I am having a hard time sending css files with express. The way my project is structured is I have a src folder and inside the src folder is the app.js for the express code as well as another folder titled "public". Inside of this public folder I have an experience.html page as well as an experience.css page. I can only get the html to render on the page and cannot get the css styling to show up. Attached is my code for the app.js page.
const express = require('express');
const app = express ();
const port = process.env.Port || 3000;
app.get('/experience', (req, res) => {
res.sendFile(__dirname+'/public/experience.html');
})
app.use(express.static('/public/experience.css'))
app.listen(port);
Just using middleware is enough, you don't need dedicated get routes to the files unless you want to mask some of the filenames.
This should work for your case
const express = require('express');
const path = require('path');
const app = express();
app.use(express.static(path.join(__dirname, 'public')));
app.listen(3000);
You can access them on http://localhost:3000/experience.html, http://localhost:3000/experience.css
You can use the Express static middleware with the path to the public folder.
Once you do that, you can expose a route to the files (or) you can access at localhost:9900
//Import modules
const express = require("express");
const path = require("path");
// Define PORT for HTTP Server
const PORT = 9900;
// Initialize Express
const app = express();
app.use(express.static(path.join(__dirname, "public")));
app.listen(PORT, (err) => {
console.log(`Your dog server is up and running!`);
});
Related
In my nodejs server file, I am trying to server static folder the code goes as below :-
server.js
const express = require("express");
const app = express();
require("dotenv").config();
const cookieParser = require("cookie-parser");
const bodyParser = require("body-parser");
const { connectDB } = require("./config/connectDB");
connectDB();
const upload = require("./routes/uploadsFile");
const user = require("./routes/user");
const path = require("path");
app.use(bodyParser.json());
app.use(bodyParser.urlencoded({ extended: true }));
app.use(cookieParser());
app.use(express.json("content-type", "application/json"));
const publicFolder = path.join(__dirname, "../uploads");
console.log(publicFolder);
app.use(express.static(publicFolder));
app.use("/api/v1/upload", upload);
app.use("/api/v1/user", user);
const PORT = process.env.PORT || 3030;
app.listen(PORT, () => {
console.log(`Server Started Listening On PORT ${PORT}`);
});
The folder structures goes below :-
The same error I am getting as everyone
Cannot GET /uploads/image/actual-size/banner-Image-1.jpg
Can someone please help me. I have gone through many problem already answered like this on Stackoverflow, but unable to get the proper solution.
You defined uploads to be the root directory for serving static files which means the request paths must not start with /uploads. In your example above change the path to:
/image/actual-size/banner-Image-1.jpg
From the docs:
Express looks up the files relative to the static directory, so the
name of the static directory is not part of the URL.
I got the solution of the problem.
I was calling the GET URL by
localhost:${port}/uploads/image/actual-size/image.jpg
But I had to call like this because uploads folder is being server by default
localhost:${port}/image/actual-size/image.jpg
I want to serve index.html and /media subdirectory as static files. The index file should be served both at /index.html and / URLs.
I have
web_server.use("/media", express.static(__dirname + '/media'));
web_server.use("/", express.static(__dirname));
but the second line apparently serves the entire __dirname, including all files in it (not just index.html and media), which I don't want.
I also tried
web_server.use("/", express.static(__dirname + '/index.html'));
but accessing the base URL / then leads to a request to web_server/index.html/index.html (double index.html component), which of course fails.
Any ideas?
By the way, I could find absolutely no documentation in Express on this topic (static() + its params)... frustrating. A doc link is also welcome.
If you have this setup
/app
/public/index.html
/media
Then this should get what you wanted
var express = require('express');
//var server = express.createServer();
// express.createServer() is deprecated.
var server = express(); // better instead
server.configure(function(){
server.use('/media', express.static(__dirname + '/media'));
server.use(express.static(__dirname + '/public'));
});
server.listen(3000);
The trick is leaving this line as last fallback
server.use(express.static(__dirname + '/public'));
As for documentation, since Express uses connect middleware, I found it easier to just look at the connect source code directly.
For example this line shows that index.html is supported
https://github.com/senchalabs/connect/blob/2.3.3/lib/middleware/static.js#L140
In the newest version of express the "createServer" is deprecated. This example works for me:
var express = require('express');
var app = express();
var path = require('path');
//app.use(express.static(__dirname)); // Current directory is root
app.use(express.static(path.join(__dirname, 'public'))); // "public" off of current is root
app.listen(80);
console.log('Listening on port 80');
express.static() expects the first parameter to be a path of a directory, not a filename. I would suggest creating another subdirectory to contain your index.html and use that.
