Count Consecutive Numbers in Column - excel

Question

I am looking to count the occurrences of consecutive numbers in a column and cannot seem to find a logical way to calculate this within a loop.
My column of values is simply entries of 0 or 1. What I want to is count each time there is two 0's in a row, three 0's a row, four 0's in a row and so on. The maximum number of times I would expect a consecutive number is 15.
Ideally, I would like the output for each occurrence entered into a table.
I have provided a snapshot below of the column in question.
My attempts so far consist of looping through the column checking for two 0's in a row, starting at row 2 but this causes issues when I have more than two 0's in a row.
'Check for 2
Dim TwoCount, RowNo As Integer, LastRow As Long
LastRow = Sheets("Data").Range("A165536").End(xlUp).Row
TwoCount = 0
RowNo = 2
For i = 2 To LastRow
If Sheets("Data").Range("H" & RowNo).Value = 1 Then
RowNo = RowNo + 1
Else
If Sheets("Data").Range("H" & RowNo).Value = 0 Then
TwoCount = 1
RowNo = RowNo + 1
If Sheets("Data").Range("H" & RowNo).Value = 0 Then
TwoCount = 2
RowNo = RowNo + 1
If Sheets("Data").Range("H" & RowNo).Value = 1 Then
End If
End If
End If
End If
Next i
I welcome any suggestions to how I should approach this? Whether it's easier as a formula or array formula.
Desired output

Answer 1

Count Consecutive Occurrences
Option Explicit
Sub CountConsecutive()
' Source
Const sName As String = "Data"
Const sFirstCellAddress As String = "H1"
Const sCriteria As Variant = 0
' Destination
Const dName As String = "Data"
Const dFirstCellAddress As String = "J1"
Dim dHeaders As Variant
dHeaders = VBA.Array("Occurrences", "Number of Times")
' Workbook
Dim wb As Workbook: Set wb = ThisWorkbook ' workbook containing this code
' Write the values from the source column to an array.
Dim sws As Worksheet: Set sws = wb.Worksheets(sName)
Dim Data As Variant
Dim rCount As Long
With sws.Range(sFirstCellAddress)
Dim slCell As Range: Set slCell = .Resize(sws.Rows.Count - .Row + 1) _
.Find("*", , xlFormulas, , , xlPrevious)
If slCell Is Nothing Then Exit Sub
rCount = slCell.Row - .Row + 1
If rCount < 2 Then Exit Sub
Data = .Resize(rCount).Value
End With
' Count the occurrences by using a dictionary.
Dim dict As Object: Set dict = CreateObject("Scripting.Dictionary")
dict.CompareMode = vbTextCompare
Dim Key As Long
Dim r As Long
Dim cCount As Long
Dim MaxCount As Long
For r = 2 To rCount
Key = Data(r, 1)
If IsNumeric(Key) Then
If Key = sCriteria Then
cCount = cCount + 1
Else
If cCount > 0 Then
dict(cCount) = dict(cCount) + 1
If cCount > MaxCount Then MaxCount = cCount
cCount = 0
End If
End If
End If
Next r
If MaxCount = 0 Then Exit Sub
' Write the values from the dictionary to the array.
rCount = MaxCount + 1
ReDim Data(1 To rCount, 1 To 2)
Data(1, 1) = dHeaders(0)
Data(1, 2) = dHeaders(1)
For r = 2 To rCount
Data(r, 1) = r - 1
If dict.Exists(r - 1) Then
Data(r, 2) = dict(r - 1)
Else
Data(r, 2) = 0
End If
Next r
' Write the values from the array to the destination range.
Dim dws As Worksheet: Set dws = wb.Worksheets(dName)
With dws.Range(dFirstCellAddress).Resize(, 2)
.Resize(rCount).Value = Data
.Resize(dws.Rows.Count - .Row - rCount + 1).Offset(rCount).Clear
'.Font.Bold = True
'.EntireColumn.AutoFit
End With
'wb.save
MsgBox "Consecutive count created.", vbInformation
End Sub

Answer 2

COUNTING THE FREQUENCY OF CONSECUTIVE OCCURRENCES OF 0 IN A COLUMN
You may try this array formula as well,
• Formula used in cell L2
=SUMPRODUCT(--(FREQUENCY(
IF($H$2:$H$32=0,ROW($H$2:$H$32)),
IF($H$2:$H$32=1,ROW($H$2:$H$32)))=K2))
And Fill Down!
Note: Array formulas need to be entered by pressing CTRL + SHIFT + ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT key then hit ENTER. If you are using Excel 2021 or O365 you can only press ENTER.

Answer 3

Imagine your numbers Win/Lose in column A then add in cell B3 (not B2 this will stay empty) the following formula and copy it down:
=IF(AND(A3=0,A3<>A4),COUNTIF($A$2:A3,A3)-SUM($B$2:B2),"")
Then to count them just use =COUNTIF(B:B,E2) in F2 and copy it down.

Answer 4

You can read this requirements in two ways as I see it:
You can count an occurence of 1,2,3 and 4 in a sequence of 4 zero's;
You can count only the max occurence of the above;
I went with the assumptions of the latter:
Formula in C1:
=LET(X,SEQUENCE(15),Y,LEN(TEXTSPLIT(CONCAT(IF(A2:A32," ",1)),," ",1)),VSTACK({"Occurences of 0","Number of Times"},HSTACK(X,BYROW(X,LAMBDA(a,SUM(--(Y=a)))))))
Important note:
It may not be best to rely on CONCAT() since depending on the amount of rows you want to concatenate, it may strike a character limit. Instead you could try something like:
=LET(X,SEQUENCE(15),Y,LEN(TEXTSPLIT(REDUCE("",A2:A32,LAMBDA(a,b,a&IF(b," ",1))),," ",1)),VSTACK({"Occurences of 0","Number of Times"},HSTACK(X,BYROW(X,LAMBDA(a,SUM(--(Y=a)))))))
Also, please note that ms365 is required for the above functions to run properly (and at time of writing VSTACK(), HSTACK() and TEXTSPLIT() are still in the insider's BETA-channels.