGui.QVBoxLayout())
self.lineEdit = QtGui.QLineEdit(self)
self.button = QtGui.QPushButton('clickme', self)
self.layout().addWidget(self.lineEdit)
self.layout().addWidget(self.button)
self.button.clicked.connect(self.testSleep)
def testSleep(self):
self.lineEdit.setText('Start')
QtCore.QTimer.singleShot(2000, lambda: self.lineEdit.setText('End'))
def mainLoop(self, app ):
sys.exit( app.exec_())
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
window = Ventana()
window.show()
sys.exit(app.exec_())
Also, take a look at the QThread sleep() function, it puts the current thread to sleep and allows other threads to run. https://doc.qt.io/qt-5/qthread.html#sleep
You can't use time.sleep here because that freezes the GUI thread, so the GUI will be completely frozen during this time.You can use QtTest module rather than time.sleep().
from PyQt4 import QtTest
QtTest.QTest.qWait(msecs)
So your code should look like:
from PyQt4 import QtGui,QtTest
from gui import *
class Ventana(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.setupUi(self)
self.button.clicked.connect(self.testSleep)
def testSleep(self):
import time
self.lineEdit.setText('Start')
QtTest.QTest.qWait(2000)
self.lineEdit.setText('Stop')
def mainLoop(self, app ):
sys.exit( app.exec_())
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
window = Ventana()
window.show()
sys.exit(app.exec_())
Related
I am programming a simple GUI, that will open a opencv window at a specific point. This window has some very basic keyEvents to control it. I want to advance this with a few functions. Since my QtGui is my Controller, I thought doing it with the KeyPressedEvent is a good way. My Problem is, that I cannot fire the KeyEvent, if I am active on the opencv window.
So How do I fire the KeyEvent, if my Gui is out of Focus?
Do I really need to use GrabKeyboard?
The following code reproduces my Problem:
import sys
from PyQt5.QtWidgets import (QApplication, QWidget)
from PyQt5.Qt import Qt
import cv2
class MainWindow(QWidget):
def __init__(self):
super().__init__()
self.first = True
def openselect(self):
im = cv2.imread(str('.\\images\\Steine\\0a5c8e512e.jpg'))
self.r = cv2.selectROI("Image", im)
def keyPressEvent(self, event):
if event.key() == Qt.Key_Space and self.first:
self.openselect()
self.first = False
print('Key Pressed!')
if __name__ == '__main__':
app = QApplication(sys.argv)
win = MainWindow()
win.show()
sys.exit(app.exec_())
The keyPressEvent method is only invoked if the widget has the focus so if the focus has another application then it will not be notified, so if you want to detect keyboard events then you must handle the OS libraries, but in python they already exist libraries that report those changes as pyinput(python -m pip install pyinput):
import sys
from PyQt5 import QtCore, QtWidgets
from pynput.keyboard import Key, Listener, KeyCode
class KeyMonitor(QtCore.QObject):
keyPressed = QtCore.pyqtSignal(KeyCode)
def __init__(self, parent=None):
super().__init__(parent)
self.listener = Listener(on_release=self.on_release)
def on_release(self, key):
self.keyPressed.emit(key)
def stop_monitoring(self):
self.listener.stop()
def start_monitoring(self):
self.listener.start()
class MainWindow(QtWidgets.QWidget):
pass
if __name__ == "__main__":
app = QtWidgets.QApplication(sys.argv)
monitor = KeyMonitor()
monitor.keyPressed.connect(print)
monitor.start_monitoring()
window = MainWindow()
window.show()
sys.exit(app.exec_())
I have created a form using PyQt4 which has a push button. On this push button I want to call another python script which looks like this:
File1.py:
import sys
from PyQt4 import QtCore, QtGui
from file1_ui import Ui_Form
class MyForm(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_Form()
self.ui.setupUi(self)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = MyForm()
myapp.show()
sys.exit(app.exec_())
File1_ui.py
from PyQt4 import QtCore, QtGui
try:
