Implementing a recursive cache in Rust [duplicate] - rust

Question

This question already has answers here:
Returning a reference from a HashMap or Vec causes a borrow to last beyond the scope it's in?
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When is it necessary to circumvent Rust's borrow checker?
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Closed 1 year ago.
use std::collections::HashMap;
#[derive(Clone, Hash, Eq, PartialEq)]
struct HeavyCloneKey;
struct Map<V> {
map : HashMap<HeavyCloneKey, V>
}
impl<V> Map<V> {
pub fn get_mut(&mut self, key: &HeavyCloneKey) -> Option<&mut V> {
if let Some(v) = self.map.get_mut(key) {
return Some(v);
}
// some logic to decide if create a new value;
if self.map.len() > 64 {
None
} else {
let v = create_v_with_long_code();
let v = self.map.entry(key.clone()).or_insert_with(|| v);
Some(v)
}
}
}
fn create_v_with_long_code<V>() -> V {
unimplemented!()
}
fn main() {
}
https://play.rust-lang.org/?version=stable&mode=debug&edition=2018&gist=19c45ebfb1a39271ff5bd2443399596a
I can't understand why this can't work:
error[E0502]: cannot borrow `self.map` as immutable because it is also borrowed as mutable
--> src/main.rs:18:12
|
12 | pub fn get_mut(&mut self, key: &HeavyCloneKey) -> Option<&mut V> {
| - let's call the lifetime of this reference `'1`
13 | if let Some(v) = self.map.get_mut(key) {
| -------- mutable borrow occurs here
14 | return Some(v);
| ------- returning this value requires that `self.map` is borrowed for `'1`
...
18 | if self.map.len() > 64 {
| ^^^^^^^^ immutable borrow occurs here
These two borrows won't appear at the same time, what's the problem? How can I do this?
Although the code can be compiled by using contains_key before get_mut, it pays more overhead;

Answer 1

It helps a little to desugar the lifetimes by providing your own annotations on the references. It doesn't really matter here though as lifetimes aren't actually the issue.
pub fn get_mut<'s, 'k>(&'s mut self, key: &'k HeavyCloneKey) -> Option<&'s mut V> {
This gets us a little better error message:
error[E0502]: cannot borrow `self.map` as immutable because it is also borrowed as mutable
--> src/main.rs:18:12
|
12 | pub fn get_mut<'s, 'k>(&'s mut self, key: &'k HeavyCloneKey) -> Option<&'s mut V> {
| -- lifetime `'s` defined here
13 | if let Some(v) = self.map.get_mut(key) {
| -------- mutable borrow occurs here
14 | return Some(v);
| ------- returning this value requires that `self.map` is borrowed for `'s`
...
18 | if self.map.len() > 64 {
| ^^^^^^^^ immutable borrow occurs here
error[E0499]: cannot borrow `self.map` as mutable more than once at a time
--> src/main.rs:22:21
|
12 | pub fn get_mut<'s, 'k>(&'s mut self, key: &'k HeavyCloneKey) -> Option<&'s mut V> {
| -- lifetime `'s` defined here
13 | if let Some(v) = self.map.get_mut(key) {
| -------- first mutable borrow occurs here
14 | return Some(v);
| ------- returning this value requires that `self.map` is borrowed for `'s`
...
22 | let v = self.map.entry(key.clone()).or_insert_with(|| v);
| ^^^^^^^^ second mutable borrow occurs here
We have two errors here. Both stem from the rust compiler not being able to tell that we don't use the mutable borrow from line 13 later in the function.
The first says "you grabbed a mutable reference to self here so we can't let you have an immutable reference there". The second says "you grabbed a mutable reference to self here so we can't let you have a second mutable reference there".
How do we fix this? By making it clearer to the compiler that we'll never hold that first mutable reference. We can do this by manually checking if that key exists first. Change this
if let Some(v) = self.map.get_mut(key) {
return Some(v);
}
to this
if self.map.contains_key(key) {
return self.map.get_mut(key);
}
and it will compile.