Serving static files in Express documentation, or more detailed serve-static documentation, including the default behavior of serving index.html:
By default this module will send “index.html” files in response to a request on a directory. To disable this set false or to supply a new index pass a string or an array in preferred order.
res.sendFile & express.static both will work for this
var express = require('express');
var app = express();
var path = require('path');
var public = path.join(__dirname, 'public');
// viewed at http://localhost:8080
app.get('/', function(req, res) {
res.sendFile(path.join(public, 'index.html'));
});
app.use('/', express.static(public));
app.listen(8080);
Where public is the folder in which the client side code is
As suggested by #ATOzTOA and clarified by #Vozzie, path.join takes the paths to join as arguments, the + passes a single argument to path.
const path = require('path');
const express = require('express');
const app = new express();
app.use(express.static('/media'));
app.get('/', (req, res) => {
res.sendFile(path.resolve(__dirname, 'media/page/', 'index.html'));
});
app.listen(4000, () => {
console.log('App listening on port 4000')
})
If you have a complicated folder structure, such as
- application
- assets
- images
- profile.jpg
- web
- server
- index.js
If you want to serve assets/images from index.js
app.use('/images', express.static(path.join(__dirname, '..', 'assets', 'images')))
To view from your browser
http://localhost:4000/images/profile.jpg
If you need more clarification comment, I'll elaborate.
use below inside your app.js
app.use(express.static('folderName'));
(folderName is folder which has files) - remember these assets are accessed direct through server path (i.e. http://localhost:3000/abc.png (where as abc.png is inside folderName folder)
npm install serve-index
var express = require('express')
var serveIndex = require('serve-index')
var path = require('path')
var serveStatic = require('serve-static')
var app = express()
var port = process.env.PORT || 3000;
/**for files */
app.use(serveStatic(path.join(__dirname, 'public')));
/**for directory */
app.use('/', express.static('public'), serveIndex('public', {'icons': true}))
// Listen
app.listen(port, function () {
console.log('listening on port:',+ port );
})
I would add something that is on the express docs, and it's sometimes misread in tutorials or others.
app.use(mountpoint, middleware)
mountpoint is a virtual path, it is not in the filesystem (even if it actually exists). The mountpoint for the middleware is the app.js folder.
Now
app.use('/static', express.static('public')`
will send files with path /static/hell/meow/a.js to /public/hell/meow/a.js
This is the error in my case when I provide links to HTML files.
before:
<link rel="stylesheet" href="/public/style.css">
After:
<link rel="stylesheet" href="/style.css">
I just removed the static directory path from the link and the error is gone. This solves my error one thing more don't forget to put this line where you are creating the server.
var path = require('path');
app.use(serveStatic(path.join(__dirname, 'public')));
You can achieve this by just passing the second parameter express.static() method to specify index files in the folder
const express = require('express');
const app = new express();
app.use(express.static('/media'), { index: 'whatever.html' })
I continue to get the error below when I try to build a production version of my app. Npm run build is looking for my index.html file in public, but it thinks my public folder is in my root directory whereas it is in the client subfolder.
Could not find a required file.
Name: index.html
Searched in: C:\Users\wharfchillin\wharf-chillin-app\public
My public folder is located in a sub-folder of my app:
client
--->public
------>index.html
I have tried to make this clear in my server.js file in numerous ways:
UPDATED
const express = require("express");
const mongoose = require("mongoose");
const bodyParser = require("body-parser");
const passport = require("passport");
const path = require('path');
const users = require("./routes/api/users");
const plaid = require("./routes/api/plaid");
const app = express();
const publicPath = path.resolve(__dirname);
// Bodyparser middleware
app.use(
bodyParser.urlencoded({
extended: false
})
);
app.use(bodyParser.json());
app.use(express.static(publicPath));
app.use('*', (req, res) => {
res.sendFile(path.resolve(publicPath));
});
// production mode
if(process.env.NODE_ENV === 'production')
app.use(express.static(path.resolve(publicPath)));
console.log('test')
console.log(publicPath)
Any advice would be more than appreciated.
You are using window os, window os's path use backward slash, but in your node app, you are define the path using forward slash, node has api to handle this, path.resolve. Stop using path.join
I have an app.js script that contains an express node website
const express = require('express');
const app = express();
const path = require('path');
const router = express.Router();
const fs = require('fs');
var bodyParser = require('body-parser');
app.use(bodyParser.json());
app.use(bodyParser.urlencoded({
extended: true
}));
app.use(express.static('public'));
…
app.listen(3000, function () {
console.log('avalaible at http://localhost:3000');
});
until now I launch website by writing in cmd
node ./app.js
Then I go to adress http://localhost:3000 in my browser
I would have a batch or another way to those operations just by doucle click on a file
Could you help me please?