_fromUtf8 = QtCore.QString.fromUtf8
except AttributeError:
_fromUtf8 = lambda s: s
class Ui_Form(object):
def setupUi(self, Form):
Form.setObjectName(_fromUtf8("Form"))
Form.resize(400, 300)
self.pushButton = QtGui.QPushButton(Form)
self.pushButton.setGeometry(QtCore.QRect(120, 200, 95, 20))
self.pushButton.setObjectName(_fromUtf8("pushButton"))
self.retranslateUi(Form)
QtCore.QObject.connect(self.pushButton, QtCore.SIGNAL(_fromUtf8("clicked()")), Form.close)
QtCore.QMetaObject.connectSlotsByName(Form)
def retranslateUi(self, Form):
Form.setWindowTitle(QtGui.QApplication.translate("Form", "Form", None, QtGui.QApplication.UnicodeUTF8))
self.pushButton.setText(QtGui.QApplication.translate("Form", "Close", None, QtGui.QApplication.UnicodeUTF8))
File2.py
import sys
from PyQt4 import Qt
from taurus.qt.qtgui.application import TaurusApplication
app = TaurusApplication(sys.argv)
panel = Qt.QWidget()
layout = Qt.QHBoxLayout()
panel.setLayout(layout)
from taurus.qt.qtgui.panel import TaurusForm
panel = TaurusForm()
model = [ 'test/i1/1/%s' % p for p in props ]
panel.setModel(model)
panel.show()
sys.exit(app.exec_())
File1_ui.py is created from the Qtdesigner and then I am using File1.py to execute it.So File2.py when executed alone opens up a panel and displays few attributes.I want this script to be called on the button click in the first form(file1.py) which I created using Qtdesigner.Could you let me know how I could achieve this functionality.Thanks.
You will need to make some modifications to File2.py to make the appropriate calls depending on whether it is running standalone or not. When you are launching the script via File1.py there will already be a QApplication instance with event loop running, so trying to create another and run its event loop will cause problems.
Firstly, move the core part of your script into its own function. This will allow you to easily call it from File1.py. You can then handle the case where the script is running standalone and needs to create a QApplication instance and start its event loop. (I am not familiar the the taurus library you are using, but you can probably substitute TaurusApplication for QtGui.QApplication)
File2.py:
import sys
from PyQt4 import QtCore, QtGui
def runscript():
panel = QtGui.QWidget()
layout = QtGui.QHBoxLayout(panel)
return panel # Must return reference or panel will be deleted upon return
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
panel = runscript()
panel.show()
sys.exit(app.exec_())
Assuming your files are in the same directory you can simply write import File2 and use File2.runscript() to run your code. You then just need to connect the function to your pushbuttons clicked() signal to run it. The only problem here is that the reference to the QWidget returned from the runscript() function will be lost (and the object deleted) if you connect directly to runscript(). For this reason I created a method launch_script() which saves a reference in MyForm.
File1.py:
import sys
from PyQt4 import QtCore, QtGui
from file1_ui import Ui_Form
import File2
class MyForm(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_Form()
self.ui.setupUi(self)
# This is a bit of a hack.
self.ui.pushButton.clicked.connect(self.launch_script)
def launch_script(self):
self.panel = File2.runscript()
self.panel.show()
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = MyForm()
myapp.show()
sys.exit(app.exec_())
I don't use Qt Designer, so I don't know the correct way to go about connecting the signal to launch_script(). The code I have written should work, but obviously violates OOP principles and is dependent on the name of the pushbutton widget assigned by the software.
I have a pyqt GUI and a method[BigramClassification()]which causes the GUI to hang for several seconds. Therefore, i figured out threading need to be used. So after reading several tutorials i came up with the following code.
import sys,os
from PyQt4 import QtCore, QtGui
from PyQt4.QtCore import QThread
import time
class MyForm(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_MainWindow()
self.ui.setupUi(self)
self.ui.lblHistory.setPixmap(QtGui.QPixmap(os.getcwd() + "/historygraph.png"))
self.workerThread=WorkingThread()
self.ui.pushButton.clicked.connect(self.generateDetails)
self.ui.btnsubmitsettings.clicked.connect(self.addDetails)
def generateDetails(self):
self.workerThread.start()
self.ui.lblHistory.setPixmap(QtGui.QPixmap(os.getcwd() + "/historygraph.png"))
self.addPiechart()
self.addWordCloud()
self.summaryText()
def addPiechart(self):
print ("Added")
def addWordCloud(self):
print ("Added")
def addDetails(self):
def summaryText(self):
print("Added")
class WorkingThread(QThread):
def __init__(self, parent=None):
super(self.__class__, self).__init__(parent)
def run(self):
BigramsClassifier()
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = MyForm()
myapp.show()
sys.exit(app.exec_())
The problem i have is when i run this and click on pushButton the thread starts but also executes the methods after the start() as seen in def generateDetails(self): I need to prepare this code so that the methods in def generateDetails(self): executes after the thread is done executing with the heavy method BigramClassification()execution.
Summary How can i stop the auto execution of the methods in def generateDetails(self): but only after the method BigramClassification() is completed.
EDIT This error is thrown up when i try to close the GUI.
Connect a slot to the thread's finished signal which can performs other actions once the long-running task is completed:
class MyForm(QtGui.QMainWindow):
def __init__(self, parent=None):
...
self.workerThread = WorkingThread()
self.workerThread.finished.connect(self.doOtherStuff)
...
def generateDetails(self):
if not self.workerThread.isRunning():
self.workerThread.start()
def doOtherStuff(self):
self.ui.lblHistory.setPixmap(QtGui.QPixmap(os.getcwd() + "/historygraph.png"))
self.addPiechart()
self.addWordCloud()
self.summaryText()
I have written python pyqt code to open a new window with a label from another window on a button click. The issue is ,new window exits as soon as it opens.How do i fix this.
The code I wrote is
import sys
from PyQt4 import QtGui,QtCore
class Window(QtGui.QWidget):
def __init__(self):
super(Window,self).__init__()
self.btn=QtGui.QPushButton('button',self)
self.btn.clicked.connect(display)
self.show()
class display(QtGui.QWidget):
def __init__(self):
super(display,self).__init__()
self.lab=QtGui.QLabel()
self.lab.setText("hi")
self.show()
def main():
App=QtGui.QApplication(sys.argv)
Gui=Window()
sys.exit(App.exec_())
main()
You need to keep a reference to the QWidget object for your second window. Currently when you click the button, the clicked signal is fired and it calls disp1. That creates the widget, but then it is immediately garbage collected.
Instead do this to keep a reference:
import sys
from PyQt4 import QtGui,QtCore
class Window(QtGui.QWidget):
def __init__(self):
super(Window,self).__init__()
self.btn=QtGui.QPushButton('button',self)
self.btn.clicked.connect(self.open_new_window)
self.show()
def open_new_window(self):
# creates the window and saves a reference to it in self.second_window
self.second_window = disp1()
class displ(QtGui.QWidget):
def __init__(self):
super(displ,self).__init__()
self.lab=QtGui.QLabel()
self.lab.setText("hello")
self.show()
def main():
App=QtGui.QApplication(sys.argv)
Gui=Window()
sys.exit(App.exec_())
main()
When passing a function as parameter, maybe it's better not to include the parentheses? Try
sys.exit(App.exec_)
Instead of
sys.exit(App.exec_())
I'd like to be able to have all text highlighted in my lineEdit. However, the default selectAll() doesn't seem to do so.
import sys
from PyQt4 import QtCore, QtGui
from gui import Ui_Form
class MyForm(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_Form()
self.ui.setupUi(self)
self.ui.lineEdit.setText("Type something here!")
self.ui.lineEdit.selectAll()
QtCore.QObject.connect(self.ui.pushButton, QtCore.SIGNAL("clicked()"), self.ui.textEdit.clear)
QtCore.QObject.connect(self.ui.lineEdit, QtCore.SIGNAL("returnPressed()"), self.add_entry)
def add_entry(self):
self.ui.lineEdit.selectAll()
self.ui.lineEdit.cut()
self.ui.textEdit.append("")
self.ui.textEdit.paste()
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = MyForm()
myapp.show()
sys.exit(app.exec_())
I want to select the text on the lineEdit in the default constructor; however, it doesn't. Any reason for this? What should I be doing instead to accomplish this?