In the Node js project folder create a .bat file and put this on it:
node ./app.js
start "" http://localhost:3000
when you click the file this should launch your nodejs app and open your default browser on the given address.
I want to serve index.html and /media subdirectory as static files. The index file should be served both at /index.html and / URLs.
I have
web_server.use("/media", express.static(__dirname + '/media'));
web_server.use("/", express.static(__dirname));
but the second line apparently serves the entire __dirname, including all files in it (not just index.html and media), which I don't want.
I also tried
web_server.use("/", express.static(__dirname + '/index.html'));
but accessing the base URL / then leads to a request to web_server/index.html/index.html (double index.html component), which of course fails.
Any ideas?
By the way, I could find absolutely no documentation in Express on this topic (static() + its params)... frustrating. A doc link is also welcome.
If you have this setup
/app
/public/index.html
/media
Then this should get what you wanted
var express = require('express');
//var server = express.createServer();
// express.createServer() is deprecated.
var server = express(); // better instead
server.configure(function(){
server.use('/media', express.static(__dirname + '/media'));
server.use(express.static(__dirname + '/public'));
});
server.listen(3000);
The trick is leaving this line as last fallback
server.use(express.static(__dirname + '/public'));
As for documentation, since Express uses connect middleware, I found it easier to just look at the connect source code directly.
For example this line shows that index.html is supported
https://github.com/senchalabs/connect/blob/2.3.3/lib/middleware/static.js#L140
In the newest version of express the "createServer" is deprecated. This example works for me:
var express = require('express');
var app = express();
var path = require('path');
//app.use(express.static(__dirname)); // Current directory is root
app.use(express.static(path.join(__dirname, 'public'))); // "public" off of current is root
app.listen(80);
console.log('Listening on port 80');
express.static() expects the first parameter to be a path of a directory, not a filename. I would suggest creating another subdirectory to contain your index.html and use that.
Serving static files in Express documentation, or more detailed serve-static documentation, including the default behavior of serving index.html:
By default this module will send “index.html” files in response to a request on a directory. To disable this set false or to supply a new index pass a string or an array in preferred order.
res.sendFile & express.static both will work for this
var express = require('express');
var app = express();
var path = require('path');
var public = path.join(__dirname, 'public');
// viewed at http://localhost:8080
app.get('/', function(req, res) {
res.sendFile(path.join(public, 'index.html'));
});
app.use('/', express.static(public));
app.listen(8080);
Where public is the folder in which the client side code is
As suggested by #ATOzTOA and clarified by #Vozzie, path.join takes the paths to join as arguments, the + passes a single argument to path.
const path = require('path');
const express = require('express');
const app = new express();
app.use(express.static('/media'));
app.get('/', (req, res) => {
res.sendFile(path.resolve(__dirname, 'media/page/', 'index.html'));
});
app.listen(4000, () => {
console.log('App listening on port 4000')
})
If you have a complicated folder structure, such as
- application
- assets
- images
- profile.jpg
- web
- server
- index.js
If you want to serve assets/images from index.js
app.use('/images', express.static(path.join(__dirname, '..', 'assets', 'images')))
To view from your browser
http://localhost:4000/images/profile.jpg
If you need more clarification comment, I'll elaborate.
use below inside your app.js
app.use(express.static('folderName'));
(folderName is folder which has files) - remember these assets are accessed direct through server path (i.e. http://localhost:3000/abc.png (where as abc.png is inside folderName folder)
npm install serve-index
var express = require('express')
var serveIndex = require('serve-index')
var path = require('path')
var serveStatic = require('serve-static')
var app = express()
var port = process.env.PORT || 3000;
/**for files */
app.use(serveStatic(path.join(__dirname, 'public')));
/**for directory */
app.use('/', express.static('public'), serveIndex('public', {'icons': true}))
// Listen
app.listen(port, function () {
console.log('listening on port:',+ port );
})
I would add something that is on the express docs, and it's sometimes misread in tutorials or others.
app.use(mountpoint, middleware)
mountpoint is a virtual path, it is not in the filesystem (even if it actually exists). The mountpoint for the middleware is the app.js folder.
Now
app.use('/static', express.static('public')`
will send files with path /static/hell/meow/a.js to /public/hell/meow/a.js
This is the error in my case when I provide links to HTML files.
before:
<link rel="stylesheet" href="/public/style.css">
After:
<link rel="stylesheet" href="/style.css">
I just removed the static directory path from the link and the error is gone. This solves my error one thing more don't forget to put this line where you are creating the server.
var path = require('path');
app.use(serveStatic(path.join(__dirname, 'public')));
You can achieve this by just passing the second parameter express.static() method to specify index files in the folder
const express = require('express');
const app = new express();
app.use(express.static('/media'), { index: 'whatever.html' })